CUET UG Physics Booster Test 3-AC Generator Technology -

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CUET UG Physics Booster Test 3-AC Generator Technology

⏱️ 30 Minutes

❓ 20 Questions

📌 Answers are locked once submitted — results and explanations appear at the end.

CUET UG Physics Booster Test 3-AC Generator Technology

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QUESTION 1 OF 20

Identify the correct combination of energy input source and converted energy output in an AC generator.

Answer Review

1 Identify the correct combination of energy input source and converted energy output in an AC generator.

A Mechanical work, Induced alternating electrical energy

B Constant magnetic field, Constant electrical energy

C Chemical energy, Mechanical rotational energy

D Electrical work, Rotational kinetic energy

💡 Short Explanation

�� Generators convert mechanical energy into electrical energy. �� Based on electromagnetic induction. �� Output is alternating electrical energy.

✅ Correct Answer Explanation

An AC generator receives mechanical work from turbines or other rotating systems. This mechanical energy rotates the armature in a magnetic field, causing a change in magnetic flux and inducing alternating EMF. Thus, mechanical work is converted into alternating electrical energy.

❓ Why Other Options Are Incorrect

�� Option B → A constant magnetic field alone cannot continuously generate electrical energy without relative motion.
�� Option C → Describes an engine rather than a generator.
�� Option D → Represents motor action, not generator action.

🎯 Strategy

Used

Contextual Matching

Application: Identify the input-output energy conversion of a generator.

Final Logic: Generator: Mechanical Energy → Electrical Energy.

🧠 Memory Trick

Generator = Motion to Electricity

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Energy Conversion in AC Generator

2 Choose the incorrect statement regarding the progression of electromagnetic induction

A It was initially considered to have no practical utility ("What is the use of a new born baby?")

B Nicola Tesla developed the highly evolved machine we use today

C It led to the AC generator which currently powers modern civilization

D The discovery proved electricity and magnetism are separate and completely unrelated phenomena

💡 Short Explanation

�� Electromagnetic induction links electricity and magnetism. �� AC generators are based on this relationship. �� Tesla advanced AC technology.

✅ Correct Answer Explanation

Electromagnetic induction demonstrates that changing magnetic fields can produce electric currents. This established a direct relationship between electricity and magnetism. Therefore, Option D is incorrect. Options A, B, and C are consistent with the historical development and applications of electromagnetic induction.

❓ Why Other Options Are Incorrect

�� Option A → Historically associated with Faraday's discovery.
�� Option B → Tesla contributed significantly to AC generation technology.
�� Option C → Modern power generation depends on electromagnetic induction.

🎯 Strategy

Used

Elimination

Application: Identify the statement contradicting electromagnetic theory.

Final Logic: Electromagnetic induction proves a connection, not separation.

🧠 Memory Trick

Induction = Electricity + Magnetism

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Historical Importance of Induction

3 In the mechanical geometry of an AC generator
1. The coil is mounted on a rotor shaft to facilitate mechanical rotation.
2. The axis of rotation is strictly perpendicular to the magnetic field direction.
3. The armature's effective area perpendicular to the field is evaluated as A cos θ.
4. The axis of rotation must be exactly parallel to the magnetic field to induce EMF.
Which of the above statements are correct?

A 1, 2, 3

B 2, 3, 4

C 1, 3, 4

D 1, 2, 4

💡 Short Explanation

�� Rotor shaft rotates the coil. �� Effective area = A cos θ. �� Axis is perpendicular to the magnetic field.

✅ Correct Answer Explanation

The rotating armature is mounted on a rotor shaft. The effective area linked with the field is A cos θ. The standard AC generator arrangement requires the axis of rotation to be perpendicular to the magnetic field. Statement 4 is incorrect because parallel alignment would not produce the required flux variation.

❓ Why Other Options Are Incorrect

�� Option B → Includes incorrect statement 4.
�� Option C → Includes incorrect statement 4.
�� Option D → Includes incorrect statement 4.

🎯 Strategy

Used

Elimination

Application: Identify the false statement.

Final Logic: Only statement 4 is incorrect.

🧠 Memory Trick

A cos θ Controls Flux

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Rotating Coil Geometry

4 Match List I with List II

List I	List II
1. Armature (Coil)	a. Experiences changing magnetic flux
2. Rotor Shaft	b. Provides mechanical axis of rotation
3. Slip rings and brushes	c. Connects the rotating ends to output
4. External circuit	d. Consumes the alternating current

A a-1, b-2, c-3, d-4

B a-2, b-1, c-4, d-3

C a-3, b-4, c-1, d-2

D a-4, b-3, c-2, d-1

💡 Short Explanation

�� Armature experiences flux change. �� Rotor shaft provides rotation. �� Brushes transfer current.

✅ Correct Answer Explanation

The correct matching is: Armature → Experiences changing magnetic flux Rotor Shaft → Provides mechanical axis of rotation Slip rings and brushes → Connect rotating coil to output External circuit → Consumes alternating current Hence Option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → Rotor shaft and armature roles are interchanged.
�� Option C → Multiple incorrect assignments.
�� Option D → All major roles are mismatched.

🎯 Strategy

Used

Option Grouping

Application: Match each component with its function.

Final Logic: Each generator component has a unique role.

🧠 Memory Trick

Coil–Flux, Shaft–Spin, Brushes–Output

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Generator Components

5 A circular coil of radius 10 cm and 500 turns is rotated in a uniform magnetic field. If it rotates at 0.5 Hz and generates a peak voltage of 3.14 V, the magnitude of the magnetic field B is approximately (using π = 3.14)

A 0.031 T

B 0.126 T

C 0.063 T

D 0.630 T

💡 Short Explanation

�� Use ε₀ = NBAω. �� A = πr². �� Solve for B.

✅ Correct Answer Explanation

Given: r = 0.1 m A = πr² = 3.14 × (0.1)² = 0.0314 m² ω = 2πν = 3.14 rad/s Using: ε₀ = NBAω 3.14 = 500 × B × 0.0314 × 3.14 B ≈ 0.0637 T ≈ 0.063 T Hence Option C is correct.

❓ Why Other Options Are Incorrect

�� Option B → Approximately twice the correct value.
�� Option A → Approximately half the correct value.
�� Option D → Ten times larger than the correct value.

🎯 Strategy

Used

Substitution

Application: Substitute values into ε₀ = NBAω.

Final Logic: Solving gives B ≈ 0.063 T.

🧠 Memory Trick

Peak EMF = NBAω

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Peak EMF Calculations

6 Consider the following statements regarding the periodic flux variation ΦB = BA cos ωt:
1. The flux is maximum when the coil plane is perpendicular to the magnetic field.
2. The flux is zero when the coil plane is parallel to the magnetic field.
3. The rate of change of flux is maximum when the flux itself is zero.
4. The rate of change of flux is maximum when the flux itself is maximum.
Which of the above statements are correct?

A 1, 2, 4

B 1, 2, 3

C 2, 3, 4

D 1, 3, 4

💡 Short Explanation

�� Flux = BA cos θ. �� Maximum flux occurs at θ = 0°. �� Maximum dΦ/dt occurs at Φ = 0.

✅ Correct Answer Explanation

When the coil plane is perpendicular to the magnetic field, the area vector is parallel to the field and flux is maximum. When the coil plane is parallel to the magnetic field, flux becomes zero. The induced EMF depends on dΦ/dt, which becomes maximum when Φ passes through zero. Statement 4 is therefore incorrect.

❓ Why Other Options Are Incorrect

�� Option A → Includes incorrect statement 4.
�� Option C → Includes incorrect statement 4.
�� Option D → Includes incorrect statement 4.

🎯 Strategy

Used

Elimination

Application: Identify the incorrect statement.

Final Logic: Maximum flux and maximum rate of flux change occur at different positions.

🧠 Memory Trick

Max Flux ≠ Max EMF

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Flux Variation in AC Generator

7 The mathematical derivative relationship governing the instantaneous EMF equation:

A is derived directly from Lenz's law without calculating any flux change

B stems from integrating the constant magnetic field over the volume of the coil

C stems from differentiating ΦB = BA cos ωt with respect to time and applying Faraday's law

D proves that EMF is completely independent of the rotational speed

💡 Short Explanation

�� Faraday's law uses dΦ/dt. �� Flux expression is differentiated. �� Results in sinusoidal EMF.

✅ Correct Answer Explanation

Starting from: ΦB = BA cos ωt Faraday's law gives: ε = −N(dΦB/dt) Differentiation leads to: ε = NBAω sin ωt Thus Option C correctly describes the derivation.

❓ Why Other Options Are Incorrect

�� Option B → Volume integration is not used.
�� Option A → Lenz's law provides direction, not the complete derivation.
�� Option D → EMF is directly proportional to ω.

🎯 Strategy

Used

Formula Recall

Application: Follow the mathematical derivation.

Final Logic: Differentiate flux and apply Faraday's law.

🧠 Memory Trick

Flux → Derivative → EMF

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Derivation of AC EMF Equation

8 Match the phase angle ωt with the corresponding state of the generator

List I	List II
1. ωt = 0	a. ε = 0, ΦB = +BA
2. ωt = π/2	b. ε = +NBAω, ΦB = 0
3. ωt = π	c. ε = 0, ΦB = −BA
4. ωt = 3π/2	d. ε = −NBAω, ΦB = 0

A a-1, b-2, c-3, d-4

B a-2, b-1, c-4, d-3

C a-3, b-4, c-1, d-2

D a-4, b-3, c-2, d-1

💡 Short Explanation

�� Flux follows cosine. �� EMF follows sine. �� Flux and EMF are 90° out of phase.

✅ Correct Answer Explanation

At: ωt = 0 → Φ = +BA, ε = 0 ωt = π/2 → Φ = 0, ε = +NBAω ωt = π → Φ = −BA, ε = 0 ωt = 3π/2 → Φ = 0, ε = −NBAω This exactly matches Option A.

❓ Why Other Options Are Incorrect

�� Option B → Incorrect phase assignments.
�� Option C → Flux and EMF states mismatched.
�� Option D → Multiple phase errors.

🎯 Strategy

Used

Option Grouping

Application: Use flux and EMF phase relationships.

Final Logic: Standard sine-cosine phase pattern gives Option A.

🧠 Memory Trick

Cos for Flux, Sin for EMF

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Phase Relationship Between Flux and EMF

9 In the formula ε₀ = NBAω, if the area A is doubled and the angular speed ω is halved while keeping turns N and field B constant, the new maximum EMF will be

A 0.5ε₀

B 2ε₀

C ε₀

D 4ε₀

💡 Short Explanation

�� ε₀ ∝ Aω. �� Area doubles. �� Angular speed halves.

✅ Correct Answer Explanation

New EMF: ε' = NB(2A)(ω/2) ε' = NBAω ε' = ε₀ Therefore, the maximum EMF remains unchanged.

❓ Why Other Options Are Incorrect

�� Option B → Requires doubling without halving ω.
�� Option A → Only ω halved.
�� Option D → Requires both A and ω to increase.

🎯 Strategy

Used

Substitution

Application: Replace A and ω in ε₀ = NBAω.

Final Logic: ×2 and ÷2 cancel exactly.

🧠 Memory Trick

Double A, Half ω → Same EMF

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Dependence of Peak EMF

10 Choose the incorrect statement regarding the dynamic conditions for peak voltage

A Peak voltage occurs when the angle θ is 0° or 180°

B Peak voltage occurs when sin ωt = ±1

C Peak voltage corresponds to the points where the change of flux is greatest

D Peak voltage occurs when the effective area perpendicular to the field is changing most rapidly

💡 Short Explanation

�� Peak EMF depends on maximum rate of flux change. �� At θ = 0° and 180°, flux is maximum. �� EMF is zero at these positions.

✅ Correct Answer Explanation

The induced EMF is: ε = ε₀ sin ωt Peak voltage occurs when: sin ωt = ±1 which corresponds to θ = 90° or 270°. At these positions, the rate of change of magnetic flux is maximum. Therefore, Option A is incorrect because θ = 0° and 180° correspond to maximum flux, not maximum EMF.

❓ Why Other Options Are Incorrect

�� Option B → Correct condition for maximum EMF.
�� Option C → EMF is maximum when dΦ/dt is maximum.
�� Option D → Rapid change in effective area produces maximum EMF.

🎯 Strategy

Used

Elimination

Application: Distinguish maximum flux from maximum EMF.

Final Logic: Maximum EMF occurs at maximum flux change, not maximum flux.

🧠 Memory Trick

Max Flux → Zero EMF

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Conditions for Maximum EMF

11 Which of the following correctly matches a variable with its physical representation in AC generation?

A θ, Time derivative of magnetic field

B ν, Peak voltage amplitude

C ε₀, Frequency of revolution

D ω, Angular speed in rad/s

💡 Short Explanation

�� ω denotes angular speed. �� Measured in rad/s. �� Used in AC generator equations.

✅ Correct Answer Explanation

In rotational motion and AC generation: ω = angular speed (rad/s) The remaining variables represent different physical quantities: ν = frequency ε₀ = peak EMF θ = angular displacement Thus Option D is correct.

❓ Why Other Options Are Incorrect

�� Option B → ν represents frequency, not voltage amplitude.
�� Option C → ε₀ is peak EMF.
�� Option A → θ is angular position, not a derivative.

🎯 Strategy

Used

Formula Recall

Application: Recall standard variable definitions.

Final Logic: ω universally denotes angular speed.

🧠 Memory Trick

ω → Angular Velocity

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Symbols and Physical Quantities

12 Consider the following statements regarding angular speed and global AC frequency standards:
1. The equation ω = 2πν links mechanical speed to electrical frequency.
2. At 50 Hz, the angular speed ω is exactly 100π rad/s.
3. At 60 Hz, the angular speed ω is exactly 120π rad/s.
4. Frequency ν has no impact on the maximum value of the generated voltage.
Which of the above statements are correct?

A 1, 2, 3

B 2, 3, 4

C 1, 3, 4

D 1, 2, 4

💡 Short Explanation

�� ω = 2πν. �� For 50 Hz, ω = 100π rad/s. �� For 60 Hz, ω = 120π rad/s.

✅ Correct Answer Explanation

Using: ω = 2πν For 50 Hz: ω = 2π × 50 = 100π rad/s For 60 Hz: ω = 2π × 60 = 120π rad/s Also: ε₀ = NBAω Therefore, frequency affects peak voltage through ω. Hence statement 4 is incorrect.

❓ Why Other Options Are Incorrect

�� Option B → Includes incorrect statement 4.
�� Option C → Includes incorrect statement 4.
�� Option D → Includes incorrect statement 4.

🎯 Strategy

Used

Substitution

Application: Apply ω = 2πν and ε₀ = NBAω.

Final Logic: Statements 1, 2 and 3 are correct; statement 4 is false.

🧠 Memory Trick

50 Hz → 100π ; 60 Hz → 120π

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Angular Speed and Frequency

13 In terms of energy transformation, a hydro-electric generator fundamentally

A utilizes high-pressure steam from nuclear reactions to turn the armature

B converts the gravitational potential energy of water into kinetic energy, then into alternating electrical energy

C ignores the principle of electromagnetic induction entirely

D requires slip rings to convert water flow directly into static charges

💡 Short Explanation

�� Water stored at height possesses potential energy. �� Falling water rotates turbines. �� Generator produces AC electricity.

✅ Correct Answer Explanation

Hydroelectric power plants convert gravitational potential energy of stored water into kinetic energy. This kinetic energy rotates turbines connected to generators. The generator then converts mechanical energy into alternating electrical energy through electromagnetic induction.

❓ Why Other Options Are Incorrect

�� Option A → Describes nuclear power plants.
�� Option C → Hydroelectric generators depend on induction.
�� Option D → Water flow does not directly create static charges.

🎯 Strategy

Used

Energy Pathway Analysis

Application: Trace the sequence of energy transformations.

Final Logic: Potential → Kinetic → Mechanical → Electrical.

🧠 Memory Trick

Dam → Turbine → Electricity

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Hydroelectric Power Generation

14 Match List I with List II

List I	List II
1. Coal combustion	a. Source for thermal generators
2. Nuclear fission	b. Source for nuclear generators
3. Shared medium	c. Steam
4. Required property of medium	d. High pressure

A a-1, b-2, c-3, d-4

B a-2, b-1, c-4, d-3

C a-3, b-4, c-1, d-2

D a-4, b-3, c-2, d-1

💡 Short Explanation

�� Coal drives thermal plants. �� Nuclear fuel drives nuclear plants. �� Steam rotates turbines. �� High pressure is required.

✅ Correct Answer Explanation

The correct matching is: Coal combustion → Source for thermal generators Nuclear fission → Source for nuclear generators Shared medium → Steam Required property → High pressure Therefore Option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → Thermal and nuclear sources are interchanged.
�� Option C → Incorrect assignment of steam and fuel sources.
�� Option D → Multiple mismatches.

🎯 Strategy

Used

Option Grouping

Application: Follow the steam-generation pathway.

Final Logic: Fuel → Steam → Turbine → Generator.

🧠 Memory Trick

Coal/Nuclear → Steam → Power

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Thermal and Nuclear Power Generation

15 A commercial generator outputs exactly 100 MW. If it is upgraded to handle an output of 500 MW without changing the 10 kV peak voltage, the peak current output will change from 10,000 A to

A 50,000 A

B 25,000 A

C 100,000 A

D 5,000 A

💡 Short Explanation

�� Use P = VI. �� Voltage remains constant. �� Current scales with power.

✅ Correct Answer Explanation

Given: P = VI Initial: 100 MW ÷ 10 kV = 10,000 A New power: 500 MW ÷ 10 kV = 50,000 A Hence Option A is correct.

❓ Why Other Options Are Incorrect

�� Option B → Half of the required increase.
�� Option C → Twice the correct value.
�� Option D → Current should increase, not decrease.

🎯 Strategy

Used

Substitution

Application: Apply P = VI.

Final Logic: Fivefold increase in power gives fivefold increase in current.

🧠 Memory Trick

Same Voltage → Current ∝ Power

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Generator Output Calculations

16 Choose the incorrect statement regarding the design choices in high-power commercial generators

A Stationary coils allow for easier extraction of massive currents without complex slip ring breakdown

B They hold the coils stationary and rotate the electromagnets to induce EMF

C The relative motion between the coils and electromagnets induces the EMF

D They rotate both the coils and the electromagnets in opposite directions simultaneously

💡 Short Explanation

�� Commercial generators keep armature stationary. �� Electromagnets rotate. �� Large currents are easier to collect.

✅ Correct Answer Explanation

Large commercial generators generally use stationary armature coils and rotating electromagnets. This design allows efficient extraction of very large currents while avoiding heavy-duty rotating current collectors. Therefore, Option D is the incorrect statement.

❓ Why Other Options Are Incorrect

�� Option B → Correct commercial design.
�� Option C → Relative motion is the basis of induction.
�� Option A → A major advantage of stationary armatures.

🎯 Strategy

Used

Elimination

Application: Compare practical commercial generator design with simple generator design.

Final Logic: Rotating both coils and electromagnets is not the standard design.

🧠 Memory Trick

Big Generator = Fixed Coil

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Commercial Generator Design

17 The fundamental reason the EMF reaches zero when θ = 0° or 180°

A is because the rate of change of flux is zero at the moment the flux itself is maximized

B is because the magnetic field naturally switches its north and south poles independent of the generator

C is because the slip rings mechanically disconnect the circuit at those exact angles

D is because Lenz's law forbids direct current from existing in any closed loop

💡 Short Explanation

�� EMF depends on dΦ/dt. �� Flux is maximum at θ = 0° and 180°. �� Rate of change becomes zero.

✅ Correct Answer Explanation

Induced EMF is proportional to the rate of change of magnetic flux. At θ = 0° or 180°: Φ = ±BA (maximum magnitude) Since flux is at an extreme value, dΦ/dt = 0, and therefore EMF becomes zero.

❓ Why Other Options Are Incorrect

�� Option B → Magnetic poles do not switch automatically.
�� Option C → Slip rings remain connected continuously.
�� Option D → Lenz's law does not prohibit DC.

🎯 Strategy

Used

Conceptual Analysis

Application: Distinguish between flux and flux change.

Final Logic: EMF is determined by dΦ/dt, not Φ itself.

🧠 Memory Trick

Extreme Flux → Zero EMF

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Flux and EMF Relationship

18 Question: Consider the following statements about the mathematical drivers of current reversal in an AC generator:
1. The fundamental driver is the derivative of cos ωt, which is −ω sin ωt.
2. The periodic varying of the sine function between +1 and −1 reverses the polarity.
3. This alternating polarity drives the current in opposite directions periodically.
4. The reversal mechanism requires constant manual switching by external brushes.
Which of the above statements are correct?

A 1, 2, 3

B 2, 3, 4

C 1, 3, 4

D 1, 2, 4

💡 Short Explanation

�� EMF arises from derivative of flux. �� Sine function changes sign. �� Current reverses automatically.

✅ Correct Answer Explanation

Flux varies as: Φ = BA cos ωt Differentiation gives: ε = NBAω sin ωt Because the sine function alternates between positive and negative values, the polarity of EMF reverses periodically. This naturally causes alternating current. Statement 4 is incorrect because brushes do not manually switch current direction.

❓ Why Other Options Are Incorrect

�� Option B → Includes incorrect statement 4.
�� Option C → Includes incorrect statement 4.
�� Option D → Includes incorrect statement 4.

🎯 Strategy

Used

Elimination

Application: Identify the false statement.

Final Logic: Current reversal is a mathematical consequence of sinusoidal EMF.

🧠 Memory Trick

Sin Changes Sign → AC

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Origin of Alternating Current

19 Industrial capability metric, Standard output:

A Nuclear generator requirement, 100 W

B Early Faraday prototype, 500 MW

C Highly evolved modern machine, 100 MW

D Hydro-electric dam, 100 V strictly DC

💡 Short Explanation

�� Commercial generators operate in MW range. �� Modern generators can produce enormous power. �� 100 MW is a realistic industrial value.

✅ Correct Answer Explanation

Modern large-scale generators commonly operate in the megawatt range. Outputs around 100 MW are realistic for industrial and utility applications. The remaining options are either historically incorrect or physically unrealistic.

❓ Why Other Options Are Incorrect

�� Option B → Faraday's early devices were not MW-scale machines.
�� Option A → 100 W is far too small for nuclear power generation.
�� Option D → Hydroelectric plants generate AC, not strictly DC.

🎯 Strategy

Used

Scale Analysis

Application: Compare realistic power-generation magnitudes.

Final Logic: Industrial generators operate in megawatts.

🧠 Memory Trick

Industry = MW Scale

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Commercial Generator Capacity

20 If a student is asked what the practical utility of electromagnetic induction is, the most complete answer drawn directly from its history is that

A it proved that only static magnetic fields can do mechanical work in physics labs

B it led directly to the development of modern day generators and transformers, to which today's civilization owes its progress

C it merely explained the northern lights without any technological application

D it demonstrated that permanent magnets lose their magnetism when rotated rapidly

💡 Short Explanation

�� Electromagnetic induction enables electricity generation. �� Transformers also depend on induction. �� Modern civilization relies on electrical power systems.

✅ Correct Answer Explanation

Faraday and Henry's discovery of electromagnetic induction led directly to the development of generators and transformers. These devices form the foundation of modern electricity generation, transmission, and distribution systems. Therefore, Option B is the most complete and historically accurate statement.

❓ Why Other Options Are Incorrect

�� Option A → Static magnetic fields do not produce induction.
�� Option C → Induction has enormous technological applications.
�� Option D → Rotating magnets do not inherently lose magnetism.

🎯 Strategy

Used

Contextual/Tonal Matching

Application: Identify the statement reflecting the true historical impact of induction.

Final Logic: Modern electrical civilization depends on generators and transformers.

🧠 Memory Trick

Induction → Generator + Transformer

📚 Class XII – Physics Part I – Chapter: Electromagnetic Induction – Topic: Applications and Importance of Electromagnetic Induction

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