CUET UG Chemistry Booster Test

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CUET UG Chemistry Booster Test - 2 Nomenclature

⏱️ 30 Minutes

❓ 20 Questions

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CUET UG Chemistry Booster Test - 2 Nomenclature

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QUESTION 1 OF 20

Match List I with List II.

List I	List II
1. Isobutyl alcohol	a. Butan-2-ol
2. sec-Butyl alcohol	b. 2-Methylpropan-2-ol
3. tert-Butyl alcohol	c. Propan-2-ol
4. Isopropyl alcohol	d. 2-Methylpropan-1-ol

Answer Review

1 Match List I with List II.

List I	List II
1. Isobutyl alcohol	a. Butan-2-ol
2. sec-Butyl alcohol	b. 2-Methylpropan-2-ol
3. tert-Butyl alcohol	c. Propan-2-ol
4. Isopropyl alcohol	d. 2-Methylpropan-1-ol

A (1)-d, (2)-a, (3)-b, (4)-c

B (1)-a, (2)-b, (3)-d, (4)-c

C (1)-d, (2)-a, (3)-c, (4)-b

D (1)-b, (2)-c, (3)-a, (4)-d

💡 Short Explanation

�� Common names correspond to specific IUPAC names. �� Butyl alcohols differ in carbon skeleton arrangement. �� Isopropyl alcohol is propan-2-ol.

✅ Correct Answer Explanation

1 → d : Isobutyl alcohol = 2-Methylpropan-1-ol. 2 → a : sec-Butyl alcohol = Butan-2-ol. 3 → b : tert-Butyl alcohol = 2-Methylpropan-2-ol. 4 → c : Isopropyl alcohol = Propan-2-ol. Therefore, option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → Isobutyl alcohol is incorrectly matched.
�� Option C → tert-Butyl alcohol is incorrectly matched.
�� Option D → Multiple common names are mismatched.

🎯 Strategy

Used

Option Grouping

Application:

Match each common alcohol name with its corresponding IUPAC name.

Final Logic:

Iso → 2-Methylpropan-1-ol; sec → Butan-2-ol; tert → 2-Methylpropan-2-ol.

🧠 Memory Trick

Iso-1, Sec-2, Tert-2°

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Common and IUPAC Names of Alcohols

2 Consider the IUPAC rules for naming alcohols:
1. The 'e' of alkane is retained when naming polyhydric alcohols.
2. The 'e' of alkane is dropped when naming monohydric alcohols.
3. The numbering starts from the end nearest to the alkyl branching over the –OH group.
4. Multiplicative prefixes like di, tri are added before 'ol' in polyhydric alcohols.

A (1), (3), (4)

B (1), (2), (4)

C (2), (3), (4)

D (1), (2), (3)

💡 Short Explanation

�� Monohydric and polyhydric alcohols follow different naming conventions. �� Hydroxyl group gets numbering priority. �� Diol and triol are common suffixes.

✅ Correct Answer Explanation

Statement 1 is correct because the terminal "e" is retained in polyhydric alcohol names such as ethane-1,2-diol. Statement 2 is correct because the terminal "e" is dropped in monohydric alcohols such as propane → propanol. Statement 3 is incorrect because numbering begins from the end nearest to the hydroxyl group, not alkyl branching. Statement 4 is correct because prefixes such as di and tri are used in diol and triol nomenclature. Therefore, statements 1, 2 and 4 are correct.

❓ Why Other Options Are Incorrect

�� Option A → Includes statement 3, which is incorrect.
�� Option C → Includes statement 3, which is incorrect.
�� Option D → Includes statement 3, which is incorrect and omits statement 4.

🎯 Strategy

Used

Elimination

Application:

Verify each statement using NCERT nomenclature rules.

Final Logic:

Statements 1, 2 and 4 are correct; statement 3 is incorrect.

🧠 Memory Trick

Mono Drop, Poly Keep

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: IUPAC Nomenclature of Alcohols

3 When identifying the parent hydrocarbon in an ether (R-O-R'), how does the IUPAC system determine which side constitutes the parent chain?

A The side with higher alphabetic priority is the parent chain.

B The side with the smaller alkyl group is the parent chain.

C The side with the larger (R) group is chosen as the parent hydrocarbon.

D Either side can arbitrarily be chosen as the parent chain.

💡 Short Explanation

�� Ethers are named as alkoxyalkanes. �� Larger alkyl group becomes parent. �� Smaller group becomes alkoxy substituent.

✅ Correct Answer Explanation

In IUPAC nomenclature, ethers are named as alkoxy derivatives of alkanes. The larger alkyl group is selected as the parent hydrocarbon, while the smaller group is treated as an alkoxy substituent. Therefore, option C is correct.

❓ Why Other Options Are Incorrect

�� Option A → Alphabetical order does not determine the parent chain.
�� Option B → The smaller group becomes the alkoxy substituent.
�� Option D → Parent chain selection follows specific rules.

🎯 Strategy

Used

Elimination

Application:

Apply alkoxyalkane nomenclature rules.

Final Logic:

Larger alkyl group = Parent chain.

🧠 Memory Trick

Large = Parent

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: IUPAC Nomenclature of Ethers

4 Based on position numbering priority, the correct IUPAC name of the compound CH₃–CH(Cl)–CH₂–CH(OH)–CH₃ is:

A 2-Chloropentan-4-ol

B 4-Chloropentan-2-ol

C 2-Hydroxy-4-chloropentane

D 4-Hydroxy-2-chloropentane

💡 Short Explanation

�� OH group receives numbering priority. �� Numbering starts nearer to the hydroxyl group. �� Chloro substituent receives the remaining locant.

✅ Correct Answer Explanation

The hydroxyl group is the principal functional group and must receive the lowest possible locant. Numbering from the right gives the hydroxyl group position 2 and chlorine position 4. Hence, the correct IUPAC name is 4-Chloropentan-2-ol.

❓ Why Other Options Are Incorrect

�� Option A → Gives OH locant 4 instead of 2.
�� Option C → Alcohol should be named using the suffix "-ol".
�� Option D → Incorrect use of hydroxy as the principal suffix.

🎯 Strategy

Used

Substitution

Application:

Assign the lowest locant to the hydroxyl group.

Final Logic:

OH priority → Pentan-2-ol → Chloro at C-4.

🧠 Memory Trick

OH Gets Lowest Number

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Functional Group Priority

5 Arrange the following naming steps in the correct sequential order for formulating an IUPAC name of a substituted alcohol:
1. Identify the longest carbon chain containing the –OH group.
2. Number the chain starting at the end nearest to the hydroxyl group.
3. Write the substituents in alphabetical order.
4. Identify the positions of the other substituents using numerals.

A (1), (2), (4), (3)

B (2), (1), (3), (4)

C (1), (4), (2), (3)

D (4), (3), (1), (2)

💡 Short Explanation

�� Parent chain is selected first. �� OH gets numbering priority. �� Substituents are assigned locants before writing the final name.

✅ Correct Answer Explanation

The correct sequence is: 1 → Select the longest chain containing OH. 2 → Number the chain from the end nearest OH. 4 → Determine the positions of substituents. 3 → Write substituents alphabetically in the final name. Therefore, option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → Numbering cannot occur before selecting the parent chain.
�� Option C → Substituent positions cannot be assigned before numbering.
�� Option D → Gives the sequence in reverse order.

🎯 Strategy

Used

Option Grouping

Application:

Arrange the naming procedure according to NCERT IUPAC rules.

Final Logic:

Chain → Number → Locants → Name.

🧠 Memory Trick

Chain → Count → Locate → Name

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Steps in IUPAC Nomenclature

6 The correct numerical locants for the methyl substituents in the IUPAC name 2,6-Dimethylphenol are:

A 1, 2

B 2, 6

C 1, 3

D 3, 5

💡 Short Explanation

�� Phenol carbon is numbered as C-1. �� Methyl groups occur at ortho positions. �� Both methyl groups receive locants 2 and 6.

✅ Correct Answer Explanation

In phenol nomenclature, the carbon carrying the hydroxyl group is assigned position 1. The two methyl groups occupy the adjacent carbons on either side, corresponding to positions 2 and 6. Therefore, option B is correct.

❓ Why Other Options Are Incorrect

�� Option A → Includes the hydroxyl-bearing carbon.
�� Option C → Represents meta substitution.
�� Option D → Represents a different substitution pattern.

🎯 Strategy

Used

Substitution

Application:

Assign carbon 1 to the hydroxyl group and number the ring.

Final Logic:

Phenol C-1 → Methyls at C-2 and C-6.

🧠 Memory Trick

OH = 1, Ortho = 2 & 6

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Nomenclature of Substituted Phenols

7 What is the IUPAC name of the compound whose common name is Resorcinol?

A Benzene-1,2-diol

B Phenol-1,3-diol

C Benzene-1,4-diol

D Benzene-1,3-diol

💡 Short Explanation

�� Resorcinol is a dihydric phenol. �� Hydroxyl groups occupy positions 1 and 3. �� It is the meta isomer.

✅ Correct Answer Explanation

Resorcinol contains hydroxyl groups at positions 1 and 3 of the benzene ring. Therefore, its IUPAC name is Benzene-1,3-diol. Hence, option D is correct.

❓ Why Other Options Are Incorrect

�� Option A → Catechol.
�� Option B → Not a valid IUPAC name.
�� Option C → Hydroquinone.

🎯 Strategy

Used

Memory-Based Elimination

Application:

Recall common names of dihydric phenols.

Final Logic:

Resorcinol = 1,3-diol.

🧠 Memory Trick

Res = 3

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Dihydric Phenols

8 Identify the classification type of the compound Propane-1,2,3-triol:

A Monohydric alcohol

B Dihydric alcohol

C Trihydric alcohol

D Symmetrical ether

💡 Short Explanation

�� Contains three hydroxyl groups. �� Commonly known as glycerol. �� Classified based on hydroxyl count.

✅ Correct Answer Explanation

Propane-1,2,3-triol contains three hydroxyl groups attached to a three-carbon chain. Alcohols containing three hydroxyl groups are classified as trihydric alcohols. Therefore, option C is correct.

❓ Why Other Options Are Incorrect

�� Option A → Contains only one OH group.
�� Option B → Contains only two OH groups.
�� Option D → Not an ether.

🎯 Strategy

Used

Odd One Out

Application:

Count the number of hydroxyl groups.

Final Logic:

Three OH groups = Trihydric.

🧠 Memory Trick

Triol = Three OH

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Classification of Alcohols

9 The IUPAC name of a five-membered saturated carbon ring carrying a hydroxyl group at C-1 and a methyl substituent at C-2 is:

A 1-Methylcyclopentan-2-ol

B 2-Methylcyclopentanol

C 2-Methylcyclohexanol

D Cyclopentylmethanol

💡 Short Explanation

�� Parent ring is cyclopentane. �� OH-bearing carbon is C-1. �� Methyl group occupies C-2.

✅ Correct Answer Explanation

In cyclic alcohols, the carbon bearing the hydroxyl group is assigned position 1. The methyl substituent is attached to carbon 2. Therefore, the correct IUPAC name is 2-Methylcyclopentanol.

❓ Why Other Options Are Incorrect

�� Option A → Incorrect numbering convention.
�� Option C → Six-membered ring.
�� Option D → Different structural arrangement.

🎯 Strategy

Used

Substitution

Application:

Assign position 1 to the hydroxyl-bearing carbon.

Final Logic:

Cyclopentanol + methyl at C-2.

🧠 Memory Trick

OH Starts Ring Count

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Cyclic Alcohol Nomenclature

10 For cyclic alcohols with an alkyl substituent (e.g., 2-Methylcyclopentanol):
1. The –OH group is assumed to be attached to C-1.
2. The methyl group determines C-1 due to alphabetical order.
3. The ring is numbered to give the methyl substituent the lowest possible number after the –OH.
4. The prefix 'cyclo' is dropped when substituents are present.

A (1), (3)

B (1), (2)

C (2), (3), (4)

D (1), (4)

💡 Short Explanation

�� OH-bearing carbon is always C-1. �� Substituents are numbered after assigning OH. �� Cyclo prefix remains unchanged.

✅ Correct Answer Explanation

Statement 1 is correct because the hydroxyl-bearing carbon in cyclic alcohols is assigned position 1. Statement 2 is incorrect because alphabetical order does not determine numbering priority. Statement 3 is correct because after assigning OH as C-1, numbering proceeds to give substituents the lowest possible locants. Statement 4 is incorrect because the prefix "cyclo" remains part of the name. Therefore, statements 1 and 3 are correct.

❓ Why Other Options Are Incorrect

�� Option B → Statement 2 is incorrect.
�� Option C → Statements 2 and 4 are incorrect.
�� Option D → Statement 4 is incorrect and statement 3 is omitted.

🎯 Strategy

Used

Elimination

Application:

Apply numbering rules for substituted cyclic alcohols.

Final Logic:

OH = C-1; then minimize substituent locants.

🧠 Memory Trick

OH First, Cyclo Stays

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Numbering of Cyclic Alcohols

11 Match List I with List II.

List I	List II
1. o-Cresol	a. 3-Methylphenol
2. m-Cresol	b. 4-Methylphenol
3. p-Cresol	c. Benzene-1,2-diol
4. Catechol	d. 2-Methylphenol

A (1)-d, (2)-a, (3)-b, (4)-c

B (1)-a, (2)-b, (3)-c, (4)-d

C (1)-d, (2)-b, (3)-a, (4)-c

D (1)-c, (2)-a, (3)-b, (4)-d

💡 Short Explanation

�� Cresols are methyl-substituted phenols. �� Ortho, meta and para indicate relative positions. �� Catechol is a dihydric phenol.

✅ Correct Answer Explanation

1 → d : o-Cresol = 2-Methylphenol. 2 → a : m-Cresol = 3-Methylphenol. 3 → b : p-Cresol = 4-Methylphenol. 4 → c : Catechol = Benzene-1,2-diol. Therefore, option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → o-Cresol and catechol are incorrectly matched.
�� Option C → m-Cresol and p-Cresol are interchanged.
�� Option D → o-Cresol is incorrectly matched with catechol.

🎯 Strategy

Used

Option Grouping

Application:

Match common names with their corresponding IUPAC structures.

Final Logic:

Ortho = 2, Meta = 3, Para = 4, Catechol = 1,2-diol.

🧠 Memory Trick

o-2, m-3, p-4

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Common and IUPAC Names of Phenols

12 Phenol serves as both a common name and an accepted IUPAC name. Why are derivatives of phenol primarily named as derivatives of "phenol" rather than "benzene" in standard IUPAC practice?

A Because phenol acts as the parent hydrocarbon base incorporating the primary functional group.

B Because benzene cannot have substituents attached.

C Because phenol has fewer carbons than benzene.

D Because the term 'benzene' is purely reserved for cyclic alkanes.

💡 Short Explanation

�� The hydroxyl group is the principal functional group. �� Phenol is a retained IUPAC name. �� Substituents are named relative to phenol.

✅ Correct Answer Explanation

Phenol contains the principal functional group (-OH) attached directly to a benzene ring. Therefore, phenol is treated as the parent structure, and derivatives are commonly named as substituted phenols. Hence, option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → Benzene can have substituents attached.
�� Option C → Phenol and benzene contain the same number of carbon atoms.
�� Option D → Benzene is aromatic, not a cyclic alkane.

🎯 Strategy

Used

Elimination

Application:

Identify the role of the principal functional group in nomenclature.

Final Logic:

Principal functional group determines the parent name.

🧠 Memory Trick

OH Makes Phenol Parent

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Nomenclature of Phenols

13 The IUPAC name of the compound commonly known as o-Cresol is:

A 3-Methylphenol

B 4-Methylphenol

C 2-Methylphenol

D 1,2-Dimethylbenzene

💡 Short Explanation

�� Ortho means adjacent positions. �� OH-bearing carbon is carbon 1. �� Methyl group occupies carbon 2.

✅ Correct Answer Explanation

In o-cresol, the methyl group is adjacent to the hydroxyl group. Numbering begins from the hydroxyl-bearing carbon, giving the methyl group position 2. Therefore, the IUPAC name is 2-Methylphenol.

❓ Why Other Options Are Incorrect

�� Option A → Meta isomer.
�� Option B → Para isomer.
�� Option D → Xylene derivative, not a phenol.

🎯 Strategy

Used

Substitution

Application:

Assign position 1 to OH and locate the methyl group.

Final Logic:

Ortho = Position 2.

🧠 Memory Trick

Ortho = 2

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Cresols

14 Analyze the naming of p-Cresol:
1. It contains a methyl group and a hydroxyl group.
2. The methyl group is at position 4 relative to the hydroxyl group.
3. Its IUPAC name is 4-Methylphenol.
4. It is a 1,3-disubstituted benzene derivative.

A (1), (2), (3)

B (1), (2), (4)

C (2), (3), (4)

D (1), (3), (4)

💡 Short Explanation

�� p-Cresol is para-substituted phenol. �� Para corresponds to positions 1 and 4. �� The IUPAC name is 4-Methylphenol.

✅ Correct Answer Explanation

Statement 1 is correct because p-cresol contains both a methyl group and a hydroxyl group. Statement 2 is correct because para substitution corresponds to position 4 relative to the hydroxyl group. Statement 3 is correct because the IUPAC name is 4-Methylphenol. Statement 4 is incorrect because p-cresol is a 1,4-disubstituted benzene derivative, not a 1,3-disubstituted derivative. Therefore, option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → Includes statement 4, which is incorrect.
�� Option C → Includes statement 4 and omits statement 1.
�� Option D → Includes statement 4, which is incorrect.

🎯 Strategy

Used

Elimination

Application:

Verify each statement using para-substitution rules.

Final Logic:

Statements 1, 2 and 3 are correct; statement 4 is incorrect.

🧠 Memory Trick

Para = 1,4

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Cresols and Aromatic Substitution

15 The common name for the ether represented by the formula C₆H₅OCH₂CH₃ is:

A Methyl phenyl ether

B Phenyl ethyl ether

C Benzyl ethyl ether

D Ethyl phenyl ether

💡 Short Explanation

�� The ether contains ethyl and phenyl groups. �� Common names list groups followed by ether. �� It is also known as phenetole.

✅ Correct Answer Explanation

The oxygen atom is bonded to an ethyl group and a phenyl group. In common nomenclature, the two groups are named followed by the word ether. Thus, the compound is called ethyl phenyl ether.

❓ Why Other Options Are Incorrect

�� Option A → Refers to anisole.
�� Option B → Not the NCERT common name format used.
�� Option C → Contains a benzyl group, not a phenyl group.

🎯 Strategy

Used

Substitution

Application:

Identify the groups attached to oxygen.

Final Logic:

Ethyl + Phenyl + Ether.

🧠 Memory Trick

Phenetole = Ethyl Phenyl Ether

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Common Names of Ethers

16 In forming the common name for CH₃–O–C₂H₅, why is it called "ethyl methyl ether" rather than "methyl ethyl ether"?

A Because ethyl has a larger molar mass.

B Because ethyl has more carbon atoms.

C Because the alkyl groups are written as separate words in alphabetical order.

D Because the methyl group is more electronegative.

💡 Short Explanation

�� Common ether names use alphabetical order. �� Both alkyl groups are named separately. �� Ether is written at the end.

✅ Correct Answer Explanation

In common nomenclature, alkyl groups attached to oxygen are written in alphabetical order followed by the word ether. Since ethyl comes before methyl alphabetically, the name becomes ethyl methyl ether.

❓ Why Other Options Are Incorrect

�� Option A → Molecular mass is not the naming criterion.
�� Option B → Carbon count is not the naming criterion.
�� Option D → Electronegativity is irrelevant.

🎯 Strategy

Used

Elimination

Application:

Apply common naming rules for ethers.

Final Logic:

Alphabetical order determines the sequence.

🧠 Memory Trick

ABC → Ether

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Common Nomenclature of Ethers

17 The IUPAC name for CH₃–O–CH₂–CH₂–O–CH₃ is:

A Dimethyl ethylene ether

B 1,2-Dimethoxyethane

C 1,2-Diethoxyethane

D Ethane-1,2-dimethoxide

💡 Short Explanation

�� Ethane is the parent chain. �� Two methoxy groups are present. �� Substituents occur at positions 1 and 2.

✅ Correct Answer Explanation

The parent chain is ethane. Each carbon bears a methoxy substituent. Therefore, the correct IUPAC name is 1,2-Dimethoxyethane.

❓ Why Other Options Are Incorrect

�� Option A → Common-style description, not IUPAC.
�� Option C → Contains ethoxy substituents, not methoxy.
�� Option D → Not a valid IUPAC name.

🎯 Strategy

Used

Substitution

Application:

Select the parent chain and identify alkoxy substituents.

Final Logic:

Ethane + Methoxy at 1 and 2.

🧠 Memory Trick

Two Methoxy = Dimethoxy

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: IUPAC Nomenclature of Ethers

18 Arrange the following groups in ascending order of their priority to be chosen as the parent hydrocarbon chain (smallest to largest):
1. Phenyl (6 carbons)
2. Methyl (1 carbon)
3. Heptyl (7 carbons)
4. Ethyl (2 carbons)

A (2), (4), (1), (3)

B (3), (1), (4), (2)

C (2), (1), (4), (3)

D (4), (2), (3), (1)

💡 Short Explanation

�� Larger carbon frameworks receive parent-chain preference. �� Parent-chain selection generally follows size. �� Heptyl is the largest group given.

✅ Correct Answer Explanation

Carbon counts are: 2 → Methyl = 1 carbon 4 → Ethyl = 2 carbons 1 → Phenyl = 6 carbons 3 → Heptyl = 7 carbons Therefore, the ascending order is: Methyl < Ethyl < Phenyl < Heptyl Hence, option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → Gives the reverse order.
�� Option C → Places phenyl before ethyl incorrectly.
�� Option D → Methyl should be first.

🎯 Strategy

Used

Option Grouping

Application:

Arrange groups according to increasing carbon count.

Final Logic:

1C < 2C < 6C < 7C.

🧠 Memory Trick

M → E → P → H

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Parent Chain Selection in Ether Nomenclature

📄 Passage

In these three types of alcohols, the –OH group is attached to primary, secondary and tertiary carbon atom, respectively. For instance, isobutyl alcohol (2-Methylpropan-1-ol) is a primary alcohol, whereas tert-butyl alcohol (2-Methylpropan-2-ol) is a tertiary alcohol. Ethers are classified as simple or symmetrical, such as diethyl ether (ethoxyethane), and mixed or unsymmetrical, such as ethyl phenyl ether (ethoxybenzene or phenetole).

According to the passage, which of the following is classified strictly as a primary alcohol?

A tert-Butyl alcohol

B Isobutyl alcohol

C Propan-2-ol

D Phenol

💡 Short Explanation

�� Primary alcohols have OH on a primary carbon. �� The passage explicitly identifies isobutyl alcohol. �� tert-Butyl alcohol is tertiary.

✅ Correct Answer Explanation

The passage directly states that isobutyl alcohol (2-Methylpropan-1-ol) is a primary alcohol. Therefore, option B is correct.

❓ Why Other Options Are Incorrect

�� Option A → Tertiary alcohol.
�� Option C → Secondary alcohol.
�� Option D → Phenol, not an alcohol classification of this type.

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

Use the classification explicitly given in the passage.

Final Logic:

Passage identifies isobutyl alcohol as primary.

🧠 Memory Trick

Isobutyl = Primary

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Classification of Alcohols

📄 Passage

Which example is explicitly identified as a mixed or unsymmetrical ether?

A Diethyl ether

B Ethoxyethane

C Ethyl phenyl ether

D 2-Methylpropan-2-ol

💡 Short Explanation

�� Mixed ethers contain different groups. �� The passage explicitly names ethyl phenyl ether. �� Ethyl and phenyl groups are different.

✅ Correct Answer Explanation

The passage states that ethyl phenyl ether (ethoxybenzene or phenetole) is an example of a mixed or unsymmetrical ether because the groups attached to oxygen are different. Therefore, option C is correct.

❓ Why Other Options Are Incorrect

�� Option A → Symmetrical ether.
�� Option B → Another name for diethyl ether, a symmetrical ether.
�� Option D → Tertiary alcohol.

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

Identify the example directly mentioned in the passage.

Final Logic:

Different groups on oxygen = Mixed ether.

🧠 Memory Trick

Ethyl + Phenyl = Mixed

📚 Class XII – NCERT Chemistry Part II – Chapter: Alcohols, Phenols and Ethers – Topic: Classification of Ethers

CUET UG Chemistry Booster Test – 2 Nomenclature

CUET UG Chemistry Booster Test - 2 Nomenclature

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