CUET UG Mathematics Booster Test 1 - Introduction & Basics
π Answers are locked once submitted β results and explanations appear at the end.
QUESTION 1 OF 20
In a graphical context, while differential calculus aims to find the tangent slope to a curve, integral calculus primarily aims to find:
QUESTION 2 OF 20
Using the area interpretation of integrals, what is the value of
β«βα΅ β(aΒ²βxΒ²) dx,
representing a quarter circle of radius a?
QUESTION 3 OF 20
Arrange the sequence to find the anti-derivative of xΒ³:
1. Apply the power rule for integration xβΏβΊΒΉ/(n+1).
2. Add the constant of integration C.
3. Substitute n=3 to get xβ΄/4.
QUESTION 4 OF 20
Match the families of curves to their general representations:
| List I | List II |
|---|---|
| 1. Family of anti-derivatives of 2x | a. eΛ£+C |
| 2. Family of anti-derivatives of cos x | b. sin x+C |
| 3. Family of anti-derivatives of 1 | c. x+C |
| 4. Family of anti-derivatives of eΛ£ | d. xΒ²+C |
QUESTION 5 OF 20
The indefinite integral
β«(f(x)Β±g(x)) dx
is equivalent to which of the following properties?
1. β«f(x) dx Β± β«g(x) dx
2. Represents a family of curves.
3. Evaluates to a discrete integer.
QUESTION 6 OF 20
Identify the INCORRECT statement concerning integral notation:
QUESTION 7 OF 20
A particle has velocity vector
vβ(t)=sin t iΜ+cos t jΜ.
If the initial position is (0,1) at t=0, integrating vβ(t) gives its position. What is the position vector at t=Ο/2?
QUESTION 8 OF 20
The probability of a random event occurring between x=0 and x=Ο/2 is modeled by
β«β^(Ο/2) cos x dx.
Evaluate this exact probability.
QUESTION 9 OF 20
Assertion (A): Evaluating β«eΛ£ dx gives exactly one specific curve, y=eΛ£.
Reason (R): The indefinite integral produces a family of anti-derivatives containing an arbitrary constant C.
QUESTION 10 OF 20
Evaluate the definite integral:
β«β^(Ο/4) secΒ²x dx.
QUESTION 11 OF 20
Data of a machine's production rate is continuously modeled by
R(t)=eα΅.
Calculate the total integrated production data from t=0 to t=ln 5.
QUESTION 12 OF 20
The connection between definite and indefinite integrals states
β«βα΅f(x)dx = F(b)βF(a).
Use this to find the value of
β«βΒ² (1/x) dx.
QUESTION 13 OF 20
In the equation
β«xeΛ£ dx = eΛ£(xβ1)+C,
the integrand is:
QUESTION 14 OF 20
Match the integral notation to its variable of integration:
| List I | List II |
|---|---|
| 1. β«sin ΞΈ dΞΈ | a. y |
| 2. β«2y dy | b. u |
| 3. β«eα΅ du | c. ΞΈ |
| 4. β«xΒ² dx | d. x |
QUESTION 15 OF 20
Assertion (A): Two indefinite integrals with the same derivative lead to different families of curves.
Reason (R): If
d/dx β«f(x)dx = d/dx β«g(x)dx,
then
β«f(x)dx = β«g(x)dx + C,
showing equivalence.
QUESTION 16 OF 20
Which of the following is INCORRECT regarding reverse differentiation?
QUESTION 17 OF 20
Why is the arbitrary constant C referred to as a parameter?
1. It determines a specific unique function if an initial condition is given.
2. Varying C yields different anti-derivatives.
3. It changes the derivative of the function entirely.
QUESTION 18 OF 20
The integral
β«2x dx = xΒ² + C
geometrically represents a family of parabolas. How do these parabolas relate to each other on a graph?
QUESTION 19 OF 20
Based on the passage's application to finance, if the marginal cost function of producing an item is
MC = 2x + 5,
find the total accumulated cost to produce 10 units (from x=0) by integration.
QUESTION 20 OF 20
According to the passage, which theorem explicitly makes the definite integral a practical tool for science, engineering, and probability?
Test Complete!
Answer Review
1 In a graphical context, while differential calculus aims to find the tangent slope to a curve, integral calculus primarily aims to find:
Differential calculus studies slopes and rates of change. Integral calculus studies accumulation and area. Area under a curve is a primary application of integration.
Differential calculus focuses on derivatives, tangent slopes, and rates of change. Integral calculus developed from problems involving area under curves and accumulation of quantities. Therefore Option B is correct. Options A, C, and D concern other geometric properties and are not the primary objective of integration.
- Option A β Concavity is determined using second derivatives.
- Option C β Midpoint determination is not a central goal of integration.
- Option D β Absolute maxima involve optimization methods.
Used: Odd One Out
Application: Distinguish area-related concepts from derivative-based concepts.
Final Logic: Integration is fundamentally associated with area calculation.
"Derivative β Slope, Integral β Area."
2 Using the area interpretation of integrals, what is the value of
β«βα΅ β(aΒ²βxΒ²) dx,
representing a quarter circle of radius a?
Equation represents the upper semicircle. Limits 0 to a select one-quarter circle. Area equals one-fourth of ΟaΒ².
The curve y=β(aΒ²βxΒ²) represents the upper half of a circle of radius a. Integrating from x=0 to x=a covers exactly one-quarter of the circle. Therefore the area equals (1/4)ΟaΒ². Options A and B represent larger portions of the circle, while D is circumference-related.
- Option A β Represents the entire circle area.
- Option B β Represents a semicircle area.
- Option D β Represents circumference formula dimensions.
Used: Contextual/Tonal Matching
Application: Recognize the graph as a quarter circle.
Final Logic: Quarter circle area = ΟaΒ²/4.
"Quarter Circle = ΟrΒ²/4."
3 Arrange the sequence to find the anti-derivative of xΒ³:
1. Apply the power rule for integration xβΏβΊΒΉ/(n+1).
2. Add the constant of integration C.
3. Substitute n=3 to get xβ΄/4.
Start with the integration rule. Substitute the exponent value. Add the integration constant last.
The correct procedure begins with applying the power rule. Next substitute n=3 to obtain xβ΄/4. Finally add the arbitrary constant C to represent the complete family of anti-derivatives. Thus the proper order is 1 β 3 β 2.
- Option A β Adds C before completing integration.
- Option B β Starts with the final step.
- Option C β Substitutes before applying the rule.
Used: Contextual/Tonal Matching
Application: Follow the logical sequence of integration.
Final Logic: Rule β Substitute β Add C.
"Rule, Result, Constant."
4 Match the families of curves to their general representations:
| List I | List II |
|---|---|
| 1. Family of anti-derivatives of 2x | a. eΛ£+C |
| 2. Family of anti-derivatives of cos x | b. sin x+C |
| 3. Family of anti-derivatives of 1 | c. x+C |
| 4. Family of anti-derivatives of eΛ£ | d. xΒ²+C |
Integrate each function separately. Match with corresponding anti-derivative family. Include arbitrary constant C.
β«2x dx = xΒ²+C, β«cos x dx = sin x+C, β«1 dx = x+C, and β«eΛ£ dx = eΛ£+C. Therefore the matching is 1-d, 2-b, 3-c, 4-a. This corresponds exactly to Option A.
- Option B β Incorrectly matches 2x and cos x.
- Option C β Swaps anti-derivatives of cos x and eΛ£.
- Option D β Multiple mismatches occur.
Used: Option Grouping
Application: Compute each anti-derivative and compare pairings.
Final Logic: Match each derivative with its anti-derivative family.
"2xβxΒ², cosβsin, 1βx, eΛ£βeΛ£."
5 The indefinite integral
β«(f(x)Β±g(x)) dx
is equivalent to which of the following properties?
1. β«f(x) dx Β± β«g(x) dx
2. Represents a family of curves.
3. Evaluates to a discrete integer.
Integration obeys linearity. Indefinite integrals form families of functions. They do not yield fixed integers.
The sum and difference rule gives β«(fΒ±g)dx = β«f dx Β± β«g dx. An indefinite integral represents a family of curves because of the arbitrary constant C. Statement 3 is false since indefinite integrals are functions, not specific numerical values.
- Option A β Statement 3 is incorrect.
- Option C β Statement 1 is also true.
- Option D β Statement 3 remains false.
Used: Option Grouping
Application: Verify each statement independently.
Final Logic: Only statements 1 and 2 describe indefinite integrals.
"Linearity + Family."
6 Identify the INCORRECT statement concerning integral notation:
Indefinite integrals have no limits. Limits are required only for definite integrals. Therefore statement C is incorrect.
An indefinite integral does not require upper or lower limits. It represents a family of anti-derivatives. Option B correctly identifies the variable of integration, and Option D correctly identifies the integrand. Therefore Option C is the incorrect statement.
- Option A β Correctly relates integration to anti-derivative families.
- Option B β dx specifies the integration variable.
- Option D β f(x) is indeed the integrand.
Used: Elimination
Application: Separate properties of definite and indefinite integrals.
Final Logic: Only definite integrals require intervals.
"No Limits = Indefinite."
7 A particle has velocity vector
vβ(t)=sin t iΜ+cos t jΜ.
If the initial position is (0,1) at t=0, integrating vβ(t) gives its position. What is the position vector at t=Ο/2?
Integrate each velocity component. Apply initial position conditions. Evaluate at t=Ο/2.
Integrating gives x(t)=βcos t+Cβ and y(t)=sin t+Cβ. Using position (0,1) at t=0 gives Cβ=1 and Cβ=1. Hence x(t)=1βcos t and y(t)=sin t+1. At t=Ο/2, position=(1,2). Therefore Option D is correct.
- Option A β Incorrect y-coordinate.
- Option B β Incorrect x-coordinate sign.
- Option C β Ignores displacement from initial conditions.
Used: Substitution
Application: Integrate velocity and apply initial conditions.
Final Logic: Position equals integrated velocity plus constants.
"Velocity Integral = Position."
8 The probability of a random event occurring between x=0 and x=Ο/2 is modeled by
β«β^(Ο/2) cos x dx.
Evaluate this exact probability.
Integral of cos x is sin x. Apply limits 0 and Ο/2. Result equals 1.
β«β^(Ο/2) cos x dx = [sin x]β^(Ο/2) = sin(Ο/2)βsin(0)=1β0=1. Therefore Option A is correct. The remaining options do not follow from evaluating the definite integral.
- Option B β Ignores positive accumulated area.
- Option C β Confuses result with interval length.
- Option D β Integral is positive, not negative.
Used: Substitution
Application: Evaluate the anti-derivative at limits.
Final Logic: sin(Ο/2)βsin(0)=1.
"Cos β Sin β One."
9 Assertion (A): Evaluating β«eΛ£ dx gives exactly one specific curve, y=eΛ£.
Reason (R): The indefinite integral produces a family of anti-derivatives containing an arbitrary constant C.
Indefinite integrals include constant C. Infinite anti-derivatives exist. Assertion ignores the constant.
The integral β«eΛ£dx equals eΛ£+C, not a single unique curve. Therefore the assertion is false. The reason is true because indefinite integrals represent a family of anti-derivatives differing by constants. Hence Option B is correct.
- Option A β Reason is true.
- Option C β Assertion is false.
- Option D β Reason is not false.
Used: Elimination
Application: Check assertion and reason independently.
Final Logic: Missing +C makes the assertion false.
"Never Forget +C."
10 Evaluate the definite integral:
β«β^(Ο/4) secΒ²x dx.
Integral of secΒ²x is tan x. Evaluate between limits. tan(Ο/4)=1 and tan(0)=0.
Using the standard integral, β«secΒ²x dx = tan x. Applying limits gives tan(Ο/4)βtan(0)=1β0=1. Therefore Option C is correct. Other options arise from incorrect use of trigonometric values or anti-derivatives.
- Option A β Integral over a positive interval cannot be zero.
- Option B β Confuses answer with upper limit.
- Option D β Result is positive, not negative.
Used: Substitution
Application: Use the standard anti-derivative and evaluate limits.
Final Logic: tan(Ο/4)βtan(0)=1.
"secΒ² β tan."
11 Data of a machine's production rate is continuously modeled by
R(t)=eα΅.
Calculate the total integrated production data from t=0 to t=ln 5.
Total production equals the definite integral of the rate. Anti-derivative of eα΅ is eα΅. Evaluate between 0 and ln 5.
Total production is β«βΛ‘βΏβ΅ eα΅ dt = [eα΅]βΛ‘βΏβ΅ = eΛ‘βΏβ΅βeβ° = 5β1 = 4. Therefore Option D is correct. Option A ignores subtraction of the lower limit, while Options B and C arise from incorrect evaluation.
- Option A β Uses only the upper-limit value.
- Option B β Incorrectly evaluates e^(ln 5).
- Option C β Does not satisfy definite integral computation.
Used: Substitution
Application: Find the anti-derivative and apply upper-minus-lower evaluation.
Final Logic: e^(ln5)β1 = 5β1 = 4.
"e and ln cancel."
12 The connection between definite and indefinite integrals states
β«βα΅f(x)dx = F(b)βF(a).
Use this to find the value of
β«βΒ² (1/x) dx.
Anti-derivative of 1/x is ln|x|. Apply limits 1 and 2. Result simplifies to ln 2.
Using F(x)=ln|x|, we obtain β«βΒ²(1/x)dx = ln2βln1. Since ln1=0, the value is ln2. Therefore Option A is correct. The other options do not follow from applying the Fundamental Theorem of Calculus correctly.
- Option B β Would require different limits.
- Option C β Not obtained from logarithmic integration.
- Option D β Incorrect numerical interpretation.
Used: Substitution
Application: Apply the Fundamental Theorem directly.
Final Logic: ln2β0 = ln2.
"1/x β Log."
13 In the equation
β«xeΛ£ dx = eΛ£(xβ1)+C,
the integrand is:
Integrand is the function being integrated. It appears between β« and dx. Here it is xeΛ£.
The integrand is the expression placed immediately after the integral sign and before dx. In β«xeΛ£dx, the integrand is xeΛ£. Option A is part of the anti-derivative, Option C is the differential, and Option D is the integration constant.
- Option A β Represents the anti-derivative result.
- Option C β Indicates the variable of integration.
- Option D β Constant added after integration.
Used: Contextual/Tonal Matching
Application: Identify standard parts of integral notation.
Final Logic: Function inside the integral sign is the integrand.
"Inside β« = Integrand."
14 Match the integral notation to its variable of integration:
| List I | List II |
|---|---|
| 1. β«sin ΞΈ dΞΈ | a. y |
| 2. β«2y dy | b. u |
| 3. β«eα΅ du | c. ΞΈ |
| 4. β«xΒ² dx | d. x |
Variable of integration is indicated by the differential. dΞΈ corresponds to ΞΈ, dy to y. Match each notation accordingly.
The variable of integration is identified by the symbol following d. Thus dΞΈβΞΈ, dyβy, duβu, and dxβx. Hence the correct matching is 1-c, 2-a, 3-b, 4-d, which corresponds to Option C.
- Option A β Incorrectly swaps ΞΈ and u.
- Option B β Multiple variables mismatched.
- Option D β Assigns incorrect variables throughout.
Used: Option Grouping
Application: Match each differential with its variable.
Final Logic: Symbol after d determines the integration variable.
"dxβx, dyβy, duβu."
15 Assertion (A): Two indefinite integrals with the same derivative lead to different families of curves.
Reason (R): If
d/dx β«f(x)dx = d/dx β«g(x)dx,
then
β«f(x)dx = β«g(x)dx + C,
showing equivalence.
Same derivative implies functions differ only by a constant. They belong to the same family. Reason correctly states this property.
If two functions have the same derivative, they differ only by a constant. Therefore they belong to the same family of anti-derivatives, making the assertion false. The reason correctly expresses this relationship through the constant C. Hence Option D is correct.
- Option A β Reason is true.
- Option B β Assertion is false.
- Option C β Assertion is not true.
Used: Elimination
Application: Test the assertion and reason independently.
Final Logic: Same derivative β same family up to a constant.
"Same Derivative, Same Family."
16 Which of the following is INCORRECT regarding reverse differentiation?
Integral reverses differentiation. Derivative of cos x is βsin x. Correct integral is βcos x + C.
Since d/dx(βcos x)=sin x, we have β«sin x dx=βcos x+C. Therefore Option A is incorrect. Options B, C, and D are standard integration formulas and are correctly stated.
- Option B β Correct because d/dx(sin x)=cos x.
- Option C β Correct because d/dx(tan x)=secΒ²x.
- Option D β Correct because eΛ£ is its own derivative.
Used: Substitution
Application: Differentiate each proposed anti-derivative.
Final Logic: Only Option A differentiates to βsin x.
"Sin integrates to βCos."
17 Why is the arbitrary constant C referred to as a parameter?
1. It determines a specific unique function if an initial condition is given.
2. Varying C yields different anti-derivatives.
3. It changes the derivative of the function entirely.
C selects a member of the family. Different C values give different curves. Derivatives remain unchanged.
The constant C acts as a parameter because changing its value produces different members of the anti-derivative family. When an initial condition is supplied, a unique value of C is determined. Statement 3 is false because constants vanish upon differentiation.
- Option A β Statement 3 is incorrect.
- Option C β Statement 1 is also true.
- Option D β Statement 3 remains false.
Used: Option Grouping
Application: Evaluate each statement independently.
Final Logic: Only statements 1 and 2 correctly describe C.
"C Chooses the Curve."
18 The integral
β«2x dx = xΒ² + C
geometrically represents a family of parabolas. How do these parabolas relate to each other on a graph?
Constant C changes only y-values. Shape of parabola remains unchanged. Vertical translations are produced.
Adding different constants to xΒ² shifts the graph upward or downward without affecting shape. Thus all curves xΒ²+C are vertical translations of one another. They are not horizontal shifts, do not necessarily share roots, and do not always pass through the origin.
- Option A β Roots change with C.
- Option B β Horizontal shifts require changes inside x.
- Option D β Most family members do not pass through the origin.
Used: Contextual/Tonal Matching
Application: Recall the geometric effect of adding a constant.
Final Logic: +C creates vertical displacement.
"+C = Vertical Shift."
19
Based on the passage's application to finance, if the marginal cost function of producing an item is
MC = 2x + 5,
find the total accumulated cost to produce 10 units (from x=0) by integration.
Total cost equals integral of marginal cost. Integrate from 0 to 10. Evaluate the definite integral.
Total accumulated cost = β«βΒΉβ°(2x+5)dx = [xΒ²+5x]βΒΉβ° = (100+50)β0 = 150. Hence Option D is correct. The remaining options result from incomplete integration or incorrect evaluation of the limits.
- Option A β Omits part of the integrated expression.
- Option B β Uses only the constant contribution.
- Option C β Results from arithmetic error.
Used: Substitution
Application: Integrate the marginal cost and evaluate limits.
Final Logic: xΒ²+5x evaluated from 0 to 10 equals 150.
"Marginal Cost β Integrate."
20
According to the passage, which theorem explicitly makes the definite integral a practical tool for science, engineering, and probability?
Passage explicitly names the theorem. It connects differentiation and integration. It enables practical computation of definite integrals.
The passage directly states that the Fundamental Theorem of Calculus connects indefinite and definite integrals and makes definite integrals practical tools in science, engineering, economics, finance, and probability. Therefore Option A is correct. The other theorems serve different purposes in calculus.
- Option B β Concerns average rates and function behavior.
- Option C β Deals with derivatives of composite functions.
- Option D β Helps evaluate certain limits, not definite integrals.
Used: Contextual/Tonal Matching
Application: Locate the theorem explicitly mentioned in the passage.
Final Logic: The passage directly names the Fundamental Theorem of Calculus.
"FTC Connects All."
