CUET UG Physics Booster Test 2- Fundamentals of Magnetism
📌 Answers are locked once submitted — results and explanations appear at the end.
QUESTION 1 OF 20
Identify the correct statements regarding Oersted's observation when Earth's magnetic field is ignored.
Statements:
1. The alignment of the needle is tangential to an imaginary circle.
2. The straight wire acts as the centre of the imaginary circle.
3. The plane of the circle is parallel to the wire.
4. The deflection increases on increasing the current.
QUESTION 2 OF 20
The unification formulated by Maxwell, which incorporated Faraday's stress on the concept of fields, resulted in the understanding that
QUESTION 3 OF 20
Incorrect statement about the Lorentz force
F = q[E(r) + v × B(r)]
QUESTION 4 OF 20
When calculating the net magnetic field at a point due to multiple current-carrying segments,
QUESTION 5 OF 20
Effect of current magnitude and distance on needle deflection (assuming Earth's field is negligible):
QUESTION 6 OF 20
Identify the correct statements about magnetic field lines represented by iron filings.
Statements:
1. Lines of constant magnetic field magnitude form concentric circles around a straight wire.
2. Magnetic field lines form closed loops.
3. Magnetic field lines originate from positive charges and end at negative charges.
4. Magnetic field lines are completely independent of the current.
QUESTION 7 OF 20
A current I flows in a circular loop of radius R located in the xy-plane. If the current is anticlockwise, by the right-hand thumb rule, the magnetic field at the center is in the +z direction. Using the dot/cross convention for a plane paper representing the xy-plane, the field at the center will be denoted by a dot. The field magnitude is given by
QUESTION 8 OF 20
Match List I with List II for a straight wire carrying current along the +y axis on a paper plane.
| List I | List II |
|---|---|
| 1. Field on the right side (+x axis) | a. Dot (Outward) |
| 2. Field on the left side (-x axis) | b. Into the plane (-z axis) |
| 3. Vector direction of field on right side | c. Cross (Inward) |
| 4. Symbol for field coming out of plane | d. +z axis |
QUESTION 9 OF 20
What is the radius of the path of an electron (m = 9 × 10⁻³¹ kg, q = 1.6 × 10⁻¹⁹ C) moving at a speed of 3 × 10⁷ m/s in a uniform magnetic field of 6 × 10⁻⁴ T perpendicular to its velocity?
QUESTION 10 OF 20
A straight wire of mass 200 g and length 1.5 m carries a steady current of 2 A. What is the magnitude of the uniform horizontal magnetic field required to suspend it in mid-air?
(g = 9.8 m/s²)
QUESTION 11 OF 20
Incorrect statement about Oersted's experiment and findings.
QUESTION 12 OF 20
The unification of electricity and magnetism by James Maxwell led to the realization that light was electromagnetic waves, which eventually paved the way for
QUESTION 13 OF 20
Identify the correct statements comparing Biot-Savart law and Coulomb's law.
Statements:
1. Both are long-range, depending inversely on the square of distance.
2. The electrostatic field is produced by a scalar source, whereas the magnetic field is produced by a vector source.
3. The magnetic field has an angle dependence (sin θ) not present in the electrostatic case.
4. μ₀ is the permeability of free space, whereas ε₀ is the permittivity of free space.
A.1 and 2 are correct
QUESTION 14 OF 20
Since the speed of light in vacuum is constant (c = 3 × 10⁸ m/s), the product μ₀ε₀ is fixed in magnitude. If
c² = 1/(μ₀ε₀)
the value of μ₀ε₀ is equal to
QUESTION 15 OF 20
A straight wire carrying a current of 12 A is bent into a semicircular arc of radius 2.0 cm. What is the magnitude of the magnetic field at the centre of the arc?
(μ₀ = 4π × 10⁻⁷ T m/A)
QUESTION 16 OF 20
In a chamber, a uniform magnetic field of 6.5 G is maintained. What is the value of this magnetic field in tesla?
QUESTION 17 OF 20
The remarkable scientific and technological progress in the 20th century was fundamentally due to
QUESTION 18 OF 20
Which property allows electromagnetic signals to be transmitted effectively as predicted by Maxwell?
QUESTION 19 OF 20
Identify the correct statements regarding Ampere's circuital law and magnetic field loops.
Statements:
1. It considers an open surface with a boundary where current passes through it.
2. The line integral ∮ B·dl around a closed loop is μ₀ times the total current enclosed.
3. It provides a theoretical framework showing that magnetic field lines form closed loops.
4. It works best for systems with cylindrical or highly symmetric configurations.
QUESTION 20 OF 20
Elementary building blocks of Electrostatics and Magnetism:
Test Complete!
Answer Review
1 Identify the correct statements regarding Oersted's observation when Earth's magnetic field is ignored.
Statements:
1. The alignment of the needle is tangential to an imaginary circle.
2. The straight wire acts as the centre of the imaginary circle.
3. The plane of the circle is parallel to the wire.
4. The deflection increases on increasing the current.
�� Magnetic field lines around a straight wire are circular. �� The wire acts as the centre of these circles. �� Stronger current produces a stronger magnetic field.
Oersted's experiment demonstrated that a current-carrying conductor produces a magnetic field around it. When the Earth's magnetic field is ignored, the magnetic field produced by the straight wire dominates the compass needle's behavior. The magnetic field lines around a long straight conductor are concentric circles centered on the wire. Since a magnetic needle always aligns tangentially to the magnetic field lines, the needle becomes tangential to these imaginary circular paths. Increasing the current increases the magnetic field strength according to the Biot-Savart law and Ampere's observations, leading to greater needle deflection. However, Statement 3 is incorrect because the plane of the circular magnetic field lines is perpendicular, not parallel, to the wire. NCERT uses this observation to explain the geometry of magnetic field lines around current-carrying conductors.
- �� Option B → Statement 3 is incorrect.
- �� Option C → Statement 3 is incorrect and Statement 1 is omitted.
- �� Option D → Statement 3 is incorrect.
Used – Concept Application
- Application
- Visualize the circular magnetic field pattern around a straight current-carrying conductor.
- Final Logic
- The needle aligns tangentially to circular field lines centered on the wire, and stronger current increases the deflection.
"Circle Around Wire, Stronger Current Higher."
2 The unification formulated by Maxwell, which incorporated Faraday's stress on the concept of fields, resulted in the understanding that
�� Maxwell built upon Faraday's field concept. �� Electromagnetic effects propagate at finite speed. �� Light is an electromagnetic wave.
Faraday introduced the revolutionary concept of fields as real physical entities filling space. Maxwell mathematically developed this idea and unified electricity and magnetism through Maxwell's equations. One of the most important consequences of his theory was that electromagnetic disturbances propagate through space with a finite speed rather than instantaneously. When Maxwell calculated this speed, he found it equal to the known speed of light. This led him to conclude that light itself is an electromagnetic wave. The theory therefore established a deep connection between electricity, magnetism and optics. NCERT highlights Maxwell's work as a major breakthrough that transformed the understanding of electromagnetic interactions and demonstrated that changes in fields require finite time to travel through space.
- �� Option A → Maxwell's theory does not state that electricity is independent of mechanical forces.
- �� Option C → Magnetic monopoles have not been experimentally observed.
- �� Option D → Magnetism is associated primarily with moving charges, not merely static charges.
Used – NCERT Recall
- Application
- Recall the key conclusions obtained from Maxwell's electromagnetic theory.
- Final Logic
- Maxwell showed that electromagnetic effects propagate at finite speed and that light is electromagnetic radiation.
"Maxwell Made Light a Wave."
3 Incorrect statement about the Lorentz force
F = q[E(r) + v × B(r)]
�� Magnetic force is given by q(v × B). �� Cross product determines direction. �� Force is perpendicular to both v and B.
The Lorentz force equation combines electric and magnetic effects acting on a charged particle. The magnetic part of the force is given by q(v × B), where × denotes the vector cross product. A cross product always produces a vector perpendicular to both participating vectors. Therefore, the magnetic force is perpendicular to both the velocity of the particle and the magnetic field. If the charge is stationary, v = 0 and the magnetic force becomes zero. The magnitude and direction of the magnetic force depend on the particle's velocity, magnetic field strength and charge. For negative charges, the force direction is opposite to that obtained for positive charges. Thus, Statement C is incorrect because the magnetic force is never parallel to both velocity and magnetic field.
- �� Option A → Correct statement based on the sign of charge.
- �� Option B → Correct because q(v × B) becomes zero when v = 0.
- �� Option D → Correct because magnetic force depends directly on velocity.
Used – Concept Application
- Application
- Apply the properties of the vector cross product in the Lorentz force equation.
- Final Logic
- Since v × B is perpendicular to both v and B, the magnetic force cannot be parallel to them.
"Cross Means Across."
4 When calculating the net magnetic field at a point due to multiple current-carrying segments,
�� Magnetic fields are vector quantities. �� Superposition applies to magnetic fields. �� Vector addition determines the resultant field.
The principle of superposition states that the resultant magnetic field at any point is obtained by adding the magnetic fields produced individually by all sources. Since magnetic fields possess both magnitude and direction, they must be added vectorially rather than algebraically. Depending on their directions, individual magnetic fields may reinforce or oppose each other. This principle is extensively used while analyzing magnetic fields due to multiple current-carrying conductors, loops and combinations of magnetic sources. NCERT emphasizes that magnetic fields obey the same superposition principle as electric fields. Therefore, the net magnetic field is the vector sum of the contributions from all individual current-carrying segments.
- �� Option A → Magnetic fields cannot generally be added as scalars.
- �� Option B → Superposition is valid for both electric and magnetic fields.
- �� Option C → Every source contributes to the resultant field.
Used – Concept Application
- Application
- Use the vector nature of magnetic fields and the superposition principle.
- Final Logic
- Magnetic fields from all sources must be added vectorially to obtain the resultant field.
"Magnetic Fields Add as Vectors."
5 Effect of current magnitude and distance on needle deflection (assuming Earth's field is negligible):
�� Magnetic field increases with current. �� Magnetic field decreases with distance. �� Greater magnetic field produces greater deflection.
The magnetic field produced by a long straight current-carrying conductor is directly proportional to the current flowing through it and inversely proportional to the distance from the wire. Mathematically, B ∝ I/r where I is the current and r is the distance from the conductor. Therefore, increasing the current increases the magnetic field strength, causing a larger torque on the magnetic needle and hence greater deflection. Similarly, bringing the needle closer to the wire reduces the distance and increases the magnetic field strength, again producing greater deflection. NCERT uses these observations to explain how magnetic field strength depends on both current and distance. Thus, increasing current and decreasing distance both increase the magnetic effect observed on the compass needle.
- �� Option B → Both effects are opposite to the actual behavior.
- �� Option C → Decreasing current reduces magnetic field strength.
- �� Option D → Moving the needle away decreases the magnetic field.
Used – Concept Application
- Application
- Use the relation B ∝ I/r for a straight current-carrying conductor.
- Final Logic
- Greater current and smaller distance both produce a stronger magnetic field and larger needle deflection.
"More Current, More Deflection; More Distance, Less Deflection."
6 Identify the correct statements about magnetic field lines represented by iron filings.
Statements:
1. Lines of constant magnetic field magnitude form concentric circles around a straight wire.
2. Magnetic field lines form closed loops.
3. Magnetic field lines originate from positive charges and end at negative charges.
4. Magnetic field lines are completely independent of the current.
�� Iron filings trace magnetic field patterns. �� Magnetic field lines around a straight wire are circular. �� Magnetic field lines always form closed loops.
Iron filings provide a visual representation of magnetic field lines because each filing behaves like a tiny magnet and aligns itself along the local magnetic field direction. Around a straight current-carrying conductor, the magnetic field lines are concentric circles centered on the wire. These circles represent locations where the magnetic field has a constant radial distance from the conductor. Another important property of magnetic field lines is that they form continuous closed loops. Unlike electric field lines, magnetic field lines do not begin or end anywhere because isolated magnetic monopoles have not been observed. Statements 3 and 4 are incorrect because electric field lines originate from positive charges and terminate on negative charges, whereas magnetic field strength depends directly on the magnitude of current producing the field.
- �� Option A → Statements 3 and 4 are both incorrect.
- �� Option B → Statement 3 is incorrect.
- �� Option D → Statement 3 is incorrect.
Used – Concept Application
- Application
- Compare magnetic field lines with electric field lines and recall the field pattern around a straight conductor.
- Final Logic
- Magnetic field lines are circular around a straight wire and always form closed loops.
"Magnetic Makes Loops."
7 A current I flows in a circular loop of radius R located in the xy-plane. If the current is anticlockwise, by the right-hand thumb rule, the magnetic field at the center is in the +z direction. Using the dot/cross convention for a plane paper representing the xy-plane, the field at the center will be denoted by a dot. The field magnitude is given by
�� Magnetic field at the center of a circular loop is a standard result. �� Anticlockwise current produces a field along +z direction. �� A dot represents a field coming out of the plane.
For a circular current loop of radius R carrying current I, the magnetic field at the center is obtained from the Biot-Savart law. Integrating the contribution of all current elements around the loop gives B = μ₀I/2R The direction of the field is determined by the right-hand thumb rule. Curling the fingers in the direction of current flow and pointing the thumb perpendicular to the plane gives the direction of the magnetic field at the center. For an anticlockwise current viewed from above, the thumb points along the positive z-axis. According to the dot-cross convention, a magnetic field directed out of the plane is represented by a dot. Therefore, both the magnitude and direction are correctly represented by Option A.
- �� Option B → This expression corresponds to the magnetic field near a long straight conductor.
- �� Option C → Incorrect dimensional form for magnetic field.
- �� Option D → The factor 2 is incorrectly replaced by 4π.
Used – NCERT Recall
- Application
- Recall the standard expression for the magnetic field at the center of a circular current loop.
- Final Logic
- The magnetic field at the center of a circular loop is μ₀I/2R and points out of the plane for anticlockwise current.
"Circle Center = Mu I by Two R."
8 Match List I with List II for a straight wire carrying current along the +y axis on a paper plane.
| List I | List II |
|---|---|
| 1. Field on the right side (+x axis) | a. Dot (Outward) |
| 2. Field on the left side (-x axis) | b. Into the plane (-z axis) |
| 3. Vector direction of field on right side | c. Cross (Inward) |
| 4. Symbol for field coming out of plane | d. +z axis |
�� Use the right-hand thumb rule. �� Right side field points into the plane. �� Left side field points out of the plane.
Consider a straight conductor carrying current along the positive y-axis. Applying the right-hand thumb rule, the magnetic field lines circle around the wire. On the right side of the conductor (+x direction), the magnetic field points into the plane of the paper, corresponding to the negative z-direction. This is represented by a cross (⊗). On the left side (-x direction), the magnetic field points out of the plane of the paper, corresponding to the positive z-direction and represented by a dot (•). Thus, the field on the right side matches the cross symbol, the field on the left side matches the dot symbol, and the vector direction on the right side corresponds to the negative z-axis. The dot symbol represents a field directed along the positive z-axis.
- �� Option A → The right and left side field directions are interchanged.
- �� Option C → The vector direction on the right side is incorrect.
- �� Option D → The field on the right side is not directly represented by −z notation.
Used – Right-Hand Rule Application
- Application
- Point the right thumb along current direction and observe the curl of fingers around the wire.
- Final Logic
- For current along +y, the right side field is inward and the left side field is outward.
"Right Side Cross, Left Side Dot."
9 What is the radius of the path of an electron (m = 9 × 10⁻³¹ kg, q = 1.6 × 10⁻¹⁹ C) moving at a speed of 3 × 10⁷ m/s in a uniform magnetic field of 6 × 10⁻⁴ T perpendicular to its velocity?
�� Magnetic force provides centripetal force. �� Use r = mv/qB. �� Convert the final answer into centimeters.
For a charged particle moving perpendicular to a magnetic field, the magnetic force acts as the centripetal force. qvB = mv²/r Therefore, r = mv/qB Substituting the given values: r = (9 × 10⁻³¹ × 3 × 10⁷) / (1.6 × 10⁻¹⁹ × 6 × 10⁻⁴) r = (27 × 10⁻²⁴) / (9.6 × 10⁻²³) r = 0.28125 m r ≈ 0.28 m Converting to centimeters: r ≈ 28 cm Thus, the radius of the circular path is approximately 28 cm.
- �� Option B → Calculation gives a larger value than 14 cm.
- �� Option C → Approximately twice the correct value.
- �� Option D → Does not satisfy the formula r = mv/qB.
Used – Substitution
- Application
- Apply the centripetal force condition for circular motion in a magnetic field.
- Final Logic
- Using r = mv/qB gives a radius of approximately 28 cm.
"Radius = Mass × Velocity ÷ Charge × Field."
10 A straight wire of mass 200 g and length 1.5 m carries a steady current of 2 A. What is the magnitude of the uniform horizontal magnetic field required to suspend it in mid-air?
(g = 9.8 m/s²)
�� Magnetic force balances weight. �� Use F = BIL. �� Set magnetic force equal to mg.
To suspend the wire in mid-air, the upward magnetic force must balance the downward gravitational force. Weight of wire: W = mg = 0.2 × 9.8 = 1.96 N Magnetic force on a current-carrying conductor: F = BIL For equilibrium, BIL = mg Therefore, B = mg/IL Substituting values: B = (0.2 × 9.8)/(2 × 1.5) B = 1.96/3 B = 0.653 T ≈ 0.65 T Hence, a magnetic field of approximately 0.65 tesla is required to suspend the conductor.
- �� Option B → Obtained by incorrect substitution.
- �� Option C → More than twice the required value.
- �� Option D → Does not satisfy B = mg/IL.
Used – Substitution
- Application
- Equate magnetic force and gravitational force for equilibrium.
- Final Logic
- When BIL = mg, the required magnetic field is approximately 0.65 T.
"Suspend Wire → Magnetic Force Equals Weight."
11 Incorrect statement about Oersted's experiment and findings.
�� Oersted discovered the magnetic effect of electric current. �� Moving charges produce magnetic fields. �� Static charges do not produce magnetic fields.
Oersted's experiment established that a current-carrying conductor produces a magnetic field around it. He observed that a compass needle placed near a conducting wire deflected whenever electric current flowed through the wire. The needle aligned tangentially to the circular magnetic field lines centered on the wire. He also found that the magnetic effect became stronger when the current increased or when the compass was brought closer to the conductor. From these observations, Oersted concluded that moving charges or electric currents generate magnetic fields in the surrounding space. However, he did not demonstrate that static charges produce magnetic forces on a compass needle. Static charges create electric fields but not magnetic fields. Therefore, Option C is the incorrect statement.
- �� Option A → Correctly describes the alignment of the compass needle.
- �� Option B → Deflection increases when the needle is brought closer to the wire.
- �� Option D → Oersted correctly concluded that currents produce magnetic fields.
Used – NCERT Recall
- Application
- Recall the observations and conclusions of Oersted's experiment.
- Final Logic
- Oersted linked magnetism with moving charges, not static charges.
"Current Creates Compass Change."
12 The unification of electricity and magnetism by James Maxwell led to the realization that light was electromagnetic waves, which eventually paved the way for
�� Maxwell predicted electromagnetic waves. �� Hertz experimentally verified them. �� Bose and Marconi developed radio-wave applications.
Maxwell's electromagnetic theory unified electricity and magnetism and predicted the existence of electromagnetic waves traveling at the speed of light. Since the calculated speed matched the known speed of light, Maxwell concluded that light itself is an electromagnetic wave. This prediction was experimentally verified by Heinrich Hertz, who successfully generated and detected radio waves. Later, J.C. Bose and Guglielmo Marconi developed techniques for producing and transmitting radio waves over long distances, laying the foundation of wireless communication. These developments revolutionized communication technology and directly resulted from Maxwell's theoretical work. NCERT highlights this sequence as one of the most important achievements in the history of physics.
- �� Option A → The cyclotron was invented by Ernest Lawrence, not Lorentz.
- �� Option B → Lorentz transformations arose from relativity, not directly from this development.
- �� Option D → Biot-Savart law was formulated before Maxwell's work.
Used – Historical Sequence Analysis
- Application
- Trace the sequence: Maxwell → Hertz → Bose & Marconi.
- Final Logic
- Maxwell predicted electromagnetic waves, Hertz discovered them, and Bose-Marconi used them for communication.
"Maxwell Predicted, Hertz Proved, Marconi Connected."
13 Identify the correct statements comparing Biot-Savart law and Coulomb's law.
Statements:
1. Both are long-range, depending inversely on the square of distance.
2. The electrostatic field is produced by a scalar source, whereas the magnetic field is produced by a vector source.
3. The magnetic field has an angle dependence (sin θ) not present in the electrostatic case.
4. μ₀ is the permeability of free space, whereas ε₀ is the permittivity of free space.
A.1 and 2 are correct
�� Biot-Savart law and Coulomb's law have similar inverse-square dependence. �� Their sources are different. �� Magnetic fields possess angular dependence.
The Biot-Savart law and Coulomb's law exhibit several mathematical similarities. Both involve inverse-square dependence on distance from the source. However, Coulomb's law describes electric fields generated by electric charges, which are scalar sources. In contrast, the Biot-Savart law describes magnetic fields generated by current elements, which have directional properties and therefore behave as vector sources. Another important difference is that the Biot-Savart law contains a sinθ term, indicating angular dependence between the current element and the position vector. Coulomb's law does not contain such a term because the electric field due to a point charge is radially symmetric. Furthermore, μ₀ denotes permeability of free space and ε₀ denotes permittivity of free space. Hence all four statements are correct.
- �� Option A → Statements 3 and 4 are also correct.
- �� Option B → Statements 2 and 4 are also correct.
- �� Option C → Statement 1 is also correct.
Used – Concept Comparison
- Application
- Compare the mathematical forms and physical meanings of both laws.
- Final Logic
- All four statements correctly describe similarities and differences between Biot-Savart and Coulomb laws.
"Coulomb Uses Charge, Biot Uses Current."
14 Since the speed of light in vacuum is constant (c = 3 × 10⁸ m/s), the product μ₀ε₀ is fixed in magnitude. If
c² = 1/(μ₀ε₀)
the value of μ₀ε₀ is equal to
�� Use Maxwell's relation. �� Substitute c = 3 × 10⁸ m/s. �� Take the reciprocal of c².
According to Maxwell's electromagnetic theory, c² = 1/(μ₀ε₀) Therefore, μ₀ε₀ = 1/c² Substituting c = 3 × 10⁸ m/s gives μ₀ε₀ = 1/(3 × 10⁸)² = 1/(9 × 10¹⁶) = (1/9) × 10⁻¹⁶ s²/m² Thus, the value of μ₀ε₀ is (1/9) × 10⁻¹⁶ s²/m². This relation is one of Maxwell's most important results because it links electric and magnetic constants with the speed of light, proving that light is electromagnetic in nature.
- �� Option A → Represents c, not μ₀ε₀.
- �� Option B → Represents c², not μ₀ε₀.
- �� Option C → Incorrect dimensions and magnitude.
Used – Substitution
- Application
- Apply μ₀ε₀ = 1/c² and substitute the value of c.
- Final Logic
- Taking the reciprocal of 9 × 10¹⁶ gives (1/9) × 10⁻¹⁶ s²/m².
"Mu-Epsilon = One Over Light Squared."
15 A straight wire carrying a current of 12 A is bent into a semicircular arc of radius 2.0 cm. What is the magnitude of the magnetic field at the centre of the arc?
(μ₀ = 4π × 10⁻⁷ T m/A)
�� Use the magnetic field due to a circular arc. �� Semicircle subtends 180°. �� Apply the standard formula.
The magnetic field at the centre of a circular arc carrying current is B = μ₀Iθ/4πR For a semicircular arc, θ = π rad Therefore, B = μ₀I/4R Substituting the given values, B = (4π × 10⁻⁷ × 12)/(4 × 0.02) = (48π × 10⁻⁷)/0.08 = 600π × 10⁻⁷ ≈ 1.88 × 10⁻⁴ T ≈ 1.9 × 10⁻⁴ T Hence, the magnetic field at the centre of the semicircular arc is 1.9 × 10⁻⁴ T.
- �� Option B → Approximately twice the calculated value.
- �� Option C → Radius conversion error leads to this value.
- �� Option D → Incorrect application of the arc formula.
Used – Formula Application
- Application
- Use the magnetic field formula for a semicircular current-carrying arc.
- Final Logic
- Substituting θ = π in B = μ₀Iθ/4πR gives 1.9 × 10⁻⁴ T.
"Semicircle = Mu I by Four R."
16 In a chamber, a uniform magnetic field of 6.5 G is maintained. What is the value of this magnetic field in tesla?
�� 1 gauss = 10⁻⁴ tesla. �� Convert directly using the standard relation. �� Tesla is the SI unit.
The SI unit of magnetic field is tesla (T), while gauss (G) is a CGS unit. The conversion factor is 1 G = 10⁻⁴ T Given, B = 6.5 G Therefore, B = 6.5 × 10⁻⁴ T This conversion is frequently used in magnetism because many practical magnetic field values are expressed in gauss while theoretical calculations use tesla. NCERT introduces both units and their conversion relation.
- �� Option B → Incorrect positive exponent.
- �� Option C → One power of ten smaller than required.
- �� Option D → One power of ten larger than required.
Used – Unit Conversion
- Application
- Multiply the value in gauss by 10⁻⁴.
- Final Logic
- 6.5 G = 6.5 × 10⁻⁴ T.
"Gauss to Tesla → Multiply by 10⁻⁴."
17 The remarkable scientific and technological progress in the 20th century was fundamentally due to
�� Electromagnetism revolutionized technology. �� Communication systems developed rapidly. �� Wireless transmission became possible.
The twentieth century experienced unprecedented scientific and technological growth due largely to advances in electromagnetism. Maxwell's theory, Hertz's experiments and the development of radio communication by Bose and Marconi led to technologies such as radio, television, radar, satellite communication, mobile phones and the internet. Understanding electromagnetic waves enabled efficient transmission and reception of information over long distances. Electromagnetism also played a crucial role in electrical engineering, electronics, medical imaging and modern computing. NCERT emphasizes that developments in electromagnetic theory transformed both science and society.
- �� Option A → Maxwell's theory was confirmed, not rejected.
- �� Option C → Time-varying electric fields are fundamental to electromagnetism.
- �� Option D → Modern technology relies heavily on electromagnets.
Used – Historical Analysis
- Application
- Relate technological developments to electromagnetic discoveries.
- Final Logic
- Modern communication technology arose directly from advances in electromagnetism.
"Electromagnetism Enabled Electronics."
18 Which property allows electromagnetic signals to be transmitted effectively as predicted by Maxwell?
�� Electromagnetic waves travel with finite speed. �� They transport energy and momentum. �� Signals can therefore be transmitted.
Maxwell's theory predicts that electromagnetic disturbances propagate through space at a finite speed equal to the speed of light. These waves carry both energy and momentum, allowing information to be transmitted from one location to another. This property forms the basis of radio communication, television broadcasting, satellite communication and wireless networks. Electromagnetic waves do not act instantaneously across space; instead, changes in electric and magnetic fields propagate continuously. NCERT emphasizes that electromagnetic waves are self-sustaining oscillations of electric and magnetic fields capable of transporting energy through vacuum without requiring a material medium.
- �� Option B → Electromagnetic effects do not propagate instantaneously.
- �� Option C → Electromagnetic waves do not require permanent magnets.
- �� Option D → Electric and magnetic fields support each other rather than cancel completely.
Used – Concept Application
- Application
- Recall the properties of electromagnetic waves predicted by Maxwell.
- Final Logic
- Electromagnetic waves carry energy and momentum while propagating at finite speed.
Wave = Energy on the Move.
19 Identify the correct statements regarding Ampere's circuital law and magnetic field loops.
Statements:
1. It considers an open surface with a boundary where current passes through it.
2. The line integral ∮ B·dl around a closed loop is μ₀ times the total current enclosed.
3. It provides a theoretical framework showing that magnetic field lines form closed loops.
4. It works best for systems with cylindrical or highly symmetric configurations.
�� Ampere's law relates magnetic field and enclosed current. �� It uses a closed integration path. �� Symmetry simplifies its application.
Ampere's circuital law states that the line integral of the magnetic field around any closed path equals μ₀ times the net current enclosed by that path. The law is mathematically expressed as ∮ B·dl = μ₀Ienc The closed path forms the boundary of an open surface through which current may pass. The law also supports the concept that magnetic field lines form continuous closed loops around currents. Ampere's law is especially useful in highly symmetric situations such as long straight conductors, solenoids and toroids, where the magnetic field can be easily determined. NCERT emphasizes these applications while deriving magnetic fields in symmetric configurations.
- �� Option A → Statements 3 and 4 are also correct.
- �� Option B → Statements 1 and 3 are also correct.
- �� Option C → Statement 2 is also correct.
Used – Concept Application
- Application
- Apply the mathematical statement and interpretation of Ampere's law.
- Final Logic
- All four statements correctly describe Ampere's circuital law.
Loop Around Current
20 Elementary building blocks of Electrostatics and Magnetism:
�� Isolated electric charges exist. �� Magnetic monopoles have not been observed. �� Magnetic dipoles are the basic magnetic entities.
In electrostatics, the fundamental source of electric fields is the electric charge, which exists independently as positive or negative charges. Therefore, electric monopoles are the elementary building blocks of electrostatics. In contrast, isolated magnetic poles or magnetic monopoles have never been experimentally observed. Every magnet possesses both north and south poles. Consequently, the simplest magnetic entity is a magnetic dipole, which may be represented by a current loop. NCERT emphasizes this distinction when comparing electric and magnetic fields. Because magnetic monopoles are unknown in nature, magnetic dipoles become the fundamental building blocks of magnetism.
- �� Option A → Magnetic monopoles have not been experimentally observed.
- �� Option C → Magnetic monopoles are not established physical entities.
- �� Option D → Electric charges, not electric dipoles, are the elementary electrostatic sources.
Used – Concept Comparison
- Application
- Compare the basic sources of electric and magnetic fields.
- Final Logic
- Electric fields originate from monopoles, whereas magnetic fields originate from dipoles.
"Electric = Charge, Magnetic = Dipole."
