CUET UG Chemistry Booster Test - 2 Electrochemical Cells
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QUESTION 1 OF 20
Identify the correct statements regarding electrochemical cells.
Statements:
1. Galvanic cells convert Gibbs free energy of spontaneous reactions into electrical work.
2. Electrolytic cells convert electrical energy into chemical energy.
3. Electrochemical cells can be used for determining the pH of solutions.
4. Electrochemical reactions are generally less polluting and highly energy efficient.
QUESTION 2 OF 20
Arrange the following conditions of opposing external potential (Eext) in decreasing order of measurable current output magnitude for a standard Daniell cell.
1. Eext = 1.0 V
2. Eext = 0.0 V
3. Eext = 1.1 V
4. Eext = 0.5 V
QUESTION 3 OF 20
In a galvanic cell, the electrical work derived from the cell may be used for running electrical gadgets. This electrical work mathematically corresponds directly to:
QUESTION 4 OF 20
Identify the reaction type that explains how a galvanic cell generates electricity.
QUESTION 5 OF 20
Which conceptual statement correctly distinguishes an electrolytic cell from a galvanic cell?
QUESTION 6 OF 20
Identify the correct IUPAC cell notation if a Daniell cell is operating as an electrolytic cell , forcing current from Zn to Cu.
QUESTION 7 OF 20
According to the passage, the negative charge on an electrode (such as the zinc electrode in a Daniell cell) develops because:
QUESTION 8 OF 20
Based on the passage, the potential difference that develops at equilibrium between the electrode and the electrolyte is formally called:
QUESTION 9 OF 20
Match the half-cell reactions with their standard electrode potentials at 298 K.
| List I | List II |
|---|---|
| 1. F2(g)+2e-→2F- | a. 0.34 V |
| 2. Cu2++2e-→Cu(s) | b. -0.76 V |
| 3. 2H++2e-→H2(g) | c. 2.87 V |
| 4. Zn2++2e-→Zn(s) | d. 0.00 V |
QUESTION 10 OF 20
In the representation
the platinum serves as an inert electrode. What is the fundamental concept behind using platinum here?
QUESTION 11 OF 20
What is the standard IUPAC name of the reference electrode assigned an exact potential of zero at all temperatures, effectively serving as the standard anode for measurement?
QUESTION 12 OF 20
Identify the reaction type occurring at the right-hand side half-cell (cathode) when constructing a galvanic cell according to accepted conventions.
QUESTION 13 OF 20
Identify the correct statements regarding standard cell notation.
Statements:
1. A vertical line separates the metal and electrolyte solution.
2. A double vertical line represents the salt bridge.
3. The anode is kept on the right and cathode on the left.
4. Under this convention, Ecell is positive.
QUESTION 14 OF 20
Arrange the following standard reduction potentials in decreasing order (highest to lowest potential) to determine which would act as the cathode when paired with a salt bridge.
1. Ag⁺ + e⁻ → Ag(s)
2. Zn²⁺ + 2e⁻ → Zn(s)
3. Au³⁺ + 3e⁻ → Au(s)
4. Li⁺ + e⁻ → Li(s)
QUESTION 15 OF 20
If the standard electrode potential of a half-cell is negative, it indicates conceptually that:
QUESTION 16 OF 20
Match the electrode behavior with its corresponding characteristic in a galvanic cell.
| List I | List II |
|---|---|
| 1. Left Electrode | a. From positive to negative electrode |
| 2. Right Electrode | b. Acts as Cathode (Reduction) |
| 3. Direction of Current | c. Acts as Anode (Oxidation) |
| 4. Direction of Electrons | d. From negative to positive electrode |
QUESTION 17 OF 20
The unit for the Faraday constant (F), which represents the charge on one mole of electrons, is:
QUESTION 18 OF 20
Why is the potential of an individual half-cell impossible to measure directly?
QUESTION 19 OF 20
The unit of the gas constant (R) used in the Nernst equation is:
QUESTION 20 OF 20
Identify the correct statements regarding standard electrode potentials.
Statements:
1. Fluorine gas (F₂) has the maximum tendency to get reduced.
2. Lithium metal is the most powerful reducing agent in aqueous solution.
3. A negative E° means the redox couple is a weaker oxidising agent than the H⁺/H₂ couple.
4. Standard potentials can be used to determine the equilibrium constant of a reaction.
Test Complete!
Answer Review
1 Identify the correct statements regarding electrochemical cells.
Statements:
1. Galvanic cells convert Gibbs free energy of spontaneous reactions into electrical work.
2. Electrolytic cells convert electrical energy into chemical energy.
3. Electrochemical cells can be used for determining the pH of solutions.
4. Electrochemical reactions are generally less polluting and highly energy efficient.
�� Electrochemical cells convert energy from one form to another. �� They have analytical and industrial applications. �� They support environmentally friendly technologies.
Electrochemical cells play an important role in both energy conversion and analytical chemistry. Galvanic cells convert the Gibbs free energy of spontaneous redox reactions into useful electrical work. Electrolytic cells consume electrical energy and store it as chemical energy through non-spontaneous reactions. Electrochemical methods are also used for determining pH, electrode potentials and ionic concentrations. Modern electrochemical technologies, including batteries, fuel cells and electrochemical sensors, are considered relatively energy efficient and environmentally friendly compared with many conventional industrial processes. Their applications extend from portable electronics to pollution control and green energy systems. Therefore all four statements are correct and option D is the correct answer.
- �� Option A → Statements 3 and 4 are also correct.
- �� Option B → Statements 1 and 2 are also correct.
- �� Option C → Statement 2 is also correct.
NCERT Recall
- Application
- Recall the broad applications and functions of electrochemical cells.
- Final Logic
- Energy conversion, pH measurement and green technologies are all electrochemical applications.
- Energy, Analysis, Environment
2 Arrange the following conditions of opposing external potential (Eext) in decreasing order of measurable current output magnitude for a standard Daniell cell.
1. Eext = 1.0 V
2. Eext = 0.0 V
3. Eext = 1.1 V
4. Eext = 0.5 V
�� Increasing opposing voltage reduces current. �� At 1.1 V the current becomes zero. �� Current is maximum when no opposing voltage exists.
The Daniell cell possesses a standard emf of approximately 1.1 V. When no opposing voltage is applied, the full cell potential drives electron flow and the current is maximum. As an external opposing voltage is gradually increased, the effective potential difference available for electron flow decreases. Consequently, the current decreases continuously. At an opposing voltage of 1.1 V, the external potential exactly balances the cell emf, causing the net driving force to become zero and the current to stop. The given values are: 1. 1.0 V 2. 0.0 V 3. 1.1 V 4. 0.5 V Therefore the decreasing order of current magnitude is: 0.0 V > 0.5 V > 1.0 V > 1.1 V Using the numbering given: 2 > 4 > 1 > 3 Hence option A is correct.
- �� Option B → Gives the exact reverse order.
- �� Option C → Places 0.5 V before the maximum-current condition incorrectly.
- �� Option D → Places 1.0 V before 0.0 V incorrectly.
Logical Analysis
- Application
- Relate current magnitude to the effective cell potential.
- Final Logic
- Greater opposing voltage means lower current.
- More Opposition = Less Current
3 In a galvanic cell, the electrical work derived from the cell may be used for running electrical gadgets. This electrical work mathematically corresponds directly to:
�� Electrical work originates from chemical energy. �� Gibbs energy determines maximum useful work. �� Spontaneous reactions have negative Gibbs energy.
The maximum electrical work obtainable from a galvanic cell is directly related to the Gibbs free energy change of the cell reaction. According to NCERT, where is the number of electrons transferred and is the Faraday constant. A spontaneous redox reaction has a negative Gibbs energy change, and this decrease in Gibbs energy becomes available as useful electrical work. The greater the magnitude of negative Gibbs energy, the larger the electrical work that can be obtained. Therefore electrical energy produced by a galvanic cell corresponds directly to the decrease in Gibbs energy of the spontaneous reaction.
- �� Option A → Entropy alone does not determine electrical work.
- �� Option C → Heat of combustion is not directly equal to electrical work.
- �� Option D → Ionization enthalpy is unrelated to cell work output.
NCERT Recall
- Application
- Recall the Gibbs energy-cell potential relationship.
- Final Logic
- Decrease in Gibbs energy produces electrical work.
- Negative G Gives Power
4 Identify the reaction type that explains how a galvanic cell generates electricity.
�� Oxidation and reduction occur simultaneously. �� The reaction proceeds spontaneously. �� Electron flow produces electrical energy.
A galvanic cell operates through a spontaneous redox reaction in which oxidation and reduction occur in separate half-cells. The separation of these reactions forces electrons to travel through an external circuit, thereby generating electrical current. This coupling of spontaneous oxidation and reduction processes is known as spontaneous redox coupling. The Daniell cell provides a classic example where zinc undergoes oxidation and copper ions undergo reduction. Because the reaction is spontaneous, chemical energy is converted into electrical energy without external assistance. Therefore option C is correct.
- �� Option A → Electrolysis is non-spontaneous.
- �� Option B → Thermal decomposition requires heat energy.
- �� Option D → Neutralization does not explain galvanic cell operation.
Concept Application
- Application
- Identify the fundamental reaction responsible for electron flow.
- Final Logic
- Spontaneous oxidation + reduction = electrical energy.
- Redox Runs the Cell
5 Which conceptual statement correctly distinguishes an electrolytic cell from a galvanic cell?
�� Electrolytic cells require external electrical energy. �� They reverse non-spontaneous reactions. �� Applied voltage must overcome the natural cell emf.
The fundamental distinction between an electrolytic cell and a galvanic cell is the direction of energy conversion. A galvanic cell generates electrical energy from a spontaneous chemical reaction. In contrast, an electrolytic cell uses an external source of electrical energy to force a non-spontaneous reaction to occur. For example, when an opposing voltage greater than 1.1 V is applied to a Daniell cell, the spontaneous reaction reverses and the system behaves as an electrolytic cell. Electrical energy is then converted into chemical energy. Therefore option B correctly describes the distinguishing feature of an electrolytic cell.
- �� Option A → Salt bridges are characteristic of galvanic cells.
- �� Option C → Non-spontaneous reactions do not occur spontaneously.
- �� Option D → The Standard Hydrogen Electrode is not required.
Concept Application
- Application
- Compare energy conversion in galvanic and electrolytic cells.
- Final Logic
- External voltage drives a non-spontaneous reaction.
- Electrolytic = Electricity Input
6 Identify the correct IUPAC cell notation if a Daniell cell is operating as an electrolytic cell , forcing current from Zn to Cu.
�� Electrolysis reverses the spontaneous Daniell cell reaction. �� Copper becomes the anode. �� Zinc becomes the cathode.
In a normal Daniell cell, zinc acts as the anode and copper acts as the cathode. However, when an external potential greater than 1.1 V is applied, the spontaneous reaction is reversed. Copper metal is oxidized: and zinc ions are reduced: According to IUPAC convention, the anode is written on the left and the cathode on the right. Since copper now acts as the anode and zinc acts as the cathode, the correct cell notation becomes: Therefore option A is correct.
- �� Option B → Represents the normal galvanic Daniell cell.
- �� Option C → Includes a hydrogen electrode not involved in the process.
- �� Option D → Does not represent the reversed Daniell cell.
Concept Application
- Application
- Reverse the electrode roles after applying an external voltage greater than the cell emf.
- Final Logic
- Electrolysis reverses oxidation and reduction, reversing the cell notation.
- Reverse Cell → Reverse Notation
7
According to the passage, the negative charge on an electrode (such as the zinc electrode in a Daniell cell) develops because:
�� Metal atoms can leave the electrode as ions. �� Electrons remain on the electrode surface. �� This creates a negative charge on the electrode.
At the electrode-electrolyte interface, two opposing processes occur. Metal ions from the solution may deposit on the electrode, making it relatively positive. Simultaneously, metal atoms of the electrode may enter the solution as positive ions, leaving their electrons behind on the metal surface. When the tendency of metal atoms to ionize is greater, excess electrons accumulate on the electrode and it becomes negatively charged relative to the solution. This charge separation leads to the development of an electrode potential. In the zinc electrode of the Daniell cell, zinc atoms readily enter the solution as ions, leaving electrons behind and producing a negative electrode potential. Therefore option D is correct.
- �� Option A → Deposition tends to reduce negative charge.
- �� Option B → Electrons are not forced into the solution by the external circuit.
- �� Option C → Salt bridges maintain neutrality but do not create electrode charge.
NCERT Recall
- Application
- Recall the origin of electrode potential at the metal-solution interface.
- Final Logic
- Metal atoms leaving as ions leave excess electrons on the electrode.
- Ions Leave, Electrons Stay
8
Based on the passage, the potential difference that develops at equilibrium between the electrode and the electrolyte is formally called:
�� Charge separation develops at the interface. �� A potential difference is created. �� This potential difference is called electrode potential.
When a metal electrode is immersed in a solution containing its ions, two competing processes occur: metal atoms may enter the solution as ions, and metal ions from the solution may deposit on the electrode. Eventually, equilibrium is established and a separation of charges develops between the electrode and the electrolyte. This charge separation produces a potential difference known as the electrode potential. The magnitude and sign of this potential depend on the relative tendencies of oxidation and reduction at the interface. Electrode potentials form the basis for measuring standard reduction potentials and calculating cell emf. Therefore option C is correct.
- �� Option A → Overpotential refers to extra voltage required during electrolysis.
- �� Option B → emf refers to the overall cell potential.
- �� Option D → Limiting molar conductivity is unrelated to electrode potentials.
NCERT Recall
- Application
- Recall the definition of electrode potential.
- Final Logic
- Electrode-Electrolyte Potential Difference = Electrode Potential.
- Interface Potential = Electrode Potential
9 Match the half-cell reactions with their standard electrode potentials at 298 K.
| List I | List II |
|---|---|
| 1. F2(g)+2e-→2F- | a. 0.34 V |
| 2. Cu2++2e-→Cu(s) | b. -0.76 V |
| 3. 2H++2e-→H2(g) | c. 2.87 V |
| 4. Zn2++2e-→Zn(s) | d. 0.00 V |
�� Fluorine has the highest standard reduction potential. �� SHE has zero potential by definition. �� Zinc has a negative standard reduction potential.
The standard reduction potentials given in NCERT are: Therefore the correct matching is: 1-c, 2-a, 3-d, 4-b which corresponds to option A.
- �� Option B → Incorrectly assigns all standard potentials.
- �� Option C → Copper and hydrogen potentials are interchanged.
- �� Option D → Fluorine and copper potentials are mismatched.
NCERT Recall
- Application
- Recall the standard electrode potential table.
- Final Logic
- Match each reaction with its standard value.
- Zn Negative
10 In the representation
the platinum serves as an inert electrode. What is the fundamental concept behind using platinum here?
�� Platinum is chemically inert. �� It conducts electrons efficiently. �� It provides a surface for electron transfer.
Some electrochemical half-cells involve only ions, gases or dissolved species and do not contain a solid conducting material. In such cases, an inert electrode is required to provide a conducting surface for electron transfer. Platinum is commonly used because it is chemically stable, resistant to corrosion and an excellent conductor of electricity. In the bromine-bromide half-cell, platinum does not participate in the chemical reaction. Instead, it merely allows electrons to enter or leave the system and provides a surface on which the oxidation or reduction process can occur. Therefore platinum functions as an inert electrode and option C is correct.
- �� Option A → Platinum remains chemically unchanged.
- �� Option B → Platinum is not a reducing agent.
- �� Option D → Platinum does not form complexes with bromide ions in this context.
NCERT Recall
- Application
- Recall the purpose of inert electrodes in electrochemical cells.
- Final Logic
- Inert electrode = Conductor + Surface, not a reactant.
- Platinum Participates in Current, Not Chemistry
11 What is the standard IUPAC name of the reference electrode assigned an exact potential of zero at all temperatures, effectively serving as the standard anode for measurement?
�� SHE is the universal reference electrode. �� Its potential is defined as zero. �� All standard electrode potentials are measured relative to it.
The Standard Hydrogen Electrode (SHE) is the primary reference electrode used in electrochemistry. It consists of a platinum electrode coated with platinum black immersed in a solution containing hydrogen ions of concentration 1 M, while hydrogen gas is bubbled at a pressure of 1 bar. By international convention, the electrode potential of SHE is assigned a value of exactly 0.00 V. This allows the standard electrode potentials of all other half-cells to be measured relative to it. Because absolute electrode potentials cannot be measured directly, the SHE serves as the universal standard reference electrode in electrochemical measurements.
- �� Option B → Calomel electrode is a secondary reference electrode.
- �� Option C → Platinum black is only a component of SHE.
- �� Option D → No such standard electrode exists.
NCERT Recall
- Application
- Recall the standard reference electrode used for measuring electrode potentials.
- Final Logic
- SHE = Universal Reference = 0.00 V.
- SHE Sets the Scale
12 Identify the reaction type occurring at the right-hand side half-cell (cathode) when constructing a galvanic cell according to accepted conventions.
�� The cathode is placed on the right side. �� Reduction always occurs at the cathode. �� The cell reaction is spontaneous in a galvanic cell.
According to IUPAC convention, the anode is written on the left side and the cathode on the right side in cell notation. In a galvanic cell, oxidation occurs spontaneously at the anode, releasing electrons. These electrons travel through the external circuit and are consumed at the cathode. Therefore reduction occurs spontaneously at the cathode. For example, in the Daniell cell: Cu²⁺(aq) + 2e⁻ → Cu(s) This reduction half-reaction takes place at the right-hand side half-cell. Hence the correct answer is spontaneous reduction.
- �� Option A → Oxidation occurs at the anode.
- �� Option B → Galvanic cell reactions are spontaneous.
- �� Option D → Dissociation is not the cathodic reaction.
NCERT Recall
- Application
- Recall the relationship between cathode and reduction.
- Final Logic
- Right Side = Cathode = Reduction.
- Cathode = Reduction
13 Identify the correct statements regarding standard cell notation.
Statements:
1. A vertical line separates the metal and electrolyte solution.
2. A double vertical line represents the salt bridge.
3. The anode is kept on the right and cathode on the left.
4. Under this convention, Ecell is positive.
�� Single line indicates phase boundary. �� Double line indicates salt bridge. �� Anode is written on the left.
In standard electrochemical cell notation, a single vertical line (|) represents a phase boundary, such as between a metal electrode and its ionic solution. A double vertical line (||) represents the salt bridge separating the two half-cells. According to IUPAC convention, the anode is written on the left and the cathode on the right. This arrangement is chosen so that the cell emf is positive for a spontaneous galvanic cell. Therefore statements 1, 2 and 4 are correct, while statement 3 is incorrect because it reverses the accepted convention.
- �� Option A → Statement 3 is incorrect.
- �� Option B → Statement 2 and statement 4 are also correct.
- �� Option C → Statement 3 is incorrect.
NCERT Recall
- Application
- Recall the standard rules used in electrochemical cell representation.
- Final Logic
- Single Line = Boundary, Double Line = Salt Bridge, Left = Anode.
- Left Anode, Right Cathode
14 Arrange the following standard reduction potentials in decreasing order (highest to lowest potential) to determine which would act as the cathode when paired with a salt bridge.
1. Ag⁺ + e⁻ → Ag(s)
2. Zn²⁺ + 2e⁻ → Zn(s)
3. Au³⁺ + 3e⁻ → Au(s)
4. Li⁺ + e⁻ → Li(s)
�� Higher reduction potential means greater tendency for reduction. �� Cathode is the site of reduction. �� Gold has the highest reduction potential among the given species.
A species with a higher standard reduction potential has a greater tendency to gain electrons and undergo reduction. Therefore it preferentially acts as the cathode when paired with another half-cell. The approximate reduction potentials are: Au³⁺/Au = +1.50 V Ag⁺/Ag = +0.80 V Zn²⁺/Zn = –0.76 V Li⁺/Li = –3.05 V Arranging these in decreasing order gives: Au³⁺/Au > Ag⁺/Ag > Zn²⁺/Zn > Li⁺/Li Using the numbering given: 3 > 1 > 2 > 4 Hence option B is correct.
- �� Option A → Places silver above gold.
- �� Option C → Reverses the reduction potential trend.
- �� Option D → Places lithium incorrectly at the highest position.
Concept Application
- Application
- Compare standard reduction potentials and arrange from highest to lowest.
- Final Logic
- Higher E° → Greater Reduction Tendency → Cathode.
- Gold First, Lithium Last
15 If the standard electrode potential of a half-cell is negative, it indicates conceptually that:
�� Negative E° indicates less tendency for reduction than hydrogen. �� The species tends to undergo oxidation more easily. �� Such electrodes act as anodes against SHE.
The Standard Hydrogen Electrode has a potential of 0.00 V. If a half-cell possesses a negative standard reduction potential, it means that its tendency to undergo reduction is lower than that of the H⁺/H₂ couple. Consequently, when connected to SHE, the half-cell tends to undergo oxidation while hydrogen ions undergo reduction. In thermodynamic terms, hydrogen gas is relatively more stable than the reduced form of the species. Metals such as zinc and lithium have negative standard reduction potentials and therefore act as strong reducing agents.
- �� Option A → Opposite of the implication of a negative E° value.
- �� Option C → Such electrodes generally act as anodes against SHE.
- �� Option D → Electrode potential does not directly determine electron flow rate.
Concept Application
- Application
- Compare the half-cell potential with the SHE value of 0.00 V.
- Final Logic
- Negative E° → Less Reduction Tendency than Hydrogen.
- Negative E° = Oxidation Friendly
16 Match the electrode behavior with its corresponding characteristic in a galvanic cell.
| List I | List II |
|---|---|
| 1. Left Electrode | a. From positive to negative electrode |
| 2. Right Electrode | b. Acts as Cathode (Reduction) |
| 3. Direction of Current | c. Acts as Anode (Oxidation) |
| 4. Direction of Electrons | d. From negative to positive electrode |
�� Left electrode is the anode. �� Right electrode is the cathode. �� Current and electron flow are opposite.
According to standard galvanic cell convention, the left electrode represents the anode where oxidation occurs, while the right electrode represents the cathode where reduction occurs. Electrons are released at the anode and travel through the external circuit toward the cathode. Conventional current is defined opposite to electron flow. Therefore electrons move from the negative electrode to the positive electrode, while current flows from the positive electrode to the negative electrode. Thus the correct matching is: 1-c, 2-b, 3-a, 4-d
- �� Option A → Reverses current and electron directions.
- �� Option B → Incorrectly matches all electrode roles.
- �� Option C → Exchanges anode and cathode.
NCERT Recall
- Application
- Recall the standard galvanic cell convention.
- Final Logic
- Anode → Oxidation → Electrons Out
- Cathode → Reduction → Electrons In
- Left Loses, Right Receives
17 The unit for the Faraday constant (F), which represents the charge on one mole of electrons, is:
�� Faraday constant represents charge per mole of electrons. �� One Faraday ≈ 96485 C mol⁻¹. �� Unit is coulomb per mole.
The Faraday constant (F) is defined as the total electric charge carried by one mole of electrons. It is numerically equal to the product of Avogadro's number and the electronic charge: F = Nₐ × e ≈ 6.022 × 10²³ × 1.602 × 10⁻¹⁹ ≈ 96485 C mol⁻¹ Since it represents electric charge associated with one mole of electrons, its SI unit is coulomb per mole (C mol⁻¹). The Faraday constant plays an important role in Faraday's laws of electrolysis and electrochemical calculations.
- �� Option A → Unit of molar energy.
- �� Option C → Related to molar conductivity.
- �� Option D → Not a unit associated with charge.
NCERT Recall
- Application
- Recall the definition and unit of the Faraday constant.
- Final Logic
- Faraday Constant = Charge per Mole of Electrons.
- F = 96500 C per Mole
18 Why is the potential of an individual half-cell impossible to measure directly?
�� Only potential differences can be measured. �� A complete electrochemical circuit is required. �� Electrode potentials are measured relative to a reference electrode.
An individual electrode potential cannot be measured directly because electrical measurements always involve a difference in potential between two points. A single half-cell by itself cannot sustain a measurable potential difference without being connected to another half-cell. Therefore electrode potentials are always determined relative to a reference electrode, most commonly the Standard Hydrogen Electrode (SHE). By constructing a complete electrochemical cell and measuring the cell emf, the potential of the unknown half-cell can be calculated. Hence a complete circuit linking two half-cells is essential.
- �� Option A → Electrode reactions involve electrons, not neutrons.
- �� Option C → Standard conditions can be established experimentally.
- �� Option D → Voltmeters can measure DC potentials.
Concept Application
- Application
- Understand the meaning of electrical potential as a relative quantity.
- Final Logic
- Potential Difference Requires Two Electrodes.
- One Electrode Cannot Make a Voltage
19 The unit of the gas constant (R) used in the Nernst equation is:
�� R is the universal gas constant. �� It appears in the Nernst equation. �� Its SI unit is J K⁻¹ mol⁻¹.
The Nernst equation is: E = E° − (RT/nF) ln Q where R is the universal gas constant. It relates cell potential to concentration and temperature. The SI unit of R is joule per kelvin per mole (J K⁻¹ mol⁻¹), and its value is approximately 8.314 J K⁻¹ mol⁻¹. This constant appears throughout thermodynamics and electrochemistry because it connects energy, temperature and amount of substance.
- �� Option A → Unit of Faraday constant.
- �� Option B → Unit of conductivity.
- �� Option C → Unit of electric field intensity.
NCERT Recall
- Application
- Recall the constants appearing in the Nernst equation.
- Final Logic
- R = 8.314 J K⁻¹ mol⁻¹.
- R Means Energy per Mole per Kelvin
20 Identify the correct statements regarding standard electrode potentials.
Statements:
1. Fluorine gas (F₂) has the maximum tendency to get reduced.
2. Lithium metal is the most powerful reducing agent in aqueous solution.
3. A negative E° means the redox couple is a weaker oxidising agent than the H⁺/H₂ couple.
4. Standard potentials can be used to determine the equilibrium constant of a reaction.
�� Fluorine has the highest standard reduction potential. �� Lithium is the strongest reducing metal. �� Standard potentials help calculate equilibrium constants.
Fluorine possesses the highest standard reduction potential (+2.87 V), making it the strongest oxidising agent and the species with the greatest tendency to undergo reduction. Lithium metal has a highly negative standard reduction potential (−3.05 V), making it an exceptionally strong reducing agent. Standard electrode potentials are also related to Gibbs free energy and equilibrium constants through thermodynamic relationships. Statement 3 is incorrect because a negative E° indicates that the species is a weaker oxidising agent than the H⁺/H₂ couple, not a weaker reducing agent. Therefore statements 1, 2 and 4 are correct.
- �� Option A → Includes incorrect statement 3.
- �� Option B → Includes incorrect statement 3 and omits statement 1.
- �� Option D → Statement 3 is incorrect.
Concept Application
- Application
- Compare standard reduction potentials with the SHE value of 0.00 V.
- Final Logic
- Positive E° → Strong Oxidising Agent
- Negative E° → Strong Reducing Agent
- Fluorine Gains, Lithium Gives
