CUET UG Chemistry Booster Test - 3Conductance of Electrolytic Solutions
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QUESTION 1 OF 20
Identify the correct statements regarding resistance measurements.
Statements:
1. Resistance is directly proportional to the area of cross-section.
2. Resistance is measured using a Wheatstone bridge.
3. Resistance of a cell filled with KCl is used to find the cell constant.
4. Resistance is independent of temperature.
QUESTION 2 OF 20
In an electrolytic solution, if the distance between electrodes is doubled and the area of cross-section is halved, the conductance will:
QUESTION 3 OF 20
The resistivity of a solution is determined to be 87.135 Ω cm. What is its conductivity?
QUESTION 4 OF 20
The unit of cell constant (G*), which links resistance and resistivity mathematically, is:
QUESTION 5 OF 20
Match the following regarding an electrolytic solution.
| List I | List II |
|---|---|
| 1. l/A = 1 m⁻¹ | d. Ideal cell parameters for conductivity to equal conductance |
| 2. l/A = G* | c. Cell constant equation |
| 3. κ = 1/ρ | b. Standard definition formula for conductivity |
| 4. κ = G*(1/R) | a. Relationship to calculate conductivity |
QUESTION 6 OF 20
Arrange the following conductivity values in decreasing order of magnitude:
1. 10 S m⁻¹
2. 1 S cm⁻¹
3. 0.1 S cm⁻¹
4. 0.01 S m⁻¹
QUESTION 7 OF 20
According to the passage, what remains unchanged during metallic conductance?
QUESTION 8 OF 20
The passage implies that prolonged passage of direct current through an ionic solution causes a change in composition because:
QUESTION 9 OF 20
Arrange the following materials in decreasing order of their conductivity at 298.15 K:
1. Graphite (1.2 × 10⁵ S m⁻¹)
2. Silver (6.2 × 10⁷ S m⁻¹)
3. Sodium (2.1 × 10⁷ S m⁻¹)
4. Copper (5.9 × 10⁷ S m⁻¹)
QUESTION 10 OF 20
Identify the insulator listed with a conductivity of 1.0 × 10⁻¹⁶ S m⁻¹.
QUESTION 11 OF 20
The mechanism of conductance through semiconductors is complex. The introduction of specific impurities to increase conductivity of silicon is called:
QUESTION 12 OF 20
Identify the correct statements regarding semiconducting materials.
Statements:
1. Silicon and germanium are examples of semiconductors.
2. Doped silicon exhibits different conductivity than pure silicon.
3. Semiconductors have zero resistivity at 150 K.
4. Gallium arsenide is a semiconductor.
QUESTION 13 OF 20
A strong electrolyte like NaCl has a higher conductivity than a weak electrolyte like acetic acid of the same concentration because:
QUESTION 14 OF 20
Arrange the following factors in the order they are listed in the text as affecting the conductivity of electrolytic solutions:
1. Nature of the electrolyte added
2. Size of the ions produced and their solvation
3. Nature of the solvent and its viscosity
4. Concentration of the electrolyte
QUESTION 15 OF 20
The overall process where electrical energy is used to carry out non-spontaneous chemical reactions involving ionic movement is called:
QUESTION 16 OF 20
Identify the correct statements regarding the solvation effect based on the text.
Statements:
1. Solvation of ions affects the conductivity of electrolytic solutions.
2. Solvation causes metallic conductors to change composition.
3. Solvation provides the energy required for AC current.
4. Solvation is completely independent of the solvent's nature.
QUESTION 17 OF 20
Match the following regarding measurement issues.
| List I | List II |
|---|---|
| 1. Direct Current (DC) | c. Changes the composition of an electrolytic solution |
| 2. Alternating Current (AC) | d. Resolves the issue of changing composition |
| 3. Solid conductor | b. Can be connected directly to a Wheatstone bridge |
| 4. Ionic solution | a. Cannot be connected to the bridge like a wire A.1-b, 2-a, 3-d, 4-c |
QUESTION 18 OF 20
An oscillator used in measuring the resistance of an ionic solution provides AC power in the audio frequency range of:
QUESTION 19 OF 20
Platinized platinum electrodes are used in a conductivity cell. What does "platinized" refer to?
QUESTION 20 OF 20
When balancing the Wheatstone bridge for a conductivity cell with unknown resistance R₂ and known resistances R₁, R₃ and R₄, the unknown resistance is calculated as:
Test Complete!
Answer Review
1 Identify the correct statements regarding resistance measurements.
Statements:
1. Resistance is directly proportional to the area of cross-section.
2. Resistance is measured using a Wheatstone bridge.
3. Resistance of a cell filled with KCl is used to find the cell constant.
4. Resistance is independent of temperature.
�� Wheatstone bridge is used to measure resistance. �� Standard KCl solution is used for determining cell constant. �� Resistance is inversely proportional to area and depends on temperature.
According to NCERT, the resistance of an electrolytic solution is measured using a Wheatstone bridge arrangement. This method allows accurate determination of unknown resistance while minimizing errors. For conductivity measurements, the conductivity cell must first be calibrated. This calibration is carried out using a potassium chloride (KCl) solution whose conductivity is known accurately. By measuring the resistance of the KCl solution, the cell constant can be determined. Statement 1 is incorrect because resistance is inversely proportional to the area of cross-section and directly proportional to the length of the conductor. Statement 2 is correct because Wheatstone bridge is used for resistance measurements. Statement 3 is correct because standard KCl solution is used to determine the cell constant. Statement 4 is incorrect because resistance varies with temperature. Therefore, only Statements 2 and 3 are correct.
- �� Option B → Statement 1 is incorrect because resistance is inversely proportional to area.
- �� Option C → Statements 1 and 4 are incorrect.
- �� Option D → Statement 4 is incorrect.
Used – NCERT Recall
- Application
- Recall the relationships governing resistance and the method used for conductivity measurements.
- Final Logic
- Only Statements 2 and 3 agree with NCERT definitions and experimental procedures.
- KCl Calibrates Cell.
2 In an electrolytic solution, if the distance between electrodes is doubled and the area of cross-section is halved, the conductance will:
�� Conductance is directly proportional to area. �� Conductance is inversely proportional to length. �� Changes in both dimensions affect conductance simultaneously.
For an electrolytic solution, conductance is given by: where κ is conductivity, A is the area of cross-section and l is the distance between electrodes. Initially: When the distance between electrodes is doubled: When the area is halved: Substituting into the conductance expression: Thus, the conductance becomes one-fourth of its original value. Therefore, conductance decreases by a factor of four.
- �� Option A → Conductance decreases rather than increases.
- �� Option C → Both dimensions change, so conductance cannot remain constant.
- �� Option D → Conductance becomes one-fourth, not twice.
Used – Formula Application
- Application
- Apply the formula using the modified dimensions.
- Final Logic
- Area becomes half and length doubles, producing a fourfold decrease in conductance.
- Half Area × Double Length = Quarter Conductance.
3 The resistivity of a solution is determined to be 87.135 Ω cm. What is its conductivity?
�� Conductivity is the reciprocal of resistivity. �� Unit conversion is necessary. �� Both values represent the same conductivity in different units.
Conductivity (κ) is related to resistivity (ρ) by: Given: Therefore: To convert S cm⁻¹ into S m⁻¹: Thus: Hence, both values represent the same conductivity expressed in different units. Therefore, Options A and B are both correct, making Option D the correct answer.
- �� Option A → Correct value but not the complete answer.
- �� Option B → Correct value but not the complete answer.
- �� Option C → Conductivity is the reciprocal of resistivity, not equal to it.
Used – Formula Application
- Application
- Use κ = 1/ρ and perform unit conversion.
- Final Logic
- Reciprocal gives 0.01148 S cm⁻¹, equivalent to 1.148 S m⁻¹.
- Reciprocal First, Convert Later.
4 The unit of cell constant (G*), which links resistance and resistivity mathematically, is:
�� Cell constant equals l/A. �� Length divided by area gives inverse length. �� It is a geometrical property of the cell.
The cell constant is an important parameter used in conductivity measurements. According to NCERT: where l is the distance between the electrodes and A is the area of cross-section of the electrodes. Since length has units of metre (m) and area has units of square metre (m²): Similarly, when centimetres are used: Therefore, the cell constant has units of m⁻¹ or cm⁻¹. It depends only on the geometry of the conductivity cell and not on the nature or concentration of the solution being studied.
- �� Option B → Unit of conductivity.
- �� Option C → Unit of molar conductivity.
- �� Option D → Unit of resistivity.
Used – Formula Application
- Application
- Use the definition Cell Constant = l/A.
- Final Logic
- Length divided by area gives inverse length units.
- Units Always Become Inverse Length.
5 Match the following regarding an electrolytic solution.
| List I | List II |
|---|---|
| 1. l/A = 1 m⁻¹ | d. Ideal cell parameters for conductivity to equal conductance |
| 2. l/A = G* | c. Cell constant equation |
| 3. κ = 1/ρ | b. Standard definition formula for conductivity |
| 4. κ = G*(1/R) | a. Relationship to calculate conductivity |
�� Cell constant relates geometry to conductivity. �� Conductivity is the reciprocal of resistivity. �� Conductivity can be calculated from resistance and cell constant.
The conductivity of an electrolytic solution is related to resistance, resistivity and cell geometry. The ratio l/A is known as the cell constant (G*). When l/A equals unity, conductivity numerically becomes equal to conductance. Therefore, l/A = 1 m⁻¹ corresponds to ideal cell parameters. The relation l/A = G* is the standard equation defining the cell constant. Conductivity is defined as the reciprocal of resistivity, giving κ = 1/ρ. Furthermore, since conductance G = 1/R and conductivity is related to conductance through the cell constant, the expression κ = G*(1/R) is used to calculate conductivity. Thus the correct matching is: 1-d, 2-c, 3-b, 4-a.
- �� Option A → Cell constant equation is incorrectly assigned.
- �� Option B → Incorrectly matches conductivity and cell relationships.
- �� Option D → Multiple definitions are mismatched.
Used – Concept Application
- Application
- Use the definitions of conductivity, resistivity and cell constant.
- Final Logic
- Match each equation with its physical meaning and definition.
- Conductivity = Cell Constant × Conductance.
6 Arrange the following conductivity values in decreasing order of magnitude:
1. 10 S m⁻¹
2. 1 S cm⁻¹
3. 0.1 S cm⁻¹
4. 0.01 S m⁻¹
�� Convert all conductivity values into the same unit. �� 1 S cm⁻¹ = 100 S m⁻¹. �� Compare magnitudes after conversion.
Conductivity values must be expressed in a common unit before comparison. According to NCERT, conductivity is commonly expressed in S m⁻¹. Converting all values: 1. 10 S m⁻¹ = 10 S m⁻¹ 2. 1 S cm⁻¹ = 100 S m⁻¹ 3. 0.1 S cm⁻¹ = 10 S m⁻¹ 4. 0.01 S m⁻¹ = 0.01 S m⁻¹ After conversion: 2 = 100 S m⁻¹ 3 = 10 S m⁻¹ 1 = 10 S m⁻¹ 4 = 0.01 S m⁻¹ Thus, the largest value is 2, followed by 3 and 1, and finally 4. Conductivity comparisons are important because different units are frequently used in electrochemistry. Proper unit conversion prevents errors in ranking conductivity values. Therefore, the decreasing order is 2, 3, 1, 4.
- �� Option A → Places 10 S m⁻¹ above 1 S cm⁻¹ incorrectly.
- �� Option C → Places 0.1 S cm⁻¹ ahead of 1 S cm⁻¹.
- �� Option D → Places 10 S m⁻¹ immediately after 1 S cm⁻¹ without considering the full order.
Used – Unit Conversion
- Application
- Convert all values into S m⁻¹ and compare.
- Final Logic
- 100 S m⁻¹ > 10 S m⁻¹ > 0.01 S m⁻¹.
- Convert before comparing.
7
According to the passage, what remains unchanged during metallic conductance?
�� Metallic conduction occurs through electrons. �� Electrons enter and leave the conductor. �� No chemical change occurs in the conductor.
Metallic or electronic conductance occurs because free electrons move through the metallic lattice. According to NCERT, electrons enter the conductor from one end and leave through the other end while carrying electrical charge. During this process, the chemical composition of the metallic conductor remains unchanged. Unlike electrolytic conductance, metallic conductance does not involve chemical reactions or movement of ions. Therefore, no alteration occurs in the composition of the conductor. This is an important distinction between electronic conductance and ionic conductance. Temperature may vary during conduction and electron energies can change depending on conditions. However, the metallic conductor itself does not undergo a compositional change. Hence, the composition of the metallic conductor remains unchanged during metallic conductance.
- �� Option A → Temperature may change during conduction.
- �� Option B → Electron kinetic energy can vary with conditions.
- �� Option C → Valence electron availability is a material property, not the unchanged feature highlighted in the passage.
Used – Passage Analysis
- Application
- Identify the statement directly mentioned in the passage.
- Final Logic
- Electronic conduction occurs without changing the composition of the metal.
- Electrons Move, Composition Stays.
8
The passage implies that prolonged passage of direct current through an ionic solution causes a change in composition because:
�� Ionic conductance involves ion movement. �� Direct current causes electrode reactions. �� Chemical composition changes due to electrolysis.
According to NCERT, electrolytic conductance occurs through the movement of ions in solution. When direct current passes through an ionic solution for a prolonged period, ions migrate toward oppositely charged electrodes. At these electrodes, oxidation and reduction reactions take place. These electrochemical reactions consume certain ions and may produce new chemical species. As a result, the composition of the solution gradually changes. This process is known as electrolysis and is responsible for the chemical effects of electric current in electrolytic solutions. The passage specifically mentions that changes in composition occur because of electrochemical reactions. Therefore, electrochemical reactions at the electrodes are responsible for the observed change in composition.
- �� Option A → Evaporation is not the cause of conductivity changes.
- �� Option B → Ions do not solidify and block current flow.
- �� Option D → Ionic solutions do not become metallic conductors.
Used – Passage Analysis
- Application
- Focus on the cause of composition change stated in the passage.
- Final Logic
- Electrode reactions alter the chemical composition of the solution.
- Current Causes Electrode Reactions.
9 Arrange the following materials in decreasing order of their conductivity at 298.15 K:
1. Graphite (1.2 × 10⁵ S m⁻¹)
2. Silver (6.2 × 10⁷ S m⁻¹)
3. Sodium (2.1 × 10⁷ S m⁻¹)
4. Copper (5.9 × 10⁷ S m⁻¹)
�� Larger conductivity means better conductor. �� Compare numerical values directly. �� Silver has the highest conductivity.
Conductivity measures the ability of a material to conduct electric current. The greater the conductivity value, the better the conductor. Given values: 1. Graphite = 1.2 × 10⁵ S m⁻¹ 2. Silver = 6.2 × 10⁷ S m⁻¹ 3. Sodium = 2.1 × 10⁷ S m⁻¹ 4. Copper = 5.9 × 10⁷ S m⁻¹ Comparing the values: 6.2 × 10⁷ > 5.9 × 10⁷ > 2.1 × 10⁷ > 1.2 × 10⁵ Therefore, the decreasing order is: Silver > Copper > Sodium > Graphite Corresponding to: 2 > 4 > 3 > 1 Silver is one of the best metallic conductors, followed closely by copper. Sodium also conducts well but less effectively than silver and copper. Graphite conducts electricity because of its delocalized electrons, but its conductivity is much lower than that of metals.
- �� Option B → Places copper above silver and graphite above sodium.
- �� Option C → Places sodium above copper.
- �� Option D → Completely reverses the conductivity order.
Used – Numerical Comparison
- Application
- Compare the conductivity values directly.
- Final Logic
- Higher numerical conductivity indicates a better conductor.
- Sodium Then Graphite.
10 Identify the insulator listed with a conductivity of 1.0 × 10⁻¹⁶ S m⁻¹.
�� Insulators possess extremely low conductivity. �� Glass is a common electrical insulator. �� Charge carriers are almost absent.
Insulators are materials that strongly resist the flow of electric current. According to NCERT, materials such as glass, rubber and Teflon possess extremely low conductivity because they contain very few mobile charge carriers. A conductivity value of 1.0 × 10⁻¹⁶ S m⁻¹ is characteristic of a very good insulator. Glass is commonly cited as an insulating material with conductivity in this extremely low range. Because electrons are tightly bound within the structure, electric current cannot pass through it easily. This property makes glass useful in electrical insulation applications and laboratory equipment. Therefore, among the given options, glass is the material identified with conductivity approximately equal to 1.0 × 10⁻¹⁶ S m⁻¹.
- �� Option B → Teflon is also an insulator but is associated with even lower conductivity values.
- �� Option C → Pure water has higher conductivity than glass.
- �� Option D → Copper oxide is not classified as an insulator of this conductivity value.
Used – NCERT Recall
- Application
- Recall conductivity values of common insulating materials.
- Final Logic
- Glass corresponds to the given conductivity value.
- Glass = Very Low Conductivity.
11 The mechanism of conductance through semiconductors is complex. The introduction of specific impurities to increase conductivity of silicon is called:
�� Semiconductors have controlled conductivity. �� Impurities are intentionally added to modify conductivity. �� This process is known as doping.
Semiconductors such as silicon and germanium possess electrical conductivity intermediate between conductors and insulators. According to NCERT, the conductivity of semiconductors can be significantly increased by introducing small amounts of suitable impurities. This controlled addition of impurities is called doping. Doping creates additional charge carriers within the semiconductor crystal. Depending on the impurity added, either electrons or holes become the major charge carriers. This greatly enhances the conductivity of pure silicon. Doped semiconductors are the foundation of modern electronic devices such as transistors, integrated circuits and solar cells. The process is carefully controlled so that the electrical properties of the material can be adjusted according to the desired application. Therefore, the introduction of specific impurities to increase the conductivity of silicon is known as doping.
- �� Option A → Solvation refers to the interaction of solvent molecules with ions.
- �� Option C → Electrolysis involves chemical changes caused by electric current.
- �� Option D → Polymerization is the formation of large molecules from monomers.
Used – NCERT Recall
- Application
- Recall the standard term used for increasing semiconductor conductivity by impurity addition.
- Final Logic
- Impurity addition in semiconductors is called doping.
- Dope the Silicon, Boost the Conduction.
12 Identify the correct statements regarding semiconducting materials.
Statements:
1. Silicon and germanium are examples of semiconductors.
2. Doped silicon exhibits different conductivity than pure silicon.
3. Semiconductors have zero resistivity at 150 K.
4. Gallium arsenide is a semiconductor.
�� Silicon, germanium and gallium arsenide are semiconductors. �� Doping changes conductivity. �� Zero resistivity is not a semiconductor property.
Semiconductors are materials whose conductivity lies between that of conductors and insulators. Common examples include silicon, germanium and gallium arsenide. These materials are extensively used in modern electronics because their conductivity can be controlled. Statement 1 is correct because silicon and germanium are standard semiconductors. Statement 2 is correct because doping introduces additional charge carriers and changes conductivity. Statement 4 is correct because gallium arsenide is an important semiconductor used in high-speed electronic and optoelectronic devices. Statement 3 is incorrect because semiconductors do not possess zero resistivity. Zero resistivity is associated with superconductors under special conditions. Semiconductors retain finite resistance and their conductivity depends on temperature and impurity concentration. Therefore, Statements 1, 2 and 4 are correct.
- �� Option B → Statement 3 is incorrect.
- �� Option C → Statement 3 is false.
- �� Option D → Statement 3 is incorrect and Statements 1 and 2 are omitted.
Used – NCERT Recall
- Application
- Recall examples and characteristics of semiconductors.
- Final Logic
- Statements 1, 2 and 4 are correct; Statement 3 is false.
- Si, Ge and GaAs = Semiconductors.
13 A strong electrolyte like NaCl has a higher conductivity than a weak electrolyte like acetic acid of the same concentration because:
�� Conductivity depends on the number of ions present. �� Strong electrolytes dissociate almost completely. �� More ions produce greater conductivity.
According to NCERT, the conductivity of an electrolytic solution depends strongly on the number of ions present in the solution. Strong electrolytes such as sodium chloride dissociate almost completely into Na⁺ and Cl⁻ ions when dissolved in water. As a result, a large number of charge carriers become available for the conduction of electricity. Weak electrolytes such as acetic acid ionize only partially. Therefore, only a small fraction of the dissolved molecules produce ions. Because the concentration of charge carriers is lower, conductivity is also lower. Since NaCl provides a much greater number of mobile ions than acetic acid at the same concentration, its conductivity is significantly higher. Thus, complete dissociation is the primary reason for the higher conductivity of strong electrolytes.
- �� Option A → Larger ions do not explain the higher conductivity.
- �� Option C → Acetic acid conductivity is not primarily determined by viscosity.
- �� Option D → Acetic acid still allows ionic movement through the ions it produces.
Used – Concept Application
- Application
- Relate conductivity to the extent of ionization.
- Final Logic
- More dissociation produces more ions and greater conductivity.
- Strong Electrolyte = More Ions = More Conductivity.
14 Arrange the following factors in the order they are listed in the text as affecting the conductivity of electrolytic solutions:
1. Nature of the electrolyte added
2. Size of the ions produced and their solvation
3. Nature of the solvent and its viscosity
4. Concentration of the electrolyte
�� Conductivity depends on several factors. �� NCERT presents these factors in a specific sequence. �� The order must be recalled accurately.
According to NCERT, the conductivity of electrolytic solutions depends upon multiple factors. These factors are presented in a particular order while discussing ionic conductance. The sequence begins with the nature of the electrolyte added because different electrolytes produce different numbers and types of ions. The next factor is the size of the ions produced and their degree of solvation, which influence ionic mobility. The third factor is the nature of the solvent and its viscosity, since viscosity affects the ease with which ions move through the solution. Finally, the concentration of the electrolyte influences the total number of ions available for conduction. Thus, the order presented in the text is: Nature of electrolyte → Size and solvation of ions → Nature and viscosity of solvent → Concentration of electrolyte.
- �� Option B → Does not follow the NCERT sequence.
- �� Option C → Begins with solvent factors rather than electrolyte nature.
- �� Option D → Places concentration first, which is incorrect.
Used – NCERT Recall
- Application
- Recall the exact sequence given in NCERT.
- Final Logic
- The listed order is 1 → 2 → 3 → 4.
- Electrolyte → Ions → Solvent → Concentration.
15 The overall process where electrical energy is used to carry out non-spontaneous chemical reactions involving ionic movement is called:
�� Electrical energy drives chemical change. �� Non-spontaneous reactions occur at electrodes. �� The process is known as electrolysis.
Electrolysis is the process in which electrical energy is used to drive a non-spontaneous chemical reaction. In an electrolytic solution, ions move toward oppositely charged electrodes when an electric current is passed through the solution. At the electrodes, oxidation and reduction reactions occur. According to NCERT, electrolysis is a fundamental electrochemical process and is responsible for many industrial applications such as electroplating, extraction of metals and purification of metals. The movement of ions and the accompanying electrode reactions result in chemical changes that would not occur spontaneously under ordinary conditions. Since electrical energy is converted into chemical energy during this process, electrolysis represents a classic example of an electrochemical reaction. Therefore, the correct answer is electrolysis.
- �� Option A → Addition reactions involve combining reactants without electrolysis.
- �� Option B → Substitution is an organic reaction type.
- �� Option D → Condensation reactions eliminate small molecules during product formation.
Used – NCERT Recall
- Application
- Recall the definition of electrolysis.
- Final Logic
- Electrical energy driving a non-spontaneous reaction is electrolysis.
- Electricity + Chemical Change = Electrolysis.
16 Identify the correct statements regarding the solvation effect based on the text.
Statements:
1. Solvation of ions affects the conductivity of electrolytic solutions.
2. Solvation causes metallic conductors to change composition.
3. Solvation provides the energy required for AC current.
4. Solvation is completely independent of the solvent's nature.
�� Solvation influences ionic mobility. �� Conductivity depends on the extent of solvation. �� Solvation depends on the nature of the solvent.
According to NCERT, conductivity of electrolytic solutions depends on several factors including the size of ions produced and their solvation. Solvation refers to the association of solvent molecules with ions present in solution. When ions become highly solvated, their effective size increases and their mobility generally decreases. Statement 1 is correct because solvation directly affects ionic mobility and conductivity. Statement 2 is incorrect because metallic conductors conduct through electrons and their composition remains unchanged during conduction. Statement 3 is incorrect because AC current is supplied by an external electrical source such as an oscillator and not by solvation. Statement 4 is incorrect because solvation strongly depends on the nature of the solvent and the interaction between solvent molecules and ions. Therefore, only Statement 1 is correct.
- �� Option B → Statement 2 is incorrect.
- �� Option C → Statements 3 and 4 are incorrect.
- �� Option D → Statements 2 and 4 are both incorrect.
Used – Concept Application
- Application
- Evaluate each statement using the concept of ion-solvent interaction.
- Final Logic
- Only Statement 1 correctly describes the effect of solvation.
- Solvation Depends on Solvent.
17 Match the following regarding measurement issues.
| List I | List II |
|---|---|
| 1. Direct Current (DC) | c. Changes the composition of an electrolytic solution |
| 2. Alternating Current (AC) | d. Resolves the issue of changing composition |
| 3. Solid conductor | b. Can be connected directly to a Wheatstone bridge |
| 4. Ionic solution | a. Cannot be connected to the bridge like a wire A.1-b, 2-a, 3-d, 4-c |
�� DC causes electrochemical changes. �� AC prevents significant composition change. �� Ionic solutions require special conductivity cells.
NCERT explains that direct current cannot be used conveniently for measuring the resistance of ionic solutions because prolonged passage of DC causes electrochemical reactions. These reactions alter the composition of the solution. To avoid this problem, alternating current is used. AC continuously reverses direction and minimizes net chemical change at the electrodes. Therefore, AC resolves the issue associated with DC measurements. Solid conductors such as metallic wires can be connected directly into a Wheatstone bridge circuit because their composition remains unchanged during current flow. Ionic solutions, however, cannot simply replace a metallic wire and must be placed inside a conductivity cell designed for resistance measurements. Thus, the correct matching is: 1-c, 2-d, 3-b, 4-a.
- �� Option A → Incorrect matching of solid conductors and ionic solutions.
- �� Option B → Incorrectly assigns AC and DC functions.
- �� Option C → Reverses the roles of AC and DC.
Used – NCERT Recall
- Application
- Recall the conductivity measurement setup and limitations of DC.
- Final Logic
- DC changes composition, AC avoids it, solids connect directly, ionic solutions require cells.
- AC Avoids Change.
18 An oscillator used in measuring the resistance of an ionic solution provides AC power in the audio frequency range of:
�� AC is used to avoid polarization effects. �� The oscillator provides audio-frequency current. �� NCERT specifies the frequency range.
When resistance of an ionic solution is measured, direct current is unsuitable because it causes electrolysis and electrode polarization. Therefore, alternating current is used. According to NCERT, an oscillator supplies AC power in the audio-frequency range. The frequency typically used lies between 550 and 5000 cycles per second. At these frequencies, ions continuously reverse their direction of motion, reducing the possibility of chemical changes at the electrodes. This allows accurate measurement of resistance using a Wheatstone bridge arrangement. The oscillator is therefore an essential component of conductivity measurement apparatus. The specified frequency range ensures reliable measurements while minimizing errors arising from polarization effects.
- �� Option A → Lower than the NCERT specified range.
- �� Option C → Much higher than the standard audio-frequency range.
- �� Option D → Far below the required frequency range.
Used – NCERT Recall
- Application
- Recall the frequency range specified for conductivity measurements.
- Final Logic
- NCERT states 550–5000 cycles per second.
- Conductivity Uses Audio Frequency.
19 Platinized platinum electrodes are used in a conductivity cell. What does "platinized" refer to?
�� Platinum electrodes are specially treated. �� A layer of platinum black is deposited. �� This improves conductivity measurements.
NCERT describes the use of platinized platinum electrodes in conductivity cells. Platinization refers to the deposition of a thin layer of finely divided metallic platinum, commonly called platinum black, onto the surface of platinum electrodes through an electrochemical process. The platinum black coating increases the effective surface area of the electrodes and reduces polarization effects during conductivity measurements. This improves the accuracy and reliability of resistance measurements in electrolytic solutions. Platinized electrodes are therefore preferred over smooth platinum surfaces because they provide better contact with the electrolyte and minimize measurement errors. Thus, platinization specifically refers to electrochemical deposition of finely divided metallic platinum.
- �� Option A → Platinization specifically involves platinum black, not merely a simple coating.
- �� Option B → A solid platinum block is not the definition of platinization.
- �� Option D → Gold is not involved in the platinization process.
Used – NCERT Recall
- Application
- Recall the preparation and purpose of platinized electrodes.
- Final Logic
- Platinization means depositing platinum black on platinum electrodes.
- Platinum Black = Platinized Electrode.
20 When balancing the Wheatstone bridge for a conductivity cell with unknown resistance R₂ and known resistances R₁, R₃ and R₄, the unknown resistance is calculated as:
�� Wheatstone bridge is used for resistance measurement. �� Balance condition provides the required equation. �� Unknown resistance is calculated from known resistances.
The Wheatstone bridge is an electrical circuit used to determine an unknown resistance accurately. In a balanced Wheatstone bridge, no current flows through the detector branch. Under this condition, the ratio of resistances in one arm equals the ratio of resistances in the other arm. The balance condition is: Rearranging: This equation allows determination of the unknown resistance of a conductivity cell. Once the resistance is known, conductivity and related parameters can be calculated. The Wheatstone bridge remains one of the most accurate methods for resistance measurement in electrochemical experiments.
- �� Option A → Incorrect rearrangement of the Wheatstone bridge equation.
- �� Option B → Resistance values are not added in the balance equation.
- �� Option C → Multiplication of all resistances does not satisfy bridge balance.
Used – Formula Application
- Application
- Apply the Wheatstone bridge balance condition.
- Final Logic
- Using , we obtain .
- R₂ = R₁R₄ ÷ R₃.
