CUET UG Physics Booster Test 3-Faraday’s Laws and Lenz’s Law
📌 Answers are locked once submitted — results and explanations appear at the end.
QUESTION 1 OF 20
In Faraday's experiments, under which of the following conditions is an induced current observed in a coil?
1.A magnet is moved towards a stationary coil.
2.A magnet is held stationary inside the coil.
3.A current-carrying coil is moved towards another coil.
4.A steady current flow continuously in a nearby stationary coil.
QUESTION 2 OF 20
Question: Match List I with List II for Faraday's Experiments
| List I | List II |
|---|---|
| (1) Magnet held stationary inside coil | (a) Deflection in opposite direction compared to North pole |
| (2) Magnet pulled away from coil | (b) Deflection direction reverses compared to pushing |
| (3) Magnet pushed faster towards coil | (c) Larger deflection in galvanometer |
| (4) South pole pushed towards coil | (d) Zero deflection in galvanometer |
QUESTION 3 OF 20
Choose the correct EMF Magnitude Equation statements.
1. The emf is independent of the resistance of the circuit.
2. The induced current depends on the resistance of the circuit.
3. The emf depends on the total change in flux, not the rate of change.
4. Emf can be induced even in an open circuit.
QUESTION 4 OF 20
Identify the incorrect statement about the time derivative of flux:
QUESTION 5 OF 20
Choose the correct statements about multiple turn coils:
Statements
1. The induced emfs in each turn of a tightly wound coil add up in series.
2. N turns decrease the total induced emf by a factor of 1/N.
3. The total induced emf formula is ε = -N(dΦB/dt).
4. The flux through each turn is vastly different in a closely wound coil.
QUESTION 6 OF 20
If the magnetic field Bi varies across different area elements dAi of a surface, the total magnetic flux ΦB is mathematically represented by the summation
QUESTION 7 OF 20
When a current-carrying coil C₂ connected to a tapping key is placed near a stationary coil C₁,...
QUESTION 8 OF 20
A loop is situated in a magnetic field of 0.10 T. If it is shrunk such that its effective area perpendicular to the field decreases by 5.0 × 10⁻³ m² in 0.20 s, what is the magnitude of the induced emf?
QUESTION 9 OF 20
Regarding rotating coils in fields, which one is correct?
Statements
1. Earth's steady magnetic field cannot induce an emf in a rotating coil.
2. The induced emf reaches its maximum magnitude when the rate of change of flux is zero.
3. Rotating a coil varies the angle θ, creating a time-varying flux.
4. The instantaneous induced emf is completely independent of the rotation speed.
QUESTION 10 OF 20
For a coil placed in a uniform magnetic field, magnetic flux is given by:
Φ = BA cos θ
If B and A remain constant, what are the values of magnetic flux when the angle θ changes from 0° to 180°?
QUESTION 11 OF 20
Match List I with List II regarding Lenz's law
| List I | List II |
|---|---|
| (1) Polarity of induced emf | (a) 1834 |
| (2) Open circuit in changing flux | (b) Opposes the change in magnetic flux |
| (3) Negative sign in Faraday's law | (c) Emf is induced but no current flows |
| (4) Lenz's law deduction year | (d) Represents Lenz's law mathematically |
QUESTION 12 OF 20
Identify the correct statements regarding the direction of induced current according to Lenz's law.
(1) Current direction depends on whether flux is increasing or decreasing.
(2) Current flows counter-clockwise to oppose a North pole approaching.
(3) Current flows clockwise to oppose a North pole withdrawing.
(4) Induced current direction always aligns to increase the original magnetic field.
QUESTION 13 OF 20
Which of the following statement about Lenz's law and the induced magnetic effects that counter changes in magnetic flux is incorrect?
QUESTION 14 OF 20
Choose the correct statements about magnetic polarity of coils
(1) A coil facing an approaching North pole develops a North polarity.
(2) The developed North polarity causes an attractive force on the magnet.
(3) A receding North pole induces a South polarity on the facing side of the coil.
(4) The induced polarities act to accelerate the magnet's motion naturally.
QUESTION 15 OF 20
If the hypothetical scenario of a perpetual-motion machine were possible through electromagnetic induction where induced current supported flux change, the kinetic energy K of an approaching magnet after a gentle push would theoretically
QUESTION 16 OF 20
The work done against the repulsive force between an approaching magnet and an induced current...
QUESTION 17 OF 20
If a person does 3.0 × 10⁻² J of work in moving a magnet, and the induced current in the 5.0 Ω closed coil lasts for 0.60 s, what is the estimated constant induced current assuming all work converts to Joule heating? (Using W = I²Rt)
QUESTION 18 OF 20
In the context of mechanical to electrical conversion, which one is correct?
Choose correct:
QUESTION 19 OF 20
Rectangular loop moving out of uniform field into field-free region at constant velocity; Circular loop moving similarly:
QUESTION 20 OF 20
Match List I with List II for moving loops in a magnetic field
| List I | List II |
|---|---|
| (1) Rectangular loop moving out of field | (a) Induced current opposes decreasing flux |
| (2) Triangular loop moving out of field | (b) No induced current exists |
| (3) Loop completely inside uniform field | (c) Rate of change of area is constant |
| (4) Irregular loop moving out of field | (d) Rate of change of area is variable |
Test Complete!
Answer Review
1 In Faraday's experiments, under which of the following conditions is an induced current observed in a coil?
1.A magnet is moved towards a stationary coil.
2.A magnet is held stationary inside the coil.
3.A current-carrying coil is moved towards another coil.
4.A steady current flow continuously in a nearby stationary coil.
1. Short Explanation
Induced current is produced only when magnetic flux changes.
Relative motion between a magnet and coil changes flux.
Relative motion between two coils changes flux.
Stationary situations with constant flux do not induce current.
- Statement 1 is correct.
Moving a magnet towards a coil changes the magnetic flux linked with the coil, inducing current.
- Statement 2 is incorrect.
A stationary magnet inside the coil produces constant flux, so no induced current is observed.
- Statement 3 is correct.
Moving a current-carrying coil towards another coil changes the magnetic flux through the second coil, inducing current.
- Statement 4 is incorrect.
A steady current in a stationary coil produces a constant magnetic field and hence no change in flux.
Therefore, induced current is observed only in statements 1 and 3.
Correct Answer: A. 1 and 3 only
Option B: Includes statement 2, where flux remains constant.
Option C: Both statements involve constant flux conditions.
Option D:
Flux-Change Analysis
Application:
Check whether magnetic flux linked with the coil changes.
Final Logic:
Changing flux → Induced current.
Constant flux → No induced current.
"Change Flux → Get Current" "No Flux Change → No Induction"
2 Question: Match List I with List II for Faraday's Experiments
| List I | List II |
|---|---|
| (1) Magnet held stationary inside coil | (a) Deflection in opposite direction compared to North pole |
| (2) Magnet pulled away from coil | (b) Deflection direction reverses compared to pushing |
| (3) Magnet pushed faster towards coil | (c) Larger deflection in galvanometer |
| (4) South pole pushed towards coil | (d) Zero deflection in galvanometer |
A stationary magnet produces no change in magnetic flux. Pulling the magnet away reverses the direction of induced current. Faster motion increases the rate of flux change and induced emf. Reversing the pole reverses the direction of galvanometer deflection.
- (1) Magnet held stationary inside coil No change in magnetic flux occurs through the coil. Hence, no induced emf is produced and the galvanometer shows zero deflection. → 1 → d → (2) Magnet pulled away from coil The change in magnetic flux is opposite to that produced when the magnet is pushed towards the coil. Therefore, the induced current and galvanometer deflection reverse direction. → 2 → b → (3) Magnet pushed faster towards coil A faster-moving magnet causes a greater rate of change of magnetic flux. Hence, a larger induced emf and larger galvanometer deflection are produced. → 3 → c → (4) South pole pushed towards coil The direction of flux change is opposite to that produced by a North pole approaching the coil. Therefore, the galvanometer deflects in the opposite direction. → 4 → a Therefore: 1 → d 2 → b 3 → c 4 → a Hence, Option A is correct.
- Option B: Incorrectly matches the effects of pulling the magnet and faster motion.
- Option C: Incorrectly assigns zero deflection and opposite-direction deflection.
- Option D: Incorrectly matches the stationary magnet case.
Used
- Option Grouping
Application:
- Analyze how each action affects the magnetic flux through the coil.
Final Logic:
- No flux change → No deflection.
- Reverse motion → Reverse deflection.
- Faster motion → Greater deflection.
- Opposite pole → Opposite deflection.
"Stationary → Zero, Faster → Bigger, South → Opposite"
3 Choose the correct EMF Magnitude Equation statements.
1. The emf is independent of the resistance of the circuit.
2. The induced current depends on the resistance of the circuit.
3. The emf depends on the total change in flux, not the rate of change.
4. Emf can be induced even in an open circuit.
�� EMF depends on flux change rate. �� Current depends on resistance. �� EMF exists even in open circuits.
- Statement 1 is correct because emf depends on dΦ/dt, not resistance. → Statement 2 is correct because I = ε/R. → Statement 3 is incorrect because emf depends on the rate of change of flux. → Statement 4 is correct because emf can exist without current in an open circuit.
- �� Option B → Includes incorrect Statement 3.
- �� Option C → Includes incorrect Statement 3.
- �� Option D → Includes incorrect Statement 3.
Used
- �� Elimination
Application:
- �� Identify the statement contradicting Faraday's law.
Final Logic:
- �� EMF depends on rate of flux change.
- EMF Needs Flux Rate
4 Identify the incorrect statement about the time derivative of flux:
�� Stationary coil means constant flux. �� Constant flux gives zero derivative. �� No induced emf is produced.
- When a coil is stationary in a constant magnetic field, magnetic flux remains constant. → Therefore: dΦ/dt = 0 → Hence induced emf is zero. → Option D is incorrect and is the correct answer.
- �� Option A → Correct statement of Faraday's law.
- �� Option B → Correct consequence of constant flux.
- �� Option C → Angle or area may change while B remains constant.
Used
- �� Elimination
Application:
- �� Check which statement contradicts Faraday's law.
Final Logic:
- �� Constant flux cannot produce maximum emf.
- Constant Flux = Zero EMF
5 Choose the correct statements about multiple turn coils:
Statements
1. The induced emfs in each turn of a tightly wound coil add up in series.
2. N turns decrease the total induced emf by a factor of 1/N.
3. The total induced emf formula is ε = -N(dΦB/dt).
4. The flux through each turn is vastly different in a closely wound coil.
�� Emfs add in series. �� EMF increases with turns. �� Same flux passes through turns.
- Statement 1 is correct because individual turn emfs add. → Statement 3 is correct because: ε = -N(dΦ/dt) → Statement 2 is incorrect because increasing N increases emf. → Statement 4 is incorrect because closely wound coils experience nearly identical flux.
- �� Option B → Both statements are false.
- �� Option C → Includes false Statement 2.
- �� Option D → Includes false Statement 4.
Used
- �� Elimination
Application:
- �� Check dependence of emf on N.
Final Logic:
- �� More turns produce greater total emf.
- More Turns = More EMF
6 If the magnetic field Bi varies across different area elements dAi of a surface, the total magnetic flux ΦB is mathematically represented by the summation
�� Flux is a dot product. �� Sum contributions from all elements. �� Basis of surface integration.
- Magnetic flux is defined as: Φ = ∫ B·dA → For discrete elements: Φ = Σ(Bi·dAi) → Therefore, Option A is correct.
- �� Option B → Cross product does not define flux.
- �� Option C → No physical meaning.
- �� Option D → Not a flux expression.
Used
- �� Conceptual Recall
Application:
- �� Recall mathematical definition of magnetic flux.
Final Logic:
- �� Flux is obtained using a dot product.
- Flux = B Dot A
7 When a current-carrying coil C₂ connected to a tapping key is placed near a stationary coil C₁,...
�� Changing current changes magnetic flux. �� Induction occurs only during change. �� Mutual induction is involved.
- When the key is pressed, current in C₂ rises from zero to a finite value. → This produces a rapidly changing magnetic field around C₂. → The changing magnetic flux linked with C₁ induces an emf and a momentary current. → Once the current becomes steady, the magnetic field becomes constant and induction stops. → Therefore Option B is correct.
- �� Option A → A constant current produces a constant magnetic field and no induced current.
- �� Option C → Releasing the key decreases current and changes magnetic flux, producing induction.
- �� Option D → An iron core increases flux linkage; it does not stop flux change.
Used
- �� Conceptual Recall
Application:
- �� Apply the principle of mutual induction.
Final Logic:
- �� Only changing current produces induced emf.
- Key Press = Flux Change
8 A loop is situated in a magnetic field of 0.10 T. If it is shrunk such that its effective area perpendicular to the field decreases by 5.0 × 10⁻³ m² in 0.20 s, what is the magnitude of the induced emf?
�� Use Faraday's law. �� Flux change occurs due to area change. �� Direct substitution.
- Given: B = 0.10 T ΔA = 5.0 × 10⁻³ m² Δt = 0.20 s → Since the field is perpendicular: ΔΦ = BΔA = (0.10)(5.0 × 10⁻³) = 5.0 × 10⁻⁴ Wb → Induced emf: ε = ΔΦ/Δt = (5.0 × 10⁻⁴)/(0.20) = 2.5 × 10⁻³ V → Therefore Option A is correct.
- �� Option B → Too small due to incorrect division.
- �� Option C → One-tenth of correct value.
- �� Option D → Twice the correct value.
Used
- �� Substitution
Application:
- �� Apply ε = BΔA/Δt.
Final Logic:
- �� ε = 2.5 × 10⁻³ V.
- Area Change ÷ Time = EMF
9 Regarding rotating coils in fields, which one is correct?
Statements
1. Earth's steady magnetic field cannot induce an emf in a rotating coil.
2. The induced emf reaches its maximum magnitude when the rate of change of flux is zero.
3. Rotating a coil varies the angle θ, creating a time-varying flux.
4. The instantaneous induced emf is completely independent of the rotation speed.
�� Rotation changes θ. �� Flux becomes time-dependent. �� Induced emf is produced.
- For a rotating coil: Φ = BA cosθ → Rotation continuously changes θ. → Therefore magnetic flux changes with time. → A changing flux induces emf. → Hence Statement 3 is correct.
- �� Option A→ A rotating coil in Earth's field can induce emf.
- �� Option B→ Maximum emf occurs when rate of change of flux is maximum.
- �� Option D→ Emf depends directly on angular speed.
Used
- �� Elimination
Application:
- �� Evaluate the effect of rotation on magnetic flux.
Final Logic:
- �� Rotation changes θ, causing induction.
- Rotate → Flux Changes
10 For a coil placed in a uniform magnetic field, magnetic flux is given by:
Φ = BA cos θ
If B and A remain constant, what are the values of magnetic flux when the angle θ changes from 0° to 180°?
�� Flux depends on cosθ. �� cos0° = 1. �� cos180° = −1.
- Magnetic flux: Φ = BA cosθ → At θ = 0°: Φ = BA cos0° = +BA → At θ = 180°: Φ = BA cos180° = −BA → Therefore, Option A is correct.
- �� Option B → Flux is not zero at θ = 0°.
- �� Option C → Reverses initial and final values.
- �� Option D → Flux at 180° is −BA, not zero.
Used
- �� Substitution
Application:
- �� Substitute angle values into Φ = BA cosθ.
Final Logic:
- �� Flux changes from +BA to −BA.
- 0° = +BA, 180° = −BA
11 Match List I with List II regarding Lenz's law
| List I | List II |
|---|---|
| (1) Polarity of induced emf | (a) 1834 |
| (2) Open circuit in changing flux | (b) Opposes the change in magnetic flux |
| (3) Negative sign in Faraday's law | (c) Emf is induced but no current flows |
| (4) Lenz's law deduction year | (d) Represents Lenz's law mathematically |
Lenz's law determines the polarity of the induced emf. An open circuit can have induced emf without current. The negative sign in Faraday's law represents opposition to flux change. Lenz proposed his law in 1834.
- (1) Polarity of induced emf According to Lenz's law, the induced emf always acts to oppose the change in magnetic flux producing it. → 1 → b → (2) Open circuit in changing flux Even though magnetic flux changes and an emf is induced, the circuit is open, so no current can flow. → 2 → c → (3) Negative sign in Faraday's law Faraday's law is: ε = − dΦ/dt The negative sign mathematically represents Lenz's law. → 3 → d → (4) Lenz's law deduction year Lenz proposed the law in 1834. → 4 → a Therefore: 1 → b 2 → c 3 → d 4 → a Hence, Option A is correct.
- Option B: Incorrectly matches polarity with the year 1834 and misassigns other concepts.
- Option C: Confuses polarity with the mathematical representation of Lenz's law.
- Option D: Incorrectly associates an open circuit with the year 1834.
Used
- Matching Logic
Application:
- Associate each concept with its precise physical meaning and historical fact.
Final Logic:
- Polarity → Opposes flux change.
- Open circuit → EMF without current.
- Negative sign → Mathematical form of Lenz's law.
- 1834 → Year of Lenz's law.
"Negative Sign = Opposition Sign"
12 Identify the correct statements regarding the direction of induced current according to Lenz's law.
(1) Current direction depends on whether flux is increasing or decreasing.
(2) Current flows counter-clockwise to oppose a North pole approaching.
(3) Current flows clockwise to oppose a North pole withdrawing.
(4) Induced current direction always aligns to increase the original magnetic field.
�� Current direction depends on flux change. �� Approaching and receding magnets produce opposite currents. �� Lenz's law opposes change.
(1) Correct — direction depends on increasing or decreasing flux. (2) Correct — an approaching North pole is opposed by creating a North face, requiring counter-clockwise current. (3) Correct — withdrawing North pole is opposed by creating a South face, requiring clockwise current. (4) Incorrect — induced field opposes flux change, not necessarily increases the original field.
- �� Option 2 → Includes incorrect statement 4.
- �� Option C → Includes incorrect statement 4.
- �� Option D → Includes incorrect statement 4.
Used
- Elimination
Application:
- Reject statements violating Lenz's law.
Final Logic:
- Induced current always opposes the flux variation.
- Oppose the Change
13 Which of the following statement about Lenz's law and the induced magnetic effects that counter changes in magnetic flux is incorrect?
�� Magnetic moment may be parallel or antiparallel. �� It depends on flux change. �� Lenz's law opposes the change.
The induced magnetic moment is determined by the need to oppose the change in flux. It may be parallel or antiparallel depending on whether flux is increasing or decreasing. Therefore statement C is incorrect.
- �� Option A → Correct application of Lenz's law.
- �� Option B → Correct because induced field supports decreasing flux.
- �� Option D → Fundamental statement of Lenz's law.
Used
- Extreme Word Filter
Application:
- The word "always" often signals an incorrect statement.
Final Logic:
- Magnetic moment direction depends on the nature of flux change.
- Increase → Oppose, Decrease → Support
14 Choose the correct statements about magnetic polarity of coils
(1) A coil facing an approaching North pole develops a North polarity.
(2) The developed North polarity causes an attractive force on the magnet.
(3) A receding North pole induces a South polarity on the facing side of the coil.
(4) The induced polarities act to accelerate the magnet's motion naturally.
�� Approaching North pole → induced North pole. �� Receding North pole → induced South pole. �� Induced force opposes motion.
(1) Correct — approaching North pole is opposed by forming a North pole. (3) Correct — receding North pole is opposed by forming a South pole. (2) Incorrect — North-North interaction is repulsive. (4) Incorrect — induced effects oppose motion rather than accelerate it.
- �� Option B → Both statements violate Lenz's law.
- �� Option C → Contains incorrect statement 2.
- �� Option D → Contains incorrect statement 4.
Used
- Elimination
Application:
- Apply magnetic pole interaction and Lenz's law.
Final Logic:
- Induced poles always resist the change producing them.
- Approach → Repel, Recede → Attract
15 If the hypothetical scenario of a perpetual-motion machine were possible through electromagnetic induction where induced current supported flux change, the kinetic energy K of an approaching magnet after a gentle push would theoretically
�� Supporting flux change would accelerate motion. �� Energy would be created without input. �� This violates conservation of energy.
If induced currents aided rather than opposed the motion, the magnet would gain kinetic energy continuously without external work. Its kinetic energy would keep increasing indefinitely, implying perpetual motion and violation of energy conservation. Hence K → ∞.
- �� Option B → Energy would not become zero.
- �� Option C → Energy would continuously increase.
- �� Option D → Kinetic energy cannot be negative.
Used
- Contextual/Tonal Matching
Application:
- Analyze the hypothetical consequence of violating Lenz's law.
Final Logic:
- Unlimited acceleration implies unlimited kinetic energy.
- No Lenz = Perpetual Motion
16 The work done against the repulsive force between an approaching magnet and an induced current...
�� Mechanical work supplies energy. �� Energy converts to electrical energy. �� Coil dissipates energy as heat.
The external agent moving the magnet performs work against the induced magnetic force. This mechanical work is converted into electrical energy and eventually dissipated as Joule heat in the coil. Hence option C is correct.
- �� Option A → Induction requires energy input.
- �� Option B → Induction does not violate energy conservation.
- �� Option D → Energy is dissipated, not fully recovered.
Used
- Energy Accounting
Application:
- Trace the source and destination of energy.
Final Logic:
- Mechanical work becomes electrical and thermal energy.
- Work In = Heat Out
17 If a person does 3.0 × 10⁻² J of work in moving a magnet, and the induced current in the 5.0 Ω closed coil lasts for 0.60 s, what is the estimated constant induced current assuming all work converts to Joule heating? (Using W = I²Rt)
�� Use W = I²Rt. �� Solve for I. �� Substitute values carefully.
W = I²Rt 3.0 × 10⁻² = I²(5)(0.60) 3.0 × 10⁻² = 3I² I² = 1.0 × 10⁻² I = 0.10 A Thus: I = 1.0 × 10⁻¹ A
- �� Option B → Gives four times larger power.
- �� Option C → Too small by factor of 10.
- �� Option D → Produces excessive energy.
Used
- Substitution
Application:
- Insert values into Joule heating formula.
Final Logic:
- Direct calculation gives 0.10 A.
- W = I²Rt
18 In the context of mechanical to electrical conversion, which one is correct?
Choose correct:
�� Energy must come from somewhere. �� Mechanical work is the source. �� Energy is transformed, not destroyed.
In electromagnetic induction, the electrical energy generated originates from the mechanical work done by the external agent moving the magnet or conductor. This ensures conservation of energy.
- �� Option A → Violates conservation of energy.
- �� Option B → Open circuit carries no current.
- �� Option D → Energy is transformed, not destroyed.
Used
- Elimination
Application:
- Remove statements violating conservation principles.
Final Logic:
- Mechanical work is converted into electrical energy.
- Generator = Work → Electricity
19 Rectangular loop moving out of uniform field into field-free region at constant velocity; Circular loop moving similarly:
�� Rectangular area decreases uniformly. �� Circular area decreases non-uniformly. �� Emf depends on rate of flux change.
For a rectangular loop moving out at constant speed, overlapping area decreases linearly with time. Hence: dΦ/dt is constant, giving constant emf. For a circular loop, the overlapping area changes nonlinearly, producing variable emf.
- �� Option B → Reverses the actual behavior.
- �� Option C → Circular loop does not give constant emf.
- �� Option D → Rectangular loop gives constant emf.
Used
- Geometrical Analysis
Application:
- Examine how overlap area changes with time.
Final Logic:
- Linear area change gives constant emf.
- Rectangle → Uniform Loss
20 Match List I with List II for moving loops in a magnetic field
| List I | List II |
|---|---|
| (1) Rectangular loop moving out of field | (a) Induced current opposes decreasing flux |
| (2) Triangular loop moving out of field | (b) No induced current exists |
| (3) Loop completely inside uniform field | (c) Rate of change of area is constant |
| (4) Irregular loop moving out of field | (d) Rate of change of area is variable |
A rectangular loop loses area uniformly while leaving the field. A triangular loop loses area non-uniformly. A loop entirely inside a uniform magnetic field experiences no flux change. An irregular loop moving out of the field experiences decreasing flux, inducing current.
- (1) Rectangular loop moving out of field The area inside the magnetic field decreases uniformly with time. Therefore, the rate of change of area is constant. → 1 → c → (2) Triangular loop moving out of field The area inside the field changes non-uniformly as the loop exits. Therefore, the rate of change of area is variable. → 2 → d → (3) Loop completely inside uniform field The magnetic flux remains constant because both the field and enclosed area remain unchanged. Hence, no induced current exists. → 3 → b → (4) Irregular loop moving out of field The magnetic flux decreases as the loop leaves the field. According to Lenz's law, the induced current opposes this decrease. → 4 → a Therefore: 1 → c 2 → d 3 → b 4 → a Hence, Option A is correct.
- Option B: Incorrectly assigns no induction to the triangular loop and constant area change to the loop inside the field.
- Option C: A loop completely inside a uniform field cannot have induced current.
- Option D: A rectangular loop moving out of the field does not correspond to no induction.
Used
- Matching Logic
Application:
- Analyze how the area enclosed within the magnetic field changes for different loop geometries.
Final Logic:
- Rectangle → Constant area loss.
- Triangle → Variable area loss.
- Uniform field with no flux change → No induction.
- Decreasing flux → Current opposes the decrease.
"No Flux Change = No Current"
