CUET UG Physics Booster Test 3-Fundamentals of Electromagnetic Induction -

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CUET UG Physics Booster Test 3-Fundamentals of Electromagnetic Induction

⏱️ 30 Minutes

❓ 20 Questions

📌 Answers are locked once submitted — results and explanations appear at the end.

CUET UG Physics Booster Test 3-Fundamentals of Electromagnetic Induction

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QUESTION 1 OF 20

Incorrect statement regarding the historical development of electromagnetism

Answer Review

1 Incorrect statement regarding the historical development of electromagnetism

A Oersted and Ampere established the link between moving charges and magnetic fields.

B The converse effect, moving magnets producing electric currents, was proven by Oersted.

C Michael Faraday and Joseph Henry independently discovered electromagnetic induction.

D Electricity and magnetism were historically considered separate phenomena.

💡 Short Explanation

�� Oersted discovered magnetic effect of current. �� Faraday and Henry discovered electromagnetic induction. �� Oersted did not prove induction.

✅ Correct Answer Explanation

Oersted demonstrated that electric current produces a magnetic effect. → Ampere further developed the relationship between electricity and magnetism. → The converse phenomenon, namely production of current by changing magnetic fields, was discovered independently by Michael Faraday and Joseph Henry. → Therefore statement B is historically incorrect.

❓ Why Other Options Are Incorrect

�� Option A → Correct historical contribution of Oersted and Ampere.
�� Option C → Correct; both independently discovered induction.
�� Option D → Correct; electricity and magnetism were once viewed separately.

🎯 Strategy

Used

�� Elimination

Application:

�� Identify which scientist actually discovered electromagnetic induction.

Final Logic:

�� Faraday and Henry, not Oersted, discovered induction.

🧠 Memory Trick

Oersted: Current → Magnet; Faraday: Magnet → Current

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Historical Development of Electromagnetism

2 Correct statements about Faraday's Experiment 6.3 (Stationary coils):
1. It showed relative motion is not an absolute requirement for induction.
2. A momentary deflection occurs only when the key is pressed or released.
3. An iron rod inserted into the coils decreases the deflection dramatically.

A 1, 2

B 2, 3

C 1, 3

D 1, 2, 3

💡 Short Explanation

�� Flux change is essential. �� Pressing or releasing key changes current. �� Iron core increases induction.

✅ Correct Answer Explanation

In Faraday's stationary-coil experiment, induction occurred without mechanical motion. → The induced current appeared only when the current in the neighboring coil changed. → Deflection occurred momentarily during pressing or releasing of the key. → An iron rod enhances magnetic flux linkage and increases, not decreases, deflection.

❓ Why Other Options Are Incorrect

�� Option B → Statement 3 is false.
�� Option C → Statement 3 is false.
�� Option D → Includes incorrect statement 3.

🎯 Strategy

Used

�� Elimination

Application:

�� Check the effect of an iron core on magnetic flux.

Final Logic:

�� Iron core strengthens induction; therefore statement 3 is wrong.

🧠 Memory Trick

Iron Core = More Flux

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Faraday's Stationary Coil Experiment

3 Regarding the core concept of induction:
1. It relies strictly on the conservation of charge.
2. An emf is induced whenever magnetic flux through a circuit changes.
3. Induced emf is produced even if the circuit is open.
Choose correct:

A 1 and 2

B 2 and 3

C 1 and 3

D 1, 2, and 3

💡 Short Explanation

�� Flux change induces emf. �� Closed circuit is required for current, not emf. �� Conservation of charge is not the primary basis.

✅ Correct Answer Explanation

Faraday's law states that a changing magnetic flux induces emf. → Induced emf exists whether the circuit is open or closed. → In an open circuit, emf is produced but current cannot flow. → Statement 1 is incorrect because induction is governed by changing magnetic flux, not solely conservation of charge.

❓ Why Other Options Are Incorrect

�� Option A → Includes incorrect statement 1.
�� Option C → Statement 1 is false.
�� Option D → Statement 1 remains incorrect.

🎯 Strategy

Used

�� Elimination

Application:

�� Distinguish between induced emf and induced current.

Final Logic:

�� Flux change creates emf even without a closed conducting path.

🧠 Memory Trick

EMF First, Current Later

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Basic Concept of Induction

4 Match List I (Experiment Setup) with List II (Current Behavior)

List I (Experiment Setup)	List II (Current Behavior)
(1) Coil C₁ fixed, C₂ (with steady current) moves towards C₁	(a) Current is induced in C₁
(2) Tapping key K connecting stationary C₂ to battery is held pressed	(b) Current in C₁ drops to zero
(3) Key K is just pressed in stationary C₂ circuit	(c) Momentary current is induced in C₁
(4) Key K is released from stationary C₂ circuit	(d) Momentary current is induced in opposite direction in C₁

A 1-a, 2-b, 3-c, 4-d

B 1-b, 2-a, 3-c, 4-d

C 1-a, 2-c, 3-b, 4-d

D 1-d, 2-b, 3-a, 4-c

💡 Short Explanation

Electromagnetic induction occurs only when magnetic flux changes. Relative motion between coils changes flux and induces current. A steady current produces constant flux and no sustained induction. Making or breaking the circuit produces momentary induction.

✅ Correct Answer Explanation

When C₂ moves towards C₁, the magnetic flux linked with C₁ changes continuously. → Therefore, a current is induced in C₁. → When the key K remains pressed, current in C₂ becomes steady after a short time. → The magnetic flux then becomes constant, so the induced current in C₁ drops to zero. → When the key is just pressed, current in C₂ rises from zero to a finite value. → This changing current produces a changing magnetic flux, causing a momentary induced current in C₁. → When the key is released, current in C₂ falls to zero. → The magnetic flux decreases, producing a momentary induced current in the opposite direction. Therefore: 1 → a 2 → b 3 → c 4 → d Hence, Option A is correct.

❓ Why Other Options Are Incorrect

Option B: Reverses the observations for moving coil and steady-current cases.
Option C: Incorrectly assigns induction to the steady-current condition.
Option D: Incorrectly matches the directions and nature of induced currents.

🎯 Strategy

Used

Matching / Flux-Change Analysis

Application:

Determine whether the magnetic flux linked with C₁ is changing or constant.

Final Logic:

Changing flux → Induced current.
Constant flux → No induced current.
Increasing and decreasing flux produce opposite current directions.

🧠 Memory Trick

"Make → Induce, Break → Reverse"

📚 Topic: Faraday's Coil Experiments and Conditions for Electromagnetic Induction.

5 Definition of Flux statements:
1. It is defined similarly to electric flux.
2. It measures the magnetic field mathematically across a given area.
3. It is maximized when the area vector is perpendicular to the magnetic field.

A 1, 2

B 2, 3

C 1, 3

D 1, 2, 3

💡 Short Explanation

�� Flux is analogous to electric flux. �� Measures magnetic field through a surface. �� Maximum flux occurs when area vector is parallel to field.

✅ Correct Answer Explanation

Magnetic flux is defined as Φ = B·A. → It measures magnetic field passing through a surface. → Maximum flux occurs when θ = 0° between B and area vector. → Therefore statement 3 is incorrect.

❓ Why Other Options Are Incorrect

�� Option B → Includes false statement 3.
�� Option C → Includes false statement 3.
�� Option D → Includes false statement 3.

🎯 Strategy

Used

�� Elimination

Application:

�� Recall condition for maximum value of cos θ.

Final Logic:

�� Maximum flux occurs when B and A are parallel.

🧠 Memory Trick

Max Flux → B ∥ A

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Magnetic Flux

6 Which mathematical operation correctly proves that magnetic flux is a scalar nature?

A The cross product of B and A

B The dot product of B and A

C The vector addition of B and A

D The scalar division of B by A

💡 Short Explanation

�� Flux = B·A. �� Dot product gives scalar quantity. �� Therefore flux is scalar.

✅ Correct Answer Explanation

Magnetic flux is defined as: Φ = B·A → Since dot product always produces a scalar quantity, magnetic flux is scalar. → This directly establishes the scalar nature of flux.

❓ Why Other Options Are Incorrect

�� Option A → Cross product gives vector.
�� Option C → Vector addition does not define flux.
�� Option D → Not used in flux definition.

🎯 Strategy

Used

�� Conceptual Recall

Application:

�� Recall mathematical definition of magnetic flux.

Final Logic:

�� Dot product yields scalar flux.

🧠 Memory Trick

Dot ⇒ Scalar

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Scalar Nature of Magnetic Flux

7 A circular coil of radius 10 cm, 500 turns, and resistance 2 Ω is placed with its plane perpendicular to the horizontal component of the earth's magnetic field (3.0 × 10⁻⁵ T). If rotated by 180° in 0.25 s, what is the magnitude of the estimated induced current? (π ≈ 3.14)

A 1.9 × 10⁻³ A

B 3.8 × 10⁻³ A

C 1.9 × 10⁻² A

D 3.8 × 10⁻² A

💡 Short Explanation

�� ΔΦ = 2BA per turn. �� Use Faraday's law. �� I = ε/R.

✅ Correct Answer Explanation

Area = π(0.1)² = 0.01π m² → Change in flux per turn: ΔΦ = 2BA = 2 × (3×10⁻⁵) × (0.01π) ≈ 1.884 ×10⁻⁶ Wb → Total induced emf: ε = NΔΦ/Δt = 500×1.884×10⁻⁶ /0.25 ≈ 3.77×10⁻³ V → Current: I = ε/R ≈ (3.77×10⁻³)/2 ≈ 1.89×10⁻³ A

❓ Why Other Options Are Incorrect

�� Option B → Equals emf value, not current.
�� Option C → Ten times larger.
�� Option D → Twenty times larger.

🎯 Strategy

Used

�� Substitution

Application:

�� Apply Faraday's law and Ohm's law sequentially.

Final Logic:

�� Numerical calculation gives 1.9 × 10⁻³ A.

🧠 Memory Trick

Flux Change → EMF → Current

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Numerical Applications of Faraday's Law

8 SI Unit Weber is equivalent to which combination of SI units for Magnetic field and Area respectively?

A Tesla, Meter squared

B Gauss, Meter squared

C Tesla, Meter

D Weber/m², Meter

💡 Short Explanation

�� Φ = BA. �� Unit of B = Tesla. �� Unit of A = m².

✅ Correct Answer Explanation

Magnetic flux: Φ = BA → SI unit: Wb = T × m² → Hence Weber corresponds to Tesla multiplied by square meter.

❓ Why Other Options Are Incorrect

�� Option B → Gauss is CGS unit.
�� Option C → Area requires m².
�� Option D → Dimensionally incorrect.

🎯 Strategy

Used

�� Dimensional/Unit Analysis

Application:

�� Derive units directly from flux formula.

Final Logic:

�� Wb = Tm².

🧠 Memory Trick

Weber = Tesla × Area

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: SI Unit of Magnetic Flux

9 When calculating flux through a complex surface, assigning an area vector dAᵢ to each element ensures that

A the varying direction of the normal to the surface is accurately accounted for

B the scalar field becomes a uniform vector

C the magnetic field lines are forced to be parallel

D the area magnitude cancels out the magnetic field magnitude

💡 Short Explanation

�� Curved surfaces have varying normals. �� Each element gets its own area vector. �� Accurate flux calculation becomes possible.

✅ Correct Answer Explanation

Different portions of a complex or curved surface possess different orientations. → Assigning dAᵢ to each element accounts for the local normal direction. → This allows correct evaluation of B·dA over the surface.

❓ Why Other Options Are Incorrect

�� Option B → Flux remains scalar.
�� Option C → Surface does not alter field lines.
�� Option D → No such cancellation occurs.

🎯 Strategy

Used

�� Conceptual Recall

Application:

�� Recall meaning of elemental area vectors.

Final Logic:

�� Local normals are required for accurate integration.

🧠 Memory Trick

dA Tracks Direction

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Area Vector and Surface Orientation

10 Incorrect statement regarding the angle theta in the flux equation

A Rotating a coil changes the angle theta, thus changing the flux.

B When theta is 90°, the magnetic flux is maximized.

C Theta is the angle between the magnetic field vector and the area vector.

D Change in theta can independently induce an emf even if B and A are constant.

💡 Short Explanation

�� Flux = BA cosθ. �� cos90° = 0. �� Maximum flux occurs at θ = 0°.

✅ Correct Answer Explanation

Magnetic flux is: Φ = BA cosθ → At θ = 90°: Φ = 0 → Maximum flux occurs when θ = 0°. → Therefore statement B is incorrect.

❓ Why Other Options Are Incorrect

�� Option A → Correct consequence of rotation.
�� Option C → Correct definition of θ.
�� Option D → Changing θ changes flux and can induce emf.

🎯 Strategy

Used

�� Substitution

Application:

�� Compare flux values at θ = 0° and 90°.

Final Logic:

�� cos0° > cos90°, so maximum flux occurs at 0°.

🧠 Memory Trick

90° = Zero Flux

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Angular Dependence of Magnetic Flux

11 Match List I (Parameter Changed) with List II (Effect on Induced EMF in a Constant B-Field)

List I (Parameter Changed)	List II (Effect on Induced EMF)
(1) Shrinking the coil	(a) Non-zero emf induced
(2) Holding the coil stationary	(b) Zero emf induced
(3) Rotating the coil in the magnetic field	(c) Non-zero emf induced
(4) Increasing the area of the coil	(d) Non-zero emf induced

A 1-a, 2-b, 3-c, 4-d

B 1-b, 2-a, 3-c, 4-d

C 1-a, 2-c, 3-b, 4-d

D 1-d, 2-b, 3-a, 4-c

💡 Short Explanation

Induced emf is produced when magnetic flux changes. Changing the area or orientation of a coil changes magnetic flux. A stationary coil with fixed area and orientation has constant flux. Constant flux means no induced emf.

✅ Correct Answer Explanation

Magnetic flux through a coil is given by: Φ = BA cosθ where (B) is the magnetic field, (A) is the area of the coil, and (\theta) is the angle between the magnetic field and the area vector. → Shrinking the coil decreases the area (A), causing the magnetic flux to change with time. → Therefore, a non-zero emf is induced. → Holding the coil stationary with unchanged area and orientation in a constant magnetic field keeps the magnetic flux constant. → Hence, zero emf is induced. → Rotating the coil changes the angle (\theta), thereby changing the magnetic flux. → Therefore, a non-zero emf is induced. → Increasing the area of the coil also changes the magnetic flux. → Hence, a non-zero emf is induced. Therefore: 1 → a 2 → b 3 → c 4 → d Hence, Option A is correct.

❓ Why Other Options Are Incorrect

Option B: Incorrectly assigns zero emf to a shrinking coil and non-zero emf to a stationary coil.
Option C: Incorrectly assigns zero emf to a rotating coil.
Option D: Does not correctly match the effects produced by changes in area and orientation.

🎯 Strategy

Used

Matching / Flux Analysis

Application:

Use the relation (\Phi = BA\cos\theta).
Check whether (A) or (\theta) changes with time.

Final Logic:

Change in area or orientation → Change in flux → Induced emf.
No change in flux → No induced emf.

🧠 Memory Trick

"Constant Flux = Zero EMF"

📚 Topic: Methods of Changing Magnetic Flux and Faraday's Law of Induction.

12 Correct statements for a plane surface flux:
1. A constant steady field through a stationary plane loop does not induce an emf.
2. If the loop's area changes, the flux changes.
3. Flux is calculated by BA cos θ.

A 1, 2

B 1, 3

C 2, 3

D 1, 2, 3

💡 Short Explanation

�� Constant flux produces no emf. �� Area affects flux. �� Flux formula is BA cosθ.

✅ Correct Answer Explanation

Statement 1 is correct because induction requires changing flux. → Statement 2 is correct since flux depends on area. → Statement 3 is the standard flux relation for a uniform magnetic field. → Therefore all three statements are correct.

❓ Why Other Options Are Incorrect

�� Option A → Omits statement 3.
�� Option B → Omits statement 2.
�� Option C → Omits statement 1.

🎯 Strategy

Used

�� Elimination

Application:

�� Verify each statement using the flux equation and Faraday's law.

Final Logic:

�� All three statements agree with NCERT definitions.

🧠 Memory Trick

Flux Depends on B, A and θ

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Flux Through Plane Surfaces

13 Regarding integration over an area for flux calculation:
1 It is mathematically represented as a summation of elements over a complex surface.
2 It is only required when the field is uniform.
3 It handles variations in both the magnitude and direction of the magnetic field.
Choose correct:

A 1 and 2

B 1 and 3

C 2 and 3

D 3 only

💡 Short Explanation

�� Integration sums elemental contributions. �� Needed for non-uniform fields and complex surfaces. �� Handles varying magnitude and direction.

✅ Correct Answer Explanation

Flux through a complex surface is evaluated by dividing it into infinitesimal elements. → Integration is the limiting form of summing elemental flux contributions. → It accommodates variations in magnetic field strength and direction. → Statement 2 is incorrect because integration is especially useful when the field is non-uniform.

❓ Why Other Options Are Incorrect

�� Option A → Statement 2 is false.
�� Option C → Statement 2 is false.
�� Option D → Statement 1 is also correct.

🎯 Strategy

Used

�� Elimination

Application:

�� Identify the purpose of surface integration.

Final Logic:

�� Integration handles complex surfaces and varying fields.

🧠 Memory Trick

Complex Surface → Integrate

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Flux Integration

14 If the magnetic field Bᵢ over a surface area element dAᵢ = 2.0 cm² changes from 2.0 T to 4.0 T in a direction parallel to the area vector, what is the change in flux through this specific element?

A 4.0 × 10⁻⁴ Wb

B 2.0 × 10⁻⁴ Wb

C 8.0 × 10⁻⁴ Wb

D 4.0 × 10⁻² Wb

💡 Short Explanation

�� ΔΦ = ΔB × A �� Area vector parallel to B. �� θ = 0°.

✅ Correct Answer Explanation

Area: A = 2.0 cm² = 2 × 10⁻⁴ m² → Change in field: ΔB = 4 − 2 = 2 T → Since B is parallel to area vector: ΔΦ = ΔB × A = 2 × 2 × 10⁻⁴ = 4 × 10⁻⁴ Wb

❓ Why Other Options Are Incorrect

�� Option B → Uses only one factor incorrectly.
�� Option C → Double the correct value.
�� Option D → Incorrect unit magnitude.

🎯 Strategy

Used

�� Substitution

Application:

�� Apply ΔΦ = AΔB cosθ.

Final Logic:

�� θ = 0° gives ΔΦ = 4 × 10⁻⁴ Wb.

🧠 Memory Trick

Parallel ⇒ cos0° = 1

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Flux Change Calculation

15 When evaluating magnetic flux through a curved surface, the surface must be conceptually broken down because

A a single area vector cannot properly define the orientation of the entire curved surface

B curved surfaces naturally repel magnetic fields

C magnetic field lines curve to match the surface

D the flux through a curved surface is always zero

💡 Short Explanation

�� Different points have different normals. �� One area vector is insufficient. �� Infinitesimal vectors are used.

✅ Correct Answer Explanation

A curved surface does not possess one unique normal direction. → Different regions have different orientations. → Therefore the surface is divided into infinitesimal elements, each with its own area vector. → Flux is then calculated by integration.

❓ Why Other Options Are Incorrect

�� Option B → No such property exists.
�� Option C → Field lines are not forced to follow surface geometry.
�� Option D → Curved surfaces can have non-zero flux.

🎯 Strategy

Used

�� Conceptual Recall

Application:

�� Recall the definition of area vector on curved surfaces.

Final Logic:

�� Curved surfaces require many local area vectors.

🧠 Memory Trick

Curved Surface = Many Normals

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Flux Through Curved Surfaces

16 If a surface comprises N discrete flat area elements dAᵢ, and the field Bᵢ is constant over each element, the integral for flux simplifies to

A N × B × A

B Σᵢ₌₁ᴺ Bᵢ · dAᵢ

C B × Σ dAᵢ

D B / Σ dAᵢ

💡 Short Explanation

�� Flux is sum of elemental contributions. �� Each element contributes Bᵢ·dAᵢ. �� Integral becomes summation.

✅ Correct Answer Explanation

The flux through an infinitesimal element is: dΦ = Bᵢ·dAᵢ → Total flux equals the sum over all elements. → For discrete elements: Φ = Σ Bᵢ·dAᵢ → Therefore option B is correct.

❓ Why Other Options Are Incorrect

�� Option A → Ignores vector orientation.
�� Option C → Valid only under special uniform conditions.
�� Option D → Not a flux expression.

🎯 Strategy

Used

�� Conceptual Recall

Application:

�� Recall discrete form of surface integration.

Final Logic:

�� Flux equals sum of elemental dot products.

🧠 Memory Trick

Total Flux = Sum of Tiny Fluxes

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Surface Integration

17 Role of varying fields in induction:
1. A changing magnetic field can exert a force on a stationary charge.
2. A time-varying magnetic field generates an electric field.
3. Moving charges in a static field and static charges in a time-varying field both relate to Faraday's law.

A 1, 2

B 2, 3

C 1, 3

D 1, 2, 3

💡 Short Explanation

A changing magnetic field produces an induced electric field. The induced electric field can exert a force on stationary charges. Both motional emf and induced emf due to changing magnetic fields are explained by Faraday's law.

✅ Correct Answer Explanation

According to Faraday's law, a time-varying magnetic field generates an electric field. → The induced electric field can act on charges even when they are initially stationary, causing them to move. → Thus, a changing magnetic field can effectively produce a force on stationary charges through the induced electric field. → Moving charges in a static magnetic field produce motional emf, while stationary charges in a time-varying magnetic field experience transformer emf. → Both situations are manifestations of electromagnetic induction described by Faraday's law. → Therefore, statements 1, 2, and 3 are correct.

❓ Why Other Options Are Incorrect

Option A: Excludes statement 3, which is correct.
Option B: Excludes statement 1, which is correct in the context of the induced electric field produced by a changing magnetic field.
Option C: Excludes statement 2, which is a direct consequence of Faraday's law.

🎯 Strategy

Used

Conceptual Analysis

Application:

Apply Faraday's law to understand the consequences of a time-varying magnetic field.
Relate induced electric fields to the motion of charges and electromagnetic induction.

Final Logic:

Changing magnetic field → Induced electric field.
Induced electric field → Force on charges.
Both motional and transformer emf arise from Faraday's law.

🧠 Memory Trick

"Faraday Links Motion and Variation"

📚 Topic: Role of Varying Magnetic Fields and Induced Electric Fields.

18 In Faraday's law, ε = -N (dΦ_B / dt), the variables N and dt represent respectively:

A Number of poles, Time rate

B Number of turns, Small time interval

C Newton force, Time interval

D Magnetic flux, Total time

💡 Short Explanation

�� N = turns in coil. �� dt = infinitesimal time interval. �� Appears in rate of flux change.

✅ Correct Answer Explanation

N represents the total number of turns linked with magnetic flux. → dt represents a very small time interval over which flux changes. → The expression gives induced emf proportional to the rate of flux change.

❓ Why Other Options Are Incorrect

�� Option A → N does not represent poles.
�� Option C → N is not Newton.
�� Option D → N is not flux.

🎯 Strategy

Used

�� Conceptual Recall

Application:

�� Recall standard form of Faraday's law.

Final Logic:

�� N counts turns and dt measures time interval.

🧠 Memory Trick

N = Number of Turns

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Faraday's Law

19 Correct statements about relative motion principles:
1. Moving coil towards magnet induces current.
2. Moving magnet towards coil induces current.
3. Moving a current-carrying coil towards another coil induces current.

A 1, 2

B 2, 3

C 1, 3

D 1, 2, 3

💡 Short Explanation

�� Relative motion changes flux. �� Coil or magnet may move. �� Mutual induction also occurs.

✅ Correct Answer Explanation

Moving a coil toward a magnet changes magnetic flux. → Moving a magnet toward a coil also changes flux. → Bringing a current-carrying coil near another coil changes linked magnetic flux and induces current. → Therefore all three statements are correct.

❓ Why Other Options Are Incorrect

�� Option A → Omits statement 3.
�� Option B → Omits statement 1.
�� Option C → Omits statement 2.

🎯 Strategy

Used

�� Elimination

Application:

�� Check whether flux changes in each case.

Final Logic:

�� Every situation involves changing flux linkage.

🧠 Memory Trick

Relative Motion = Induction

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Relative Motion Principle

20 Incorrect statement regarding coil and magnet interactions in Faraday's experiments

A Deflection of the galvanometer lasts as long as the bar magnet is in motion.

B Pushing the South-pole towards the coil produces the same deflection direction as pushing the North-pole.

C The deflection is larger when the magnet is pushed faster.

D When the magnet is pulled away, the deflection is in the opposite direction compared to pushing it in.

💡 Short Explanation

�� Pole reversal reverses current direction. �� Faster motion increases emf. �� Opposite motions produce opposite deflections.

✅ Correct Answer Explanation

The direction of induced current depends on the direction of flux change. → Bringing a North pole and bringing a South pole toward the coil produce opposite flux changes. → Therefore galvanometer deflections occur in opposite directions. → Hence statement B is incorrect.

❓ Why Other Options Are Incorrect

�� Option A → Correct; current exists while flux changes.
�� Option C → Faster motion increases rate of flux change.
�� Option D → Opposite motions produce opposite current directions.

🎯 Strategy

Used

�� Contextual/Tonal Matching

Application:

�� Analyze direction of magnetic flux change.

Final Logic:

�� Opposite poles produce opposite induced current directions.

🧠 Memory Trick

Reverse Pole → Reverse Deflection

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Faraday's Magnet-Coil Experiment

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