CUET UG Physics Booster Test 2-Dual Nature of Matter and De Broglie -

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CUET UG Physics Booster Test 2-Dual Nature of Matter and De Broglie

⏱️ 30 Minutes

❓ 20 Questions

📌 Answers are locked once submitted — results and explanations appear at the end.

CUET UG Physics Booster Test 2-Dual Nature of Matter and De Broglie

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QUESTION 1 OF 20

Dual nature of radiation statements
1. Both descriptions are essential to fully explain human vision.
2. The gathering and focusing mechanism by the eye lens uses the wave picture.
3. Absorption of light by the retina's rods and cones uses the photon picture.
4. The wave picture alone can fully describe all light-matter interactions.

Answer Review

1 Dual nature of radiation statements
1. Both descriptions are essential to fully explain human vision.
2. The gathering and focusing mechanism by the eye lens uses the wave picture.
3. Absorption of light by the retina's rods and cones uses the photon picture.
4. The wave picture alone can fully describe all light-matter interactions.

A (1), (2), (3)

B (1), (3), (4)

C (2), (3), (4)

D (1), (2), (4)

💡 Short Explanation

�� Human vision requires both wave and particle descriptions. �� Lens action is explained by wave optics. �� Retinal absorption involves photons.

✅ Correct Answer Explanation

Statement 1 is correct because complete understanding of vision requires both wave and particle aspects of light. → Statement 2 is correct because image formation and focusing by the eye lens are explained using wave optics. → Statement 3 is correct because rods and cones absorb light through photon interactions. → Statement 4 is incorrect because many light-matter interactions require the photon picture.

❓ Why Other Options Are Incorrect

�� Statement 4 → Wave theory alone cannot explain photoelectric-type absorption processes.

🎯 Strategy

Used

�� Elimination

Application:

�� Remove the statement claiming wave theory alone explains all interactions.

Final Logic:

�� Statements 1, 2 and 3 are correct.

🧠 Memory Trick

Lens = Wave, Retina = Photon

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Wave-Particle Duality of Radiation

2 Match List I with List II based on experimental phenomena

List I	List II
1. Interference	a. Validated by wave picture
2. Photoelectric effect	b. Validated by photon picture
3. Polarization	c. Validated by wave picture
4. Compton effect	d. Validated by photon picture

A 1-a, 2-b, 3-c, 4-d

B 1-c, 2-d, 3-a, 4-b

C 1-a, 2-d, 3-c, 4-b

D 1-b, 2-a, 3-d, 4-c

💡 Short Explanation

�� Interference and polarization support wave nature. �� Photoelectric and Compton effects support particle nature. �� Both pictures are necessary.

✅ Correct Answer Explanation

Correct matching: List I — List II 1. Interference — a. Validated by wave picture 2. Photoelectric effect — b. Validated by photon picture 3. Polarization — c. Validated by wave picture 4. Compton effect — d. Validated by photon picture → Therefore Option A is correct.

❓ Why Other Options Are Incorrect

�� Options B, C and D contain incorrect associations between phenomena and their interpretations.

🎯 Strategy

Used

�� Option Grouping

Application:

�� Match each phenomenon with the theory that successfully explains it.

Final Logic:

�� Only Option A provides all correct pairings.

🧠 Memory Trick

IP = Wave, PC = Photon (Interference/Polarization vs Photoelectric/Compton)

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Experimental Evidence of Dual Nature

3 In reasoning about the symmetrical character of nature, de Broglie logically inferred that

A matter and energy have completely opposing mathematical characteristics

B since radiation acts as a wave, matter is fundamentally prohibited from wave behavior

C energy and matter are disconnected entities with no parallel physical behaviors

D since radiation exhibits dual aspects, moving matter should also exhibit dual aspects

💡 Short Explanation

�� de Broglie used symmetry arguments. �� Radiation shows wave-particle duality. �� Matter should also possess duality.

✅ Correct Answer Explanation

de Broglie reasoned that if radiation possesses both wave and particle characteristics, matter should also exhibit a dual nature. → This led to the matter-wave hypothesis. → Hence option D is correct.

❓ Why Other Options Are Incorrect

�� Option A → Not part of de Broglie's reasoning.
�� Option B → Opposite of de Broglie's proposal.
�� Option C → Contradicts the symmetry argument.

🎯 Strategy

Used

�� Contextual/Tonal Matching

Application:

�� Recall the logical basis of de Broglie's hypothesis.

Final Logic:

�� Radiation duality inspired matter duality.

🧠 Memory Trick

Radiation Dual → Matter Dual

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Symmetry in Nature

4 Incorrect statement about de Broglie's bold hypothesis

A It applies to both macroscopic and microscopic moving particles

B It states that moving particles of matter display wave-like properties under suitable conditions

C It was immediately verified experimentally in 1924 by A.H. Compton's X-ray scattering

D It was based on the premise that nature is symmetrical regarding matter and energy

💡 Short Explanation

�� Compton effect concerned photons. �� Matter-wave verification came later. �� de Broglie's hypothesis was proposed in 1924.

✅ Correct Answer Explanation

Compton scattering verified the particle nature of light, not the wave nature of matter. → Experimental verification of matter waves was later provided through electron diffraction experiments. → Therefore option C is correct.

❓ Why Other Options Are Incorrect

�� Option A → Correct statement.
�� Option B → Correct description of the hypothesis.
�� Option D → Correct basis of de Broglie's reasoning.

🎯 Strategy

Used

�� Elimination

Application:

�� Distinguish photon experiments from matter-wave experiments.

Final Logic:

�� Compton scattering did not verify matter waves.

🧠 Memory Trick

Compton → Light, Davisson-Germer → Matter

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: de Broglie Hypothesis

5 If the momentum p of a given particle is doubled, what happens to its initial de Broglie wavelength λ₁?

A 2.0 λ₁

B 0.5 λ₁

C 0.25 λ₁

D 4.0 λ₁

💡 Short Explanation

�� λ = h/p. �� Wavelength is inversely proportional to momentum. �� Doubling momentum halves wavelength.

✅ Correct Answer Explanation

Initially: λ₁ = h/p After doubling momentum: λ₂ = h/(2p) = λ₁/2 = 0.5 λ₁ → Therefore option B is correct.

❓ Why Other Options Are Incorrect

�� Option A → Indicates direct proportionality.
�� Option C → Would require fourfold momentum.
�� Option D → Opposite trend.

🎯 Strategy

Used

�� Substitution

Application:

�� Apply λ = h/p.

Final Logic:

�� Doubling p halves λ.

🧠 Memory Trick

More Momentum → Less Wavelength

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: de Broglie Relation

6 Correct statements about h in the de Broglie equation
1. It acts as the mathematical link relating the wave attribute λ to the particle attribute p.
2. Its value is 6.626 × 10⁻³⁴ J s.
3. It is a universal constant, independent of the nature of the material particle.
4. Its value changes proportionally depending on the mass of the material.

A (1), (2), (3)

B (1), (2), (4)

C (2), (3), (4)

D (1), (3), (4)

💡 Short Explanation

�� h links wave and particle properties. �� h is universal. �� h does not depend on mass.

✅ Correct Answer Explanation

Statement 1 is correct because h connects wavelength and momentum. → Statement 2 is correct because h = 6.626 × 10⁻³⁴ J s. → Statement 3 is correct because h is a universal constant. → Statement 4 is incorrect because h never changes with particle mass.

❓ Why Other Options Are Incorrect

�� Statement 4 → Contradicts the definition of a universal constant.

🎯 Strategy

Used

�� Elimination

Application:

�� Remove the statement assigning variability to Planck's constant.

Final Logic:

�� Statements 1, 2 and 3 are correct.

🧠 Memory Trick

h = Universal Bridge

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Planck's Constant in de Broglie Theory

7 The de Broglie wavelength λ expressed explicitly in terms of mass m and speed v is:

A v(hm)⁻¹

B h(m+v)⁻¹

C m(hv)⁻¹

D h(mv)⁻¹

💡 Short Explanation

�� p = mv. �� λ = h/p. �� Substitute momentum.

✅ Correct Answer Explanation

Using: λ = h/p and p = mv Therefore: λ = h/mv = h(mv)⁻¹ → Hence option D is correct.

❓ Why Other Options Are Incorrect

�� Option A → Incorrect dimensions.
�� Option B → Uses addition instead of multiplication.
�� Option C → Incorrect arrangement.

🎯 Strategy

Used

�� Substitution

Application:

�� Replace p by mv.

Final Logic:

�� λ = h/mv.

🧠 Memory Trick

Matter Wave = h/mv

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: de Broglie Wavelength Formula

8 The mathematical relation λ = h/p clearly indicates:
1. The left-hand side expresses a pure wave attribute.
2. The right-hand side contains a typical particle attribute.
3. The dual aspect of matter is inherently integrated.
4. Mass is directly proportional to the generated wavelength.

A (1), (2), (3)

B (1), (2), (4)

C (2), (3), (4)

D (1), (3), (4)

💡 Short Explanation

�� λ is a wave property. �� p is a particle property. �� Equation unifies both aspects.

✅ Correct Answer Explanation

Statement 1 is correct because wavelength is a wave characteristic. → Statement 2 is correct because momentum is a particle characteristic. → Statement 3 is correct because the equation combines wave and particle ideas. → Statement 4 is incorrect since wavelength is inversely proportional to momentum and mass.

❓ Why Other Options Are Incorrect

�� Statement 4 → Increasing mass decreases wavelength.

🎯 Strategy

Used

�� Elimination

Application:

�� Remove the statement contradicting λ = h/p.

Final Logic:

�� Statements 1, 2 and 3 are correct.

🧠 Memory Trick

λ = Wave, p = Particle

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Wave-Particle Integration

9 For a photon, the equation λ = h/p maps to its dual properties as:

A Wave attribute, Particle attribute

B Particle attribute, Wave attribute

C Energy attribute, Mass attribute

D Mass attribute, Energy attribute

💡 Short Explanation

�� λ represents wave nature. �� p represents particle nature. �� Photon exhibits both.

✅ Correct Answer Explanation

In λ = h/p, λ denotes wavelength (wave property) and p denotes momentum (particle property). → Therefore option A correctly identifies the dual aspects.

❓ Why Other Options Are Incorrect

�� Option B → Reverses the meanings.
�� Option C → Not represented in the equation.
�� Option D → Not represented in the equation.

🎯 Strategy

Used

�� Contextual/Tonal Matching

Application:

�� Identify the physical significance of λ and p.

Final Logic:

�� Wavelength corresponds to wave nature and momentum to particle nature.

🧠 Memory Trick

λ → Wave, p → Particle

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Photon Duality Consistency

10 When confirming the applicability of the de Broglie relation to a photon

A its matter wavelength calculates to zero because photons lack rest mass

B substituting p = hν/c yields a matter wavelength that exactly equals the electromagnetic radiation wavelength

C its predicted momentum approaches infinity, breaking the equation

D its phase velocity precisely equates to its observable physical speed

💡 Short Explanation

�� Photon momentum p = hν/c. �� Apply λ = h/p. �� Obtained wavelength equals EM wavelength.

✅ Correct Answer Explanation

Using: λ = h/p and p = hν/c Therefore: λ = h/(hν/c) = c/ν → This is exactly the electromagnetic wavelength of the photon. → Hence option B is correct.

❓ Why Other Options Are Incorrect

�� Option A → Photons possess momentum and finite wavelength.
�� Option C → Momentum remains finite.
�� Option D → Not the conclusion obtained from the derivation.

🎯 Strategy

Used

�� Substitution

Application:

�� Substitute photon momentum into de Broglie's relation.

Final Logic:

�� λ = c/ν, identical to electromagnetic wavelength.

🧠 Memory Trick

Photon: λ = h/p = c/ν

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Applicability of de Broglie Relation to Photons

11 Incorrect statement about moving macroscopic objects

A Their massive scale inherently makes their de Broglie wavelengths extremely small

B They easily show observable wave-like diffraction properties in daily life

C Their large momentum values push wavelengths beyond experimental measurement limits

D The de Broglie hypothesis still theoretically covers their physical behavior

💡 Short Explanation

�� Macroscopic objects have very large momentum. �� Their de Broglie wavelengths are extremely small. �� Observable diffraction is practically impossible.

✅ Correct Answer Explanation

According to de Broglie's relation: λ = h/p → Macroscopic objects possess very large mass and momentum, making λ extremely small. → Such tiny wavelengths cannot produce observable diffraction effects in everyday life. → Therefore option B is correct.

❓ Why Other Options Are Incorrect

�� Option A → Correct. Large mass results in extremely small wavelength.
�� Option C → Correct. Their wavelengths are beyond practical measurement.
�� Option D → Correct. The de Broglie hypothesis applies to all moving particles.

🎯 Strategy

Used

�� Elimination

Application:

�� Identify the statement contradicting the consequences of extremely small de Broglie wavelengths.

Final Logic:

�� Macroscopic objects do not exhibit observable diffraction in daily life.

🧠 Memory Trick

Big Mass → Invisible Wave

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Matter Waves of Macroscopic Objects

12 Calculate the de Broglie wavelength for a ball of mass 0.150 kg travelling at 30.0 m/s.
(h = 6.63 × 10⁻³⁴ J s)

A 1.47 × 10⁻³⁴ m

B 1.47 × 10⁻³⁵ m

C 1.47 × 10⁻³³ m

D 1.47 × 10⁻³² m

💡 Short Explanation

�� Use λ = h/mv. �� Calculate momentum first. �� Substitute numerical values.

✅ Correct Answer Explanation

Momentum: p = mv = 0.150 × 30 = 4.5 kg m s⁻¹ → Therefore: λ = h/p = (6.63 × 10⁻³⁴)/4.5 = 1.47 × 10⁻³⁴ m → Hence option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → One order smaller than calculated.
�� Option C → One order larger than calculated.
�� Option D → Two orders larger than calculated.

🎯 Strategy

Used

�� Substitution

Application:

�� Apply λ = h/mv directly.

Final Logic:

�� λ = 1.47 × 10⁻³⁴ m.

🧠 Memory Trick

Matter Wave = h/mv

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Calculation of de Broglie Wavelength

13 The typical ratio of the de Broglie wavelength of an electron moving at 10⁶ m/s to a macroscopic ball moving at 30 m/s is of the order:

A 10¹ to 10²

B 10⁻²⁴ to 10⁻²⁵

C 10²⁴ to 10²⁵

D 10⁻¹ to 10⁻²

💡 Short Explanation

�� Electron wavelength ≈ 10⁻¹⁰ m. �� Ball wavelength ≈ 10⁻³⁴ m. �� Ratio is enormous.

✅ Correct Answer Explanation

Typical electron wavelength: ≈ 10⁻¹⁰ m → Typical macroscopic ball wavelength: ≈ 10⁻³⁴ m → Ratio: 10⁻¹⁰ / 10⁻³⁴ = 10²⁴ → Therefore option C is correct.

❓ Why Other Options Are Incorrect

�� Option A → Far too small.
�� Option B → Inverse ratio.
�� Option D → Completely incorrect scale.

🎯 Strategy

Used

�� Dimensional/Unit Analysis

Application:

�� Compare wavelength orders of magnitude.

Final Logic:

�� Electron wavelengths exceed macroscopic wavelengths by about 10²⁴.

🧠 Memory Trick

Electron Wave ≫ Ball Wave

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Comparison of Matter Wavelengths

14 Match List I with List II based on the comparison provided in the text

List I	List II
1. Electron wavelength order	a. 10⁻¹⁰ meters (comparable to X-rays)
2. Macroscopic ball wavelength order	b. 10⁻³⁴ meters
3. Electron momentum scale	c. 10⁻²⁴ kg m/s
4. Macroscopic ball momentum scale	d. 10⁰ kg m/s

A 1-a, 2-b, 3-c, 4-d

B 1-b, 2-a, 3-d, 4-c

C 1-a, 2-c, 3-b, 4-d

D 1-c, 2-d, 3-a, 4-b

💡 Short Explanation

�� Electrons have measurable wavelengths. �� Macroscopic wavelengths are extremely small. �� Momentum scales differ greatly.

✅ Correct Answer Explanation

Correct Match: List I — List II 1. Electron wavelength order — a. 10⁻¹⁰ meters (comparable to X-rays) 2. Macroscopic ball wavelength order — b. 10⁻³⁴ meters 3. Electron momentum scale — c. 10⁻²⁴ kg m/s 4. Macroscopic ball momentum scale — d. 10⁰ kg m/s → Hence option A is correct.

❓ Why Other Options Are Incorrect

�� Options B, C and D contain incorrect associations of wavelength and momentum scales.

🎯 Strategy

Used

�� Option Grouping

Application:

�� Match physical quantities with their correct orders of magnitude.

Final Logic:

�� Only Option A gives all correct pairings.

🧠 Memory Trick

Electron: 10⁻¹⁰ m, Ball: 10⁻³⁴ m

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Orders of de Broglie Wavelengths

15 Regarding Erwin Schrodinger's fundamental contributions:
1. He developed de Broglie's initial idea into a full-fledged quantum theory.
2. His developed theory is commonly known as wave mechanics.
3. His work relies fundamentally on the wave nature of matter.
4. He personally proved the particle nature of the photon via X-ray scattering.

A (1), (2), (3)

B (1), (2), (4)

C (2), (3), (4)

D (1), (3), (4)

💡 Short Explanation

�� Schrodinger developed wave mechanics. �� Based on de Broglie's matter waves. �� Compton performed X-ray scattering studies.

✅ Correct Answer Explanation

Statements 1, 2 and 3 are correct. → Statement 4 is incorrect because the particle nature of light through X-ray scattering was established by Compton, not Schrodinger.

❓ Why Other Options Are Incorrect

�� Statement 4 → Related to Compton effect, not Schrodinger's contribution.

🎯 Strategy

Used

�� Elimination

Application:

�� Remove the statement belonging to another scientist.

Final Logic:

�� Statements 1, 2 and 3 correctly describe Schrodinger's work.

🧠 Memory Trick

Schrodinger = Wave Mechanics

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Schrodinger's Wave Mechanics

16 In 1929, the Nobel Prize in Physics was officially awarded to Louis de Broglie because

A he discovered the wave nature of electrons through his theoretical hypothesis

B he experimentally verified the photoelectric effect using alkali metals

C he developed the general theory of relativity

D he precisely measured the elementary charge of an electron

💡 Short Explanation

�� de Broglie proposed matter waves. �� Nobel Prize awarded in 1929. �� Recognition of wave nature of electrons.

✅ Correct Answer Explanation

Louis de Broglie proposed that moving particles possess wave properties. → This revolutionary hypothesis led to the concept of matter waves. → He received the 1929 Nobel Prize for this contribution.

❓ Why Other Options Are Incorrect

�� Option B → Related to photoelectric studies.
�� Option C → General relativity was Einstein's work.
�� Option D → Associated with Millikan's measurements.

🎯 Strategy

Used

�� Elimination

Application:

�� Identify the contribution specifically linked to de Broglie.

Final Logic:

�� Nobel Prize recognized the wave nature of electrons.

🧠 Memory Trick

de Broglie → Nobel 1929

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Nobel Prize for Matter Waves

17 Compton experiment statements
1. It involved the scattering of X-rays from electrons.
2. The experiment took place in the year 1924.
3. It confirmed the particle-like behaviour of electromagnetic light.
4. It directly proved that macroscopic matter has measurable wave properties.

A (1), (2), (3)

B (1), (3), (4)

C (2), (3), (4)

D (1), (2), (4)

💡 Short Explanation

�� X-rays scattered from electrons. �� Conducted in 1924. �� Confirmed photon nature.

✅ Correct Answer Explanation

Statements 1, 2 and 3 are correct. → Statement 4 is incorrect because Compton scattering concerns photon behaviour, not measurable matter waves of macroscopic objects.

❓ Why Other Options Are Incorrect

�� Statement 4 → Not demonstrated by Compton's experiment.

🎯 Strategy

Used

�� Elimination

Application:

�� Remove the statement unrelated to Compton scattering.

Final Logic:

�� Statements 1, 2 and 3 are correct.

🧠 Memory Trick

Compton = X-rays + Photons

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Compton Effect

18 Correct statements about measuring matter waves experimentally
1. Measurable matter wavelengths are typically of the order of atomic-planes spacing.
2. Wave character is significantly measurable mainly for sub-atomic particles.
3. Electrons exhibit wavelengths comparable to X-ray wavelengths.
4. They are easily measurable for moving macroscopic 0.150 kg balls.

A (2), (3), (4)

B (1), (2), (4)

C (1), (2), (3)

D (1), (3), (4)

💡 Short Explanation

�� Electron wavelengths are comparable to atomic spacing. �� Matter-wave effects are significant for microscopic particles. �� Macroscopic wavelengths are too small.

✅ Correct Answer Explanation

Statements 1, 2 and 3 are correct. → Statement 4 is incorrect because the wavelength of a 0.150 kg ball is around 10⁻³⁴ m, making it impossible to measure practically.

❓ Why Other Options Are Incorrect

�� Statement 4 → Macroscopic matter waves are unobservable.

🎯 Strategy

Used

�� Elimination

Application:

�� Remove the statement contradicting de Broglie wavelength magnitudes.

Final Logic:

�� Statements 1, 2 and 3 are correct.

🧠 Memory Trick

Electron λ ≈ Atomic Spacing

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Experimental Observation of Matter Waves

19 The meaningful velocity and the unmeaningful velocity associated with a matter wave are respectively:

A Particle velocity, Light velocity

B Phase velocity, Group velocity

C Light velocity, Particle velocity

D Group velocity, Phase velocity

💡 Short Explanation

�� Group velocity represents particle motion. �� Phase velocity lacks direct physical significance. �� Wave packets travel with group velocity.

✅ Correct Answer Explanation

Group velocity is physically meaningful because it equals the velocity of the particle. → Phase velocity does not correspond to observable transport of matter. → Therefore option D is correct.

❓ Why Other Options Are Incorrect

�� Option A → Incorrect classification.
�� Option B → Reversed relationship.
�� Option C → Not the standard matter-wave interpretation.

🎯 Strategy

Used

�� Contextual/Tonal Matching

Application:

�� Recall physical significance of matter-wave velocities.

Final Logic:

�� Group velocity is meaningful; phase velocity is not.

🧠 Memory Trick

Group = Real, Phase = Formal

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Group and Phase Velocity

20 Incorrect statement about free electrons in a metal

A They have a certain energy distribution at a given temperature

B Their energy distribution perfectly follows the usual Maxwell's distribution for gases

C Their specific distribution difference is directly tied to Pauli's exclusion principle

D Because of the distribution, different electrons require different additional energy to escape

💡 Short Explanation

�� Electrons obey quantum statistics. �� Pauli exclusion principle is important. �� Maxwell distribution is not applicable.

✅ Correct Answer Explanation

Free electrons in metals obey Fermi-Dirac statistics, not Maxwell-Boltzmann statistics. → The difference arises because electrons are fermions and obey Pauli's exclusion principle. → Therefore option B is incorrect.

❓ Why Other Options Are Incorrect

�� Option A → Correct statement.
�� Option C → Correct explanation.
�� Option D → Correct consequence of energy distribution.

🎯 Strategy

Used

�� Elimination

Application:

�� Identify the statement contradicting quantum statistics.

Final Logic:

�� Metal electrons do not follow the usual Maxwell distribution.

🧠 Memory Trick

Electrons → Fermi, Not Maxwell

📚 Class XII – Physics Part II – Chapter: Dual Nature of Radiation and Matter – Topic: Free Electron Energy Distribution in Metals

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