CUET UG Chemistry Booster Test -2 Carboxylic Acids (Structure, Properties, Reactions & Uses)
📌 Answers are locked once submitted — results and explanations appear at the end.
QUESTION 1 OF 20
Properties of the carboxyl group:
(A) It consists of a carbonyl group attached to a hydroxyl group.
(B) It acts as a starting material for anhydrides, esters, and amides.
(C) The carboxyl carbon is sp³ hybridized.
(D) It can be attached to either an alkyl or an aryl group.
QUESTION 2 OF 20
Which of the following represents the general formula for a simple straight-chain dicarboxylic acid?
QUESTION 3 OF 20
The higher members of aliphatic carboxylic acids, which occur in natural fats, typically contain how many carbon atoms?
QUESTION 4 OF 20
IUPAC name of Ph-CH₂-COOH is:
QUESTION 5 OF 20
The common name "phthalic acid" corresponds to which structural arrangement on a benzene ring?
QUESTION 6 OF 20
Arrange the following carboxylic acids in increasing order of their principal carbon chain length according to IUPAC nomenclature:
(A) Butyric acid
(B) Formic acid
(C) Propionic acid
(D) Acetic acid
QUESTION 7 OF 20
Based on the geometric description in the passage, what is the hybridization state of the carboxyl carbon atom?
QUESTION 8 OF 20
According to the passage, why is the carboxyl carbon less electrophilic than a standard carbonyl carbon?
QUESTION 9 OF 20
Identify reaction type when 1-Decanol is reacted with chromic acid (Jones reagent) to form Decanoic acid.
QUESTION 10 OF 20
Which of the following compounds is an intermediate when preparing a carboxylic acid from a primary alcohol using a mild oxidizing agent?
QUESTION 11 OF 20
Preparation of carboxylic acids from nitriles:
(A) The reaction uses H⁺ or OH⁻ as a catalyst.
(B) The intermediate formed is an amide.
(C) Harsh conditions bypass the amide stage to directly yield amides.
(D) Heating the amide with an acid or base yields the carboxylic acid.
QUESTION 12 OF 20
Identify reaction type taking place when carbon dioxide reacts with a Grignard reagent to form a carboxylate salt.
QUESTION 13 OF 20
Hydrogen bonding in carboxylic acids:
(A) They form more extensive associations than alcohols.
(B) Hydrogen bonds are broken completely in the vapor phase.
(C) They mostly exist as dimers in the vapor phase.
(D) They exist as dimers in aprotic solvents.
QUESTION 14 OF 20
Match List-I (Carboxylic Acid) with List-II (Solubility in cold water):
| List-I | List-II |
|---|---|
| 1. Methanoic acid | a. Miscible in all proportions |
| 2. Pentanoic acid | b. Slightly soluble |
| 3. Benzoic acid | c. Nearly insoluble |
| 4. Stearic acid (C18) | d. Practically insoluble wax-like solid |
QUESTION 15 OF 20
Arrange the following in decreasing order of pKa (weaker acid to stronger acid):
(A) Acetic acid
(B) Trichloroacetic acid
(C) Benzoic acid
(D) Trifluoroacetic acid
QUESTION 16 OF 20
Arrange the following carboxylic acids in increasing order of their acidity:
(A) Chloroacetic acid
(B) Dichloroacetic acid
(C) Trichloroacetic acid
(D) Acetic acid
QUESTION 17 OF 20
During the esterification of a carboxylic acid with an alcohol, what must be done to drive the equilibrium in the forward direction?
QUESTION 18 OF 20
The reagent 'sodalime' used in the decarboxylation of carboxylic acids is a mixture of NaOH and CaO in what ratio?
QUESTION 19 OF 20
Match List-I (Application) with List-II (Carboxylic acid):
| List-I (Application) | List-II (Carboxylic Acid) |
|---|---|
| 1. Nylon-6,6 production | a. Hexanedioic acid |
| 2. Perfumery blending | b. Esters of benzoic acid |
| 3. Rubber and electroplating industries | c. Methanoic acid |
| 4. Soaps and detergents | d. Higher fatty acids |
QUESTION 20 OF 20
Which specific carboxylic acid is primarily used as vinegar in the food industry?
Test Complete!
Answer Review
1 Properties of the carboxyl group:
(A) It consists of a carbonyl group attached to a hydroxyl group.
(B) It acts as a starting material for anhydrides, esters, and amides.
(C) The carboxyl carbon is sp³ hybridized.
(D) It can be attached to either an alkyl or an aryl group.
�� Carboxyl group contains both carbonyl and hydroxyl groups. �� Carboxylic acids are important precursors of several derivatives. �� The carboxyl carbon is sp² hybridized, not sp³.
The carboxyl group (–COOH) is composed of a carbonyl group (C=O) and a hydroxyl group (–OH) attached to the same carbon atom. Carboxylic acids readily form important derivatives such as: Anhydrides Esters Amides The carboxyl group may be attached to: An alkyl group (aliphatic acids) An aryl group (aromatic acids) The carboxyl carbon is sp² hybridized due to resonance and trigonal planar geometry. Therefore, statements A, B and D are correct.
- �� Statement C is incorrect because the carboxyl carbon is sp² hybridized, not sp³ hybridized.
- �� Options B, C and D include the incorrect statement C.
Used
- Statement-based MCQ
- Carboxyl = Carbonyl + Hydroxyl
2 Which of the following represents the general formula for a simple straight-chain dicarboxylic acid?
�� Dicarboxylic acids contain two carboxyl groups. �� Both ends of the chain carry –COOH groups. �� Examples include oxalic acid and adipic acid.
A straight-chain dicarboxylic acid contains two carboxyl groups attached at the ends of a carbon chain. General formula: [ HOOC-(CH_2)_n-COOH ] Examples: Ethanedioic acid (Oxalic acid) Butanedioic acid (Succinic acid) Hexanedioic acid (Adipic acid) Hence option B is correct.
- �� Option A represents a monocarboxylic acid.
- �� Option C represents an aromatic carboxylic acid.
- �� Option D represents an acid anhydride.
Used
- Unit-based MCQ
- Di-carboxylic = Two COOH groups
3 The higher members of aliphatic carboxylic acids, which occur in natural fats, typically contain how many carbon atoms?
�� Higher aliphatic carboxylic acids are called fatty acids. �� They are present in natural fats and oils. �� Most contain 12–18 carbon atoms.
Higher members of aliphatic carboxylic acids are commonly known as fatty acids. Examples: Lauric acid (C12) Palmitic acid (C16) Stearic acid (C18) These acids occur naturally as esters of glycerol in fats and oils. Therefore the typical carbon range is: C12 – C18
- �� Options A and B represent lower acids.
- �� Option D is not the common carbon range found in natural fats.
Used
- Concept MCQ
- Fatty acids = C12 to C18
4 IUPAC name of Ph-CH₂-COOH is:
�� The parent chain contains two carbon atoms. �� The phenyl group is attached to carbon-2. �� Hence the name is 2-Phenylethanoic acid.
Structure: C6H5CH2COOH The principal functional group is –COOH. Parent chain: Ethanoic acid (2 carbon atoms) Substituent: Phenyl group at carbon-2 Therefore the IUPAC name is: 2-Phenylethanoic acid (Common name: Phenylacetic acid)
- �� Option A (Benzoic acid) is C₆H₅COOH.
- �� Option B is the common name, not the IUPAC name.
- �� Option D refers to benzoic acid.
Used
- Naming
- Phenyl + CH₂ + COOH = Phenylacetic acid = 2-Phenylethanoic acid
5 The common name "phthalic acid" corresponds to which structural arrangement on a benzene ring?
�� Phthalic acid contains two adjacent carboxyl groups. �� Adjacent positions correspond to 1,2-substitution. �� It is an ortho-dicarboxylic acid.
Phthalic acid has the structure: C6H4(COOH)2 with the two carboxyl groups located at positions 1 and 2 on the benzene ring. Thus its IUPAC name is: Benzene-1,2-dicarboxylic acid Related compounds: Isophthalic acid → Benzene-1,3-dicarboxylic acid Terephthalic acid → Benzene-1,4-dicarboxylic acid
- �� Option B is isophthalic acid.
- �� Option C is terephthalic acid.
- �� Option D is benzoic acid.
Used
- Concept MCQ
- Phthalic = Ortho = 1,2-dicarboxylic acid
6 Arrange the following carboxylic acids in increasing order of their principal carbon chain length according to IUPAC nomenclature:
(A) Butyric acid
(B) Formic acid
(C) Propionic acid
(D) Acetic acid
�� Formic acid has 1 carbon. �� Acetic acid has 2 carbons. �� Propionic acid has 3 carbons. �� Butyric acid has 4 carbons.
The increasing order of carbon chain length is: Common Name — IUPAC Name — Carbon Atoms Formic acid — Methanoic acid — 1 Acetic acid — Ethanoic acid — 2 Propionic acid — Propanoic acid — 3 Butyric acid — Butanoic acid — 4 Therefore: Formic acid < Acetic acid < Propionic acid < Butyric acid So the correct order is: (B), (D), (C), (A)
- �� Options B, C and D do not follow increasing carbon chain length.
Used
- Ordering
- Formic-1, Acetic-2, Propionic-3, Butyric-4
7 Based on the geometric description in the passage, what is the hybridization state of the carboxyl carbon atom?
�� Bonds lie in one plane. �� Bond angle is about 120°. �� This indicates sp² hybridisation.
The passage states that the bonds to the carboxyl carbon lie in one plane and are separated by about 120°. These features are characteristic of sp² hybridisation and trigonal planar geometry.
- �� Option A: sp³ has tetrahedral geometry and 109.5° bond angle.
- �� Option C: sp has linear geometry and 180° bond angle.
- �� Option D: dsp² is not applicable here.
Used
- Passage-Based MCQ
- 120° + planar = sp²
8 According to the passage, why is the carboxyl carbon less electrophilic than a standard carbonyl carbon?
�� Hydroxyl oxygen donates lone pair by resonance. �� This reduces positive character on carboxyl carbon. �� Hence carboxyl carbon is less electrophilic.
The passage explains that the lone pair of electrons on the hydroxyl oxygen delocalizes toward the carbonyl carbon. This resonance gives partial double bond character to the C–O bond and reduces the electrophilic nature of the carboxyl carbon.
- �� Option A: No halogen is involved.
- �� Option B: Resonance, not steric hindrance, is the main reason.
- �� Option D: Hydrogen bonding affects physical properties, not mainly electrophilicity.
Used
- Passage-Based MCQ
- OH lone pair donation lowers electrophilicity.
9 Identify reaction type when 1-Decanol is reacted with chromic acid (Jones reagent) to form Decanoic acid.
�� 1-Decanol is a primary alcohol. �� Jones reagent is a strong oxidising agent. �� It converts primary alcohols to carboxylic acids.
1-Decanol is a primary alcohol. When treated with chromic acid/Jones reagent, it undergoes strong or vigorous oxidation to form decanoic acid. CH3(CH2)8CH_2OH O CH3(CH2)8COOH
- �� Option A: Mild oxidation usually stops at aldehyde stage.
- �� Option C: No substitution occurs.
- �� Option D: No ester is formed.
Used
- Reaction Type
- Primary alcohol + strong oxidant = Carboxylic acid.
10 Which of the following compounds is an intermediate when preparing a carboxylic acid from a primary alcohol using a mild oxidizing agent?
�� Primary alcohol first oxidises to aldehyde. �� Further oxidation gives carboxylic acid. �� Aldehyde is the intermediate.
The oxidation sequence of a primary alcohol is: Primary alcohol Aldehyde Carboxylic acid Therefore, aldehyde is the intermediate during the conversion of a primary alcohol into a carboxylic acid.
- �� Option A: Ketones form from secondary alcohols.
- �� Option B: Alkane is not an oxidation intermediate.
- �� Option D: Ester is formed by esterification, not direct oxidation.
Used
- Concept MCQ
- 1° alcohol → Aldehyde → Acid
11 Preparation of carboxylic acids from nitriles:
(A) The reaction uses H⁺ or OH⁻ as a catalyst.
(B) The intermediate formed is an amide.
(C) Harsh conditions bypass the amide stage to directly yield amides.
(D) Heating the amide with an acid or base yields the carboxylic acid.
�� Nitriles hydrolyse through an amide intermediate. �� Acidic or basic catalysts are required. �� Further hydrolysis converts the amide into a carboxylic acid.
The hydrolysis of nitriles proceeds in two stages: [ R-CN \rightarrow R-CONH_2 \rightarrow R-COOH ] H⁺ or OH⁻ acts as a catalyst. The first intermediate formed is an amide. Further heating with acid or base converts the amide into the corresponding carboxylic acid. Therefore statements A, B and D are correct.
- �� Statement C is incorrect because the reaction does not bypass the amide stage. The amide is a necessary intermediate.
Used
- Statement-based MCQ
- Nitrile → Amide → Acid
12 Identify reaction type taking place when carbon dioxide reacts with a Grignard reagent to form a carboxylate salt.
�� Grignard reagents behave as nucleophiles. �� Carbon dioxide acts as an electrophile. �� The nucleophile adds to the carbon of CO₂.
Grignard reagents contain a highly nucleophilic carbon atom. RMgX + CO2 RCOO-MgX+ The nucleophilic carbon attacks the electrophilic carbon of carbon dioxide, producing a carboxylate salt. Acidification then yields the corresponding carboxylic acid. Hence the reaction is classified as nucleophilic addition.
- �� Option A: Electrophilic addition is typical of alkenes.
- �� Option C: No free-radical mechanism is involved.
- �� Option D: No elimination occurs.
Used
- Reaction Type
- Grignard attacks CO₂ → Addition → Acid
13 Hydrogen bonding in carboxylic acids:
(A) They form more extensive associations than alcohols.
(B) Hydrogen bonds are broken completely in the vapor phase.
(C) They mostly exist as dimers in the vapor phase.
(D) They exist as dimers in aprotic solvents.
�� Carboxylic acids form strong intermolecular hydrogen bonds. �� They commonly exist as dimers. �� Dimers are observed in vapour phase and non-polar solvents.
Carboxylic acids form two intermolecular hydrogen bonds between two molecules, producing stable cyclic dimers. As a result: They show stronger association than alcohols. They exist largely as dimers in the vapour phase. They also exist as dimers in aprotic solvents such as benzene. Therefore statements A, C and D are correct.
- �� Statement B is incorrect because hydrogen bonding is not completely broken in the vapour phase; dimeric molecules are still observed.
Used
- Statement-based MCQ
- Carboxylic acids travel in pairs (dimers).
14 Match List-I (Carboxylic Acid) with List-II (Solubility in cold water):
| List-I | List-II |
|---|---|
| 1. Methanoic acid | a. Miscible in all proportions |
| 2. Pentanoic acid | b. Slightly soluble |
| 3. Benzoic acid | c. Nearly insoluble |
| 4. Stearic acid (C18) | d. Practically insoluble wax-like solid |
�� Lower acids are highly soluble in water. �� Solubility decreases with increasing hydrocarbon chain length. �� Long-chain fatty acids are practically insoluble.
Carboxylic Acid — Solubility Methanoic acid — Miscible in all proportions Pentanoic acid — Slightly soluble Benzoic acid — Nearly insoluble Stearic acid — Practically insoluble wax-like solid Therefore: 1-a, 2-b, 3-c, 4-d
- �� Options B, C and D contain incorrect solubility matches.
Used
- Match the Following
- Longer carbon chain = Lower water solubility
15 Arrange the following in decreasing order of pKa (weaker acid to stronger acid):
(A) Acetic acid
(B) Trichloroacetic acid
(C) Benzoic acid
(D) Trifluoroacetic acid
�� Higher pKa means weaker acid. �� Electron-withdrawing groups lower pKa and increase acidity. �� CF₃ and CCl₃ strongly increase acidity.
Approximate pKa values: Compound — pKa Acetic acid — 4.76 Benzoic acid — 4.19 Trichloroacetic acid — 0.70 Trifluoroacetic acid — 0.23 Decreasing pKa (weakest acid → strongest acid): [ \text{Acetic acid} > \text{Benzoic acid} > \text{Trichloroacetic acid} > \text{Trifluoroacetic acid} ] Therefore: (A), (C), (B), (D)
- �� Options B, C and D do not follow the correct pKa sequence.
Used
- Ordering
- Stronger EWG → Lower pKa → Stronger Acid
16 Arrange the following carboxylic acids in increasing order of their acidity:
(A) Chloroacetic acid
(B) Dichloroacetic acid
(C) Trichloroacetic acid
(D) Acetic acid
�� Chlorine is an electron-withdrawing group (-I effect). �� More chlorine atoms increase acidity. �� Acetic acid is the least acidic among the given compounds.
The acidity of carboxylic acids depends on the stability of the carboxylate ion formed after loss of H⁺. Chlorine atoms withdraw electron density through the inductive effect (-I effect) and stabilize the negative charge on the carboxylate ion. Acidity increases as the number of chlorine atoms increases: Acetic acid (CH₃COOH) Chloroacetic acid (ClCH₂COOH) Dichloroacetic acid (Cl₂CHCOOH) Trichloroacetic acid (Cl₃CCOOH) Therefore: Acetic acid < Chloroacetic acid < Dichloroacetic acid < Trichloroacetic acid Hence the increasing order of acidity is: (D) → (A) → (B) → (C)
- �� Options B, C and D do not correctly follow the increasing electron-withdrawing effect of chlorine substitution.
Used
- Ordering
- More Cl atoms = Stronger acid
17 During the esterification of a carboxylic acid with an alcohol, what must be done to drive the equilibrium in the forward direction?
�� Esterification is a reversible reaction. �� Removing products shifts equilibrium forward. �� This follows Le Chatelier's principle.
Esterification is represented as: [ RCOOH + R'OH \rightleftharpoons RCOOR' + H_2O ] Since the reaction is reversible, the yield of ester can be increased by: Removing water as it forms, or Distilling out the ester. According to Le Chatelier's principle, removing products shifts equilibrium toward the product side.
- �� Option A: Esterification requires acidic conditions, not alkaline conditions.
- �� Option C: Lower temperature alone does not effectively drive the reaction forward.
- �� Option D: Adding products shifts equilibrium backward.
Used
- Concept MCQ
- Remove Water = More Ester
18 The reagent 'sodalime' used in the decarboxylation of carboxylic acids is a mixture of NaOH and CaO in what ratio?
�� Sodalime is a mixture of NaOH and CaO. �� The usual ratio is 3:1. �� It is used for decarboxylation reactions.
Sodalime is prepared by mixing: Sodium hydroxide (NaOH) Calcium oxide (CaO) in the ratio: [ \text{NaOH : CaO} = 3 : 1 ] It is commonly used to remove carbon dioxide from sodium salts of carboxylic acids, producing hydrocarbons with one less carbon atom.
- �� Options A, B and D do not represent the standard composition of sodalime.
Used
- Concept MCQ
- Sodalime = 3 parts NaOH + 1 part CaO
19 Match List-I (Application) with List-II (Carboxylic acid):
| List-I (Application) | List-II (Carboxylic Acid) |
|---|---|
| 1. Nylon-6,6 production | a. Hexanedioic acid |
| 2. Perfumery blending | b. Esters of benzoic acid |
| 3. Rubber and electroplating industries | c. Methanoic acid |
| 4. Soaps and detergents | d. Higher fatty acids |
�� Hexanedioic acid is used in nylon manufacture. �� Benzoate esters are used in perfumes. �� Methanoic acid is used in rubber and electroplating industries. �� Higher fatty acids are used in soaps.
Application — Carboxylic Acid 1. Nylon-6,6 production — a. Hexanedioic acid 2. Perfumery blending — b. Esters of benzoic acid 3. Rubber and electroplating industries — c. Methanoic acid 4. Soaps and detergents — d. Higher fatty acids Therefore: 1-a, 2-b, 3-c, 4-d
- �� Options B, C and D contain incorrect application matches.
Used
- Match the Following
- Soap → Fatty Acids
20 Which specific carboxylic acid is primarily used as vinegar in the food industry?
�� Vinegar is a dilute aqueous solution of ethanoic acid. �� Ethanoic acid is also called acetic acid. �� It is widely used in food preservation and flavoring.
Vinegar contains about 5–8% ethanoic acid (acetic acid) in water. [ CH_3COOH ] Ethanoic acid gives vinegar its characteristic sour taste and odor and is extensively used in food processing and preservation.
- �� Option A: Propanoic acid is mainly used as a preservative.
- �� Option B: Methanoic acid is used in leather, textile and rubber industries.
- �� Option D: Butanoic acid has an unpleasant rancid odor and is not used as vinegar.
Used
- Concept MCQ
- Vinegar = Acetic Acid = Ethanoic Acid
