CUET UG Chemistry Booster Test

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CUET UG Chemistry Booster Test - 2 Nomenclature

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❓ 20 Questions

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CUET UG Chemistry Booster Test - 2 Nomenclature

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QUESTION 1 OF 20

The IUPAC nomenclature system is crucial in coordination chemistry because it provides an unambiguous method for naming formulas, especially when dealing with:

Answer Review

1 The IUPAC nomenclature system is crucial in coordination chemistry because it provides an unambiguous method for naming formulas, especially when dealing with:

A Compounds that only dissolve in water

B Isomers, which have the same empirical formula but distinct properties

C Metals with a zero-oxidation state

D Simple salts that completely dissociate

💡 Short Explanation

�� Coordination compounds often show isomerism. �� Isomers may have identical formulas but different properties. �� IUPAC nomenclature prevents ambiguity.

✅ Correct Answer Explanation

Coordination compounds frequently exhibit structural and stereoisomerism. Different compounds may possess the same empirical formula but differ in arrangement of ligands and properties. A systematic IUPAC nomenclature provides unique names that distinguish such isomers clearly. Therefore, nomenclature is especially important when dealing with isomers.

❓ Why Other Options Are Incorrect

�� Option A → Solubility is unrelated to nomenclature.
�� Option C → Oxidation state zero does not justify the need for nomenclature.
�� Option D → Simple salts generally do not present complex naming challenges.

🎯 Strategy

Used

Definition Matching

Application:

Identify the primary purpose of nomenclature.

Final Logic:

IUPAC naming uniquely identifies isomers.

🧠 Memory Trick

Same Formula ≠ Same Compound → Use IUPAC.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Importance of Nomenclature

2 Regarding the 2004 IUPAC draft recommendations for nomenclature, choose the correct statements:
1. Ligands will be sorted alphabetically, irrespective of charge.
2. Anionic ligands will end with -ido (e.g., chlorido).
3. Central atoms are named last in formulas.
4. Neutral ligands always end in -o.

A 1, 2

B 3, 4

C 1, 3

D 2, 4

💡 Short Explanation

�� Ligands are arranged alphabetically. �� Modern IUPAC uses -ido for anionic ligands. �� Central atom is written first in formulas.

✅ Correct Answer Explanation

Statement 1 → Correct. Ligands are listed alphabetically irrespective of charge. Statement 2 → Correct. Modern IUPAC recommends names such as chlorido, cyanido and hydroxido. Statement 3 → Incorrect. In formulas, the central atom is written first. Statement 4 → Incorrect. Only anionic ligands generally end in -o/-ido; neutral ligands do not. Therefore Statements 1 and 2 are correct.

❓ Why Other Options Are Incorrect

�� Option B → Statements 3 and 4 are incorrect.
�� Option C → Statement 3 is incorrect.
�� Option D → Statement 4 is incorrect.

🎯 Strategy

Used

Elimination

Application:

Check each statement against IUPAC recommendations.

Final Logic:

Only Statements 1 and 2 are correct.

🧠 Memory Trick

Alphabet + -ido = Modern IUPAC.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: IUPAC Recommendations

3 Arrange the following components in the correct sequence to form the chemical formula of tetraammineaquachloridocobalt(III) chloride:
Statements:
1. (NH₃)₄
2. [Co
3. Cl]
4. (H₂O)
5. Cl₂

A 2, 1, 4, 3, 5

B 2, 4, 1, 3, 5

C 1, 2, 4, 3, 5

D 2, 1, 3, 4, 5

💡 Short Explanation

�� Central atom is written first. �� Ligands are arranged alphabetically by formula. �� Counter ions are written outside brackets.

✅ Correct Answer Explanation

Formula is: [Co(NH₃)₄(H₂O)Cl]Cl₂ Construction: 2 → [Co 1 → (NH₃)₄ 4 → (H₂O) 3 → Cl] 5 → Cl₂ Therefore the correct sequence is: 2 → 1 → 4 → 3 → 5

❓ Why Other Options Are Incorrect

�� Option B → Water incorrectly placed before ammonia.
�� Option C → Begins with ligand before metal.
�� Option D → Water placed outside the coordination sequence.

🎯 Strategy

Used

Sequential Ordering

Application:

Apply formula-writing rules stepwise.

Final Logic:

Metal → Ligands → Bracket → Counter Ions.

🧠 Memory Trick

Metal First, Counter Last.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Formula Writing

4 When writing the formula for [Co(en)₃]³⁺, why is the ligand 'en' placed inside parentheses?

A Because it has a negative charge.

B Because ligand abbreviations are enclosed in parentheses.

C Because it represents a metal counter ion.

D Because it is the central atom.

💡 Short Explanation

�� en is the abbreviation for ethane-1,2-diamine. �� Abbreviated ligands are enclosed in parentheses. �� This improves clarity.

✅ Correct Answer Explanation

The ligand ethane-1,2-diamine is commonly abbreviated as "en". Abbreviated ligand symbols are enclosed in parentheses when written in coordination formulas. Therefore [Co(en)₃]³⁺ is written using parentheses around en.

❓ Why Other Options Are Incorrect

�� Option A → en is neutral.
�� Option C → en is a ligand, not a counter ion.
�� Option D → Co is the central atom.

🎯 Strategy

Used

Direct Recall

Application:

Recall notation rules for ligand abbreviations.

Final Logic:

Ligand abbreviations are enclosed in parentheses.

🧠 Memory Trick

Abbreviation → Parentheses.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Formula Writing

5 In the formula [Co(NH₃)₄(H₂O)Cl]Cl₂, the order of the ligands inside the square brackets is NH₃, H₂O, then Cl. What dictates this specific sequence?

A The number of ligands present

B Alphabetical order based on their chemical formulas

C Alphabetical order based on the ligand names (ammine, aqua, chlorido)

D The oxidation state of the cobalt ion

💡 Short Explanation

�� Formula writing uses alphabetical order of ligand formulas. �� Charge is ignored. �� Oxidation state is irrelevant.

✅ Correct Answer Explanation

While nomenclature uses ligand names, formula writing arranges ligands alphabetically according to their chemical formulas. NH₃ precedes H₂O, which precedes Cl⁻. Therefore the sequence follows alphabetical order based on ligand formulas.

❓ Why Other Options Are Incorrect

�� Option A → Number of ligands does not determine order.
�� Option C → This rule applies to naming, not formula writing.
�� Option D → Oxidation state does not determine ligand order.

🎯 Strategy

Used

Definition Matching

Application:

Differentiate formula-writing rules from naming rules.

Final Logic:

Formula order follows ligand formulas alphabetically.

🧠 Memory Trick

Formula → Formula Alphabet.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Formula Writing Rules

6 Which of the following principles strictly overrides the electrical charge of a ligand when determining its position in the written formula of a coordination entity?

A The size of the ligand molecule

B The alphabetical order of the ligands

C The denticity of the ligand

D The atomic mass of the donor atom

💡 Short Explanation

�� Ligands are listed alphabetically. �� Charge is ignored. �� Denticity is not considered.

✅ Correct Answer Explanation

According to IUPAC rules, ligands are written alphabetically irrespective of whether they are neutral or charged. Thus alphabetical order overrides ligand charge.

❓ Why Other Options Are Incorrect

�� Option A → Size is irrelevant.
�� Option C → Denticity does not determine position.
�� Option D → Atomic mass is irrelevant.

🎯 Strategy

Used

Direct Recall

Application:

Recall ligand-ordering rules.

Final Logic:

Alphabetical order determines placement.

🧠 Memory Trick

Alphabet Beats Charge.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Ligand Order

7 In the name diamminesilver(I) dicyanidoargentate(I), the prefix "di-" acts as a quantitative unit multiplier indicating the presence of how many ammine and cyanido ligands respectively?

A 1

B 2

C 3

D 4

💡 Short Explanation

�� Di means two. �� Ammine appears twice. �� Cyanido appears twice.

✅ Correct Answer Explanation

The prefix "di-" is the standard multiplicative prefix representing two identical ligands. Thus diammine indicates two NH₃ ligands and dicyanido indicates two CN⁻ ligands.

❓ Why Other Options Are Incorrect

�� Option A → Mono indicates one.
�� Option C → Tri indicates three.
�� Option D → Tetra indicates four.

🎯 Strategy

Used

Direct Recall

Application:

Recall multiplicative prefixes.

Final Logic:

Di = 2.

🧠 Memory Trick

Di = Double = Two.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Prefix Usage

8 Match List-I (Ligand condition) with List-II (Prefix used):

List I	List II
1. Simple ligand, 2 present	a. Tris
2. Simple ligand, 3 present	b. Tri
3. Ligand name includes a numerical prefix, 2 present	c. Di
4. Ligand name includes a numerical prefix, 3 present	d. Bis

A 1-c, 2-b, 3-d, 4-a

B 1-d, 2-a, 3-c, 4-b

C 1-b, 2-c, 3-a, 4-d

D 1-c, 2-d, 3-b, 4-a

💡 Short Explanation

�� Simple ligands use di, tri. �� Complex ligand names use bis, tris. �� Prefix choice depends on ligand name complexity.

✅ Correct Answer Explanation

1 → Simple ligand, 2 present → Di → c 2 → Simple ligand, 3 present → Tri → b 3 → Complex ligand name, 2 present → Bis → d 4 → Complex ligand name, 3 present → Tris → a Therefore: 1-c, 2-b, 3-d, 4-a

❓ Why Other Options Are Incorrect

�� Options B, C and D contain incorrect prefix assignments.

🎯 Strategy

Used

Direct Recall

Application:

Match multiplicative prefixes correctly.

Final Logic:

Simple → Di/Tri; Complex → Bis/Tris.

🧠 Memory Trick

Complex Ligand = Bis/Tris.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Multiplicative Prefixes

9 According to the 2004 IUPAC draft recommendation, the anionic ligand Cl⁻ should be named:

A Chloro

B Chlorate

C Chlorido

D Chlorite

💡 Short Explanation

�� Modern IUPAC uses -ido endings. �� Cl⁻ becomes chlorido. �� Similar examples: cyanido, hydroxido.

✅ Correct Answer Explanation

The 2004 IUPAC recommendations replaced traditional forms such as chloro with chlorido. Therefore Cl⁻ is named chlorido.

❓ Why Other Options Are Incorrect

�� Option A → Older nomenclature.
�� Option B → Different oxyanion.
�� Option D → Different oxyanion.

🎯 Strategy

Used

Direct Recall

Application:

Recall updated ligand names.

Final Logic:

Cl⁻ → Chlorido.

🧠 Memory Trick

Modern Cl = Chlorido.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Ligand Names

10 Identify the correct classification of the ligand NO based on IUPAC naming exceptions for neutral molecules:

A It is named nitrito-N

B It is named nitrate

C It is named nitrosyl

D It is named ammine

💡 Short Explanation

�� NO is a neutral ligand. �� It has a special name. �� The accepted name is nitrosyl.

✅ Correct Answer Explanation

NO is one of the important neutral ligands with a special IUPAC name. NO → Nitrosyl Therefore Option C is correct.

❓ Why Other Options Are Incorrect

�� Option A → Refers to NO₂⁻ linkage nomenclature.
�� Option B → Refers to nitrate ion.
�� Option D → NH₃ is ammine.

🎯 Strategy

Used

Direct Recall

Application:

Recall special neutral ligand names.

Final Logic:

NO is named nitrosyl.

🧠 Memory Trick

NO → Nitrosyl.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Neutral Ligands and Exceptions

11 In the coordination compound [Pt(NH₃)₂Cl(NO₂)], the platinum metal is part of a neutral complex. How is the metal named?

A Platinate

B Platinum

C Platinic

D Platinous

💡 Short Explanation

�� Neutral complexes retain the normal metal name. �� The suffix "-ate" is used only for anionic complexes. �� Platinum remains unchanged.

✅ Correct Answer Explanation

In neutral and cationic coordination entities, the central metal retains its elemental name. Since [Pt(NH₃)₂Cl(NO₂)] is a neutral complex, the metal is named platinum. Therefore, the correct name uses "platinum" rather than "platinate."

❓ Why Other Options Are Incorrect

�� Option A → Platinate is used for anionic platinum complexes.
�� Option C → Platinic is not used in modern IUPAC nomenclature.
�� Option D → Platinous is obsolete nomenclature.

🎯 Strategy

Used

Definition Matching

Application:

Determine whether the complex is neutral, cationic or anionic.

Final Logic:

Neutral complex → Metal retains elemental name.

🧠 Memory Trick

Neutral/Cationic → Normal Metal Name.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Metal Naming Rules

12 When naming K₃[Fe(C₂O₄)₃], the complex ion is an anion. What is the correct name for the central metal in this compound?

A Iron(III)

B Ferrate(III)

C Ironate(III)

D Ferric(III)

💡 Short Explanation

�� The complex ion is negatively charged. �� Anionic complexes use "-ate". �� Iron becomes ferrate.

✅ Correct Answer Explanation

For anionic complexes, the metal name ends with "-ate". Certain metals use Latin-derived names: Iron → Ferrate Copper → Cuprate Silver → Argentate Thus [Fe(C₂O₄)₃]³⁻ contains ferrate(III).

❓ Why Other Options Are Incorrect

�� Option A → Used for neutral/cationic complexes.
�� Option C → Not accepted IUPAC nomenclature.
�� Option D → Old nomenclature.

🎯 Strategy

Used

Direct Recall

Application:

Recall naming conventions for anionic complexes.

Final Logic:

Anionic iron complex → Ferrate.

🧠 Memory Trick

Fe⁻ Complex → Ferrate.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Anionic Complex Nomenclature

13 In the name potassium tetrahydroxidozincate(II), what does the Roman numeral (II) strictly represent?

A The coordination number of zinc

B The number of potassium counter ions

C The oxidation state of the zinc ion

D The overall charge of the complex anion

💡 Short Explanation

�� Roman numerals indicate oxidation state. �� They do not indicate charge or coordination number. �� Zinc is present as Zn²⁺.

✅ Correct Answer Explanation

IUPAC nomenclature uses Roman numerals in parentheses immediately after the metal name to indicate the oxidation state of the central metal ion. In zincate(II), the numeral II indicates that zinc has oxidation state +2.

❓ Why Other Options Are Incorrect

�� Option A → Coordination number is not written using Roman numerals.
�� Option B → Counter ions are not represented this way.
�� Option D → Complex charge is not represented by Roman numerals.

🎯 Strategy

Used

Direct Recall

Application:

Recall the significance of Roman numerals in coordination nomenclature.

Final Logic:

Roman numeral = Oxidation state.

🧠 Memory Trick

Metal Name + (Roman Numeral).

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Oxidation State Representation

14 Calculate the oxidation state of cobalt in [Co(H₂NCH₂CH₂NH₂)₃]₂(SO₄)₃, given that ethane-1,2-diamine is neutral and sulphate has a -2 charge.

A +1

B +2

C +3

D +4

💡 Short Explanation

�� en is a neutral ligand. �� Sulphate has charge −2. �� Total charge balance determines cobalt oxidation state.

✅ Correct Answer Explanation

Let oxidation state of cobalt = x. There are two complex cations and three sulphate ions. Total negative charge: 3 × (−2) = −6 Hence total positive charge = +6. Therefore: 2x = +6 x = +3 Thus cobalt is in the +3 oxidation state.

❓ Why Other Options Are Incorrect

�� Option A → Does not balance sulphate charge.
�� Option B → Gives total charge +4.
�� Option D → Gives total charge +8.

🎯 Strategy

Used

Substitution

Application:

Apply overall charge neutrality.

Final Logic:

2x = 6 → x = 3.

🧠 Memory Trick

Two Co Balance Three Sulphates.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Oxidation Number Calculation

15 When systematically naming a coordination compound like [Co(NH₃)₆]Cl₃, which part of the salt is named first?

A The counter ion (chloride)

B The cationic coordination entity

C The metal regardless of the charge

D The ligand regardless of the charge

💡 Short Explanation

�� Cation is always named first. �� Anion is named second. �� This applies to coordination compounds.

✅ Correct Answer Explanation

In IUPAC nomenclature, the cation is always named before the anion. For [Co(NH₃)₆]Cl₃: Hexaamminecobalt(III) chloride The cationic coordination entity is named first.

❓ Why Other Options Are Incorrect

�� Option A → Anion is named second.
�� Option C → The metal alone is not named first.
�� Option D → Ligands are part of the coordination entity name.

🎯 Strategy

Used

Direct Recall

Application:

Apply naming order rules.

Final Logic:

Cation first, anion second.

🧠 Memory Trick

Positive Before Negative.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Naming Coordination Compounds

16 In the compound K₂[Zn(OH)₄], the [Zn(OH)₄]²⁻ entity is best described as a(n):

A Homoleptic neutral complex

B Heteroleptic cationic complex

C Homoleptic anionic complex

D Ambidentate complex

💡 Short Explanation

�� Only one ligand type is present. �� The complex carries a negative charge. �� Hence it is homoleptic and anionic.

✅ Correct Answer Explanation

[Zn(OH)₄]²⁻ contains only hydroxido ligands. Therefore it is homoleptic. The complex ion carries a −2 charge. Hence it is an anionic complex.

❓ Why Other Options Are Incorrect

�� Option A → The complex is not neutral.
�� Option B → The complex is not cationic.
�� Option D → OH⁻ is not an ambidentate ligand.

🎯 Strategy

Used

Definition Matching

Application:

Classify according to ligand type and charge.

Final Logic:

One ligand type + negative charge.

🧠 Memory Trick

One Ligand = Homo.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Types of Complexes

17 In the formula K₃[Cr(C₂O₄)₃], why are there three potassium (K⁺) ions?

A Because chromium has an oxidation state of +6.

B Because the trioxalatochromate(III) complex anion has a net charge of -3.

C Because there are three oxalate ligands.

D Because the coordination number is 3.

💡 Short Explanation

�� Three K⁺ ions balance a −3 charge. �� Formula must be electrically neutral. �� Counter ions maintain charge balance.

✅ Correct Answer Explanation

For [Cr(C₂O₄)₃]³⁻: Cr = +3 Three oxalate ligands = 3 × (−2) = −6 Net charge = −3 Three K⁺ ions are required to neutralize the −3 charge.

❓ Why Other Options Are Incorrect

�� Option A → Chromium is +3, not +6.
�� Option C → Number of ligands alone does not determine K⁺ count.
�� Option D → Coordination number is unrelated.

🎯 Strategy

Used

Substitution

Application:

Calculate complex charge.

Final Logic:

��3 charge requires 3 K⁺ ions.

🧠 Memory Trick

Charge −3 → Need 3 K⁺.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Charge Balance

18 Which of the following representations perfectly adheres to the IUPAC spacing rules for writing coordination formulas?

A [Co (NH₃)₅ Cl] Cl₂

B [Co(NH₃)₅Cl]Cl₂

C [Co(NH₃)₅ Cl] Cl₂

D [ Co(NH₃)₅Cl ]Cl₂

💡 Short Explanation

�� No spaces are allowed inside coordination formulas. �� Metal and ligands are written continuously. �� Brackets are written without spaces.

✅ Correct Answer Explanation

IUPAC formula-writing rules require that coordination formulas be written without spaces between metal atoms, ligands and brackets. Therefore: [Co(NH₃)₅Cl]Cl₂ is the correct representation.

❓ Why Other Options Are Incorrect

�� Option A → Contains spaces.
�� Option C → Contains spaces.
�� Option D → Contains spaces around brackets.

🎯 Strategy

Used

Direct Recall

Application:

Apply spacing rules.

Final Logic:

No spaces anywhere inside the coordination formula.

🧠 Memory Trick

Coordination Formula = No Gaps.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Formula Writing Rules

📄 Passage

The names of coordination compounds are derived by following the principles of additive nomenclature. Thus, the groups that surround the central atom must be identified in the name. They are listed as prefixes to the name of the central atom along with any appropriate multipliers. The following rules are used when naming coordination compounds: (i) The cation is named first in both positively and negatively charged coordination entities. (ii) The ligands are named in an alphabetical order before the name of the central atom/ion.

Question:
According to the passage, when deriving the name for [Pt(NH₃)₂Cl₂], how should the groups surrounding the central atom be treated?

A They are listed as suffixes to the central atom.

B They are listed as prefixes to the name of the central atom.

C They are named after the cation but before the anion.

D They are ignored in additive nomenclature.

💡 Short Explanation

�� Additive nomenclature names ligands first. �� Ligands appear as prefixes. �� Metal name comes after ligand names.

✅ Correct Answer Explanation

The passage clearly states that groups surrounding the central atom are identified and written as prefixes before the metal name. For example: Diamminedichloridoplatinum(II) Here ligand names appear before platinum.

❓ Why Other Options Are Incorrect

�� Option A → Ligands are not suffixes.
�� Option C → Does not describe additive nomenclature.
�� Option D → Ligands are essential and cannot be ignored.

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

Use the naming rule stated in the passage.

Final Logic:

Ligands are written as prefixes.

🧠 Memory Trick

Ligands First, Metal Later.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Additive Nomenclature

📄 Passage

Question:
Based on the rules in the passage, if a compound consists of a potassium cation and a complex anion, which is named first?

A The complex anion

B The central metal

C The ligands

D The potassium cation

💡 Short Explanation

�� Cation is always named first. �� Potassium is the cation. �� The complex anion is named second.

✅ Correct Answer Explanation

According to IUPAC nomenclature, the cation is always named before the anion. For a compound containing K⁺ and a complex anion, potassium is named first, followed by the name of the complex anion. Therefore, Option D is correct.

❓ Why Other Options Are Incorrect

�� Option A → Anion is named second.
�� Option B → Metal naming follows ligand naming within the complex.
�� Option C → Ligands are not named before the cation.

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

Apply the cation-first naming rule from the passage.

Final Logic:

Cation precedes anion in nomenclature.

🧠 Memory Trick

Positive First, Negative Next.

📚 Class XII – Chemistry Part II – Chapter: Coordination Compounds – Topic: Naming Coordination Compounds

CUET UG Chemistry Booster Test – 2 Nomenclature

CUET UG Chemistry Booster Test - 2 Nomenclature

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