UNIT 1 - BIOLOGY CATEGORISED- PYQ
BIOLOGY
π Answers are locked once submitted β results and explanations appear at the end.
QUESTION 1 OF 27
Types of cells in 2 celled pollen grains are ______. (PYQ 2022 Shift 1)
QUESTION 2 OF 27
What will be the number of chromosomes in the gamete of maize if its meiocyte contains 20 chromosomes? (PYQ 2023 Shift 1)
QUESTION 3 OF 27
Which layer of microsporangium nourishes the developing pollen grains? (PYQ 2023 Shift 1)
QUESTION 4 OF 27
Match the following: (PYQ 2023 Shift 1)
| List I | List II |
|---|---|
| A. Albuminous seed | I. Groundnut |
| B. Parthenocarpic fruit | II. Apple |
| C. Non-albuminous seed | III. Castor |
| D. False fruit | IV. Banana |
QUESTION 5 OF 27
Maximum number of male gametes produced from one pollen mother cell (microspore mother cell) will be : (PYQ 2023 Shift 2)
QUESTION 6 OF 27
QUESTION 7 OF 27
QUESTION 8 OF 27
QUESTION 9 OF 27
QUESTION 10 OF 27
QUESTION 11 OF 27
In artificial hybridisation bagging is done to: (PYQ 2023 Shift 3)
QUESTION 12 OF 27
Match List I with List II (PYQ 2023 Shift 3)
| List I | List II |
|---|---|
| A. Attaches ovule to the placenta | I. Hilum |
| B. Region where ovule fuses with its stalk | II. Chalaza |
| C. Place where integuments are not present | III. Funicle |
| D. Basal part of ovule | IV. Micropyle |
QUESTION 13 OF 27
Observe the given diagram and answer the questions given below:
Question: The method of embryo sac formation from a single megaspore is termed ______ development. (PYQ 2023 Shift 3)
QUESTION 14 OF 27
Observe the given diagram and answer the questions given below:
Question: Identify the correct statements with respect to female gametophyte. (PYQ 2023 Shift 3)
Choose the correct answer from the options given below:
QUESTION 15 OF 27
Observe the given diagram and answer the questions given below:
Question: Match the following: (PYQ 2023 Shift 3)
| List I | List II |
|---|---|
| A. Nucellus | I. G |
| B. Megaspore dyad | II. B |
| C. Micropylar end | III. D |
| D. Megaspore mother cell | IV. C |
QUESTION 16 OF 27
Observe the given diagram and answer the questions given below:
Question: Which part of the ovule differentiates a large cell with dense cytoplasm and a prominent nucleus during megasporogenesis? (PYQ 2023 Shift 3)
QUESTION 17 OF 27
Observe the given diagram and answer the questions given below:
Question: How many mitotic divisions occur in the nucleus of the functional megaspore to form embryo sac? (PYQ 2023 Shift 3)
QUESTION 18 OF 27
In a velvet grass seed, the cotyledon is called : (PYQ 2024 Shift 1, 2024 Shift 2)
QUESTION 19 OF 27
Which one of the following is not associated with megasporangium ? (PYQ 2024 Shift 1)
QUESTION 20 OF 27
In diploid organisms, which of the following undergoes meiosis? (PYQ 2024 Shift 1)
QUESTION 21 OF 27
Which one of the following guides the entry of the pollen tube into the embryo sac? (PYQ 2025 Shift 1)
QUESTION 22 OF 27
Which one of the following is opposite part of micropylar end of ovule? (PYQ 2025 Shift 1)
QUESTION 23 OF 27
Question:
With reference to reproduction in flowering plants, which one of the following is incorrect? (PYQ 2025 Shift 1)
QUESTION 24 OF 27
Question:
Which of the following is not a stage of growing embryo in dicotyledon plants? (PYQ 2025 Shift 1)
QUESTION 25 OF 27
Question:
The coconut water from tender coconut, a good source of nutrition is nothing but: (PYQ 2025 Shift 1)
QUESTION 26 OF 27
Question:
Formation of diploid zygote is a result of: (PYQ 2025 Shift 1)
QUESTION 27 OF 27
Question:
If there are 38 chromosomes in the zygote, how many chromosomes will be there in its haploid egg cell? (PYQ 2025 Shift 1)
Test Complete!
Answer Review
1 Types of cells in 2 celled pollen grains are ______. (PYQ 2022 Shift 1)
οΏ½οΏ½ Mature pollen grain usually has two cells. οΏ½οΏ½ Vegetative cell forms pollen tube. οΏ½οΏ½ Generative cell forms male gametes.
At shedding, most angiosperm pollen grains are two-celled. They contain a large vegetative cell and a smaller generative cell. The generative cell later divides to produce two male gametes.
- Option A) Components of embryo sac.
- Option B) Female reproductive structures.
- Option C) Not pollen cell types.
Used: NCERT Recall
- οΏ½οΏ½ Option A β Embryo sac.
- οΏ½οΏ½ Option B β Female structures.
- οΏ½οΏ½ Option C β Incorrect terms.
- οΏ½οΏ½ Option D β Correct.
- οΏ½οΏ½ Final Answer β Vegetative and Generative.
2 What will be the number of chromosomes in the gamete of maize if its meiocyte contains 20 chromosomes? (PYQ 2023 Shift 1)
οΏ½οΏ½ Meiocyte is diploid (2n). οΏ½οΏ½ Gametes are haploid (n). οΏ½οΏ½ Meiosis reduces chromosome number by half.
Meiocytes undergo meiosis to produce gametes. During meiosis, the chromosome number is reduced from diploid (2n) to haploid (n). Since the meiocyte of maize contains 20 chromosomes (2n = 20), the resulting gametes will contain 10 chromosomes (n = 10).
- Option B) 20 β Represents diploid chromosome number, not gametic number.
- Option C) 24 β Not related to chromosome reduction from 20.
- Option D) 40 β Chromosome number cannot double during gamete formation.
Used: Dimensional/Unit Analysis
- οΏ½οΏ½ Option A β Half of diploid number.
- οΏ½οΏ½ Option B β Original diploid count.
- οΏ½οΏ½ Option C β Arbitrary value.
- οΏ½οΏ½ Option D β Opposite of meiosis outcome.
- οΏ½οΏ½ Final Answer β Meiosis halves chromosome number.
3 Which layer of microsporangium nourishes the developing pollen grains? (PYQ 2023 Shift 1)
οΏ½οΏ½ Innermost wall layer. οΏ½οΏ½ Rich in nutrients. οΏ½οΏ½ Feeds developing microspores.
Tapetum is the innermost layer of the microsporangium wall. It supplies nourishment and essential materials required for pollen grain development. It is metabolically active and often multinucleate.
- Option A) Epidermis β Protective outer layer.
- Option B) Endothecium β Helps anther dehiscence.
- Option C) Middle layer β Temporary supporting layer.
Used: Elimination
- οΏ½οΏ½ Option A β Protection.
- οΏ½οΏ½ Option B β Dehiscence.
- οΏ½οΏ½ Option C β Support.
- οΏ½οΏ½ Option D β Nutrition.
- οΏ½οΏ½ Final Answer β Tapetum nourishes pollen grains.
4 Match the following: (PYQ 2023 Shift 1)
| List I | List II |
|---|---|
| A. Albuminous seed | I. Groundnut |
| B. Parthenocarpic fruit | II. Apple |
| C. Non-albuminous seed | III. Castor |
| D. False fruit | IV. Banana |
οΏ½οΏ½ Castor β Albuminous seed. οΏ½οΏ½ Banana β Parthenocarpic fruit. οΏ½οΏ½ Groundnut β Non-albuminous seed. οΏ½οΏ½ Apple β False fruit.
Albuminous seed retains endosperm (Castor). Non-albuminous seeds consume endosperm during development (Groundnut). Banana develops without fertilization and is parthenocarpic. Apple is a false fruit because the thalamus contributes to fruit formation.
- Option A β Incorrect matching of albuminous and false fruit.
- Option C β Multiple incorrect associations.
- Option D β Albuminous and parthenocarpic fruit mismatched.
Used: Option Grouping
- οΏ½οΏ½ Option A β Partial mismatch.
- οΏ½οΏ½ Option B β All correct matches.
- οΏ½οΏ½ Option C β Multiple errors.
- οΏ½οΏ½ Option D β Multiple errors.
- οΏ½οΏ½ Final Answer β Only Option B satisfies all pairs.
5 Maximum number of male gametes produced from one pollen mother cell (microspore mother cell) will be : (PYQ 2023 Shift 2)
οΏ½οΏ½ One PMC forms four microspores. οΏ½οΏ½ Each pollen grain forms two male gametes. οΏ½οΏ½ Total = 4 Γ 2 = 8.
One pollen mother cell undergoes meiosis to produce four microspores. Each microspore develops into a pollen grain that ultimately produces two male gametes. Therefore, maximum male gametes = 4 Γ 2 = 8.
- Option A) Too few.
- Option B) Counts only microspores.
- Option D) Exceeds biological limit.
Used: Substitution
- οΏ½οΏ½ Option A β Incorrect.
- οΏ½οΏ½ Option B β Microspore count only.
- οΏ½οΏ½ Option C β Correct calculation.
- οΏ½οΏ½ Option D β Excessive value.
- οΏ½οΏ½ Final Answer β Eight.
6
οΏ½οΏ½ X represents embryo. οΏ½οΏ½ Embryo develops after fertilization. οΏ½οΏ½ Formed from zygote.
The embryo of a seed develops from the zygote formed after fertilization. In maize grain, the embryonal axis and associated structures originate from the zygote.
- Option A) Ovary cell β Forms fruit wall.
- Option C) Sepals β Floral accessory parts.
- Option D) Petals β Floral accessory parts.
Used: NCERT Recall
- οΏ½οΏ½ Option A β Fruit formation.
- οΏ½οΏ½ Option B β Embryo origin.
- οΏ½οΏ½ Option C β Floral whorl.
- οΏ½οΏ½ Option D β Floral whorl.
- οΏ½οΏ½ Final Answer β Zygote.
7
οΏ½οΏ½ Y represents endosperm. οΏ½οΏ½ Endosperm stores food. οΏ½οΏ½ Nourishes developing embryo.
Maize is an endospermic seed. The endosperm persists in the mature seed and serves as the major food reserve supplying nutrients to the developing embryo.
- Option A) A β Embryonic structure.
- Option C) B β Protective sheath.
- Option D) D β Embryonic part.
Used: Diagram Identification
- οΏ½οΏ½ Option A β Not storage tissue.
- οΏ½οΏ½ Option B β Endosperm.
- οΏ½οΏ½ Option C β Protective structure.
- οΏ½οΏ½ Option D β Embryonic structure.
- οΏ½οΏ½ Final Answer β Y.
8
οΏ½οΏ½ Radicle covering = Coleorhiza. οΏ½οΏ½ Protective sheath. οΏ½οΏ½ Characteristic of monocot seeds.
In maize grain, the radicle is enclosed within a protective sheath called coleorhiza. This structure protects the radicle during seed germination.
- Option A) Not coleorhiza.
- Option C) Usually represents plumule sheath.
- Option D) Other embryonic structure.
Used: NCERT Recall
- οΏ½οΏ½ Option A β Incorrect.
- οΏ½οΏ½ Option B β Coleorhiza.
- οΏ½οΏ½ Option C β Coleoptile.
- οΏ½οΏ½ Option D β Embryonic part.
- οΏ½οΏ½ Final Answer β B.
9
οΏ½οΏ½ Scutellum is the cotyledon of maize. οΏ½οΏ½ Located between embryo and endosperm. οΏ½οΏ½ Absorbs food from endosperm.
The scutellum is the single cotyledon present in monocot seeds such as maize. It absorbs nutrients from the endosperm and transfers them to the embryo.
- Option A) Different embryonic structure.
- Option B) Endosperm.
- Option D) Protective sheath.
Used: Diagram Identification
- οΏ½οΏ½ Option A β Not cotyledon.
- οΏ½οΏ½ Option B β Endosperm.
- οΏ½οΏ½ Option C β Scutellum.
- οΏ½οΏ½ Option D β Protective structure.
- οΏ½οΏ½ Final Answer β Z.
10
οΏ½οΏ½ Plumule covering = Coleoptile. οΏ½οΏ½ Protects shoot apex. οΏ½οΏ½ Characteristic monocot structure.
In monocot seeds such as maize, the plumule is enclosed by a protective sheath called coleoptile. It protects the young shoot during germination.
- Option A) Not coleoptile.
- Option B) Coleorhiza surrounds radicle.
- Option D) Other embryonic structure.
Used: NCERT Recall
- οΏ½οΏ½ Option A β Incorrect.
- οΏ½οΏ½ Option B β Radicle sheath.
- οΏ½οΏ½ Option C β Coleoptile.
- οΏ½οΏ½ Option D β Other structure.
- οΏ½οΏ½ Final Answer β C.
11 In artificial hybridisation bagging is done to: (PYQ 2023 Shift 3)
οΏ½οΏ½ Bagging follows emasculation. οΏ½οΏ½ Protects stigma. οΏ½οΏ½ Prevents unwanted pollen deposition.
In artificial hybridisation, the emasculated flower is covered with a bag to prevent contamination of the stigma by unwanted pollen grains. This ensures controlled pollination with desired pollen.
- Option A) Removal of anthers is emasculation.
- Option B) Not the purpose of bagging.
- Option C) Bagging prevents contamination, not pollination itself.
Used: NCERT Recall
- οΏ½οΏ½ Option A β Emasculation.
- οΏ½οΏ½ Option B β Incorrect.
- οΏ½οΏ½ Option C β Indirect effect.
- οΏ½οΏ½ Option D β Correct.
- οΏ½οΏ½ Final Answer β Option D.
12 Match List I with List II (PYQ 2023 Shift 3)
| List I | List II |
|---|---|
| A. Attaches ovule to the placenta | I. Hilum |
| B. Region where ovule fuses with its stalk | II. Chalaza |
| C. Place where integuments are not present | III. Funicle |
| D. Basal part of ovule | IV. Micropyle |
οΏ½οΏ½ Funicle attaches ovule to placenta. οΏ½οΏ½ Hilum is fusion point. οΏ½οΏ½ Micropyle lacks integuments. οΏ½οΏ½ Chalaza is basal region.
Funicle connects ovule to placenta. Hilum is the junction where ovule fuses with stalk. Micropyle is the opening left by integuments. Chalaza is the basal part opposite the micropyle.
- Option B) Hilum and micropyle mismatched.
- Option C) Chalaza incorrectly matched.
- Option D) Multiple mismatches.
Used: Option Grouping
- οΏ½οΏ½ Option A β Correct.
- οΏ½οΏ½ Option B β Incorrect.
- οΏ½οΏ½ Option C β Incorrect.
- οΏ½οΏ½ Option D β Incorrect.
- οΏ½οΏ½ Final Answer β Option A.
13 Observe the given diagram and answer the questions given below:
Question: The method of embryo sac formation from a single megaspore is termed ______ development. (PYQ 2023 Shift 3)
οΏ½οΏ½ One megaspore remains functional. οΏ½οΏ½ Embryo sac develops from it. οΏ½οΏ½ Most common type in angiosperms.
In most flowering plants, only one megaspore remains functional and develops into the embryo sac. Such development is called monosporic development.
- Option A) Embryo sac develops from four nuclei.
- Option C) Not a standard embryo sac type.
- Option D) Embryo sac develops from two nuclei.
Used: NCERT Recall
- οΏ½οΏ½ Option A β Tetrasporic.
- οΏ½οΏ½ Option B β Correct.
- οΏ½οΏ½ Option C β Incorrect.
- οΏ½οΏ½ Option D β Bisporic.
- οΏ½οΏ½ Final Answer β Monosporic.
14 Observe the given diagram and answer the questions given below:
Question: Identify the correct statements with respect to female gametophyte. (PYQ 2023 Shift 3)
Choose the correct answer from the options given below:
οΏ½οΏ½ Egg apparatus occurs at micropylar end. οΏ½οΏ½ Female gametophyte = embryo sac. οΏ½οΏ½ MMC undergoes meiosis.
Statement A is incorrect because the egg apparatus is present at the micropylar end. Statements B, C and D are correct according to the standard Polygonum type embryo sac development.
- Option A) Includes incorrect statement A.
- Option B) Includes incorrect statement A.
- Option D) Includes incorrect statement A.
Used: Elimination
- οΏ½οΏ½ Option A β A incorrect.
- οΏ½οΏ½ Option B β A incorrect.
- οΏ½οΏ½ Option C β Correct.
- οΏ½οΏ½ Option D β A incorrect.
- οΏ½οΏ½ Final Answer β Option C.
15 Observe the given diagram and answer the questions given below:
Question: Match the following: (PYQ 2023 Shift 3)
| List I | List II |
|---|---|
| A. Nucellus | I. G |
| B. Megaspore dyad | II. B |
| C. Micropylar end | III. D |
| D. Megaspore mother cell | IV. C |
οΏ½οΏ½ Nucellus surrounds MMC. οΏ½οΏ½ Dyad forms after first meiotic division. οΏ½οΏ½ Micropylar end contains micropyle.
Based on the standard NCERT megasporogenesis diagram: Nucellus β G Megaspore dyad β C Micropylar end β B Megaspore mother cell β D Hence Option A is correct.
- Option B) Nucellus incorrectly matched.
- Option C) Multiple mismatches.
- Option D) Incorrect diagram labels.
Used: Diagram Identification
- οΏ½οΏ½ Option A β Correct.
- οΏ½οΏ½ Option B β Incorrect.
- οΏ½οΏ½ Option C β Incorrect.
- οΏ½οΏ½ Option D β Incorrect.
- οΏ½οΏ½ Final Answer β Option A.
16 Observe the given diagram and answer the questions given below:
Question: Which part of the ovule differentiates a large cell with dense cytoplasm and a prominent nucleus during megasporogenesis? (PYQ 2023 Shift 3)
οΏ½οΏ½ Archesporial cell develops here. οΏ½οΏ½ Gives rise to MMC. οΏ½οΏ½ Initiates megasporogenesis.
A hypodermal cell in the micropylar region of the nucellus enlarges, develops dense cytoplasm and a prominent nucleus, and differentiates into the archesporial cell, which ultimately forms the megaspore mother cell.
- Option B) Not the site of archesporial differentiation.
- Option C) Not specified in NCERT.
- Option D) Does not form MMC.
Used: NCERT Recall
- οΏ½οΏ½ Option A β Correct.
- οΏ½οΏ½ Option B β Incorrect.
- οΏ½οΏ½ Option C β Incorrect.
- οΏ½οΏ½ Option D β Incorrect.
- οΏ½οΏ½ Final Answer β Option A.
17 Observe the given diagram and answer the questions given below:
Question: How many mitotic divisions occur in the nucleus of the functional megaspore to form embryo sac? (PYQ 2023 Shift 3)
οΏ½οΏ½ Functional megaspore is haploid. οΏ½οΏ½ Undergoes three mitotic divisions. οΏ½οΏ½ Produces eight nuclei.
The functional megaspore undergoes three successive mitotic divisions: 1 β 2 nuclei 2 β 4 nuclei 4 β 8 nuclei This results in the typical eight-nucleate embryo sac.
- Option A) Produces only four nuclei.
- Option B) Excessive divisions.
- Option C) Produces sixteen nuclei.
Used: Substitution
- οΏ½οΏ½ Option A β Too few.
- οΏ½οΏ½ Option B β Too many.
- οΏ½οΏ½ Option C β Produces 16 nuclei.
- οΏ½οΏ½ Option D β Produces 8 nuclei.
- οΏ½οΏ½ Final Answer β Three.
18 In a velvet grass seed, the cotyledon is called : (PYQ 2024 Shift 1, 2024 Shift 2)
οΏ½οΏ½ Grass seeds are monocot seeds. οΏ½οΏ½ Monocot cotyledon is called scutellum. οΏ½οΏ½ Helps absorb nutrients from endosperm.
In monocotyledonous seeds such as grasses, the single cotyledon is called the scutellum. It lies between the embryo and endosperm and absorbs nutrients from the endosperm during germination for transfer to the growing embryo.
- Option B β Coleorrhiza is the protective sheath covering the radicle.
- Option C β Coleoptile is the protective sheath covering the plumule.
- Option D β Testa is the seed coat.
Used: Odd One Out
- οΏ½οΏ½ Option A β Cotyledon structure.
- οΏ½οΏ½ Option B β Radicle covering.
- οΏ½οΏ½ Option C β Plumule covering.
- οΏ½οΏ½ Option D β Seed coat.
- οΏ½οΏ½ Final Answer β Only scutellum is the cotyledon.
19 Which one of the following is not associated with megasporangium ? (PYQ 2024 Shift 1)
οΏ½οΏ½ Megasporangium refers to ovule. οΏ½οΏ½ Funicle, integument and micropyle are ovule parts. οΏ½οΏ½ Generative cell belongs to pollen grain.
The megasporangium (ovule) consists of nucellus, integuments, micropyle and funicle. The generative cell is a component of the male gametophyte (pollen grain) and is not associated with the ovule.
- Option A β Funicle attaches ovule to placenta.
- Option B β Integuments surround the nucellus.
- Option D β Micropyle is the opening in ovule.
Used: Odd One Out
- οΏ½οΏ½ Option A β Ovule structure.
- οΏ½οΏ½ Option B β Ovule structure.
- οΏ½οΏ½ Option C β Male gametophyte structure.
- οΏ½οΏ½ Option D β Ovule structure.
- οΏ½οΏ½ Final Answer β Generative cell.
20 In diploid organisms, which of the following undergoes meiosis? (PYQ 2024 Shift 1)
οΏ½οΏ½ Meiosis forms haploid spores. οΏ½οΏ½ Sporogenous tissue is diploid. οΏ½οΏ½ Pollen grains and synergids are already haploid.
The diploid sporogenous tissue inside microsporangia undergoes meiosis to produce haploid microspores. These later develop into pollen grains.
- Option A β Does not undergo meiosis.
- Option C β Product of meiosis.
- Option D β Haploid female gametophyte cell.
Used: Elimination
- οΏ½οΏ½ Option A β No meiosis.
- οΏ½οΏ½ Option B β Undergoes meiosis.
- οΏ½οΏ½ Option C β Produced after meiosis.
- οΏ½οΏ½ Option D β Haploid cell.
- οΏ½οΏ½ Final Answer β Sporogenous tissue.
21 Which one of the following guides the entry of the pollen tube into the embryo sac? (PYQ 2025 Shift 1)
Present in synergid cells. Guides pollen tube towards egg apparatus. Helps in pollen tube reception.
The filiform apparatus is a specialized structure present at the micropylar end of synergid cells. It plays a crucial role in attracting and guiding the pollen tube into the embryo sac. After reaching the embryo sac, the pollen tube enters one synergid through the filiform apparatus and releases the male gametes. Thus, the filiform apparatus acts as the guiding structure during fertilization in angiosperms.
- A) Antipodal cells
- Located at the chalazal end and mainly provide nourishment. They do not guide the pollen tube.
- C) Micropyle
- It is the opening through which the pollen tube enters the ovule, but it does not actively guide it.
- D) Synergids
- Synergids help in pollen tube reception, but the specific guiding structure within them is the filiform apparatus.
Used: Elimination
- Option A β Located at opposite end of embryo sac.
- Option B β Known guiding structure.
- Option C β Only an opening.
- Final Answer β Based on elimination.
"Filiform = File the pollen tube in the right direction."
22 Which one of the following is opposite part of micropylar end of ovule? (PYQ 2025 Shift 1)
Micropyle at one end. Chalaza at opposite end. Characteristic ovule structure.
The chalaza is the basal region of the ovule opposite to the micropylar end. It is the area where integuments and nucellus merge. The embryo sac is situated between the micropylar and chalazal ends.
- A) Hilum
- Attachment point of ovule.
- C) Funicle
- Stalk connecting ovule and placenta.
- D) Nucellus
- Nutritive tissue of ovule.
Used: NCERT Recall
- Option A β Attachment region.
- Option B β Opposite of micropyle.
- Option C β Connecting stalk.
- Final Answer β Based on NCERT recall.
Micro β Chalaza (Opposite Ends)
23
Question:
With reference to reproduction in flowering plants, which one of the following is incorrect? (PYQ 2025 Shift 1)
Seed develops from ovule. Endosperm provides nourishment. Endosperm does not become the seed.
After fertilization, the ovule develops into a seed while the ovary develops into a fruit. Endosperm is a nutritive tissue formed from the primary endosperm nucleus and supplies nutrients to the developing embryo. Therefore, the statement that endosperm develops into seed is incorrect.
- B) Ovary develops into fruit
- Correct statement.
- C) Fusion of polar nuclei
- Occurs during triple fusion.
- D) Syngamy is fusion of male and female gamete
- Correct definition of syngamy.
Used: Elimination
- Option A β Incorrect developmental pathway.
- Option B β Correct post-fertilization event.
- Option C β Correct reproductive process.
- Final Answer β Based on elimination.
Ovule β Seed, Ovary β Fruit
24
Question:
Which of the following is not a stage of growing embryo in dicotyledon plants? (PYQ 2025 Shift 1)
Dicot embryo passes through globular stage. Heart-shaped stage follows. Bird is not an embryonic stage.
Development of a dicot embryo proceeds through stages such as proembryo (pre-embryo), globular embryo, heart-shaped embryo, and mature embryo. "Bird" is not a recognized developmental stage in plant embryology. Hence it is the incorrect option.
- A) Heart-shaped
- A valid dicot embryo stage.
- B) Globular
- An early embryonic stage.
- C) Pre-embryo
- Occurs before later embryo differentiation.
Used: Odd One Out
- Option A β Embryonic stage.
- Option B β Embryonic stage.
- Option C β Embryonic stage.
- Final Answer β Based on odd one out.
Globular β Heart-shaped β Mature
25
Question:
The coconut water from tender coconut, a good source of nutrition is nothing but: (PYQ 2025 Shift 1)
Coconut water is liquid endosperm. Rich in nutrients. Formed by free nuclear divisions.
In coconut, the liquid found inside tender fruits is free nuclear endosperm. During development, nuclei divide repeatedly without immediate cell wall formation, creating a multinucleate liquid tissue. This liquid later contributes to the nutritive endosperm of the seed.
- B) Synergids
- Cells associated with the egg apparatus.
- C) Antipodal cells
- Located at the chalazal end of embryo sac.
- D) Scutellum
- Cotyledon of monocot embryo.
Used: NCERT Recall
- Option A β Standard NCERT example.
- Option B β Embryo sac cell.
- Option C β Embryo sac cell.
- Final Answer β Based on NCERT recall.
Tender Coconut Water = Liquid Endosperm
26
Question:
Formation of diploid zygote is a result of: (PYQ 2025 Shift 1)
Male and female gametes fuse. Diploid zygote is formed. Fundamental fertilization event.
Syngamy is the fusion of one male gamete with the egg cell. This fusion restores the diploid chromosome number and forms the zygote. Triple fusion forms the primary endosperm nucleus and does not produce the zygote.
- A) Emasculation
- Removal of anthers during artificial hybridization.
- B) Triple fusion
- Forms primary endosperm nucleus.
- D) Bagging
- Prevents unwanted pollination.
Used: NCERT Recall
- Option A β Hybridization technique.
- Option B β Endosperm formation.
- Option C β Zygote formation.
- Final Answer β Based on fertilization process.
Syngamy = Sperm + Egg
27
Question:
If there are 38 chromosomes in the zygote, how many chromosomes will be there in its haploid egg cell? (PYQ 2025 Shift 1)
Zygote is diploid (2n). Egg cell is haploid (n). Haploid number is half of diploid number.
A zygote is formed by the fusion of two haploid gametes and therefore contains the diploid chromosome number (2n). If the zygote contains 38 chromosomes, the haploid number is 19. Thus, the egg cell contributing to the zygote would contain 19 chromosomes.
- A) 38
- Represents diploid number, not haploid.
- B) 57
- Not related to chromosome reduction.
- D) 76
- Represents chromosome doubling beyond diploid level.
Used: Substitution
- Option A β Diploid count.
- Option B β Incorrect calculation.
- Option C β 38 Γ· 2 = 19.
- Final Answer β Based on chromosome number reduction.
Gamete = Half of Zygote
