CUET UG Physics Booster Test - 3 Material Properties and Coulomb\'s Law
📌 Answers are locked once submitted — results and explanations appear at the end.
QUESTION 1 OF 20
A cubic piece of conducting copper of side 1 cm contains approximately how many free or bound electrons in total?
QUESTION 2 OF 20
The following statements relate to charging of an insulator by friction:
1. The lack of mobile charges heavily restricts charge spreading.
2. The acquired charge remains localized near the rubbed region.
3. Mobile electrons quickly migrate to neutralize the charge.
4. The charge instantly leaks to earth.
QUESTION 3 OF 20
Match the following regarding conductors in electrostatic equilibrium.
| List I | List II |
|---|---|
| 1. Excess charge inside conductor | a. Electrostatic equilibrium condition |
| 2. Electric field inside conductor | b. Charge migrates outward |
| 3. Free electrons | c. Mobile charge carriers |
| 4. Static conductor | d. Zero electric field |
QUESTION 4 OF 20
Incorrect statement about localized charge behavior in insulators:
QUESTION 5 OF 20
Statements regarding grounding and earthing:
1. A conducting path to earth allows excess charge to flow.
2. Insulating handles reduce charge leakage.
3. A metal rod held directly by hand often loses charge through the body.
4. Earth acts as an infinite sink for charge through proper conductive contact.
QUESTION 6 OF 20
If a highly charged spherical metal conductor having total initial charge Q is grasped by a barefoot human standing on the earth, the steady-state final charge left on the sphere is ideally:
QUESTION 7 OF 20
Two charged macroscopic spheres of radius R are separated by distance r, where r is not much greater than R. Another pair of spheres of the same radius R are separated by distance d, where d >> R. The respective classifications are:
QUESTION 8 OF 20
Statements regarding the rigorous assumption of point charges:
1. It simplifies Coulomb-force calculations considerably.
2. All charge is assumed concentrated at a single point.
3. It remains perfectly valid even when charged spheres physically touch.
4. It remains useful for many microscopic and subatomic interactions.
QUESTION 9 OF 20
Unlike mass, which is always positive, the algebraic summation of charge in an isolated system:
QUESTION 10 OF 20
Match the following.
| List I | List II |
|---|---|
| 1. Vector Quantity | a. Total charge of a system |
| 2. Scalar Quantity | b. Electric charge |
| 3. Coulomb Force | c. Has magnitude and direction |
| 4. Net Charge | d. Electrostatic interaction force |
QUESTION 11 OF 20
In the context of charge conservation in an isolated system:
1. Individual charge-carrying particles may be created or destroyed in some processes.
2. The net total charge remains constant.
3. Electrons may be transferred between bodies.
4. Charge conservation fails during nuclear reactions.
QUESTION 12 OF 20
Incorrect statement about charge conservation during subatomic processes:
QUESTION 13 OF 20
What is the approximate total positive charge present in 250 g of pure water?
Given:
Molecular mass of water = 18 g mol⁻¹
Avogadro number = 6.02 × 10²³ mol⁻¹
QUESTION 14 OF 20
Correct statements about microscopic electric charges:
1. The number of charges may be only a few tens or hundreds of e.
2. Charge appears in discrete lumps.
3. Quantization cannot be ignored at microscopic scales.
4. Charge behaves as a perfectly continuous quantity.
QUESTION 15 OF 20
Statements about the Coulomb unit:
1. The coulomb is defined through electric current in SI units.
2. A charge of 1 C exerts approximately 9 × 10⁹ N force on an identical charge 1 m away in vacuum.
3. The coulomb is a relatively large unit for electrostatics.
4. Microcoulombs and millicoulombs are commonly used in practice.
QUESTION 16 OF 20
If a localized volume contains N free electrons as its only charge carriers, the total net charge Q is:
QUESTION 17 OF 20
Coulomb discovered experimentally that the electrostatic force between two point charges:
QUESTION 18 OF 20
The ratio of electric force to gravitational force for an electron-proton pair and a proton-proton pair respectively is approximately:
QUESTION 19 OF 20
Incorrect statement regarding Coulomb's torsion balance experiment:
QUESTION 20 OF 20
If
k = 9 × 10⁹ N m² C⁻²
and two identical charges of 1 μC are placed 1 cm apart in vacuum, the electrostatic force between them is:
Test Complete!
Answer Review
1 A cubic piece of conducting copper of side 1 cm contains approximately how many free or bound electrons in total?
�� Copper contains an enormous number of atoms. �� Each atom contains electrons. �� Total electrons are of the order of 10²⁴.
According to NCERT, ordinary macroscopic objects contain an extraordinarily large number of charged particles. A copper cube of side 1 cm has a volume of 1 cm³ and contains roughly 10²² atoms. Since each copper atom contains 29 electrons, the total number of electrons present becomes approximately 2.5 × 10²⁴. This includes both bound electrons and conduction electrons. This large value illustrates why matter is electrically neutral under normal conditions despite containing huge amounts of positive and negative charges. Electrostatic phenomena arise due to the transfer of only a tiny fraction of these electrons. The result also highlights the microscopic basis of charge and the enormous number of charge carriers present in conductors. Therefore, the correct answer is 2.5 × 10²⁴ electrons.
- �� Option A → Corresponds to the reciprocal of the electronic charge order.
- �� Option B → Represents Avogadro's number and is much smaller than the total electron count.
- �� Option D → Represents the order of ε₀-related constants, not electron count.
NCERT Recall
- Application
- Recall the approximate number of atoms present in 1 cm³ of copper and multiply by electrons per atom.
- Final Logic
- Large numbers of atoms × electrons per atom give approximately 2.5 × 10²⁴ electrons.
"One cm Copper → Twenty-Four Powers"
2 The following statements relate to charging of an insulator by friction:
1. The lack of mobile charges heavily restricts charge spreading.
2. The acquired charge remains localized near the rubbed region.
3. Mobile electrons quickly migrate to neutralize the charge.
4. The charge instantly leaks to earth.
�� Insulators lack free charge carriers. �� Charge remains localized. �� Leakage is minimal.
NCERT explains that insulators do not contain free electrons capable of moving throughout the material. When an insulator such as glass, rubber or plastic is rubbed, charge transfer occurs due to friction. Since charges cannot move freely, the acquired charge remains localized near the rubbed region. This localized charge retention is responsible for many electrostatic phenomena such as attraction of paper bits by a charged comb and charging of plastic rods. Statements 1 and 2 correctly describe the behavior of insulators. Statements 3 and 4 are incorrect because rapid charge migration and instant grounding require mobile charge carriers, which are absent in insulators. Hence only Statements 1 and 2 are correct.
- �� Option B → Insulators do not exhibit rapid charge migration or immediate grounding.
- �� Option C → Statement 3 is incorrect.
- �� Option D → Statement 4 is incorrect.
Concept Application
- Application
- Apply the difference between conductors and insulators regarding charge mobility.
- Final Logic
- No free charge carriers means charge remains localized.
"Rub and Remain"
3 Match the following regarding conductors in electrostatic equilibrium.
| List I | List II |
|---|---|
| 1. Excess charge inside conductor | a. Electrostatic equilibrium condition |
| 2. Electric field inside conductor | b. Charge migrates outward |
| 3. Free electrons | c. Mobile charge carriers |
| 4. Static conductor | d. Zero electric field |
�� Charges move to the surface. �� Internal electric field becomes zero. �� Free electrons ensure equilibrium.
According to NCERT, when excess charge is placed on a conductor, free electrons move under mutual repulsion until electrostatic equilibrium is established. As a result, excess charge resides on the outer surface of the conductor. The electric field inside a conductor at electrostatic equilibrium is zero. If any field existed, free charges would continue moving. Therefore, the existence of zero internal electric field is a defining characteristic of electrostatic equilibrium. Thus: 1 → b 2 → d 3 → c 4 → a The matching reflects the fundamental properties of conductors discussed in NCERT.
- �� Option B → Incorrectly associates excess charge with zero field.
- �� Option C → Misplaces free electron behavior.
- �� Option D → Incorrect field matching.
Concept Application
- Application
- Use conductor equilibrium conditions from NCERT.
- Final Logic
- Charge moves outward until the interior field becomes zero.
"Surface Charge, Zero Core"
4 Incorrect statement about localized charge behavior in insulators:
�� Charges remain trapped. �� Insulators resist charge motion. �� Static electricity relies on localization.
NCERT explains that insulators do not permit free movement of charge. Consequently, charges produced by friction remain trapped at localized positions. This localization allows static electricity to persist for long periods. The attraction of paper pieces by a charged comb and charging of plastic objects are common examples. Because charges cannot move freely, localized charges do not rapidly neutralize one another unless a conducting path is provided. Therefore, Statement B is incorrect. The other statements correctly describe the behavior of static charge on insulating materials and agree with NCERT discussions of frictional electricity.
- �� Option A → Correct description of static charge.
- �� Option C → Frictional charging depends on localization.
- �� Option D → Common NCERT example of static electricity.
NCERT Recall
- Application
- Recall the behavior of charge on insulating materials.
- Final Logic
- Insulators retain localized charge because charge mobility is restricted.
"Insulators Hold, Not Neutralize"
5 Statements regarding grounding and earthing:
1. A conducting path to earth allows excess charge to flow.
2. Insulating handles reduce charge leakage.
3. A metal rod held directly by hand often loses charge through the body.
4. Earth acts as an infinite sink for charge through proper conductive contact.
�� Earth acts as a charge reservoir. �� Conductive paths enable charge flow. �� Insulators block leakage.
Earthing is the process of connecting a charged body to the earth through a conducting path. NCERT treats the earth as a vast reservoir capable of accepting or supplying charge without appreciable change in its electrical state. Therefore, excess charge can flow through a conducting connection to the ground. The human body behaves as a conductor because it contains water and dissolved ions. Hence a charged metal rod held directly by hand often loses its charge through the body to the earth. To prevent this, insulating handles made of wood or plastic are used. These materials interrupt the conducting path and reduce leakage. All four statements correctly describe the process of grounding and earthing.
- �� Option A → Statement 2 is also correct.
- �� Option B → Statements 3 and 4 are also correct.
- �� Option C → Statement 1 is also correct.
Logical Analysis
- Application
- Analyze the role of conducting and insulating paths in earthing.
- Final Logic
- Charge flows only when a conducting connection to earth exists.
"Ground Gives a Path"
6 If a highly charged spherical metal conductor having total initial charge Q is grasped by a barefoot human standing on the earth, the steady-state final charge left on the sphere is ideally:
�� Human body provides a conducting path. �� Earth acts as a charge reservoir. �� Excess charge flows to the ground.
According to NCERT, the earth behaves as an enormous reservoir of electric charge. When a charged conductor is connected to the earth through a conducting path, excess charge flows between the conductor and the earth until electrostatic equilibrium is established. A barefoot human standing on the ground provides such a conducting path because the body contains water and dissolved salts, making it a conductor. Therefore, when a charged metal sphere is touched, the excess charge leaks through the body to the earth. In the idealized NCERT treatment, all excess charge is removed from the sphere and transferred to the earth. Hence the final charge on the sphere becomes zero. Therefore: Final charge = Q − Q = 0 Thus Option C is correct.
- �� Option A → Charge cannot remain unchanged after grounding.
- �� Option B → Only partial discharge is not assumed in the ideal model.
- �� Option D → Grounding neutralizes charge rather than reversing its sign.
Concept Application
- Application
- Apply the concept of earthing and charge leakage through a conducting path.
- Final Logic
- Grounding removes excess charge until the conductor becomes neutral.
"Touch Ground, Charge Gone"
7 Two charged macroscopic spheres of radius R are separated by distance r, where r is not much greater than R. Another pair of spheres of the same radius R are separated by distance d, where d >> R. The respective classifications are:
�� Point charge approximation depends on size comparison. �� Object dimensions must be negligible. �� Large separation permits point-charge treatment.
NCERT defines a point charge as a charged body whose dimensions are negligible compared with the distance involved in the interaction. For the first pair of spheres, r is not much larger than R. Therefore, the size of the spheres cannot be ignored and the point charge approximation becomes invalid. For the second pair, d >> R. The sphere dimensions are negligible compared with the separation distance. Consequently, each sphere may safely be treated as a point charge. This distinction is important because Coulomb's law is strictly applicable to point charges. Extended charge distributions require more advanced treatment when object size becomes comparable to separation. Hence the correct classification is: Not point charges, Point charges.
- �� Option B → Reverses the validity conditions.
- �� Option C → First case violates point-charge requirements.
- �� Option D → Second case satisfies point-charge conditions.
NCERT Recall
- Application
- Recall the definition of a point charge and compare object size with distance.
- Final Logic
- Distance must be much larger than size for the point-charge model.
"Far Means Point"
8 Statements regarding the rigorous assumption of point charges:
1. It simplifies Coulomb-force calculations considerably.
2. All charge is assumed concentrated at a single point.
3. It remains perfectly valid even when charged spheres physically touch.
4. It remains useful for many microscopic and subatomic interactions.
�� Point charges simplify analysis. �� Charge is concentrated at one point. �� Approximation fails for touching bodies.
The point charge concept is one of the most useful idealizations in electrostatics. According to NCERT, a point charge is a charged body whose size is negligible compared to the distance of interest. This allows Coulomb's law to be applied using simple geometry instead of dealing with complicated charge distributions. The model assumes that the entire charge content is concentrated at a single point in space. Therefore Statements 1 and 2 are correct. Statement 4 is also correct because many microscopic interactions involving elementary particles are modeled successfully using point charges. Statement 3 is incorrect because when two charged spheres touch each other, their finite sizes become important. In such situations, the point-charge approximation is no longer valid. Hence Statements 1, 2 and 4 are correct.
- �� Option A → Statement 3 is incorrect.
- �� Option C → Statement 3 is incorrect.
- �� Option D → Statement 3 is incorrect and Statement 2 is omitted.
Concept Application
- Application
- Apply the assumptions behind the point-charge model.
- Final Logic
- Point charges require negligible size and separated bodies.
"One Point, Easy Physics"
9 Unlike mass, which is always positive, the algebraic summation of charge in an isolated system:
�� Charge is a scalar quantity. �� Positive and negative signs matter. �� Charges add algebraically.
NCERT states that electric charge is a scalar quantity. However, unlike mass, charge may be positive or negative. Therefore, while determining the net charge of a system, algebraic signs must always be taken into account. For example, a charge of +5 C and a charge of −3 C combine to produce a net charge of +2 C. Simply adding magnitudes would produce an incorrect result. Charge addition follows ordinary algebraic rules rather than vector addition. The sign indicates the nature of the charge and determines whether charges reinforce or partially cancel one another. Therefore, the correct statement is that proper positive and negative signs must be used during charge summation.
- �� Option B → Ignores the fundamental sign of charge.
- �� Option C → Charge is scalar, not vector.
- �� Option D → Systems need not be electrically neutral.
NCERT Recall
- Application
- Recall the scalar nature and algebraic addition of charge.
- Final Logic
- Net charge equals algebraic sum of individual charges.
"Signs Decide Charge"
10 Match the following.
| List I | List II |
|---|---|
| 1. Vector Quantity | a. Total charge of a system |
| 2. Scalar Quantity | b. Electric charge |
| 3. Coulomb Force | c. Has magnitude and direction |
| 4. Net Charge | d. Electrostatic interaction force |
�� Force is a vector. �� Charge is a scalar. �� Net charge is obtained algebraically.
NCERT distinguishes clearly between scalar and vector quantities. A vector quantity possesses both magnitude and direction, whereas a scalar quantity possesses only magnitude. Electric charge is a scalar quantity because it does not have any spatial direction associated with it. Coulomb force, however, is a vector because it acts along the line joining two charges and has both magnitude and direction. Therefore: 1 → c (Vector quantity → Has magnitude and direction) 2 → b (Scalar quantity → Electric charge) 3 → d (Coulomb force → Electrostatic interaction force) 4 → a (Net charge → Total charge of a system) This matching correctly reflects the NCERT treatment of charge and force.
- �� Option A → Incorrect association of vector quantities.
- �� Option B → Interchanges scalar and vector properties.
- �� Option C → Misidentifies Coulomb force and charge.
NCERT Recall
- Application
- Identify which physical quantities are scalar and which are vector.
- Final Logic
- Charge is scalar; force is vector.
"Charge Counts, Force Points"
11 In the context of charge conservation in an isolated system:
1. Individual charge-carrying particles may be created or destroyed in some processes.
2. The net total charge remains constant.
3. Electrons may be transferred between bodies.
4. Charge conservation fails during nuclear reactions.
�� Total charge is conserved. �� Charge carriers may be created or destroyed in pairs. �� Electrons can be transferred between bodies.
According to NCERT, the algebraic sum of charges in an isolated system remains constant. This is the law of conservation of charge. While certain elementary particles may be created or annihilated in high-energy processes, the total charge before and after the process remains unchanged. Electrons can move from one body to another during charging by friction, conduction or induction. However, such transfer does not alter the net charge of the isolated system. Statement 4 is incorrect because charge conservation is a universal law and remains valid even during nuclear and particle interactions. Numerous experiments confirm that total charge remains unchanged in all known physical processes. Therefore, Statements 1, 2 and 3 are correct.
- �� Option B → Statement 4 is incorrect.
- �� Option C → Statement 1 is also correct.
- �� Option D → Statement 4 is incorrect.
NCERT Recall
- Application
- Recall the law of conservation of charge and its application to physical processes.
- Final Logic
- Charge may move or be redistributed, but total charge remains constant.
"Charge Changes Place, Not Amount"
12 Incorrect statement about charge conservation during subatomic processes:
�� Charge conservation is universal. �� Beta decay obeys charge conservation. �� Net charge is unchanged.
NCERT emphasizes that electric charge is conserved in every physical process. During beta decay, a neutron transforms into a proton, an electron and an antineutrino. Before decay: Net charge = 0 After decay: Proton = +e Electron = −e Antineutrino = 0 Total charge = +e − e = 0 Thus, the total charge after decay remains equal to the initial charge. No net positive charge is created. This provides strong experimental evidence for the conservation law. Therefore, the statement claiming that nature creates a net positive charge during beta decay is incorrect.
- �� Option A → Correct example of charge conservation.
- �� Option B → Correct statement of the conservation law.
- �� Option D → Proton and electron have equal and opposite charges.
Logical Analysis
- Application
- Compare total charge before and after beta decay.
- Final Logic
- Initial and final charges are equal.
"Before Equals After"
13 What is the approximate total positive charge present in 250 g of pure water?
Given:
Molecular mass of water = 18 g mol⁻¹
Avogadro number = 6.02 × 10²³ mol⁻¹
�� Water contains enormous numbers of protons. �� Positive charge is extremely large. �� Matter remains neutral due to equal negative charge.
Number of water molecules: N = (250/18) × (6.02 × 10²³) ≈ 8.36 × 10²⁴ Each H₂O molecule contains 10 protons. Total protons: = 10 × 8.36 × 10²⁴ = 8.36 × 10²⁵ Total positive charge: Q = Ne = (8.36 × 10²⁵)(1.6 × 10⁻¹⁹) ≈ 1.34 × 10⁷ C Unit Verification Number of charges × charge per proton = Coulomb This enormous value demonstrates that ordinary matter contains huge amounts of positive and negative charge, which cancel each other to produce electrical neutrality. Therefore, Option A is correct.
- �� Option B → Represents the charge of a single electron.
- �� Option C → Incorrect unit conversion.
- �� Option D → Much smaller than the calculated value.
Substitution
- Application
- Calculate molecules, determine proton count and multiply by elementary charge.
- Final Logic
- Large numbers of protons produce a very large total positive charge.
"Water Holds Massive Charge"
14 Correct statements about microscopic electric charges:
1. The number of charges may be only a few tens or hundreds of e.
2. Charge appears in discrete lumps.
3. Quantization cannot be ignored at microscopic scales.
4. Charge behaves as a perfectly continuous quantity.
�� Charge is quantized. �� Small systems reveal discreteness. �� Continuous approximation may fail.
At microscopic scales, the number of charge carriers may be very small. In such situations, charge quantization becomes important. NCERT states that charge exists only in integral multiples of the elementary charge e. When only a few electrons are present, charge appears as distinct, countable units rather than a continuous quantity. Therefore Statements 1, 2 and 3 are correct. Statement 4 is incorrect because the continuous approximation is mainly useful for macroscopic systems containing enormous numbers of elementary charges. The microscopic world reveals the discrete nature of charge very clearly, a fact established experimentally through Millikan's oil-drop experiment.
- �� Option B → Statement 4 is incorrect.
- �� Option C → Statement 4 is incorrect.
- �� Option D → Statement 4 is incorrect.
NCERT Recall
- Application
- Recall the principle of charge quantization.
- Final Logic
- Microscopic systems reveal discrete charge units.
"Micro Means Discrete"
15 Statements about the Coulomb unit:
1. The coulomb is defined through electric current in SI units.
2. A charge of 1 C exerts approximately 9 × 10⁹ N force on an identical charge 1 m away in vacuum.
3. The coulomb is a relatively large unit for electrostatics.
4. Microcoulombs and millicoulombs are commonly used in practice.
�� Coulomb is linked to electric current. �� 1 C is a large amount of charge. �� Smaller units are commonly used.
In SI units, electric charge is defined in terms of electric current. One coulomb is the amount of charge transported by a current of one ampere in one second. Using Coulomb's law: F = kq₁q₂/r² For q₁ = q₂ = 1 C and r = 1 m, F = 9 × 10⁹ N Therefore Statement 2 is correct. In practical electrostatics, charges are usually of the order of microcoulombs or millicoulombs because one coulomb is a very large quantity of charge. Hence Statement 4 is correct. Statement 3 is omitted from the correct set because the intended NCERT emphasis is on practical usage rather than simply calling the unit "large."
- �� Option A → Statement 2 is also correct.
- �� Option B → Statement 1 is correct but omitted.
- �� Option D → Statement 4 is also correct.
NCERT Recall
- Application
- Recall SI definitions and practical electrostatic charge magnitudes.
- Final Logic
- The coulomb is defined via current and represents a large quantity of charge.
"Current Creates Coulomb"
16 If a localized volume contains N free electrons as its only charge carriers, the total net charge Q is:
�� Each electron carries charge −e. �� Total charge equals number × charge per electron. �� Charge is negative because electrons are negatively charged.
According to NCERT, the charge on a single electron is: e = 1.6 × 10⁻¹⁹ C Since an electron carries negative charge, its charge is represented as −e. If a system contains N electrons, the total charge is obtained by multiplying the number of electrons by the charge carried by each electron: Q = N(−e) Q = −Ne The negative sign indicates an excess of electrons in the system. This relation is fundamental to the quantization of charge and is widely used in electrostatics, current electricity and atomic physics. Thus, the correct expression for the total charge is −Ne.
- �� Option B → Ignores the negative sign of electron charge.
- �� Option C → Incorrect mathematical relationship.
- �� Option D → Charge is not obtained by dividing N by e.
NCERT Recall
- Application
- Recall the value and sign of the electronic charge.
- Final Logic
- Total charge = Number of electrons × Charge per electron.
"Electron Means Minus"
17 Coulomb discovered experimentally that the electrostatic force between two point charges:
�� Coulomb used a torsion balance. �� Force depends strongly on distance. �� Inverse square law was established experimentally.
Coulomb's experiments showed that the electrostatic force between two stationary point charges depends inversely on the square of the distance separating them. This relationship is expressed mathematically as: F ∝ 1/r² Combining this result with the dependence on charge magnitudes gives Coulomb's law: F = k(q₁q₂)/r² This inverse-square dependence is similar to Newton's law of gravitation. It implies that doubling the distance reduces the force to one-fourth, while halving the distance increases the force four times. The experimental verification of this law using a torsion balance was one of the most important achievements in electrostatics and forms the foundation of the chapter.
- �� Option B → Force follows an inverse-square relation, not an exponential law.
- �� Option C → Force strongly depends on distance.
- �� Option D → Resistance is not the determining factor in Coulomb's law.
NCERT Recall
- Application
- Recall the mathematical form of Coulomb's law.
- Final Logic
- Force decreases as the square of distance increases.
"Distance Square Down, Force Down"
18 The ratio of electric force to gravitational force for an electron-proton pair and a proton-proton pair respectively is approximately:
�� Electric force is enormously stronger than gravity. �� Ratio is independent of distance. �� Electrostatic interactions dominate atomic structure.
NCERT compares the electric and gravitational forces between elementary particles to demonstrate the relative strength of the electromagnetic interaction. For an electron-proton pair: Fe/Fg ≈ 2.4 × 10³⁹ For a proton-proton pair: Fe/Fg ≈ 1.3 × 10³⁶ These extremely large ratios show that electrostatic forces are many orders of magnitude stronger than gravitational forces at atomic scales. This is why atomic and molecular structures are governed primarily by electromagnetic interactions rather than gravity. The result also highlights the importance of Coulomb's law in explaining microscopic physical phenomena. Therefore, Option B is correct.
- �� Option A → Interchanges the two standard NCERT values.
- �� Option C → Gives incorrect orders of magnitude.
- �� Option D → Reverses the physical relationship completely.
NCERT Recall
- Application
- Recall the standard NCERT comparison between electric and gravitational forces.
- Final Logic
- Electrostatic force dominates gravity by an enormous factor.
"Electric Beats Gravity"
19 Incorrect statement regarding Coulomb's torsion balance experiment:
�� Coulomb measured relative forces. �� Exact initial charge values were not required. �� Charge sharing was used extensively.
Coulomb's torsion balance experiment was designed to determine how electrostatic force depends on charge and distance. The experiment used charged conducting spheres attached to a sensitive torsion balance. A major strength of the method was that Coulomb did not need to know the exact magnitude of the charges initially present. Instead, he used identical conducting spheres to divide charge into predictable fractions through contact. This allowed him to compare forces corresponding to different charge values. The experiment successfully established the inverse-square law of electrostatic force. Therefore, the statement that Coulomb started with precisely known absolute charge magnitudes is incorrect. Hence Option C is the correct answer.
- �� Option A → Correct description of the experimental apparatus.
- �� Option B → Charge conservation and sharing were used.
- �� Option D → Identical spheres approximately divide charge equally.
NCERT Recall
- Application
- Recall the procedure used in Coulomb's torsion balance experiment.
- Final Logic
- Relative charge comparisons were sufficient; exact values were unnecessary.
"Compare, Don't Calibrate"
20 If
k = 9 × 10⁹ N m² C⁻²
and two identical charges of 1 μC are placed 1 cm apart in vacuum, the electrostatic force between them is:
�� Use Coulomb's law. �� Convert units carefully. �� Force is inversely proportional to distance squared.
Using Coulomb's law: F = kq₁q₂/r² Given: k = 9 × 10⁹ N m² C⁻² q₁ = q₂ = 1 μC = 10⁻⁶ C r = 1 cm = 10⁻² m Substituting: F = (9 × 10⁹)(10⁻⁶)(10⁻⁶)/(10⁻²)² = (9 × 10⁹)(10⁻¹²)/(10⁻⁴) = 9 × 10⁻³ × 10⁴ = 90 N Unit Verification (N m² C⁻²)(C²)/m² = N Therefore, the electrostatic force between the two charges is 90 N. Hence Option A is correct.
- �� Option B → Results from an incorrect power calculation.
- �� Option C → Underestimates the force by a factor of 100.
- �� Option D → Overestimates the force by a factor of 10.
Substitution
- Application
- Substitute the given values into Coulomb's law and simplify powers of ten.
- Final Logic
- Correct unit conversion and exponent handling give 90 N.
"Micro and Centi → Ninety"
