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CUET UG Physics Booster Test 2-Ampere\'s Circuital Law
📌 Answers are locked once submitted — results and explanations appear at the end.
QUESTION 1 OF 20
Incorrect statement regarding the line integral in Ampere's circuital law:
QUESTION 2 OF 20
A loop encloses three wires carrying steady currents of 2 A, 3 A and -1 A respectively. If the loop is traversed in a direction such that the first two are positive according to the right-hand rule, what is the value of ∮B⋅dl?
μ_0=4π×10^(-7) T m A^(-1)
QUESTION 3 OF 20
When applying Ampere's circuital law to find the magnetic field of a current configuration, the open surface bounded by the chosen loop:
QUESTION 4 OF 20
Match the right-hand rule sign convention elements used in Ampere's circuital law.
| List I | List II |
|---|---|
| 1. Curl of fingers | a. Positive direction of enclosed current |
| 2. Direction of thumb | b. Sense of traversal of the boundary loop |
| 3. Reversing thumb direction | c. Reverses the sign of enclosed current |
| 4. Reversing finger curl direction | d. Reverses the loop traversal direction |
QUESTION 5 OF 20
Identify the correct statements regarding the selection of an ideal Amperian loop for simplifying magnetic field calculations.
Statements:
1. B should be tangential to the loop and constant.
2. B should be normal to the loop.
3. B may vanish on certain parts of the loop.
4. B must be entirely parallel to the current element.
QUESTION 6 OF 20
If an Amperian loop of length L is chosen such that the magnetic field is tangential and constant over the entire loop, and it encloses a net current I_e, the magnitude of the field is given by:
QUESTION 7 OF 20
For a long straight wire, the magnetic field outside the wire depends ________ on the radial distance r, and the lines of constant magnitude form ________.
QUESTION 8 OF 20
Identify the correct statements regarding the magnetic field outside a thick infinite straight wire carrying uniform current I.
Statements:
1. The field is B=μ_0I/(2πr).
2. The field magnitude decreases as the inverse square of the distance.
3. The expression is derived using a circular Amperian loop.
4. The field is directly proportional to the distance from the center.
QUESTION 9 OF 20
Identify the correct statements regarding a system with cylindrical symmetry like an infinite straight wire.
Statements:
1. The magnetic field depends on three spatial coordinates.
2. The magnetic field magnitude depends only on the radial distance r.
3. This symmetry simplifies the evaluation of Ampere's integral.
4. The field direction is purely radial.
QUESTION 10 OF 20
Unlike electrostatic field lines which originate from positive charges and terminate at negative charges, the magnetic field lines formed around a straight current-carrying wire:
QUESTION 11 OF 20
Match the application of the right-hand rule based on its specific geometry.
| List I | List II |
|---|---|
| 1. Axis of a circular current loop | a. Thumb points along current, fingers curl along magnetic field |
| 2. Long straight conducting wire | b. Thumb points along magnetic field, fingers curl along current |
| 3. Solenoid magnetic field direction | c. Field direction obtained along the axis of the coil |
| 4. Circular field lines around a wire | d. Magnetic field forms concentric circles around the conductor |
QUESTION 12 OF 20
When analytically applying the right-hand rule to a straight wire, if the thumb points vertically downwards representing the current, the fingers will curl in the ________ direction when viewed from above.
QUESTION 13 OF 20
A solid straight wire of radius a carries a steady uniform current I. If the magnetic field at r=a/2 is B_1 and at r=a is B_2, what is the ratio B_1/B_2?
QUESTION 14 OF 20
For a solid thick wire of radius a carrying a uniform current, the magnetic field ________ linearly with distance r for r<a, and then ________ inversely with r for r>a.
QUESTION 15 OF 20
Identify the correct statements regarding the structural parameters of a long solenoid.
Statements:
1. Its length is large compared to its radius.
2. It consists of a long wire wound in a continuous helix.
3. Each turn can be regarded as an independent circular loop.
4. The net magnetic field is the vector sum of fields due to all turns.
QUESTION 16 OF 20
Incorrect statement about the construction and resulting field of a finite solenoid:
QUESTION 17 OF 20
Identify the correct statements regarding the Amperian loop used to calculate the magnetic field inside a long solenoid.
Statements:
1. The loop chosen is a rectangular loop abcd.
2. The transverse sections contribute fully to the line integral.
3. The exterior section contributes zero because the external field is nearly zero.
4. The relevant length of the loop is the portion parallel to the axis inside the solenoid.
QUESTION 18 OF 20
As the solenoid geometry is made longer and longer compared to its radius, the exterior magnetic field:
QUESTION 19 OF 20
Both Ampere's law and Gauss's law elegantly relate a physical quantity on the ________ to another physical quantity, namely the primary source, in the ________.
QUESTION 20 OF 20
Identify the correct statements regarding Ampere's law compared to the Biot–Savart law.
Statements:
1. Ampere's law is an alternative and appealing expression of the Biot–Savart law.
2. Ampere's law is strictly valid only for rapidly time-varying currents.
3. Both express the physical consequences of steady electrical current.
4. Ampere's law relates the magnetic field on a boundary to the current in the interior.
Test Complete!
Answer Review
1 Incorrect statement regarding the line integral in Ampere's circuital law:
�� Ampere's law involves a closed path integral. �� Direction of traversal affects the sign convention. �� The integral arises from summing infinitesimal elements.
Ampere's circuital law is expressed as ∮B⋅dl=μ_0I_(enc) where the line integral is taken over a closed path. The dot product involves the tangential component of the magnetic field along the infinitesimal path element dl. The integral can be visualized as the limit of a summation of many small magnetic field contributions around the loop. The direction in which the boundary is traversed is important because it determines the positive direction of the enclosed current through the right-hand rule. Reversing the traversal direction reverses the sign convention. Therefore, the statement that the sign convention is independent of traversal direction is incorrect.
- �� Option A → Correctly states that the integral is evaluated over a closed path.
- �� Option B → Correctly describes the dot product B⋅dl.
- �� Option D → Correctly explains the transition from summation to integration.
Concept Application
- Application
- Analyze the mathematical meaning of line integration and the associated sign convention.
- Final Logic
- Changing the direction of traversal changes the sign convention, making Option C incorrect.
"Reverse Loop, Reverse Sign"
2 A loop encloses three wires carrying steady currents of 2 A, 3 A and -1 A respectively. If the loop is traversed in a direction such that the first two are positive according to the right-hand rule, what is the value of ∮B⋅dl?
μ_0=4π×10^(-7) T m A^(-1)
�� Add currents algebraically. �� Apply Ampere's circuital law. �� Multiply enclosed current by μ₀.
Ampere's circuital law states ∮B⋅dl=μ_0I_(enc) The algebraic sum of enclosed currents is I_(enc)=2+3-1=4A Substituting into Ampere's law, ∮B⋅dl=(4π×10^(-7))(4)=16π×10^(-7) T m The sign of each current depends on the right-hand rule associated with the chosen direction of traversal. Since the first two currents are positive and the third is negative, the net enclosed current is 4 A. Therefore, the value of the line integral is 16π×10^(-7) T m.
- �� Option B → Corresponds to an enclosed current of only 2 A.
- �� Option C → Corresponds to an enclosed current of 6 A.
- �� Option D → Corresponds to an enclosed current of 1 A.
Substitution
- Application
- Calculate the algebraic sum of enclosed currents and substitute into Ampere's law.
- Final Logic
- I_(enc)=4A∮B⋅dl=16π×10^(-7) T m
"Add Current Signs Before Applying μ₀"
3 When applying Ampere's circuital law to find the magnetic field of a current configuration, the open surface bounded by the chosen loop:
�� Only the boundary loop is fixed. �� Different surfaces may share the same boundary. �� Enclosed current determines the integral.
Ampere's circuital law relates the line integral of the magnetic field around a closed loop to the total current passing through any open surface bounded by that loop. The choice of surface is arbitrary as long as its boundary remains the selected Amperian loop. The surface need not be planar, perpendicular to the conductor or enclose the entire conductor. What matters is the net current crossing the surface. This flexibility is similar to the freedom available in choosing Gaussian surfaces in electrostatics. NCERT emphasizes that Ampere's law depends only on the boundary and enclosed current, not on the exact shape of the surface.
- �� Option A → The entire conductor need not be enclosed.
- �� Option B → Current must pass through the surface for Ampere's law to have a non-zero value.
- �� Option C → The surface need not be flat or planar.
NCERT Recall
- Application
- Recall the geometric interpretation of surfaces bounded by an Amperian loop.
- Final Logic
- Any open surface with the same boundary loop is acceptable.
"Same Boundary, Any Surface"
4 Match the right-hand rule sign convention elements used in Ampere's circuital law.
| List I | List II |
|---|---|
| 1. Curl of fingers | a. Positive direction of enclosed current |
| 2. Direction of thumb | b. Sense of traversal of the boundary loop |
| 3. Reversing thumb direction | c. Reverses the sign of enclosed current |
| 4. Reversing finger curl direction | d. Reverses the loop traversal direction |
�� Fingers determine the direction of loop traversal. �� Thumb determines the positive current direction. �� Reversing either changes the sign convention.
The right-hand rule provides the sign convention used in Ampere's circuital law. When the fingers of the right hand curl in the direction in which the Amperian loop is traversed, the extended thumb points in the direction that is considered positive for the enclosed current. Thus, the curl of the fingers corresponds to the sense of traversal of the boundary loop, while the thumb represents the positive current direction. If the thumb direction is reversed, the positive direction of enclosed current is reversed. Similarly, if the finger curl direction is reversed, the sense of traversal of the boundary loop also reverses. This convention ensures consistency between the line integral (\oint \mathbf{B}\cdot d\mathbf{l}) and the algebraic sign of the enclosed current. NCERT uses this right-hand rule to establish the relationship between loop orientation and current sign in Ampere's circuital law.
- �� Option A → Incorrectly matches curl of fingers with positive current direction and thumb with loop traversal.
- �� Option B → Incorrectly assigns reversal effects and mismatches the primary sign convention.
- �� Option D → Completely reverses the physical interpretation of thumb and finger directions.
Logical Analysis
- Application
- Apply the standard right-hand rule used in Ampere's circuital law and identify the role of fingers, thumb and their reversals.
- Final Logic
- Fingers → Loop Traversal
- Thumb → Positive Current
- Reverse Thumb → Reverse Current Sign
- Reverse Fingers → Reverse Loop Direction
"Fingers Follow Loop, Thumb Shows Current"
5 Identify the correct statements regarding the selection of an ideal Amperian loop for simplifying magnetic field calculations.
Statements:
1. B should be tangential to the loop and constant.
2. B should be normal to the loop.
3. B may vanish on certain parts of the loop.
4. B must be entirely parallel to the current element.
�� Tangential constant fields simplify integration. �� Normal fields contribute zero. �� Vanishing fields also contribute zero.
An ideal Amperian loop is selected so that the evaluation of the line integral becomes simple. If the magnetic field is tangential to the loop and has constant magnitude, the integral reduces to B×L. If the magnetic field is normal to the path element, the angle between B and dl is 90^∘, making the contribution zero. Similarly, sections where the magnetic field vanishes contribute nothing to the integral. These conditions are frequently used in NCERT derivations involving straight conductors and solenoids. However, the magnetic field need not be parallel to the current element. The field direction is determined by symmetry and geometry, not by the direction of current elements themselves.
- �� Option A → Includes Statement 4, which is incorrect, and excludes Statement 1.
- �� Option C → Includes Statement 4, which is incorrect.
- �� Option D → Includes Statement 4, which is incorrect.
Concept Application
- Application
- Examine which field orientations simplify the line integral in Ampere's law.
- Final Logic
- Tangential constant fields help, while normal or zero fields contribute nothing to the integral.
"Tangent Helps, Normal Nulls, Zero Vanishes"
6 If an Amperian loop of length L is chosen such that the magnetic field is tangential and constant over the entire loop, and it encloses a net current I_e, the magnitude of the field is given by:
�� Apply Ampere's circuital law. �� Magnetic field is constant along the loop. �� Take B outside the integral.
Ampere's circuital law states ∮B⋅dl=μ_0I_e When the magnetic field is tangential and has the same magnitude at every point on the Amperian loop, B remains constant throughout the integration. Therefore, ∮B⋅dl=B∮dl Since the total length of the loop is L, BL=μ_0I_e Rearranging, B=μ_0I_e/L This is one of the most important simplifications used in Ampere's law. By selecting a symmetric loop where the magnetic field is constant and tangential, the integral becomes easy to evaluate. This approach is used extensively in NCERT while deriving magnetic fields due to straight conductors, solenoids and toroids.
- �� Option A → The denominator should contain L, not L^2.
- �� Option B → Field is inversely proportional to loop length.
- �� Option C → Current appears in the numerator, not denominator.
Substitution
- Application
- Replace the line integral by BL because the field is constant and tangential.
- Final Logic
- BL=μ_0I_eB=μ_0I_e/L
"Constant B ⇒ Divide by Loop Length"
7 For a long straight wire, the magnetic field outside the wire depends ________ on the radial distance r, and the lines of constant magnitude form ________.
�� Field decreases with distance. �� Symmetry is cylindrical. �� Equal-field points form circles.
For an infinitely long straight conductor carrying current I, the magnetic field is given by B=μ_0I/2πr This equation shows that the magnetic field is inversely proportional to the radial distance r from the conductor. As the distance from the wire increases, the magnetic field decreases. Due to cylindrical symmetry, every point located at the same radial distance from the wire experiences the same magnetic field magnitude. Therefore, the loci of constant magnetic field magnitude are concentric circles centered on the conductor. These circular field lines are a direct consequence of the right-hand thumb rule and Ampere's circuital law. Hence, the correct combination is inverse dependence on distance and concentric circles as lines of constant magnitude.
- �� Option A → Magnetic field lines are circular, not helical.
- �� Option B → The field is not directly proportional to distance.
- �� Option D → Neither exponential dependence nor spiral field lines occur.
NCERT Recall
- Application
- Recall the standard magnetic field expression around a long straight conductor.
- Final Logic
- B∝1/r
- and equal-field paths are concentric circles.
"Farther from Wire, Weaker Circle"
8 Identify the correct statements regarding the magnetic field outside a thick infinite straight wire carrying uniform current I.
Statements:
1. The field is B=μ_0I/(2πr).
2. The field magnitude decreases as the inverse square of the distance.
3. The expression is derived using a circular Amperian loop.
4. The field is directly proportional to the distance from the center.
�� Outside the wire, field varies as 1/r. �� Circular symmetry simplifies Ampere's law. �� The field is not proportional to distance.
Outside a long straight conductor carrying current I, Ampere's circuital law gives B=μ_0I/2πr This relation shows that the magnetic field is inversely proportional to the distance from the conductor. Therefore, Statement 1 is correct. The derivation is performed using a circular Amperian loop centered on the wire because the magnetic field has cylindrical symmetry and remains constant at every point on the circle. Hence, Statement 3 is also correct. Statement 2 is incorrect because the dependence is inverse first power (1/r) and not inverse square (1/r^2). Statement 4 is also incorrect because the field decreases rather than increases with distance.
- �� Option B → Both included statements are incorrect.
- �� Option C → Statement 2 is incorrect.
- �� Option D → Statement 4 is incorrect.
Concept Application
- Application
- Examine each statement using the expression B=μ_0I/2πr.
- Final Logic
- Only Statements 1 and 3 agree with the standard NCERT formula.
"Outside Wire → One by r"
9 Identify the correct statements regarding a system with cylindrical symmetry like an infinite straight wire.
Statements:
1. The magnetic field depends on three spatial coordinates.
2. The magnetic field magnitude depends only on the radial distance r.
3. This symmetry simplifies the evaluation of Ampere's integral.
4. The field direction is purely radial.
�� Cylindrical symmetry reduces coordinate dependence. �� Magnetic field depends only on r. �� Symmetry simplifies integration.
For an infinitely long straight conductor, the magnetic field possesses cylindrical symmetry. This means the field magnitude depends only on the radial distance from the conductor and is independent of angular position and axial position. Therefore, Statement 2 is correct. Because of this symmetry, a circular Amperian loop can be chosen such that the magnetic field remains constant over the loop. This greatly simplifies the evaluation of Ampere's integral, making Statement 3 correct. Statement 1 is incorrect because the field does not depend on all three spatial coordinates. Statement 4 is also incorrect because the magnetic field direction is tangential to circular field lines rather than radial.
- �� Option A → Statements 1 and 4 are both incorrect.
- �� Option B → Statement 4 is incorrect.
- �� Option D → Statement 1 is incorrect.
Logical Analysis
- Application
- Use the properties of cylindrical symmetry around a straight conductor.
- Final Logic
- Only radial distance determines magnitude, and symmetry simplifies Ampere's law.
"Cylinder ⇒ Only r Matters"
10 Unlike electrostatic field lines which originate from positive charges and terminate at negative charges, the magnetic field lines formed around a straight current-carrying wire:
�� Magnetic field lines are closed curves. �� Around a wire, they form concentric circles. �� Magnetic field lines never intersect.
The magnetic field produced by a long straight current-carrying conductor consists of concentric circular field lines centered on the wire. Unlike electric field lines, which originate from positive charges and terminate on negative charges, magnetic field lines always form continuous closed loops. This reflects the absence of isolated magnetic monopoles. The circular nature of these field lines can be determined using the right-hand thumb rule. Every magnetic field line forms a closed curve and does not have a starting or ending point. NCERT emphasizes that magnetic field lines are fundamentally different from electric field lines in this respect. Therefore, the correct statement is that magnetic field lines form closed loops as concentric circles.
- �� Option A → Magnetic field lines do not terminate at infinity.
- �� Option C → The field direction is tangential to circles, not parallel to the current element.
- �� Option D → Magnetic field lines never intersect each other.
NCERT Recall
- Application
- Recall the characteristics of magnetic field lines around a straight conductor.
- Final Logic
- Magnetic field lines around a wire are concentric circular closed loops.
"Magnetic Lines Loop Forever"
11 Match the application of the right-hand rule based on its specific geometry.
| List I | List II |
|---|---|
| 1. Axis of a circular current loop | a. Thumb points along current, fingers curl along magnetic field |
| 2. Long straight conducting wire | b. Thumb points along magnetic field, fingers curl along current |
| 3. Solenoid magnetic field direction | c. Field direction obtained along the axis of the coil |
| 4. Circular field lines around a wire | d. Magnetic field forms concentric circles around the conductor |
�� Different current geometries require different applications of the right-hand rule. �� Circular loops and solenoids use thumb for magnetic field direction. �� Straight wires use thumb for current direction.
The right-hand rule is applied differently depending on the geometry of the current-carrying conductor. For a long straight wire, the thumb points in the direction of current while the curled fingers indicate the direction of magnetic field lines around the conductor. For a circular current loop, the fingers curl in the direction of current and the thumb points along the magnetic field axis through the center of the loop. A solenoid can be regarded as a collection of circular current loops, so the thumb again indicates the magnetic field direction along the axis of the solenoid. Around a straight wire, the magnetic field forms concentric circles centered on the conductor. These applications are extensively used in NCERT to determine magnetic field directions without mathematical calculations.
- �� Option A → Uses the straight-wire interpretation for the circular loop.
- �� Option C → Incorrectly interchanges the loop and solenoid interpretations.
- �� Option D → Incorrectly matches the field pattern around a straight conductor.
NCERT Recall
- Application
- Recall the different forms of the right-hand rule used for straight wires, circular loops and solenoids.
- Final Logic
- Circular Loop → Thumb = Magnetic Field
- Straight Wire → Thumb = Current
- Solenoid → Thumb = Axial Magnetic Field
- Wire → Circular Magnetic Field Lines
"Loop and Solenoid → Thumb Shows Field, Wire → Thumb Shows Current"
12 When analytically applying the right-hand rule to a straight wire, if the thumb points vertically downwards representing the current, the fingers will curl in the ________ direction when viewed from above.
�� Thumb represents current direction. �� Fingers indicate magnetic field direction. �� Downward current produces clockwise field when viewed from above.
According to the right-hand thumb rule, the thumb is aligned in the direction of conventional current while the curled fingers indicate the direction of the magnetic field lines around the conductor. If the current flows vertically downward, point the right-hand thumb downward. The natural curling of the fingers then indicates the magnetic field direction around the wire. When viewed from above, this curl appears clockwise. This result can also be verified by reversing the usual case of upward current, which produces an anticlockwise magnetic field when viewed from above. Therefore, downward current corresponds to clockwise circulation of magnetic field lines.
- �� Option B → Corresponds to upward current, not downward current.
- �� Option C → Magnetic field lines circulate around the wire rather than point upward.
- �� Option D → Magnetic field lines do not point vertically downward.
Concept Application
- Application
- Apply the right-hand thumb rule with the thumb directed downward.
- Final Logic
- Downward Current → Clockwise Magnetic Field (Viewed from Above).
"Down Current, Clock Runs Down"
13 A solid straight wire of radius a carries a steady uniform current I. If the magnetic field at r=a/2 is B_1 and at r=a is B_2, what is the ratio B_1/B_2?
�� Inside a conductor, magnetic field varies linearly with radius. �� Use B∝r for r<a. �� Compare the two radii.
Inside a solid conductor carrying uniformly distributed current, the magnetic field is given by B=μ_0Ir/2πa^2 Thus, the magnetic field is directly proportional to the radial distance r. At r=a/2, B_1=μ_0I(a/2)/2πa^2 At r=a, B_2=μ_0Ia/2πa^2 Taking the ratio, B_1/B_2=a/2/a=1/2 Therefore, B_1:B_2=1:2 This result directly follows from the linear variation of magnetic field inside a uniformly current-carrying conductor.
- �� Option A → Reverses the correct ratio.
- �� Option B → Assumes quadratic variation instead of linear variation.
- �� Option C → Opposite of the actual ratio.
Substitution
- Application
- Use the proportionality B∝r inside the conductor.
- Final Logic
- B_1/B_2=a/2/a=1/2
"Inside Wire, Double r → Double B"
14 For a solid thick wire of radius a carrying a uniform current, the magnetic field ________ linearly with distance r for r<a, and then ________ inversely with r for r>a.
�� Inside the wire, B∝r. �� Outside the wire, B∝1/r. �� Surface gives the maximum field.
For a uniformly current-carrying solid conductor, Ampere's law gives two different field expressions. For r<a, B=μ_0Ir/2πa^2 which shows that the magnetic field increases linearly with radial distance. At the center, the field is zero and it gradually increases toward the surface. For r>a, B=μ_0I/2πr which shows that the magnetic field decreases inversely with distance from the wire. Thus, the magnetic field reaches its maximum value at the surface and then decreases outside the conductor. Therefore, the correct description is "increases linearly" inside and "decreases inversely" outside.
- �� Option A → Opposite of the actual behavior.
- �� Option B → Outside the conductor, the field decreases.
- �� Option D → Inside the conductor, the field increases.
Concept Application
- Application
- Apply the separate field expressions for regions inside and outside the conductor.
- Final Logic
- Inside → B∝r
- Outside → B∝1/r
"Grow Inside, Glow Outside, Then Go Down"
15 Identify the correct statements regarding the structural parameters of a long solenoid.
Statements:
1. Its length is large compared to its radius.
2. It consists of a long wire wound in a continuous helix.
3. Each turn can be regarded as an independent circular loop.
4. The net magnetic field is the vector sum of fields due to all turns.
�� A solenoid is long compared to its radius. �� It is formed by helical winding. �� Total field results from all turns.
A long solenoid is a tightly wound helical coil whose length is much greater than its radius. This geometry allows the magnetic field inside the solenoid to become nearly uniform. Each turn of the solenoid behaves like a circular current loop and produces its own magnetic field. According to the principle of superposition, the resultant magnetic field inside the solenoid is the vector sum of the magnetic fields produced by all individual turns. Since neighbouring turns are closely spaced, their fields reinforce each other in the interior region, creating a strong and nearly uniform magnetic field. Therefore, all four statements correctly describe the structure and magnetic behavior of a long solenoid.
- �� Option A → Omits Statement 4, which is correct.
- �� Option B → Omits Statement 3, which is correct.
- �� Option D → Omits Statement 1, which is correct.
NCERT Recall
- Application
- Recall the NCERT definition and construction features of a long solenoid.
- Final Logic
- All four statements correctly describe a long solenoid and its magnetic field formation.
"Long, Helical, Many Loops, One Field"
16 Incorrect statement about the construction and resulting field of a finite solenoid:
�� Solenoids use insulated wire. �� Enamel prevents short-circuiting. �� External field is weak compared to the internal field.
A finite solenoid is constructed by winding a long insulated wire in the form of a closely packed helix. The insulation is usually provided by an enamel coating on the wire. The purpose of the enamel coating is to prevent electrical contact between neighbouring turns, thereby avoiding short circuits. It does not electrically connect adjacent turns. The magnetic field inside the solenoid is strong due to the combined contribution of all turns, whereas the field outside is comparatively weak. Between neighbouring turns, transverse field components largely cancel because of symmetry and superposition. Therefore, the statement that enamelled wires are used to ensure electrical connection between adjacent turns is incorrect.
- �� Option A → Closely spaced turns are a characteristic feature of a solenoid.
- �� Option C → Transverse components largely cancel due to symmetry.
- �� Option D → The external field is much weaker than the internal field.
NCERT Recall
- Application
- Recall the purpose of enamel insulation in solenoid construction.
- Final Logic
- Enamel prevents electrical contact; it does not create electrical connections between turns.
"Enamel = Insulate, Not Interconnect"
17 Identify the correct statements regarding the Amperian loop used to calculate the magnetic field inside a long solenoid.
Statements:
1. The loop chosen is a rectangular loop abcd.
2. The transverse sections contribute fully to the line integral.
3. The exterior section contributes zero because the external field is nearly zero.
4. The relevant length of the loop is the portion parallel to the axis inside the solenoid.
�� A rectangular Amperian loop is used. �� Outside field is approximately zero. �� Only the interior axial segment contributes significantly.
To derive the magnetic field inside a long solenoid using Ampere's circuital law, NCERT considers a rectangular Amperian loop abcd. One side of the rectangle lies inside the solenoid parallel to its axis, while another side lies outside where the magnetic field is nearly zero. The transverse sides are perpendicular to the magnetic field direction. Since B is perpendicular to dl along these transverse sections, their contribution to the line integral is zero. The external side contributes negligibly because the external magnetic field is nearly zero for a long solenoid. Consequently, the only significant contribution comes from the segment inside the solenoid that is parallel to the axis. Thus, Statements 1, 3 and 4 are correct.
- �� Option B → Statement 2 is incorrect because transverse sections contribute zero.
- �� Option C → Statement 2 is incorrect.
- �� Option D → Statement 2 is incorrect.
Concept Application
- Application
- Analyze the contribution of each segment of the rectangular Amperian loop.
- Final Logic
- Only the interior axial segment contributes significantly to the integral.
"Inside Counts, Outside Fades, Sides Cancel"
18 As the solenoid geometry is made longer and longer compared to its radius, the exterior magnetic field:
�� Longer solenoids confine magnetic field lines. �� Internal field becomes more uniform. �� External field becomes negligible.
As the length of a solenoid increases relative to its radius, the magnetic field lines become increasingly confined within the interior region. The magnetic fields produced by different turns cancel each other more effectively outside the solenoid. Consequently, the external magnetic field becomes weaker and tends toward zero. In the ideal case of an infinitely long solenoid, the external magnetic field is considered zero, while the internal field remains strong and uniform. This property greatly simplifies the application of Ampere's circuital law and is one of the key assumptions used in NCERT derivations. Therefore, the correct statement is that the external magnetic field approaches zero as the solenoid becomes longer.
- �� Option A → The external field becomes weaker, not stronger.
- �� Option B → The field does not become completely perpendicular to the axis.
- �� Option D → Concentric circles characterize straight wires, not long solenoids.
NCERT Recall
- Application
- Recall the limiting behavior of a very long solenoid.
- Final Logic
- Longer Solenoid → External Field Approaches Zero.
"Long Solenoid, Lost Outside Field"
19 Both Ampere's law and Gauss's law elegantly relate a physical quantity on the ________ to another physical quantity, namely the primary source, in the ________.
�� Both laws connect a boundary quantity to an enclosed source. �� Ampere's law relates circulation to enclosed current. �� Gauss's law relates flux to enclosed charge.
Ampere's circuital law and Gauss's law possess a similar mathematical structure. Ampere's law relates the line integral of the magnetic field along a closed boundary to the current enclosed within that boundary. Similarly, Gauss's law relates the electric flux through a closed boundary surface to the electric charge enclosed within it. In both cases, a measurable quantity defined on the boundary depends only on the total source present in the interior region. This elegant relationship simplifies the analysis of highly symmetric systems and forms one of the central ideas of field theory. Therefore, the correct statement is that both laws relate a quantity on the boundary to a source located in the interior.
- �� Option A → Reverses the actual relationship.
- �� Option B → Does not apply simultaneously to both laws.
- �� Option C → Describes specific geometries rather than the general principle.
Logical Analysis
- Application
- Compare the mathematical structure of Ampere's law and Gauss's law.
- Final Logic
- Boundary Quantity ↔ Interior Source.
"Boundary Reveals the Source Within"
20 Identify the correct statements regarding Ampere's law compared to the Biot–Savart law.
Statements:
1. Ampere's law is an alternative and appealing expression of the Biot–Savart law.
2. Ampere's law is strictly valid only for rapidly time-varying currents.
3. Both express the physical consequences of steady electrical current.
4. Ampere's law relates the magnetic field on a boundary to the current in the interior.
�� Both laws describe magnetic effects of steady currents. �� Ampere's law is especially useful for symmetric systems. �� The standard form does not apply to rapidly varying currents.
Ampere's circuital law and the Biot–Savart law are two complementary methods used to determine magnetic fields generated by steady currents. Ampere's law can be viewed as an elegant alternative expression of the Biot–Savart law, particularly for systems possessing high symmetry. Both laws describe the magnetic consequences of steady electrical currents. Ampere's law specifically relates a boundary quantity, namely the circulation of the magnetic field, to the enclosed current within the interior region. However, the standard form of Ampere's law discussed in NCERT is valid for steady currents and not for rapidly varying currents. The latter situation requires Maxwell's correction involving displacement current. Therefore, Statements 1, 3 and 4 are correct, while Statement 2 is incorrect.
- �� Option A → Statement 2 is incorrect.
- �� Option C → Includes Statement 2, which is false.
- �� Option D → Includes Statement 2, which is false.
Concept Application
- Application
- Compare the domain of validity and interpretation of Ampere's law and Biot–Savart law.
- Final Logic
- Statements 1, 3 and 4 are correct; Statement 2 is incorrect because Ampere's law in NCERT applies to steady currents.
"Biot Gives Origin, Ampere Gives Symmetry"
