CUET UG Categorised PYQ Biology Unit 4
BIOLOGY
📌 Answers are locked once submitted — results and explanations appear at the end.
QUESTION 1 OF 20
QUESTION 2 OF 20
The reason for deviation from Mendel's dihybrid cross in T.H. Morgan's experiment is (PYQ 2022 Shift 1)
QUESTION 3 OF 20
Given below are two statements:
Statement I: Phenylketonuria is an example of Pleiotropy
Statement II: Affected individuals lack an enzyme which converts phenylalanine into tyrosine (PYQ 2022 Shift 1)
QUESTION 4 OF 20
Why was Drosophila melanogaster used for studies in Genetics? (PYQ 2022 Shift 1)
(A) They could be cultured easily in the laboratory
(B) They showed many contrasting traits
(C) The generation time was one year
(D) There was clear differentiation of sexes
(E) Very few progeny were produced in a single mating
QUESTION 5 OF 20
What will be the number of genotypes and phenotypes obtained in F₂ generation when male parent RRYY is crossed with female parent rryy? (PYQ 2023 Shift 1)
QUESTION 6 OF 20
QUESTION 7 OF 20
Match the following: (PYQ 2023 Shift 1)
| List I | List II |
|---|---|
| A. Human skin colour | I. Multiple allelism |
| B. Pair of alleles expressing contrasting traits | II. Polygenic inheritance |
| C. ABO blood group | III. Incomplete dominance |
| D. Antirrhinum flower colour | IV. Heterozygous |
QUESTION 8 OF 20
The genetic disorder caused due to presence of an additional copy of the chromosome number 21 is: (PYQ 2023 Shift 2)
QUESTION 9 OF 20
In a garden pea, the axial flower is dominant to terminal flower. What will be the percentage of offsprings with terminal flowers, when two heterozygous plants are crossed ? (PYQ 2023 Shift 2)
QUESTION 10 OF 20
A classical example of mutation arise due to change in a single base pair of DNA is : (PYQ 2023 Shift 2)
QUESTION 11 OF 20
Colour blindness is a ______. (PYQ 2023 Shift 3)
QUESTION 12 OF 20
The term used for the association of two genes is: (PYQ 2023 Shift 3)
QUESTION 13 OF 20
If a pink flowered snapdragon plant is crossed with a white flowered snapdragon plant. What will be the phenotype of the progeny? (PYQ 2023 Shift 3)
QUESTION 14 OF 20
Which of the following represents a test cross in which half the offspring is heterozygous and half would be homozygous recessive? (PYQ 2024 Shift 1, 2024 Shift 2)
QUESTION 15 OF 20
Which of the following is a recessive trait for garden pea plant ? (PYQ 2024 Shift 1, 2024 Shift 2)
QUESTION 16 OF 20
Which disorder is caused by the substitution of Glutamic acid (Glu) by Valine (Val) at the sixth position of the beta globin chain of the haemoglobin ? (PYQ 2024 Shift 1, 2024 Shift 2)
QUESTION 17 OF 20
When one of the parents has 'A' blood group and the other parent has 'O' blood group, then their child can have ______ blood group. (PYQ 2024 Shift 1)
QUESTION 18 OF 20
Match the following: (PYQ 2025 Shift 1)
| Column A (Character) | Column B (Recessive Trait) |
|---|---|
| A. Flower colour | I. Green |
| B. Seed colour | II. Yellow |
| C. Pod colour | III. Constricted |
| D. Pod shape | IV. White |
QUESTION 19 OF 20
Which of the following disorders are the results of aneuploidy? (PYQ 2025 Shift 1)
QUESTION 20 OF 20
Which one of the following options will express intermediate skin colour in an individual? (PYQ 2025 Shift 1)
Test Complete!
Answer Review
1
Down syndrome is chromosomal. Mendelian disorders involve single genes. Aneuploidy causes Down syndrome.
Down syndrome results from trisomy 21, a chromosomal abnormality caused by nondisjunction. Mendelian disorders arise due to mutations in single genes and follow Mendelian inheritance patterns.
- Option A) Colour blindness → X-linked Mendelian disorder.
- Option C) Haemophilia → X-linked Mendelian disorder.
- Option D) Thalassemia → Autosomal Mendelian disorder.
Used: Odd One Out
- Option A → Mendelian.
- Option B → Chromosomal disorder.
- Option C → Mendelian.
- Option D → Mendelian.
- Final Answer → Down syndrome.
2 The reason for deviation from Mendel's dihybrid cross in T.H. Morgan's experiment is (PYQ 2022 Shift 1)
Morgan observed genes inherited together. Linked genes are located on the same chromosome. This caused deviation from independent assortment.
T.H. Morgan discovered that some genes do not assort independently because they are located on the same chromosome. Such genes are said to be linked. Linkage results in parental combinations appearing more frequently than expected in Mendel's dihybrid ratio.
- Option A) Pleiotropy → One gene affects multiple traits.
- Option C) Overlapping → Not a recognized genetic principle here.
- Option D) Polygenic Inheritance → One trait controlled by multiple genes.
Used: NCERT Recall
- Option A → Different concept.
- Option B → Correct.
- Option C → Incorrect term.
- Option D → Different inheritance pattern.
- Final Answer → Linkage.
3 Given below are two statements:
Statement I: Phenylketonuria is an example of Pleiotropy
Statement II: Affected individuals lack an enzyme which converts phenylalanine into tyrosine (PYQ 2022 Shift 1)
Phenylketonuria is caused by a single gene mutation. One mutation causes multiple effects. Enzyme deficiency blocks phenylalanine metabolism.
Phenylketonuria (PKU) is a classic example of pleiotropy because a mutation in a single gene causes multiple phenotypic effects. The affected person lacks phenylalanine hydroxylase, which normally converts phenylalanine into tyrosine.
- Option B) Both statements are true.
- Option C) Statement II is also correct.
- Option D) Statement I is also correct.
Used: NCERT Recall
- Option A → Correct.
- Option B → Incorrect.
- Option C → Statement II true.
- Option D → Statement I true.
- Final Answer → Option A.
4 Why was Drosophila melanogaster used for studies in Genetics? (PYQ 2022 Shift 1)
(A) They could be cultured easily in the laboratory
(B) They showed many contrasting traits
(C) The generation time was one year
(D) There was clear differentiation of sexes
(E) Very few progeny were produced in a single mating
Easily cultured in laboratories. Sexes are easily distinguishable. Short generation time.
Drosophila melanogaster became a preferred genetic model because it is easy to culture, has distinct male and female forms, a short life cycle and produces many offspring. Statement C is incorrect because generation time is about two weeks, not one year. Statement E is incorrect because a large number of progeny are produced.
- Option A) Does not include easy culturing.
- Option C) Contains incorrect statement C.
- Option D) Contains incorrect statement E.
Used: Elimination
- Option A → Incomplete.
- Option B → Correct.
- Option C → C incorrect.
- Option D → E incorrect.
- Final Answer → Option B.
5 What will be the number of genotypes and phenotypes obtained in F₂ generation when male parent RRYY is crossed with female parent rryy? (PYQ 2023 Shift 1)
Dihybrid cross. F₂ genotype classes = 9. F₂ phenotype classes = 4.
RRYY × rryy produces F₁ RrYy. Selfing F₁ gives a classic Mendelian dihybrid F₂ generation with 9 genotypic combinations and 4 phenotypic classes in a 9:3:3:1 ratio.
- Option A) 16 refers to Punnett square cells, not genotype count.
- Option B) Values reversed.
- Option D) Phenotype count incorrect.
Used: Substitution
- Option A → Confuses combinations with genotypes.
- Option B → Reversed.
- Option C → Correct.
- Option D → Incorrect phenotype count.
- Final Answer → 9 genotypes, 4 phenotypes.
6
Down syndrome is chromosomal. Mendelian disorders involve single genes. Aneuploidy causes Down syndrome.
Down syndrome results from trisomy 21, a chromosomal abnormality caused by nondisjunction. Mendelian disorders arise due to mutations in single genes and follow Mendelian inheritance patterns.
- Option A) Colour blindness → X-linked Mendelian disorder.
- Option C) Haemophilia → X-linked Mendelian disorder.
- Option D) Thalassemia → Autosomal Mendelian disorder.
Used: Odd One Out
- Option A → Mendelian.
- Option B → Chromosomal disorder.
- Option C → Mendelian.
- Option D → Mendelian.
- Final Answer → Down syndrome.
7 Match the following: (PYQ 2023 Shift 1)
| List I | List II |
|---|---|
| A. Human skin colour | I. Multiple allelism |
| B. Pair of alleles expressing contrasting traits | II. Polygenic inheritance |
| C. ABO blood group | III. Incomplete dominance |
| D. Antirrhinum flower colour | IV. Heterozygous |
Human skin colour → Polygenic inheritance. ABO blood group → Multiple allelism. Antirrhinum flower → Incomplete dominance. Contrasting traits are represented by alleles in heterozygous condition.
Human skin colour is controlled by multiple genes and is an example of polygenic inheritance. ABO blood groups are governed by three alleles (IA, IB, i), making it a classic example of multiple allelism. Flower colour in Antirrhinum exhibits incomplete dominance, where heterozygotes show an intermediate phenotype. Contrasting traits are expressed through allelic pairs in heterozygous individuals.
- Option B → Incorrect matching of skin colour and blood group.
- Option C → ABO blood group and heterozygous pair mismatched.
- Option D → Multiple incorrect associations.
Used: Option Grouping
- Option A → All matches correct.
- Option B → Blood group mismatched.
- Option C → Multiple errors.
- Option D → Multiple errors.
- Final Answer → Option A.
8 The genetic disorder caused due to presence of an additional copy of the chromosome number 21 is: (PYQ 2023 Shift 2)
Trisomy 21. One extra chromosome 21. Most common chromosomal disorder.
Down's syndrome occurs due to nondisjunction resulting in an extra copy of chromosome 21 (47 chromosomes). This condition is known as Trisomy 21.
- Option B) XXY condition.
- Option C) XO condition.
- Option D) X-linked Mendelian disorder.
Used: NCERT Recall
- Option A → Trisomy 21.
- Option B → XXY.
- Option C → XO.
- Option D → Gene disorder.
- Final Answer → Down's syndrome.
9 In a garden pea, the axial flower is dominant to terminal flower. What will be the percentage of offsprings with terminal flowers, when two heterozygous plants are crossed ? (PYQ 2023 Shift 2)
Heterozygous cross = Aa × Aa. Terminal flower is recessive. Recessive phenotype appears in 1/4 offspring.
Let axial flower = A (dominant) and terminal flower = a (recessive). Cross: Aa × Aa Genotypic ratio = 1 AA : 2 Aa : 1 aa Terminal flowers appear only in genotype aa. Probability = 1/4 = 25%.
- Option B) Represents 2/4 offspring.
- Option C) Represents dominant phenotype frequency.
- Option D) Recessive phenotype definitely appears.
Used: Substitution
- Option A → Correct Mendelian ratio.
- Option B → Incorrect.
- Option C → Dominant phenotype ratio.
- Option D → Impossible.
- Final Answer → 25%.
10 A classical example of mutation arise due to change in a single base pair of DNA is : (PYQ 2023 Shift 2)
Caused by point mutation. Single nucleotide substitution. Changes glutamic acid to valine.
Sickle cell anaemia is caused by a point mutation in the β-globin gene. A single base substitution changes the codon GAG to GUG, resulting in replacement of glutamic acid by valine. This is the classical example of a mutation involving a single base pair change.
- Option B) Thalassemia → Usually involves deletions or reduced globin synthesis.
- Option C) Colour blindness → X-linked recessive disorder but not the classical point mutation example.
- Option D) Cystic fibrosis → Commonly due to deletion mutation (ΔF508).
Used: NCERT Recall
- Option A → Classic point mutation.
- Option B → Different mutation type.
- Option C → X-linked disorder.
- Option D → Deletion mutation.
- Final Answer → Sickle cell anaemia.
11 Colour blindness is a ______. (PYQ 2023 Shift 3)
Located on X chromosome. Recessive inheritance. More common in males.
Colour blindness is an X-linked recessive disorder. Males express the disorder when they inherit the affected X chromosome because they possess only one X chromosome.
- Option B) Not dominant.
- Option C) Not autosomal.
- Option D) Not autosomal dominant.
Used: NCERT Recall
- Option A → Correct.
- Option B → Incorrect.
- Option C → Incorrect.
- Option D → Incorrect.
- Final Answer → Option A.
12 The term used for the association of two genes is: (PYQ 2023 Shift 3)
Linked genes occur on same chromosome. Tend to be inherited together. Association is called linkage.
Linkage refers to the tendency of genes located on the same chromosome to be inherited together because of their physical association. This concept was established through Morgan's experiments.
- Option A) Recombination separates linked genes.
- Option C) General Mendelian term.
- Option D) Broad biological process.
Used: NCERT Recall
- Option A → Opposite concept.
- Option B → Correct.
- Option C → General term.
- Option D → Broad term.
- Final Answer → Linkage.
13 If a pink flowered snapdragon plant is crossed with a white flowered snapdragon plant. What will be the phenotype of the progeny? (PYQ 2023 Shift 3)
Snapdragon exhibits incomplete dominance. Pink flower is heterozygous (Rr). Pink × White gives pink and white offspring.
In Snapdragon (Antirrhinum), flower colour shows incomplete dominance. Let: Red = RR White = rr Pink = Rr Cross: Rr × rr Offspring: 50% Rr (Pink) 50% rr (White) Hence, the progeny will have pink and white flowers in a 1:1 ratio.
- Option A) Only pink flowered → White-flowered offspring are also produced.
- Option B) Pink, white and red flowered → Red flowers cannot be produced in this cross.
- Option C) Only white flowered → Pink offspring are also formed.
Used: Substitution
- Option A → Incomplete outcome.
- Option B → Impossible genotype produced.
- Option C → Incomplete outcome.
- Option D → Matches Punnett cross.
- Final Answer → Pink and white flowered.
14 Which of the following represents a test cross in which half the offspring is heterozygous and half would be homozygous recessive? (PYQ 2024 Shift 1, 2024 Shift 2)
Test cross involves recessive parent. Heterozygote crossed with recessive. Produces 1:1 ratio.
A test cross is performed by crossing an individual showing dominant phenotype with a homozygous recessive individual. Tt × tt produces: 50% Tt 50% tt offspring.
- Option A → Produces all Tt offspring.
- Option C → Produces 1:2:1 genotypic ratio.
- Option D → Produces all recessive offspring.
Used: Substitution
- Option A → All heterozygous.
- Option B → 1:1 ratio.
- Option C → Mendelian monohybrid ratio.
- Option D → No heterozygotes.
- Final Answer → Substitution of genotypes.
15 Which of the following is a recessive trait for garden pea plant ? (PYQ 2024 Shift 1, 2024 Shift 2)
Mendel studied seven contrasting traits. Inflated pod is dominant. Constricted pod is recessive.
In Mendel's pea plant experiments, pod shape showed complete dominance. Inflated pod shape is dominant whereas constricted pod shape appears only in the homozygous recessive condition.
- Option A → Round seed is dominant over wrinkled seed.
- Option C → Tall plant is dominant over dwarf plant.
- Option D → Violet flower is dominant over white flower.
Used: Elimination
- Option A → Dominant.
- Option B → Recessive.
- Option C → Dominant.
- Option D → Dominant.
- Final Answer → Only constricted pod is recessive.
16 Which disorder is caused by the substitution of Glutamic acid (Glu) by Valine (Val) at the sixth position of the beta globin chain of the haemoglobin ? (PYQ 2024 Shift 1, 2024 Shift 2)
Point mutation disorder. Sixth amino acid altered. Produces abnormal haemoglobin.
Sickle-cell anaemia is caused by replacement of glutamic acid with valine at the sixth position of the β-globin chain. This single base substitution results in abnormal HbS, causing sickle-shaped RBCs.
- Option A → Caused by defective phenylalanine metabolism.
- Option C → Blood clotting disorder.
- Option D → Reduced synthesis of globin chains.
Used: Contextual/Tonal Matching
- Option A → Metabolic disorder.
- Option B → Specific amino acid substitution.
- Option C → Clotting disorder.
- Option D → Quantitative globin defect.
- Final Answer → Sickle-cell anaemia.
17 When one of the parents has 'A' blood group and the other parent has 'O' blood group, then their child can have ______ blood group. (PYQ 2024 Shift 1)
A parent may be IAIA or IAi. O parent is ii. Offspring can be A or O.
If the A-group parent is heterozygous (IAi) and the O-group parent is ii, offspring can be IAi (A group) or ii (O group). Therefore both A and O blood groups are possible.
- Option A → O group may also occur.
- Option B → A group may also occur.
- Option C → Incomplete statement; the standard answer is either A or O.
Used: Substitution
- Option A → Not always true.
- Option B → Not always true.
- Option C → Conceptually similar but incomplete.
- Option D → Correct genetic possibility.
- Final Answer → Option D.
18 Match the following: (PYQ 2025 Shift 1)
| Column A (Character) | Column B (Recessive Trait) |
|---|---|
| A. Flower colour | I. Green |
| B. Seed colour | II. Yellow |
| C. Pod colour | III. Constricted |
| D. Pod shape | IV. White |
White flower is recessive. Green seed is recessive. Yellow pod is recessive. Constricted pod is recessive.
Mendel identified white flower colour as recessive to violet flower colour. Green seed colour is recessive to yellow seed colour. Yellow pod colour is recessive to green pod colour, and constricted pod shape is recessive to inflated pod shape. Hence the correct matching is A-IV, B-I, C-II and D-III.
- Option A) (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
- Flower and seed traits are incorrectly matched.
- Option B) (A) - (I), (B) - (IV), (C) - (II), (D) - (III)
- Flower colour and seed colour pairings are incorrect.
- Option C) (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
- Dominant traits have been wrongly treated as recessive.
Used: NCERT Recall
- Option A → Wrong recessive traits.
- Option B → Incorrect mapping.
- Option D → Matches Mendelian inheritance.
- Final Answer → Based on NCERT recall.
White-Green-Yellow-Constricted = Recessive Set
19 Which of the following disorders are the results of aneuploidy? (PYQ 2025 Shift 1)
Aneuploidy involves chromosome number abnormalities. Down syndrome is trisomy 21. Turner syndrome is monosomy X.
Aneuploidy refers to the gain or loss of one or more chromosomes. Down syndrome occurs due to trisomy of chromosome 21 and Turner syndrome results from monosomy of the X chromosome. Haemophilia and thalassemia are gene disorders caused by mutations and are not examples of aneuploidy.
- B) (A), (B) and (C) only
- Haemophilia and thalassemia are not chromosomal disorders.
- C) (A), (B), (C) and (D)
- Includes gene mutations along with aneuploid conditions.
- D) (A) and (C) only
- Neither haemophilia nor thalassemia results from aneuploidy.
Used: Option Grouping
- Option A → Only aneuploid disorders.
- Option B → Includes gene disorders.
- Option C → Mixed category.
- Final Answer → Based on grouping.
Down = Extra Chromosome, Turner = Missing Chromosome
20 Which one of the following options will express intermediate skin colour in an individual? (PYQ 2025 Shift 1)
Skin colour is polygenic. Intermediate phenotype has balanced alleles. AaBbCc gives medium pigmentation.
Human skin colour is controlled by multiple genes. The intensity of pigmentation depends on the number of dominant alleles present. AaBbCc contains three dominant and three recessive alleles, producing an intermediate skin colour between the darkest and lightest extremes.
- A) AABBCC
- Contains maximum dominant alleles and produces the darkest pigmentation.
- B) aabbcc
- Contains no dominant alleles and produces the lightest pigmentation.
- D) aaBbcc
- Contains only one dominant allele and does not represent an intermediate condition.
Used: Option Grouping
- Option A → Dark extreme.
- Option B → Light extreme.
- Option C → Intermediate genotype.
- Final Answer → Based on polygenic inheritance.
3 Dominant + 3 Recessive = Middle Shade
