CUET UG Physics Booster Test 3- Fundamentals of Magnetism
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QUESTION 1 OF 20
Incorrect statement regarding the nature of Oersted's discovery and the resulting magnetic field B
QUESTION 2 OF 20
Concept originator for "fields propagating in finite time" vs "mathematical unification of light and electromagnetism"
QUESTION 3 OF 20
A particle with charge q = 1.6 × 10⁻¹⁹ C moves with velocity v = 3 × 10⁷ m/s purely in the +x-direction and experiences a Lorentz force strictly in the -z direction due to a magnetic field of 6 × 10⁻⁴ T. Assuming no electric field, what must be the direction of the magnetic field if the particle is an electron?
A.+z axis
QUESTION 4 OF 20
Correct statements about the principle of superposition applied to Biot-Savart law
Statements:
1. The magnetic field is a linear vector field in relation to its source I dl.
2. If there are more current elements, the fields add vectorially.
3. The magnetic field dB due to an element has an angle dependence sinθ which is maintained during superposition.
4. Superposition allows integration of dB over the entire loop to find the net field at the center.
QUESTION 5 OF 20
If a current-carrying wire is placed exactly along the earth's magnetic north-south direction, and a compass needle is placed directly above the wire, how does the needle align if the current is strong enough to dominate the Earth's field?
QUESTION 6 OF 20
Identify the correct statements regarding the limitation of iron filing patterns.
Statements:
1. They show the magnitude of the field quantitatively at any given distance r.
2. They form concentric circles reflecting the tangent nature of magnetic field lines around a straight conductor.
3. They indicate the presence of a magnetic field but do not directly show the vector direction without a compass.
4. They provide visual evidence of cylindrical symmetry around a straight current-carrying conductor.
QUESTION 7 OF 20
A circular loop carrying current I lies in the xy-plane. If the magnetic field at the center is represented by a dot (·), the magnetic moment vector m of the loop can be expressed as:
QUESTION 8 OF 20
Match the following.
| List I | List II |
|---|---|
| 1. Wire along +x, current +x, observation at +y | a. Dot (Outward) |
| 2. Wire along +x, current +x, observation at –y | b. Cross (Inward) |
| 3. Loop in xy-plane, clockwise current, center point | c. Inward magnetic field |
| 4. Loop in xy-plane, anticlockwise current, center point | d. Outward magnetic field |
QUESTION 9 OF 20
The fact that a moving charge experiences a magnetic force that is perpendicular to both its velocity and the magnetic field ensures that:
QUESTION 10 OF 20
A tightly wound 100-turn coil of radius 10 cm carrying a steady current of 1 A is evaluated for its central magnetic field. The magnitude of this field is:
QUESTION 11 OF 20
Which fundamental insight was gained immediately from Oersted's observation of the compass needle deflection?
QUESTION 12 OF 20
Maxwell's theoretical unification extended Faraday's field concept to imply that electric and magnetic fields:
QUESTION 13 OF 20
Using Ampere's circuital law, the magnetic field B inside a long solenoid carrying a current I with n turns per unit length is derived as:
QUESTION 14 OF 20
Given c=1/√(μ_0ε_0), if μ₀ is exactly fixed to 4π×10^(-7)T m/A and c=3×10^8 m/s, what is the calculated value of ε₀?
QUESTION 15 OF 20
Identify the correct statements concerning the unit Tesla and the force equation F=qvBsinθ.
Statements:
1. Its dimensional formula is [M T⁻² A⁻¹].
2. It is defined when a 1 C charge moving at 1 m/s perpendicular to B experiences 1 N force.
3. It can be expressed as Newton second/(coulomb metre).
4. It is considered a rather small unit for laboratory purposes.
QUESTION 16 OF 20
The horizontal component of the Earth's magnetic field at a certain place is 3.0×10^(-5)T. What is this value in Gauss?
QUESTION 17 OF 20
Incorrect statement regarding electromagnetic waves and their origins.
QUESTION 18 OF 20
Identify the correct statements about fields conveying signals and energy.
Statements:
1. The electric field is an artifact and cannot convey real physical momentum.
2. Both electric and magnetic fields can vary with time and propagate through space.
3. The magnetic field B is a vector field that is established instantaneously.
4. Moving charges and currents are the sources of the magnetic field used in these transmissions.
QUESTION 19 OF 20
Comparing Ampere's law loops to Gauss's law surfaces:
QUESTION 20 OF 20
For an electric dipole, the field at a distant point on its axis is
E≃2p_e/4πε_0x^3
By replacing p_e with m and 1/ε_0 with μ_0, the magnetic field B on the axis of a point magnetic dipole (current loop) at a large distance x is:
Test Complete!
Answer Review
1 Incorrect statement regarding the nature of Oersted's discovery and the resulting magnetic field B
�� Oersted discovered the magnetic effect of electric current. �� Magnetic field lines around a straight conductor are circular. �� The compass aligns along the magnetic field direction, not parallel to the wire.
Hans Christian Oersted observed that a compass needle placed near a current-carrying conductor gets deflected whenever current flows through the wire. This observation provided the first experimental evidence that electricity and magnetism are related phenomena. According to NCERT, the magnetic field produced by a straight current-carrying conductor consists of concentric circular field lines centered on the conductor. The direction of the magnetic field at any point is tangential to these circular field lines and can be determined using the right-hand thumb rule. Since the compass needle always aligns itself along the magnetic field direction, it becomes tangent to the circular magnetic field lines. Therefore, the needle is not parallel to the conductor. If the current direction is reversed, the magnetic field direction also reverses, causing the compass needle to deflect in the opposite direction. Iron filings reveal the pattern of magnetic field lines as concentric circles around the wire. Hence, statement B is incorrect and is the correct answer to the question.
- �� Option A → Correct because iron filings arrange themselves along circular magnetic field lines.
- �� Option C → Correct because reversing current reverses the magnetic field direction.
- �� Option D → Correct because Oersted's experiment established the connection between electricity and magnetism.
NCERT Recall
- Application
- Recall the observations and conclusions of Oersted's experiment from NCERT. Understand the geometry of magnetic field lines around a straight conductor.
- Final Logic
- A compass aligns with magnetic field lines, which are circular around the wire. Therefore, it cannot be completely parallel to the wire.
Current Creates Circles
2 Concept originator for "fields propagating in finite time" vs "mathematical unification of light and electromagnetism"
�� Faraday introduced the concept of fields. �� Maxwell developed electromagnetic theory mathematically. �� Maxwell linked light with electromagnetic waves.
Michael Faraday introduced the revolutionary concept of electric and magnetic fields. Before Faraday, interactions were generally explained using action-at-a-distance ideas. Faraday proposed that charges and magnets create fields in the surrounding space, and changes in these fields propagate through space. This idea laid the foundation for modern electromagnetic theory. James Clerk Maxwell later formulated a complete mathematical theory of electromagnetism using a set of equations now known as Maxwell's equations. These equations unified electricity and magnetism into a single framework and predicted the existence of electromagnetic waves. Maxwell showed that electromagnetic waves travel with a speed equal to the speed of light, leading to the conclusion that light itself is an electromagnetic wave. Thus, Faraday is credited with introducing the field concept and finite propagation ideas, while Maxwell provided the mathematical unification of electricity, magnetism and light. Therefore, option A is correct.
- �� Option B → Maxwell did not originate the field concept; Faraday did.
- �� Option C → Oersted discovered the magnetic effect of current but did not formulate field theory.
- �� Option D → Ampere contributed to electrodynamics but not to the field concept and unification of light.
NCERT Recall
- Application
- Identify the historical contributions of major scientists discussed in NCERT.
- Final Logic
- Faraday introduced fields; Maxwell unified electricity, magnetism and light mathematically.
Faraday Felt Fields, Maxwell Made Mathematics
3 A particle with charge q = 1.6 × 10⁻¹⁹ C moves with velocity v = 3 × 10⁷ m/s purely in the +x-direction and experiences a Lorentz force strictly in the -z direction due to a magnetic field of 6 × 10⁻⁴ T. Assuming no electric field, what must be the direction of the magnetic field if the particle is an electron?
A.+z axis
�� Magnetic force is given by q(v × B). �� Electron has negative charge. �� Force direction reverses for negative charge.
The magnetic force acting on a moving charged particle is given by the Lorentz force equation: F = q(v × B) The velocity is along the +x-direction. The force experienced by the electron is along the −z-direction. Since the electron carries a negative charge, the direction of force is opposite to the direction of the vector product (v × B). If B is along the +y-axis, then: î × ĵ = k̂ Thus, v × B points along +z. Because the particle is an electron, the force acts opposite to +z, which is −z. This matches the given condition exactly. The magnetic field cannot be along the z-axis because then the cross product would produce force along the y-direction. Therefore, only a magnetic field along the +y-axis satisfies the given information. Hence, option C is correct.
- �� Option A → Gives force perpendicular to the required direction.
- �� Option B → Produces force in the opposite direction.
- �� Option D → Does not produce the specified force direction.
Concept Application
- Application
- Use the Lorentz force equation and right-hand rule, then reverse the direction because the charge is negative.
- Final Logic
- For v along +x and B along +y, v × B = +z. Electron reverses this to −z.
Electron Flips the Force
4 Correct statements about the principle of superposition applied to Biot-Savart law
Statements:
1. The magnetic field is a linear vector field in relation to its source I dl.
2. If there are more current elements, the fields add vectorially.
3. The magnetic field dB due to an element has an angle dependence sinθ which is maintained during superposition.
4. Superposition allows integration of dB over the entire loop to find the net field at the center.
�� Biot-Savart law is linear. �� Magnetic fields add vectorially. �� Integration gives net field.
According to the Biot-Savart law, the magnetic field due to a current element is proportional to I dl sinθ. This expression is linear in the current element, which allows the principle of superposition to be applied. When several current elements contribute to the magnetic field at a point, the total magnetic field is obtained by vector addition of individual contributions. The angle dependence represented by sinθ remains part of each differential contribution and is considered throughout the integration process. Because magnetic fields obey superposition, the net field due to an extended conductor or current loop can be calculated by integrating dB over the entire current distribution. For example, the magnetic field at the center of a circular current loop is obtained by summing the contributions of all current elements around the loop. Therefore, all four statements correctly describe the role of superposition in the Biot-Savart law.
- �� Option A → Omits statement 2 which is correct.
- �� Option B → Omits statements 3 and 4 which are correct.
- �� Option C → Omits statement 1 which is correct.
NCERT Recall
- Application
- Recall the derivation and interpretation of Biot-Savart law.
- Final Logic
- All four statements directly follow from the mathematical form of Biot-Savart law.
"Linear → Add → Integrate"
5 If a current-carrying wire is placed exactly along the earth's magnetic north-south direction, and a compass needle is placed directly above the wire, how does the needle align if the current is strong enough to dominate the Earth's field?
�� A current-carrying wire produces concentric circular magnetic field lines. �� A compass needle always aligns along the magnetic field direction. �� If the wire's magnetic field dominates, the needle aligns tangentially to the circular field lines.
According to NCERT, the magnetic field produced by a straight current-carrying conductor consists of concentric circles centered on the conductor. The direction of these magnetic field lines can be determined using the right-hand thumb rule. A compass needle always aligns itself along the direction of the resultant magnetic field at its location. When the conductor is placed along the Earth's north-south direction and a compass is positioned directly above the wire, the magnetic field due to the conductor is tangential to the circular field lines. If the current is sufficiently large, the magnetic field produced by the wire becomes much stronger than the Earth's magnetic field. In such a situation, the compass responds mainly to the magnetic field of the wire rather than the Earth's field. At the point directly above the wire, the magnetic field is directed along the east-west direction. Therefore, the compass needle aligns tangentially to the circular magnetic field lines and becomes perpendicular to the wire. Hence, the needle points along the east-west direction, making Option B correct.
- �� Option A → Incorrect because the compass aligns with the magnetic field direction, not necessarily parallel to the wire. Around a straight conductor, the magnetic field is circular and tangent to the circles.
- �� Option C → Incorrect because magnetic field lines around a straight conductor are horizontal circular loops, not directed vertically downward toward the wire.
- �� Option D → Incorrect because the compass needle reaches a stable equilibrium position along the resultant magnetic field direction and does not rotate randomly.
Concept Application
- Application
- Apply the concept of magnetic field lines around a straight current-carrying conductor and the fact that a compass needle aligns along the local magnetic field direction.
- Final Logic
- The magnetic field around a straight conductor is circular. Directly above the wire, the field is along the east-west direction. Therefore, the compass aligns perpendicular to the wire.
- Above wire → East-West direction
6 Identify the correct statements regarding the limitation of iron filing patterns.
Statements:
1. They show the magnitude of the field quantitatively at any given distance r.
2. They form concentric circles reflecting the tangent nature of magnetic field lines around a straight conductor.
3. They indicate the presence of a magnetic field but do not directly show the vector direction without a compass.
4. They provide visual evidence of cylindrical symmetry around a straight current-carrying conductor.
�� Iron filings reveal magnetic field patterns. �� They do not provide numerical values of magnetic field strength. �� A compass is required to determine field direction.
Iron filings are commonly used to visualize magnetic field patterns around magnets and current-carrying conductors. When sprinkled around a straight current-carrying wire, the filings arrange themselves along concentric circular paths, revealing the shape of the magnetic field lines. This demonstrates the cylindrical symmetry of the magnetic field around the conductor. However, iron filings only provide a qualitative representation of the magnetic field. They do not measure the magnitude of the field at different points. To determine the exact strength of the magnetic field, mathematical expressions such as the Biot–Savart law or Ampere's law must be used. Furthermore, iron filings alone cannot indicate the direction of the magnetic field. A magnetic compass is needed to identify the direction of the field at a particular point because the compass needle aligns tangentially to the field lines. Therefore, statements 2, 3 and 4 are correct, whereas statement 1 is incorrect.
- �� Option B → Includes statement 1, which is incorrect because iron filings do not provide quantitative field values.
- �� Option C → Includes statement 1 and excludes statements 2 and 3, both of which are correct.
- �� Option D → Excludes statement 4, which is also correct.
NCERT Recall
- Application
- Recall the limitations of field visualization techniques discussed in NCERT and distinguish between qualitative and quantitative information.
- Final Logic
- Iron filings reveal field patterns and symmetry but cannot measure field strength or independently indicate direction.
"Filings Show Shape, Not Strength"
7 A circular loop carrying current I lies in the xy-plane. If the magnetic field at the center is represented by a dot (·), the magnetic moment vector m of the loop can be expressed as:
�� Magnetic moment is perpendicular to the plane of the loop. �� A dot indicates an outward direction. �� Area of a circular loop is πR².
The magnetic dipole moment of a current-carrying circular loop is given by: m = IA where I is the current and A is the area vector. The magnitude of the area vector for a circular loop is πR². The direction of the magnetic moment is determined using the right-hand thumb rule. If the fingers curl in the direction of current, the thumb points in the direction of the magnetic moment. A dot (·) represents a vector coming out of the plane of the paper. Since the loop lies in the xy-plane, the outward direction corresponds to the positive z-axis or k̂ direction. Therefore, the magnetic moment vector is: m = I(πR²)k̂
- �� Option A → Magnetic moment cannot lie in the plane of the loop.
- �� Option B → Represents the magnetic moment along the negative z-direction.
- �� Option D → Uses circumference instead of area and has an incorrect direction.
Concept Application
- Application
- Apply the formula m = IA and determine direction using the right-hand thumb rule.
- Final Logic
- Dot means outward (+z direction), and area of the loop equals πR². Therefore m = I(πR²)k̂.
Dot Means Positive Pot
8 Match the following.
| List I | List II |
|---|---|
| 1. Wire along +x, current +x, observation at +y | a. Dot (Outward) |
| 2. Wire along +x, current +x, observation at –y | b. Cross (Inward) |
| 3. Loop in xy-plane, clockwise current, center point | c. Inward magnetic field |
| 4. Loop in xy-plane, anticlockwise current, center point | d. Outward magnetic field |
�� Right-hand thumb rule determines magnetic field direction. �� Clockwise current produces inward field. �� Anticlockwise current produces outward field.
For a straight conductor carrying current along the positive x-axis, the magnetic field direction is determined using the right-hand thumb rule. At a point on the positive y-axis, the magnetic field points outward from the plane, represented by a dot. At a point on the negative y-axis, the field points inward, represented by a cross. For a circular loop, the right-hand thumb rule is again applied. If the current is clockwise when viewed from above, the magnetic field at the center is directed inward. If the current is anticlockwise, the magnetic field at the center is directed outward. Thus: 1 → a 2 → b 3 → c 4 → d Therefore, Option A gives the correct matching.
- �� Option B → Reverses the field directions for the straight conductor.
- �� Option C → Incorrectly assigns the same field direction to both observation points.
- �� Option D → Reverses loop field directions and conductor field directions.
Logical Analysis
- Application
- Apply the right-hand thumb rule separately for straight conductors and circular loops.
- Final Logic
- Positive y gives outward field, negative y gives inward field, clockwise loop gives inward field and anticlockwise loop gives outward field.
"Clockwise Cross, Anticlockwise Arrow"
9 The fact that a moving charge experiences a magnetic force that is perpendicular to both its velocity and the magnetic field ensures that:
�� Magnetic force is always perpendicular to velocity. �� Work done by magnetic force is zero. �� Speed remains constant.
The magnetic force acting on a moving charged particle is given by: F = q(v × B) The force is always perpendicular to the instantaneous velocity of the particle. Since work done is given by: W = F · s and the force remains perpendicular to displacement, the scalar product becomes zero. Therefore, the magnetic force does no work on the particle. As a result, the kinetic energy of the particle remains constant. Since kinetic energy depends on speed, the magnitude of velocity remains unchanged. However, the direction of velocity may change continuously, causing the particle to move in circular or helical paths. This property is fundamental to the operation of cyclotrons, mass spectrometers and many charged particle devices. Hence Option D correctly describes the consequence of the magnetic force being perpendicular to velocity.
- �� Option A → The particle does not slow down because no energy is removed.
- �� Option B → Magnetic force cannot increase kinetic energy because it does no work.
- �� Option C → Magnetic force often causes circular or helical motion rather than straight-line motion.
Concept Application
- Application
- Use the work-energy theorem and the perpendicular nature of magnetic force.
- Final Logic
- Force perpendicular to motion implies zero work; therefore speed and kinetic energy remain constant.
"Magnetic Turns, Never Burns"
10 A tightly wound 100-turn coil of radius 10 cm carrying a steady current of 1 A is evaluated for its central magnetic field. The magnitude of this field is:
�� Use magnetic field at the center of a circular coil. �� B = μ₀NI / 2R. �� Substitute values carefully with SI units.
The magnetic field at the center of a circular coil having N turns is: B=μ_0NI/2R Given: N = 100 I = 1 A R = 10 cm = 0.1 m μ₀ = 4π × 10⁻⁷ T m A⁻¹ Substituting: B=(4π×10^(-7))(100)(1)/2(0.1)B=4π×10^(-5)/0.2B=20π×10^(-5)B=6.28×10^(-4) T Unit Verification (T·m/A × A)/m = T Thus, the SI unit obtained is Tesla, confirming dimensional correctness. Therefore, the magnetic field at the center of the coil is 6.28 × 10⁻⁴ T.
- �� Option B → Exactly half of the correct value due to incorrect substitution.
- �� Option C → Hundred times larger than the correct value.
- �� Option D → Results from an incorrect numerical calculation.
Substitution
- Application
- Apply the standard NCERT formula and substitute all quantities in SI units.
- Final Logic
- Using B=μ_0NI/2R with N = 100 and R = 0.1 m gives 6.28×10^(-4)T.
"Center Coil → μ₀NI by 2R"
11 Which fundamental insight was gained immediately from Oersted's observation of the compass needle deflection?
�� Oersted observed compass needle deflection near a current-carrying wire. �� The observation established a connection between electricity and magnetism. �� It was the first experimental proof linking the two phenomena.
In 1820, Hans Christian Oersted discovered that a compass needle placed near a current-carrying conductor undergoes deflection whenever electric current flows through the wire. Before this discovery, electricity and magnetism were considered entirely separate branches of physics. Oersted's experiment demonstrated that an electric current can produce a magnetic effect, thereby revealing a direct relationship between electrical and magnetic phenomena. This observation became one of the most important milestones in the development of electromagnetism. It provided the first empirical evidence that electricity and magnetism are interconnected. The discovery inspired scientists such as Ampere, Faraday and Maxwell to investigate electromagnetic interactions further. Ultimately, these studies led to Maxwell's electromagnetic theory, which unified electricity, magnetism and light. Therefore, the immediate and fundamental insight obtained from Oersted's experiment was that electricity and magnetism are closely related physical phenomena. Hence, Option B is correct.
- �� Option A → Incorrect because Oersted's experiment confirmed the existence of magnetic effects produced by electric currents.
- �� Option C → Incorrect because the experiment does not imply the existence of magnetic monopoles.
- �� Option D → Incorrect because the relationship between light and electromagnetism was established later through Maxwell's theory.
NCERT Recall
- Application
- Recall the significance of Oersted's experiment and its contribution to the historical development of electromagnetism.
- Final Logic
- Compass deflection due to electric current directly showed that electricity and magnetism are connected.
"Oersted Opened Electromagnetism"
12 Maxwell's theoretical unification extended Faraday's field concept to imply that electric and magnetic fields:
�� Maxwell extended Faraday's field concept. �� Electromagnetic fields can vary with time. �� Electromagnetic waves transport energy and momentum.
Faraday introduced the concept of electric and magnetic fields as physical entities filling space. Maxwell extended this idea mathematically through his famous equations. One of Maxwell's most significant contributions was showing that electric and magnetic fields are dynamic quantities that can change with both position and time. According to Maxwell's equations, a changing electric field produces a magnetic field, and a changing magnetic field produces an electric field. This mutual generation allows electromagnetic disturbances to propagate through space in the form of electromagnetic waves. These waves travel at the speed of light and carry both energy and momentum. This theoretical framework led Maxwell to conclude that light itself is an electromagnetic wave. Therefore, electromagnetic fields are not merely static entities; they can evolve with time and transport energy across space. This insight forms the basis of modern electromagnetic theory and many technologies such as radio communication and optical transmission. Hence, Option C is correct.
- �� Option A → Incorrect because electromagnetic interactions propagate at finite speed, namely the speed of light.
- �� Option B → Incorrect because Maxwell's theory rejects instantaneous action at a distance.
- �� Option D → Incorrect because electromagnetic waves are dynamic, not purely static, and can carry momentum.
Concept Application
- Application
- Apply Maxwell's interpretation of time-varying electric and magnetic fields.
- Final Logic
- Changing electric and magnetic fields sustain each other and propagate energy as electromagnetic waves.
"Maxwell Made Fields Move"
13 Using Ampere's circuital law, the magnetic field B inside a long solenoid carrying a current I with n turns per unit length is derived as:
�� Ampere's circuital law is applied to a long solenoid. �� Magnetic field inside a long solenoid is uniform. �� Field depends on turn density and current.
A long solenoid consists of a large number of closely wound turns carrying current. Using Ampere's circuital law, ∮ B · dl = μ₀Ienclosed an Amperian rectangular path is chosen partly inside and partly outside the solenoid. For an ideal long solenoid, the magnetic field outside is nearly zero, while the field inside is uniform and parallel to the axis. If n represents the number of turns per unit length and I is the current through each turn, then the enclosed current for a length l is: Ienclosed = nlI Substituting into Ampere's law: Bl = μ₀nlI Therefore, B = μ₀nI This result shows that the magnetic field inside a long solenoid depends only on the current and the turn density. It is independent of the radius of the solenoid, making the field highly uniform and useful in electromagnetic devices. Hence, Option A is correct.
- �� Option B → Represents the magnetic field due to a long straight conductor.
- �� Option C → Incorrect because the factor 1/2 does not appear in the solenoid field expression.
- �� Option D → Represents the field at the center of a circular loop, not a solenoid.
NCERT Recall
- Application
- Recall the derivation of magnetic field inside a long solenoid using Ampere's circuital law.
- Final Logic
- For a long solenoid, Ampere's law directly gives B = μ₀nI.
"Solenoid = μ₀ × Turns Density × Current"
14 Given c=1/√(μ_0ε_0), if μ₀ is exactly fixed to 4π×10^(-7)T m/A and c=3×10^8 m/s, what is the calculated value of ε₀?
�� Use the relation connecting c, μ₀ and ε₀. �� Substitute the known values. �� Verify equivalent numerical forms.
Maxwell's electromagnetic theory established the relation: c=1/√(μ_0ε_0) Rearranging, ε_0=1/μ_0c^2 Substituting: μ_0=4π×10^(-7)c=3×10^8 m/sε_0=1/(4π×10^(-7))(9×10^(16))ε_0=1/36π×10^9 Evaluating numerically, ε_0=8.85×10^(-12) C^2/Nm^2 Thus, Option A and Option C are simply two different representations of the same physical constant. Since both values are equivalent, Option D is the correct answer.
- �� Option A → Numerically correct but incomplete because Option D recognizes its equivalence with Option C.
- �� Option B → Gives an incorrect expression for permittivity.
- �� Option C → Numerically correct but not the most complete answer since A and C are equivalent.
Substitution
- Application
- Substitute the known constants into Maxwell's relation and compare numerical forms.
- Final Logic
- Both 1/(36π×10^9)and 8.85×10^(-12)represent ε₀.
"Eight Point Eight Five → Permittivity Alive"
15 Identify the correct statements concerning the unit Tesla and the force equation F=qvBsinθ.
Statements:
1. Its dimensional formula is [M T⁻² A⁻¹].
2. It is defined when a 1 C charge moving at 1 m/s perpendicular to B experiences 1 N force.
3. It can be expressed as Newton second/(coulomb metre).
4. It is considered a rather small unit for laboratory purposes.
�� Tesla is the SI unit of magnetic field. �� It is derived from the Lorentz force equation. �� Tesla is actually a large practical unit.
The SI unit of magnetic field strength is Tesla (T). From the Lorentz force equation, F=qvBsinθ For perpendicular motion (θ=90^∘), B=F/qv If a charge of 1 C moving with a velocity of 1 m/s experiences a force of 1 N, then the magnetic field is defined as 1 Tesla. Therefore, statement 2 is correct. Using the unit expression, T=N/Cm/s=Ns/Cm Thus statement 3 is also correct. The dimensional formula becomes: [M T^(-2) A^(-1)] making statement 1 correct. However, Tesla is a comparatively large unit. In many laboratory measurements, smaller units such as millitesla or microtesla are frequently encountered. Therefore, statement 4 is incorrect. Hence, statements 1, 2 and 3 are correct.
- �� Option A → Includes statement 4 and excludes statement 2, which is correct.
- �� Option B → Includes statement 4, which is incorrect.
- �� Option D → Includes statement 4 and excludes statement 3, which is correct.
Concept Application
- Application
- Apply the Lorentz force equation and derive the SI unit and dimensions of Tesla.
- Final Logic
- Tesla is derived from B=F/qv; statements 1, 2 and 3 are correct, while statement 4 is false.
Tesla = Newton Second per Coulomb Metre
16 The horizontal component of the Earth's magnetic field at a certain place is 3.0×10^(-5)T. What is this value in Gauss?
�� Tesla and Gauss are units of magnetic field. �� 1 T=10^4 G �� Convert Tesla to Gauss using the conversion factor.
The SI unit of magnetic field is Tesla (T), while Gauss (G) is a commonly used CGS unit. The relationship between these units is: 1 T=10^4 G Given: B=3.0×10^(-5) T Converting to Gauss: B=(3.0×10^(-5))×10^4B=3.0×10^(-1)B=0.3 G The horizontal component of the Earth's magnetic field is typically of the order of 10^(-5) T, which corresponds to a fraction of a Gauss. Therefore, the converted value is 0.3 G. Unit Verification T×10^4=G Thus, the unit conversion is dimensionally correct. Hence, Option A is the correct answer.
- �� Option B → Ten times larger than the correct value.
- �� Option C → Ten times smaller than the correct value.
- �� Option D → Hundred times larger than the correct value.
Substitution
- Application
- Use the standard conversion 1 T=10^4 G and substitute the given value.
- Final Logic
- 3.0×10^(-5)T×10^4=0.3G
"Tesla to Gauss → Multiply by Ten Thousand"
17 Incorrect statement regarding electromagnetic waves and their origins.
�� Maxwell predicted electromagnetic waves theoretically. �� Hertz verified their existence experimentally. �� Bose and Marconi contributed to wireless communication.
James Clerk Maxwell developed a mathematical theory of electromagnetism and predicted the existence of electromagnetic waves. His equations showed that oscillating electric and magnetic fields could propagate through space at the speed of light. From this result, Maxwell concluded that light itself is an electromagnetic wave. Several years later, Heinrich Hertz experimentally generated and detected electromagnetic waves, thereby confirming Maxwell's prediction. Hertz's experiments provided direct evidence for the existence of radio waves and validated Maxwell's electromagnetic theory. The subsequent work of scientists such as Jagadish Chandra Bose and Guglielmo Marconi helped develop practical applications of electromagnetic waves, especially in wireless communication. These developments revolutionized science, engineering and technology throughout the twentieth century. Therefore, the statement that Hertz theorized electromagnetic waves before Maxwell formulated his laws is historically incorrect. Maxwell's theoretical prediction came first, followed by Hertz's experimental verification.
- �� Option A → Correct because Maxwell demonstrated that light is electromagnetic in nature.
- �� Option C → Correct because electromagnetic wave technology transformed communication, broadcasting and electronics.
- �� Option D → Correct because Bose and Marconi contributed significantly after Hertz's experiments.
NCERT Recall
- Application
- Recall the chronological development of electromagnetic wave theory from Maxwell to Hertz and later pioneers.
- Final Logic
- Maxwell predicted electromagnetic waves first; Hertz verified them experimentally later.
"Maxwell Predicted, Hertz Proved"
18 Identify the correct statements about fields conveying signals and energy.
Statements:
1. The electric field is an artifact and cannot convey real physical momentum.
2. Both electric and magnetic fields can vary with time and propagate through space.
3. The magnetic field B is a vector field that is established instantaneously.
4. Moving charges and currents are the sources of the magnetic field used in these transmissions.
�� Electromagnetic fields carry energy and momentum. �� Time-varying fields propagate through space. �� Magnetic effects do not propagate instantaneously.
Modern electromagnetic theory treats electric and magnetic fields as real physical entities capable of storing and transporting energy and momentum. Maxwell's equations show that time-varying electric fields produce magnetic fields and vice versa. This mutual interaction allows electromagnetic waves to travel through space. Electromagnetic waves are responsible for radio communication, television broadcasting, mobile communication and many other technologies. These waves carry energy and momentum from one location to another. Moving electric charges and electric currents are the primary sources of magnetic fields. Therefore, statement 4 is correct. Statement 2 is also correct because electric and magnetic fields can vary with time and propagate through space. Statement 1 is incorrect because electromagnetic fields are physical entities capable of carrying momentum. Statement 3 is incorrect because changes in electromagnetic fields propagate at a finite speed equal to the speed of light rather than instantaneously. Hence, only statements 2 and 4 are correct.
- �� Option B → Includes statements 1 and 3, both of which are incorrect.
- �� Option C → Includes statement 3, which is incorrect.
- �� Option D → Includes statement 1, which is incorrect.
Concept Application
- Application
- Apply Maxwell's theory regarding propagation of electromagnetic fields and energy transfer.
- Final Logic
- Fields are real physical entities, propagate at finite speed and originate from charges and currents.
"Fields Carry, Not Imaginary"
19 Comparing Ampere's law loops to Gauss's law surfaces:
�� Ampere's law uses a closed path. �� Gauss's law uses a closed surface. �� Both simplify highly symmetric problems.
Ampere's circuital law and Gauss's law are powerful tools used in electromagnetism. Although both are based on symmetry considerations, they differ in the type of mathematical integration involved. Ampere's law is expressed as: ∮B⋅dl=μ_0I_(enc) This involves line integration of the magnetic field around a closed one-dimensional path called an Amperian loop. Gauss's law for electricity is expressed as: ∮E⋅dA=Q_(enc)/ε_0 This involves surface integration of the electric field over a closed two-dimensional surface known as a Gaussian surface. Thus, Ampere's law deals with boundary line integrals, whereas Gauss's law involves flux through a closed surface. This distinction is fundamental in electromagnetic field analysis and forms the basis of many NCERT derivations. Therefore, Option D is correct.
- �� Option A → Neither law is fundamentally expressed as a volume integral.
- �� Option B → Ampere's law does not use surface integration and Gauss's law does not use volume integration.
- �� Option C → Interchanges the roles of Ampere's law and Gauss's law.
NCERT Recall
- Application
- Recall the mathematical forms of Ampere's law and Gauss's law.
- Final Logic
- Ampere's law uses a closed path integral; Gauss's law uses a closed surface integral.
"Ampere Around, Gauss Across"
20 For an electric dipole, the field at a distant point on its axis is
E≃2p_e/4πε_0x^3
By replacing p_e with m and 1/ε_0 with μ_0, the magnetic field B on the axis of a point magnetic dipole (current loop) at a large distance x is:
�� Magnetic dipole field resembles electric dipole field. �� Replace electric dipole moment by magnetic dipole moment. �� Distance dependence remains x^(-3).
A current-carrying circular loop behaves like a magnetic dipole. At distances much larger than the size of the loop, the magnetic field resembles the field of an ideal magnetic dipole. For an electric dipole, the axial field is: E=2p_e/4πε_0x^3 A useful analogy exists between electric and magnetic dipoles. Replacing the electric dipole moment p_e with the magnetic dipole moment m, and replacing the electric constant term 1/ε_0 with the magnetic constant μ_0, the axial magnetic field becomes: B=μ_0/4π2m/x^3 or B=μ_02m/4πx^3 This expression is widely used for describing the field of a magnetic dipole at distant points along its axis. The inverse cube dependence indicates that the magnetic field decreases rapidly with increasing distance. Therefore, Option B is correct.
- �� Option A → Missing the factor of 2 present in the axial dipole field expression.
- �� Option B → Incorrect distance dependence; should vary as 1/x^3.
- �� Option D → Incorrect coefficient and mathematical form.
Analogy Method
- Application
- Use the correspondence between electric dipole and magnetic dipole field expressions.
- Final Logic
- Replace p_e by m and 1/ε_0 by μ_0, keeping the axial dipole factor 2 unchanged.
Dipole Axis → Factor Two Applies
