CUET UG Chemistry Booster Test - 2 Factors and Theories
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QUESTION 1 OF 20
Arrange the following in decreasing order of the time taken for half of the original amount of N₂O₅ to decompose:
1. At 50°C
2. At 25°C
3. At 0°C
QUESTION 2 OF 20
When a Maxwell-Boltzmann distribution curve goes from t to (t + 10):
1. The maximum of the curve moves to a higher energy value.
2. The curve broadens out.
3. Total probability area under the curve increases.
4. The area showing the fraction of molecules having energy equal to or greater than activation energy gets doubled.
QUESTION 3 OF 20
In the plot of ln k versus 1/T derived from the Arrhenius equation, the y-intercept is equal to:
B.1/T
QUESTION 4 OF 20
Based on the table of units of rate constants, what are the units for a second order rate constant?
QUESTION 5 OF 20
Match List-I with List-II:
| List I | List II |
|---|---|
| 1. Threshold energy | a. Depends upon nature of reactants and products |
| 2. Activation Energy | b. Profile of energy change |
| 3. Reaction coordinate | c. Energy required to form activated complex |
| 4. Final enthalpy | d. Ea + energy possessed by reacting species |
QUESTION 6 OF 20
According to the Arrhenius equation, decreasing the activation energy will result in:
QUESTION 7 OF 20
The species formed at the peak of the potential energy vs reaction coordinate diagram is scientifically named:
QUESTION 8 OF 20
Regarding potential energy profiles of chemical reactions:
1. Final enthalpy of the reaction depends on the nature of reactants and products.
2. Energy is released when the complex decomposes to form products.
3. The activated complex exists for a very long time.
QUESTION 9 OF 20
When a substance's temperature is raised, what happens to the proportion of molecules with much higher energies on the distribution curve?
QUESTION 10 OF 20
Identify the type of statistical distribution used to plot the fraction of molecules with a given kinetic energy:
QUESTION 11 OF 20
Which thermodynamic property is definitively NOT altered by the addition of a catalyst?
QUESTION 12 OF 20
Statements regarding equilibrium and catalysts:
1. A catalyst catalyses the forward as well as the backward reactions to the same extent.
2. A catalyst changes the equilibrium constant to favor products.
3. A catalyst helps in attaining the equilibrium faster.
QUESTION 13 OF 20
Based on the passage, the true molecular nature of the hydrolysis of ethyl acetate is:
QUESTION 14 OF 20
Why does the rate of the reaction depend practically only on ethyl acetate?
QUESTION 15 OF 20
In the context of the intermediate complex theory, the intermediate has a:
QUESTION 16 OF 20
When a substance is added to a reaction and it reduces the rate rather than increasing it, it is properly named:
QUESTION 17 OF 20
Collision frequency (Z) is measured in terms of the number of collisions per unit time per unit:
QUESTION 18 OF 20
For complex molecules, the collision theory predicted rate constant often shows significant deviations because:
QUESTION 19 OF 20
Match List-I (Terms in Modified Collision Theory) with List-II (Meanings):
| List I | List II |
|---|---|
| 1. P | a. Fraction of molecules with sufficient energy |
| 2. ZAB | b. Activation energy |
| 3. Ea | c. Collision frequency |
| 4. e^(-Ea/RT) | d. Steric factor |
QUESTION 20 OF 20
Identify the reaction occurrence condition when bromoethane molecules collide with improper orientation:
Test Complete!
Answer Review
1 Arrange the following in decreasing order of the time taken for half of the original amount of N₂O₅ to decompose:
1. At 50°C
2. At 25°C
3. At 0°C
�� Higher temperature increases reaction rate. �� Faster reactions have shorter half-life. �� Lower temperature gives longer decomposition time.
The decomposition of N₂O₅ follows first-order kinetics. According to the Arrhenius equation, the rate constant increases with increase in temperature because a larger fraction of molecules possess energy greater than the activation energy. Therefore: At 0°C → Slowest reaction → Longest time for half decomposition At 25°C → Intermediate time At 50°C → Fastest reaction → Shortest time Hence, the decreasing order of time taken for half decomposition is: 3 > 2 > 1 Therefore, the correct answer is B. 3, 2, 1.
- �� Option A → Gives the reverse trend of temperature dependence.
- �� Option C → Incorrectly places 25°C before 0°C.
- �� Option D → Incorrect ordering of 50°C and 25°C.
Used: Logical Analysis
- Application
- Higher temperature increases rate constant and decreases decomposition time.
- Final Logic
- Lower temperature → Longer half-life → Greater time required.
- Hotter = Faster = Less Time
2 When a Maxwell-Boltzmann distribution curve goes from t to (t + 10):
1. The maximum of the curve moves to a higher energy value.
2. The curve broadens out.
3. Total probability area under the curve increases.
4. The area showing the fraction of molecules having energy equal to or greater than activation energy gets doubled.
�� Increasing temperature shifts the curve rightward. �� The curve becomes broader. �� Total area under the curve remains constant.
When temperature increases by 10°C, the Maxwell-Boltzmann distribution curve shifts toward higher energy values and becomes broader. Consequently, the fraction of molecules possessing energy greater than the activation energy increases significantly, often approximately doubling for many reactions. Statement 1 is correct because the peak shifts toward higher energy. Statement 2 is correct because the distribution broadens. Statement 3 is incorrect because the total area under the curve always remains equal to unity. Statement 4 is considered correct according to NCERT's empirical observation that reaction rate often doubles with a 10°C rise due to increased energetic molecules. Therefore, Statements 1, 2 and 4 are correct.
- �� Option B → Statement 3 is incorrect.
- �� Option C → Statement 1 is also correct.
- �� Option D → Statement 3 is incorrect and Statement 2 is omitted.
Used: Elimination
- Application
- Identify the statement that violates properties of probability distributions.
- Final Logic
- Total area remains constant while energetic molecules increase.
- Hotter → Broader → More Energetic
3 In the plot of ln k versus 1/T derived from the Arrhenius equation, the y-intercept is equal to:
B.1/T
�� Arrhenius equation can be linearized. �� ln k vs 1/T gives a straight line. �� Intercept equals ln A.
The Arrhenius equation is: k = Ae^(-Ea/RT) Taking natural logarithm: ln k = ln A − (Ea/R)(1/T) Comparing with the straight-line equation: y = c + mx we obtain: y = ln k x = 1/T Slope = -Ea/R Intercept = ln A Hence, the y-intercept is ln A. Therefore, the correct answer is D. ln A.
- �� Option A → Represents the slope component.
- �� Option B → Represents the x-axis variable.
- �� Option C → Activation energy itself is not the intercept.
Used: Substitution
- Application
- Compare the Arrhenius equation with y = mx + c.
- Final Logic
- Intercept corresponds to ln A.
- Arrhenius Intercept = ln A
4 Based on the table of units of rate constants, what are the units for a second order rate constant?
�� Units depend on reaction order. �� Second order rate constants have concentration⁻¹ terms. �� Derived from rate law dimensions.
For a second order reaction: Rate = k[R]² Rate units: mol L⁻¹ s⁻¹ Therefore: k = (mol L⁻¹ s⁻¹)/(mol² L⁻²) = L mol⁻¹ s⁻¹ Hence, the unit of a second order rate constant is: L mol⁻¹ s⁻¹ Therefore, the correct answer is C.
- �� Option A → Unit of reaction rate, not second-order k.
- �� Option B → Unit of first-order rate constant.
- �� Option D → Corresponds to third-order rate constant.
Used: Dimensional/Unit Analysis
- Application
- Substitute rate law units and simplify.
- Final Logic
- Second order k = Rate ÷ Concentration².
- Order 2 → One L and One mol⁻¹
5 Match List-I with List-II:
| List I | List II |
|---|---|
| 1. Threshold energy | a. Depends upon nature of reactants and products |
| 2. Activation Energy | b. Profile of energy change |
| 3. Reaction coordinate | c. Energy required to form activated complex |
| 4. Final enthalpy | d. Ea + energy possessed by reacting species |
�� Threshold energy is minimum collision energy. �� Activation energy forms activated complex. �� Reaction coordinate shows reaction progress.
In chemical kinetics: 1. Threshold energy is the minimum energy required for effective collision and equals activation energy plus energy already possessed by reactants. 2. Activation energy is the energy required to form the activated complex. 3. Reaction coordinate represents the profile of energy change during conversion of reactants to products. 4. Final enthalpy depends upon the nature of reactants and products. Therefore: 1 → d 2 → c 3 → b 4 → a Hence, the correct answer is A.
- �� Option B → Incorrectly assigns threshold energy and reaction coordinate.
- �� Option C → Activation energy and reaction coordinate are mismatched.
- �� Option D → Final enthalpy and activation energy are incorrectly paired.
Used: NCERT Recall
- Application
- Recall definitions from the potential energy profile diagram.
- Final Logic
- Each energy term has a specific NCERT definition.
- Coordinate = Path
6 According to the Arrhenius equation, decreasing the activation energy will result in:
�� Rate constant depends exponentially on activation energy. �� Lower activation energy increases successful collisions. �� Reaction rate increases significantly.
According to the Arrhenius equation: k = Ae^(-Ea/RT) where Ea is the activation energy. Since Ea appears in the exponent with a negative sign, decreasing Ea makes the exponent less negative. As a result, the value of e^(-Ea/RT) increases exponentially. Consequently, the rate constant k increases rapidly. This is the fundamental reason why catalysts increase reaction rates—they lower the activation energy barrier. Therefore, decreasing the activation energy causes an exponential increase in the rate constant. Hence, the correct answer is B. An exponential increase in the rate constant.
- �� Option A → Lowering Ea increases, not decreases, the rate constant.
- �� Option C → Steric factor is independent of activation energy.
- �� Option D → The reaction rate increases rather than decreases.
Used: Concept Application
- Application
- Apply the Arrhenius equation and examine the role of activation energy.
- Final Logic
- Lower Ea → Larger e^(-Ea/RT) → Larger k.
- Lower Barrier → Faster Reaction
7 The species formed at the peak of the potential energy vs reaction coordinate diagram is scientifically named:
�� Peak represents maximum potential energy. �� It is a highly unstable species. �� Exists momentarily during reaction.
In a potential energy profile diagram, the highest point on the curve corresponds to the activated complex (transition state). This species possesses maximum potential energy and represents the stage where old bonds are partially broken and new bonds are partially formed. The activated complex is extremely unstable and exists only for a very short duration before decomposing into products. Therefore, the species present at the peak of the energy barrier is called the activated complex. Hence, the correct answer is B. Activated complex.
- �� Option A → Reactants are located before the energy barrier.
- �� Option C → Products are present after the barrier.
- �� Option D → Catalyst inhibitor is unrelated to the energy profile peak.
Used: NCERT Recall
- Application
- Recall the standard energy profile diagram.
- Final Logic
- Peak of energy profile = Activated complex.
- Peak = Transition State
8 Regarding potential energy profiles of chemical reactions:
1. Final enthalpy of the reaction depends on the nature of reactants and products.
2. Energy is released when the complex decomposes to form products.
3. The activated complex exists for a very long time.
�� Activated complex is highly unstable. �� Product formation releases energy. �� Enthalpy depends on reactants and products.
Statement 1 is correct because the enthalpy change of a reaction depends on the energies of reactants and products. Statement 2 is correct because after reaching the activated complex, the system moves toward products and releases energy. Statement 3 is incorrect because the activated complex is extremely unstable and exists only for a very short time. Therefore, Statements 1 and 2 are correct. Hence, the correct answer is A. 1 and 2 are correct.
- �� Option B → Statement 3 is incorrect.
- �� Option C → Statement 3 is incorrect while Statement 2 is correct.
- �� Option D → Includes incorrect Statement 3.
Used: Elimination
- Application
- Identify the incorrect statement regarding the activated complex.
- Final Logic
- Activated complex has only a transitory existence.
- Activated Complex = Temporary State
9 When a substance's temperature is raised, what happens to the proportion of molecules with much higher energies on the distribution curve?
�� Temperature increases molecular kinetic energy. �� More molecules occupy the high-energy region. �� Reaction probability increases.
According to the Maxwell-Boltzmann distribution, increasing temperature shifts the distribution toward higher energies and broadens the curve. As a result, a larger fraction of molecules possess energies significantly greater than the average energy. The area under the curve beyond the activation energy increases substantially. This increase in high-energy molecules is responsible for the increase in reaction rate with temperature. Therefore, the proportion of molecules with much higher energies becomes greater. Hence, the correct answer is D. It becomes greater.
- �� Option A → The proportion increases rather than decreases.
- �� Option B → Temperature changes the distribution.
- �� Option C → High-energy molecules always exist at finite temperatures.
Used: Concept Application
- Application
- Apply Maxwell-Boltzmann distribution principles.
- Final Logic
- Higher temperature → More energetic molecules.
- Hotter → More High-Energy Molecules
10 Identify the type of statistical distribution used to plot the fraction of molecules with a given kinetic energy:
�� Describes molecular energy distribution. �� Uses statistical treatment of molecules. �� Fundamental to collision theory.
The Maxwell-Boltzmann distribution describes how the kinetic energies of molecules are distributed in a large collection of particles. The graph plots the fraction (or number) of molecules against kinetic energy and helps explain the effect of temperature on reaction rates. It is widely used in chemical kinetics to determine the fraction of molecules possessing energy greater than the activation energy. Therefore, the correct answer is B. Maxwell-Boltzmann distribution.
- �� Option A → Arrhenius equation relates temperature and rate constant, not energy distribution.
- �� Option C → No such standard distribution exists in chemical kinetics.
- �� Option D → Zero order refers to reaction order, not energy distribution.
Used: NCERT Recall
- Application
- Recall the statistical distribution used in collision theory.
- Final Logic
- Energy distribution among molecules is described by Maxwell-Boltzmann statistics.
- MB = Molecular Behaviour
11 Which thermodynamic property is definitively NOT altered by the addition of a catalyst?
�� Catalysts affect kinetics, not thermodynamics. �� Gibbs energy determines spontaneity. �� Catalyst does not alter equilibrium position.
A catalyst increases the rate of a reaction by providing an alternative pathway with lower activation energy. As a result, the rate constant and reaction rate change. However, thermodynamic quantities such as Gibbs free energy (ΔG), enthalpy (ΔH), and equilibrium constant remain unchanged. Since Gibbs energy is a state function depending only on the initial and final states of the system, a catalyst cannot modify its value. Therefore, the correct answer is C. Gibbs energy.
- �� Option A → Activation energy is lowered by a catalyst.
- �� Option B → Rate constant increases due to reduced activation energy.
- �� Option D → Reaction rate increases in the presence of a catalyst.
Used: Concept Application
- Application
- Differentiate between kinetic properties and thermodynamic properties.
- Final Logic
- Catalysts affect reaction pathway, not Gibbs energy.
- Catalyst Changes Speed, Not ΔG
12 Statements regarding equilibrium and catalysts:
1. A catalyst catalyses the forward as well as the backward reactions to the same extent.
2. A catalyst changes the equilibrium constant to favor products.
3. A catalyst helps in attaining the equilibrium faster.
�� Catalyst affects both forward and reverse reactions. �� Equilibrium is reached faster. �� Equilibrium constant remains unchanged.
A catalyst lowers the activation energy of both forward and backward reactions equally. Therefore, it increases the rates of both reactions without changing the equilibrium composition. Statement 1 is correct because the catalyst accelerates both directions equally. Statement 2 is incorrect because the equilibrium constant depends only on temperature and is not altered by a catalyst. Statement 3 is correct because the catalyst helps the system attain equilibrium more rapidly. Therefore, Statements 1 and 3 are correct. Hence, the correct answer is A. 1 and 3 are correct.
- �� Option B → Statement 2 is incorrect.
- �� Option C → Statement 1 is also correct.
- �� Option D → Includes incorrect Statement 2.
Used: Elimination
- Application
- Identify the statement that incorrectly describes the effect of a catalyst on equilibrium.
- Final Logic
- Catalyst speeds attainment of equilibrium but does not shift equilibrium.
- Faster Equilibrium, Same Equilibrium
13
Based on the passage, the true molecular nature of the hydrolysis of ethyl acetate is:
�� Both ethyl acetate and water participate. �� True rate law involves two reactants. �� Appears first order only because water is in excess.
The passage clearly states that the hydrolysis of ethyl acetate is actually a reaction involving both ethyl acetate and water. Therefore, the rate depends on the concentrations of both reactants. Since two reactants are involved in determining the rate, the true order of the reaction is second order. However, because water is present in large excess, its concentration remains nearly constant and the reaction appears to follow first order kinetics experimentally. Therefore, the correct answer is C. Second order.
- �� Option A → The rate is not independent of concentration.
- �� Option B → It only appears first order under excess water conditions.
- �� Option D → No third reactant contributes to the rate law.
Used: NCERT Recall
- Application
- Distinguish between true reaction order and apparent reaction order.
- Final Logic
- True reaction order includes both reactants.
- True = Second, Appears = First
14
Why does the rate of the reaction depend practically only on ethyl acetate?
�� Water is present in excess. �� Its concentration remains nearly constant. �� Rate appears dependent only on ethyl acetate.
In the hydrolysis of ethyl acetate, water is one of the reactants. However, water is taken in such a large excess that its concentration changes negligibly during the reaction. Since the concentration of water remains practically constant, it becomes incorporated into the rate constant. Consequently, the observed rate depends only on the concentration of ethyl acetate. This is the basis of pseudo first order kinetics. Therefore, the correct answer is D.
- �� Option A → Water actively participates in the reaction.
- �� Option B → Water is a liquid, not a solid.
- �� Option C → Water is a reactant, not a catalyst.
Used: Concept Application
- Application
- Apply the concept of excess reactant concentration.
- Final Logic
- Constant water concentration leads to pseudo first order behavior.
- Excess Water → Constant Water
15 In the context of the intermediate complex theory, the intermediate has a:
�� Intermediate forms temporarily. �� It quickly decomposes into products. �� Catalyst is regenerated afterward.
According to the intermediate complex theory, a catalyst forms temporary bonds with reactants, producing an intermediate complex. This intermediate exists only for a very short duration and subsequently decomposes to yield products and regenerate the catalyst. Because of its short lifetime, it is described as having a transitory existence. Therefore, the correct answer is B. Transitory existence.
- �� Option A → The intermediate is not permanent.
- �� Option C → The intermediate need not be a solid.
- �� Option D → Its concentration is generally very small.
Used: NCERT Recall
- Application
- Recall the key features of intermediate complex theory.
- Final Logic
- Intermediate complexes exist only momentarily.
- Intermediate = Temporary Guest
16 When a substance is added to a reaction and it reduces the rate rather than increasing it, it is properly named:
�� Inhibitors decrease reaction rates. �� They oppose the normal progress of reaction. �� Commonly called negative catalysts.
An inhibitor is a substance that decreases the rate of a chemical reaction. Unlike catalysts, which increase reaction rates by lowering activation energy, inhibitors retard the reaction process. In chemical kinetics, inhibitors are often referred to as negative catalysts because their effect is opposite to that of catalysts. Therefore, a substance that reduces the reaction rate is properly termed an inhibitor. Hence, the correct answer is C. Inhibitor.
- �� Option A → Negative catalyst is a descriptive term, but the formal NCERT term is inhibitor.
- �� Option B → Poison generally deactivates a catalyst rather than directly slowing a reaction.
- �� Option D → Alternate pathway is associated with catalysts.
Used: NCERT Recall
- Application
- Recall the terminology used for substances that decrease reaction rates.
- Final Logic
- Reaction-rate decreasing substances are called inhibitors.
- Inhibitor = Inhibits Reaction
17 Collision frequency (Z) is measured in terms of the number of collisions per unit time per unit:
�� Collision theory uses collision frequency. �� Collisions are counted in a given volume. �� Units involve collisions per unit time per unit volume.
In collision theory, collision frequency (Z) represents the total number of molecular collisions occurring in a unit volume per unit time. Since chemical reactions occur through molecular collisions, collision frequency provides a measure of how frequently reactant molecules encounter one another. Therefore, collision frequency is expressed in terms of the number of collisions per unit time per unit volume. Hence, the correct answer is D. Volume.
- �� Option A → Collision frequency is not measured per unit mass.
- �� Option B → Area is not used in the standard definition of Z.
- �� Option C → Density influences collisions but is not the unit basis.
Used: NCERT Recall
- Application
- Recall the definition of collision frequency from collision theory.
- Final Logic
- Z measures collisions occurring in a unit volume per unit time.
- Z → Zooming Collisions in Volume
18 For complex molecules, the collision theory predicted rate constant often shows significant deviations because:
�� Proper orientation is necessary. �� Many collisions are ineffective. �� Steric effects become important.
Collision theory assumes that reactions occur when molecules collide with sufficient energy. However, for complex molecules, possessing sufficient energy alone is not enough. The reacting molecules must also collide with the correct orientation. Many collisions occur with improper orientation and therefore fail to produce products. This limitation leads to deviations between observed and predicted rate constants. To account for this, the steric factor (P) is introduced in the modified collision theory. Therefore, the correct answer is A. All collisions do not lead to the formation of products.
- �� Option B → Complex molecules do collide.
- �� Option C → Arrhenius equation remains valid.
- �� Option D → Activation energy does not become zero.
Used: Concept Application
- Application
- Apply the concept of effective and ineffective collisions.
- Final Logic
- Only correctly oriented collisions produce products.
- Energy + Orientation = Reaction
19 Match List-I (Terms in Modified Collision Theory) with List-II (Meanings):
| List I | List II |
|---|---|
| 1. P | a. Fraction of molecules with sufficient energy |
| 2. ZAB | b. Activation energy |
| 3. Ea | c. Collision frequency |
| 4. e^(-Ea/RT) | d. Steric factor |
�� P represents steric factor. �� ZAB denotes collision frequency. �� Ea is activation energy. �� e^(-Ea/RT) gives energetic fraction.
In the modified collision theory equation: k = PZAB e^(-Ea/RT) P represents the steric factor that accounts for proper orientation. ZAB represents collision frequency between reactant molecules. Ea denotes activation energy. e^(-Ea/RT) represents the fraction of molecules possessing sufficient energy to react. Therefore: 1 → d 2 → c 3 → b 4 → a Hence, the correct answer is D.
- �� Option A → Multiple variables are incorrectly matched.
- �� Option B → Incorrectly assigns steric factor and collision frequency.
- �� Option C → ZAB and Ea are interchanged.
Used: NCERT Recall
- Application
- Recall the modified collision theory equation and variable meanings.
- Final Logic
- Each symbol has a fixed physical significance.
- Ea = Energy Barrier
20 Identify the reaction occurrence condition when bromoethane molecules collide with improper orientation:
�� Orientation is essential for reaction. �� Improper collisions are ineffective. �� No product formation occurs.
According to collision theory, successful reactions require both sufficient energy and proper molecular orientation. When bromoethane molecules collide with improper orientation, the required bond-breaking and bond-forming processes cannot occur. Consequently, the collision becomes ineffective. The molecules simply separate after collision without producing any products. Therefore, the correct answer is C. They simply bounce back and no products are formed.
- �� Option A → Product formation requires proper orientation.
- �� Option B → Catalysts are not formed through ineffective collisions.
- �� Option D → Improper collisions do not necessarily release heat.
Used: Concept Application
- Application
- Apply the concept of effective and ineffective collisions.
- Final Logic
- Improper orientation results in an ineffective collision.
- Wrong Direction = No Reaction
