Basics of Chemical KineticsCUET UG Chemistry Booster Test - 3 Basics of Chemical Kinetics
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QUESTION 1 OF 20
Identify the correct statements regarding the conversion of diamond to graphite.
Statements:
1. Thermodynamic data establishes that diamond shall convert to graphite.
2. The actual conversion rate is imperceptibly slow.
3. Kinetic studies alone predict the thermodynamic feasibility of this conversion.
4. Graphite is thermodynamically more stable than diamond under ordinary conditions.
QUESTION 2 OF 20
If thermodynamic data yields a negative ΔG for a chemical change, but no macroscopic change is observed over several years, the most analytically sound conclusion is that:
QUESTION 3 OF 20
While thermodynamics successfully dictates the direction of a spontaneous change, its primary limitation in comprehensive chemical analysis is that it:
QUESTION 4 OF 20
For a reaction where ΔG < 0, a catalyst is introduced. What is the effect of the catalyst on the Gibbs energy and the reaction speed?
QUESTION 5 OF 20
A catalyst helps in attaining equilibrium faster. Which statement analytically describes its effect on the state of equilibrium?
QUESTION 6 OF 20
If a complex chemical reaction appears to be of tenth order based on the balanced stoichiometric equation, it actually takes place in several steps. The extent to which the overall rate is controlled depends on:
QUESTION 7 OF 20
What is the standard unit of the rate constant for a first-order chemical reaction?
QUESTION 8 OF 20
Analytically, why is the average rate generally incapable of predicting the true rate of a reaction at a particular exact instant?
QUESTION 9 OF 20
Based strictly on the passage, the order of a chemical reaction is defined as:
QUESTION 10 OF 20
According to the passage, the representation of the reaction rate in terms of the reactant concentrations is formally referred to as:
QUESTION 11 OF 20
Analytically, mitigating food spoilage by utilizing refrigeration relies on which core kinetic principle described by the Arrhenius equation?
QUESTION 12 OF 20
Match the chemical kinetics concept in List I with its corresponding characteristic in List II.
| List I | List II |
|---|---|
| 1. Rate law prediction | a. Can be zero and even a fraction |
| 2. Activation energy | b. Minimum energy required for an effective collision |
| 3. Molecularity | c. Must be determined experimentally, not merely by looking at the balanced equation |
| 4. Reaction order | d. Cannot be zero or a non-integer |
QUESTION 13 OF 20
Arrange the following conditions based on the half-life of N₂O₅ decomposition (from shortest half-life to longest half-life):
1. Decomposition at 25°C
2. Decomposition at 0°C
3. Decomposition at 50°C
QUESTION 14 OF 20
Identify the kinetic class of a reaction where a solid surface completely saturates with gas molecules at high pressure, causing the rate to become independent of further concentration changes.
QUESTION 15 OF 20
Evaluating the rate of a chemical reaction by continuously tracking the measurable decrease in the partial pressure of a reactant gas and integrating it mathematically over time yields an equation that equates a rate constant (k) to directly measured experimental data. This equation is known as:
QUESTION 16 OF 20
In collision theory, the factor "P" is introduced to account for effective collisions. What is the specific name for this factor?
QUESTION 17 OF 20
The collision theory proposed by Max Trautz and William Lewis models molecules as hard spheres. A significant deviation observed for complex molecules is that:
QUESTION 18 OF 20
Identify the correct statements regarding the molecular view of temperature dependence of reaction rates.
Statements:
1. The area under the Maxwell-Boltzmann distribution curve remains constant.
2. Increasing temperature increases the fraction of molecules having energy greater than Ea.
3. A rise of 10°C generally halves the rate constant of a reaction.
4. Increasing temperature increases the number of effective collisions.
QUESTION 19 OF 20
If a student is analyzing why the hydrolysis of ethyl acetate with excess water behaves kinetically as a first-order process despite having a molecularity of two, they are studying a:
QUESTION 20 OF 20
The derived integrated rate equation for a first-order reaction shows that its half-life (t½) is:
Test Complete!
Answer Review
1 Identify the correct statements regarding the conversion of diamond to graphite.
Statements:
1. Thermodynamic data establishes that diamond shall convert to graphite.
2. The actual conversion rate is imperceptibly slow.
3. Kinetic studies alone predict the thermodynamic feasibility of this conversion.
4. Graphite is thermodynamically more stable than diamond under ordinary conditions.
�� Graphite is thermodynamically more stable. �� Conversion is extremely slow. �� Kinetics does not determine thermodynamic feasibility.
Thermodynamic studies indicate that graphite is more stable than diamond under ordinary conditions. Therefore, the conversion of diamond into graphite is thermodynamically feasible. This makes Statement 1 correct. However, the conversion occurs at an extremely slow rate because of a very high activation energy barrier. Consequently, no noticeable change is observed during a human lifetime, making Statement 2 correct. Statement 3 is incorrect because thermodynamic feasibility is determined by thermodynamics, not by kinetics. Chemical kinetics only determines how rapidly the conversion occurs. Statement 4 is correct because the spontaneous tendency of diamond to convert into graphite arises from the greater thermodynamic stability of graphite. Thus, Statements 1, 2 and 4 are correct.
- �� Option B → Statement 3 is incorrect.
- �� Option C → Statement 3 is incorrect.
- �� Option D → Statement 3 is incorrect.
Used – Concept Application
- Application
- Differentiate thermodynamic feasibility from reaction rate.
- Final Logic
- Feasible conversion + extremely slow rate = diamond appears permanent.
- Diamond Can Change, But Not Today.
2 If thermodynamic data yields a negative ΔG for a chemical change, but no macroscopic change is observed over several years, the most analytically sound conclusion is that:
�� Negative ΔG indicates feasibility. �� No visible change indicates a slow reaction. �� High activation energy reduces reaction rate.
A negative Gibbs energy change indicates that the reaction is thermodynamically feasible. However, thermodynamics provides no information regarding the speed of the reaction. If no observable change occurs over many years despite ΔG being negative, the reaction must be proceeding at an extremely slow rate. This generally occurs when the activation energy barrier is very high. Only a very small fraction of molecules possess sufficient energy to cross this barrier, resulting in a negligible reaction rate. Therefore, the correct interpretation is not that the reaction is impossible, but that the kinetics are extremely unfavorable. This distinction between feasibility and rate is one of the most important concepts in chemical kinetics.
- �� Option A → Negative ΔG indicates feasibility.
- �� Option B → Lack of visible change does not necessarily imply equilibrium.
- �� Option D → Thermodynamic calculations are not necessarily incorrect.
Used – Concept Application
- Application
- Relate Gibbs energy to feasibility and activation energy to reaction speed.
- Final Logic
- Negative ΔG + no observable change = very slow kinetics.
- Can Happen ≠ Happens Fast.
3 While thermodynamics successfully dictates the direction of a spontaneous change, its primary limitation in comprehensive chemical analysis is that it:
�� Thermodynamics predicts spontaneity. �� It does not predict reaction speed. �� Reaction rate is studied by kinetics.
Thermodynamics is concerned with energy changes and spontaneity of reactions. It can predict whether a reaction is feasible under specified conditions by using parameters such as Gibbs energy. However, thermodynamics cannot answer questions regarding how quickly a reaction will occur. A thermodynamically feasible reaction may occur in a fraction of a second or may take millions of years. The study of reaction speed, activation energy and reaction mechanisms belongs to chemical kinetics. Therefore, the principal limitation of thermodynamics is that it provides no information about the time required for a reaction to proceed.
- �� Option A → Molecular orientation is explained by collision theory.
- �� Option C → Fractional order reactions are unrelated to thermodynamics.
- �� Option D → Thermodynamics applies to all types of systems.
Used – NCERT Recall
- Application
- Recall the distinction between thermodynamics and kinetics.
- Final Logic
- Thermodynamics answers "Can it occur?" not "How fast?"
- Kinetics = How Fast.
4 For a reaction where ΔG < 0, a catalyst is introduced. What is the effect of the catalyst on the Gibbs energy and the reaction speed?
�� Catalysts affect kinetics. �� Catalysts do not affect thermodynamics. �� Activation energy is reduced.
A catalyst provides an alternative reaction pathway having a lower activation energy. As a result, a greater fraction of molecules can undergo successful collisions, increasing the reaction rate. However, a catalyst does not alter the initial and final thermodynamic states of the system. Therefore, Gibbs energy change (ΔG), enthalpy change (ΔH) and equilibrium constant remain unchanged. The catalyst accelerates both forward and backward reactions equally and only affects the speed with which equilibrium is attained. Hence, ΔG remains unchanged while the reaction becomes faster due to a decrease in activation energy.
- �� Option A → Catalysts do not change ΔG.
- �� Option B → Equilibrium constant remains unchanged.
- �� Option C → Catalysts cannot reverse spontaneity.
Used – Concept Application
- Application
- Separate thermodynamic effects from kinetic effects.
- Final Logic
- Catalyst changes activation energy, not Gibbs energy.
- Catalyst Changes Path, Not Destination.
5 A catalyst helps in attaining equilibrium faster. Which statement analytically describes its effect on the state of equilibrium?
�� Catalysts increase both forward and reverse rates. �� Equilibrium is reached faster. �� Equilibrium position remains unchanged.
A catalyst lowers the activation energy for both forward and reverse reactions. Consequently, both reactions proceed more rapidly. Since the catalyst affects both directions equally, the ratio of forward and reverse rate constants remains unchanged. Therefore, the equilibrium constant is unaffected. The catalyst only reduces the time required to attain equilibrium. It does not change the equilibrium composition, equilibrium constant or position of equilibrium. Thus, the equilibrium state remains exactly the same, although it is reached more quickly.
- �� Option A → Equilibrium constant remains unchanged.
- �� Option B → Catalysts accelerate both directions.
- �� Option D → Catalysts do not suppress reverse reactions.
Used – Concept Application
- Application
- Analyze catalyst effects on forward and reverse reactions.
- Final Logic
- Catalyst speeds equilibrium attainment but does not shift equilibrium.
- Faster Equilibrium, Same Equilibrium.
6 If a complex chemical reaction appears to be of tenth order based on the balanced stoichiometric equation, it actually takes place in several steps. The extent to which the overall rate is controlled depends on:
�� Complex reactions occur through several elementary steps. �� One step is usually much slower than the others. �� The slowest step controls the overall reaction rate.
Many chemical reactions do not occur in a single step. Instead, they proceed through a sequence of elementary reactions collectively known as the reaction mechanism. Among these elementary steps, one step is usually slower than all the others. This slowest step acts as a bottleneck and limits the speed of the entire reaction. Therefore, it is called the rate determining step (RDS). No matter how rapidly the other steps occur, the overall reaction cannot proceed faster than the slowest step. Chemical kinetics uses this concept extensively to explain reaction rates and derive rate laws. Thus, for complex reactions, the overall reaction rate is governed primarily by the slowest elementary step rather than the average speed of all steps.
- �� Option B → Concentration affects rate but does not define the controlling step.
- �� Option C → Fast steps do not control the overall rate.
- �� Option D → The overall rate is not determined by the average of all steps.
Used – Concept Application
- Application
- Identify the step that limits the progress of a multistep reaction.
- Final Logic
- Slowest Step = Rate Determining Step = Overall Rate Control.
- Slowest Step Rules the Reaction.
7 What is the standard unit of the rate constant for a first-order chemical reaction?
�� First-order rate law: Rate = k[A]. �� Unit of rate = mol L⁻¹ s⁻¹. �� Unit of k becomes s⁻¹.
For a first-order reaction: The unit of rate is: and the unit of concentration is: Therefore, Hence, the rate constant of a first-order reaction has units of reciprocal time. This property is unique because the numerical value of the first-order rate constant remains independent of concentration units.
- �� Option A → Incorrect dimensional form.
- �� Option C → Unit of a second-order rate constant.
- �� Option D → Not the unit of a first-order rate constant.
Used – Unit Analysis
- Application
- Divide the unit of rate by the unit of concentration.
- Final Logic
- For first order, concentration units cancel completely.
- First Order → First Power Removed → s⁻¹.
8 Analytically, why is the average rate generally incapable of predicting the true rate of a reaction at a particular exact instant?
�� Average rate uses a finite time interval. �� Reaction rate often changes continuously. �� Instantaneous rate refers to one exact moment.
The average rate of a reaction is defined as the change in concentration divided by the time interval during which that change occurs. Since the calculation is performed over a measurable interval of time, it provides only the average behavior during that interval. In reality, reaction rates generally change continuously as concentrations of reactants and products change. Therefore, the true rate at a specific instant is called the instantaneous rate, which is obtained by considering an extremely small time interval approaching zero. Thus, average rate cannot accurately represent the exact reaction rate at a particular instant because it is based on a finite time interval.
- �� Option A → Stoichiometric coefficients are unrelated.
- �� Option B → Average rate applies to all reaction orders.
- �� Option D → Δt approaching zero defines instantaneous rate, not average rate.
Used – Concept Application
- Application
- Differentiate average rate from instantaneous rate.
- Final Logic
- Finite Interval → Average Rate; Instant → Instantaneous Rate.
- Instantaneous = Moment.
9
Based strictly on the passage, the order of a chemical reaction is defined as:
�� Order is obtained from the rate law. �� It is the sum of concentration powers. �� It may be zero, fractional or integral.
The rate law expresses the reaction rate in terms of reactant concentrations. For example: The order of the reaction is defined as: that is, the sum of the powers of concentration terms appearing in the rate law expression. The order of reaction is determined experimentally and need not be related to the stoichiometric coefficients of the balanced equation. It may be zero, fractional, integral or even negative in certain cases. Therefore, the correct definition is the sum of powers of reactant concentrations appearing in the rate law.
- �� Option A → Describes molecularity, not order.
- �� Option C → Order may be fractional.
- �� Option D → Represents concentration change, not reaction order.
Used – NCERT Recall
- Application
- Recall the formal definition of reaction order.
- Final Logic
- Order = Sum of Powers in the Rate Law.
- Add the Powers = Order.
10
According to the passage, the representation of the reaction rate in terms of the reactant concentrations is formally referred to as:
�� Rate law relates rate to concentrations. �� Also called rate equation or rate expression. �� Fundamental concept of kinetics.
The passage states that the representation of reaction rate in terms of the concentrations of reactants is known as the rate law. For a general reaction: the rate law can be written as: This expression relates the reaction rate to reactant concentrations and contains the rate constant k. The rate law is also known as the rate equation or rate expression. It forms the foundation for determining reaction order, predicting reaction behavior and analyzing kinetic data. Hence, the correct term is rate law or rate equation.
- �� Option A → Arrhenius factor relates to temperature dependence of k.
- �� Option B → Equilibrium constant describes equilibrium state.
- �� Option C → Integrated rate equation is derived from the rate law.
Used – NCERT Recall
- Application
- Recall the terminology used in chemical kinetics.
- Final Logic
- Rate expressed through concentrations = Rate Law.
- Rate + Concentration = Rate Law.
11 Analytically, mitigating food spoilage by utilizing refrigeration relies on which core kinetic principle described by the Arrhenius equation?
�� Refrigeration lowers temperature. �� Lower temperature decreases the rate constant. �� Fewer molecules possess energy greater than activation energy.
The Arrhenius equation, k = Ae^(-Ea/RT) shows the relationship between temperature and the rate constant of a reaction. According to NCERT, the rate constant increases with increasing temperature because a greater fraction of molecules acquires energy equal to or greater than the activation energy (Ea). Conversely, when temperature decreases, the fraction of energetic molecules decreases significantly. Food spoilage occurs through various chemical and biochemical reactions. Refrigeration slows these reactions by reducing the kinetic energy of molecules. As a result, fewer molecules can overcome the activation energy barrier, leading to a decrease in the rate constant. Since reaction rate is directly related to the rate constant, spoilage reactions proceed much more slowly. This principle explains why refrigerated food remains fresh for longer periods. The process does not change molecularity or spontaneity; it simply reduces the number of effective molecular collisions. Therefore, refrigeration works because decreasing temperature causes an exponential decrease in the rate constant.
- �� Option B → Molecularity is a fixed characteristic of an elementary reaction and is not altered by refrigeration.
- �� Option C → Refrigeration slows spoilage but does not necessarily make it thermodynamically non-spontaneous.
- �� Option D → Lowering temperature does not increase the pre-exponential factor.
Concept Application
- Application
- Apply the Arrhenius equation and relate temperature changes to the rate constant.
- Final Logic
- Lower temperature → Smaller fraction of energetic molecules → Smaller rate constant → Slower spoilage.
"Cold Food, Slow Molecules"
12 Match the chemical kinetics concept in List I with its corresponding characteristic in List II.
| List I | List II |
|---|---|
| 1. Rate law prediction | a. Can be zero and even a fraction |
| 2. Activation energy | b. Minimum energy required for an effective collision |
| 3. Molecularity | c. Must be determined experimentally, not merely by looking at the balanced equation |
| 4. Reaction order | d. Cannot be zero or a non-integer |
�� Rate laws are determined experimentally. �� Activation energy is the minimum energy needed for reaction. �� Molecularity is always a whole number. �� Reaction order can be zero or fractional.
According to NCERT, the rate law of a reaction generally cannot be predicted from the balanced chemical equation. It must be determined experimentally. Therefore, Rate law prediction matches with "must be determined experimentally." Activation energy is defined as the minimum amount of energy required for reactant molecules to undergo effective collisions and form products. Hence, Activation energy matches with "minimum energy required for an effective collision." Molecularity refers to the number of reacting species participating in an elementary reaction. Since it represents an actual count of particles, it can never be zero or fractional. Thus, Molecularity matches with "cannot be zero or a non-integer." Reaction order is the sum of the powers of concentration terms in the rate equation. It is experimentally determined and may be zero, integral, or fractional. Therefore, Reaction order matches with "can be zero and even a fraction." Thus, the correct matching is: 1-c, 2-b, 3-d, 4-a
- �� Option B → Molecularity cannot be fractional and activation energy is not determined experimentally in this context.
- �� Option C → Rate law prediction cannot be assigned to fractional order characteristics.
- �� Option D → Activation energy is not related to reaction order and rate law prediction is incorrectly matched.
NCERT Recall
- Application
- Recall the NCERT definitions of rate law, activation energy, molecularity, and order of reaction.
- Final Logic
- Rate Law → Experimental
- Activation Energy → Minimum Energy
- Molecularity → Whole Number Only
- Reaction Order → Can Be Fractional
- Order → Flexible Value
13 Arrange the following conditions based on the half-life of N₂O₅ decomposition (from shortest half-life to longest half-life):
1. Decomposition at 25°C
2. Decomposition at 0°C
3. Decomposition at 50°C
�� Higher temperature increases reaction rate. �� Faster reactions have shorter half-lives. �� Lower temperature increases half-life.
The Arrhenius equation states that the rate constant increases with increasing temperature. As temperature rises, a greater fraction of molecules possesses energy greater than the activation energy, resulting in more effective collisions and a faster reaction rate. The decomposition of N₂O₅ is a first-order reaction. For first-order reactions, half-life is inversely proportional to the rate constant: t½ = 0.693/k Thus, a larger rate constant corresponds to a shorter half-life. Among the given temperatures, 50°C provides the highest rate constant and therefore the shortest half-life. At 25°C, the rate constant is lower, producing an intermediate half-life. At 0°C, the rate constant is smallest, resulting in the longest half-life. Hence, the correct order from shortest half-life to longest half-life is: 50°C → 25°C → 0°C or 3 → 1 → 2
- �� Option A → Places the lowest temperature before the highest temperature.
- �� Option C → Does not follow the temperature dependence of half-life.
- �� Option D → Incorrectly places 0°C before 25°C.
Formula Application
- Application
- Use the relationship between temperature, rate constant, and half-life.
- Final Logic
- Higher temperature → Higher k → Smaller t½
- Therefore:
- 3 > 1 > 2 in rate and 3 → 1 → 2 in shortest-to-longest half-life.
"Hotter Means Shorter Half-Life"
14 Identify the kinetic class of a reaction where a solid surface completely saturates with gas molecules at high pressure, causing the rate to become independent of further concentration changes.
�� Surface saturation limits reaction rate. �� Additional reactant concentration has no effect. �� Rate becomes constant.
A zero-order reaction is one in which the reaction rate becomes independent of reactant concentration. According to NCERT, this situation may occur when a catalytic surface becomes completely saturated by reactant molecules. At high pressure, all available active sites on the catalyst surface are occupied. Once saturation is achieved, increasing the concentration or pressure of the reactant cannot increase the number of reacting molecules on the surface. As a result, the reaction rate remains constant. A classic example is the decomposition of HI on a gold surface. Since the catalyst surface is already fully occupied, the rate no longer depends on reactant concentration. The rate law becomes: Rate = k This is the defining characteristic of a zero-order reaction. Therefore, the correct kinetic classification is zero order reaction.
- �� Option A → Second-order reactions depend on concentration terms.
- �� Option B → Fractional-order reactions still show concentration dependence.
- �� Option D → Pseudo first-order reactions behave as first-order reactions under excess reactant conditions.
Concept Application
- Application
- Identify whether the rate changes with concentration.
- Final Logic
- Rate independent of concentration = Zero-order reaction.
"Surface Full, Rate Fixed"
15 Evaluating the rate of a chemical reaction by continuously tracking the measurable decrease in the partial pressure of a reactant gas and integrating it mathematically over time yields an equation that equates a rate constant (k) to directly measured experimental data. This equation is known as:
�� Experimental measurements are collected over time. �� Mathematical integration relates concentration or pressure to time. �� The resulting equation is called the integrated rate equation.
Chemical kinetics uses both differential and integrated rate equations. A differential rate equation expresses the rate of reaction in terms of concentration change at a particular instant. However, experimental measurements are often made by observing concentration or pressure changes over a period of time. To connect measurable quantities with the rate constant, the differential rate equation is mathematically integrated. The resulting expression is known as the integrated rate equation. According to NCERT, integrated rate equations relate concentration, pressure, or other measurable quantities directly to time and the rate constant. For example, in gaseous reactions, partial pressure measurements can be used in place of concentration. By integrating the rate law, one obtains equations that allow determination of the rate constant from experimental data. Therefore, the equation obtained through integration of rate expressions is called the integrated rate equation.
- �� Option A → Differential rate equations describe instantaneous rates rather than integrated relationships.
- �� Option C → The Arrhenius distribution curve describes energy distribution among molecules.
- �� Option D → The steric factor represents collision orientation probability.
NCERT Recall
- Application
- Recall the distinction between differential and integrated rate equations.
- Final Logic
- Integration of rate expressions gives integrated rate equations.
"Integrate the Rate, Get the Equation"
16 In collision theory, the factor "P" is introduced to account for effective collisions. What is the specific name for this factor?
�� Not all molecular collisions produce products. �� Proper orientation is necessary for effective collisions. �� The steric factor accounts for orientation requirements.
According to collision theory, molecules must collide with sufficient energy and proper orientation for a reaction to occur. However, even when molecules possess adequate energy, many collisions fail because the molecules are not oriented correctly for bond breaking and bond formation. To account for this observation, the factor "P" is introduced into collision theory. This factor is called the steric factor or probability factor. It represents the fraction of collisions that occur with the proper orientation required for product formation. For simple molecules, the steric factor is often close to unity. For complex molecules, the value may be very small because only a limited number of orientations lead to successful reactions. Thus, the steric factor helps explain why experimentally observed reaction rates are often lower than those predicted solely on the basis of collision frequency. Therefore, factor P is known as the steric factor or probability factor.
- �� Option B → Frequency factor refers to collision frequency and is represented by A in the Arrhenius equation.
- �� Option C → Arrhenius factor is not the specific term used for P.
- �� Option D → Boltzmann factor refers to the exponential term involving activation energy.
NCERT Recall
- Application
- Recall the modification introduced into collision theory to account for molecular orientation.
- Final Logic
- P represents the probability of proper orientation during collision.
"P = Proper Position"
17 The collision theory proposed by Max Trautz and William Lewis models molecules as hard spheres. A significant deviation observed for complex molecules is that:
�� Collision theory assumes reacting particles collide. �� Effective collisions require sufficient energy. �� Proper orientation is also necessary.
Collision theory was developed by Max Trautz and William Lewis to explain chemical reaction rates. The theory assumes that molecules behave like hard spheres that move continuously and collide with one another. However, experimental observations show that not every collision results in product formation. According to NCERT, effective collisions require two important conditions. First, colliding molecules must possess energy greater than or equal to the threshold energy. Second, the molecules must approach one another with a suitable orientation that allows bond breaking and bond formation. Complex molecules often have many possible orientations, but only a few of them are favorable for reaction. As a result, many collisions are ineffective despite occurring frequently. This explains why observed reaction rates are lower than those predicted by simple collision frequency calculations. Therefore, all collisions do not lead to product formation because of improper orientation and insufficient energy.
- �� Option A → Molecules do not possess infinite activation energy.
- �� Option B → Collision theory clearly states that only effective collisions form products.
- �� Option D → Collision theory is based on concepts derived from the kinetic theory of gases.
Concept Application
- Application
- Identify the conditions necessary for an effective collision.
- Final Logic
- Energy and orientation determine whether a collision becomes successful.
"Collision Alone Is Not Enough"
18 Identify the correct statements regarding the molecular view of temperature dependence of reaction rates.
Statements:
1. The area under the Maxwell-Boltzmann distribution curve remains constant.
2. Increasing temperature increases the fraction of molecules having energy greater than Ea.
3. A rise of 10°C generally halves the rate constant of a reaction.
4. Increasing temperature increases the number of effective collisions.
�� Temperature affects molecular energy distribution. �� More molecules exceed activation energy at higher temperatures. �� Effective collision frequency increases.
The Maxwell-Boltzmann distribution describes the distribution of molecular energies in a system. According to NCERT, the total area under the distribution curve remains constant because it represents the total number of molecules present. Therefore, Statement 1 is correct. As temperature increases, the distribution curve broadens and shifts so that a larger fraction of molecules possesses energy greater than the activation energy (Ea). Consequently, Statement 2 is correct. Because more molecules now possess sufficient energy for reaction, the number of effective collisions increases. Hence, Statement 4 is also correct. Statement 3 is incorrect because a rise of 10°C generally increases the reaction rate, often approximately doubling it, rather than halving the rate constant. Therefore, Statements 1, 2, and 4 are correct.
- �� Option A → Statement 3 is incorrect.
- �� Option B → Includes incorrect Statement 3 and omits Statement 1.
- �� Option C → Includes incorrect Statement 3 and omits Statement 2.
NCERT Recall
- Application
- Recall the effect of temperature on Maxwell-Boltzmann energy distribution.
- Final Logic
- Higher temperature means more energetic molecules and more effective collisions.
"Hotter Means More Above Ea"
19 If a student is analyzing why the hydrolysis of ethyl acetate with excess water behaves kinetically as a first-order process despite having a molecularity of two, they are studying a:
�� Molecularity remains two. �� Water is present in large excess. �� Its concentration remains nearly constant.
The hydrolysis of ethyl acetate normally involves two reactants: ethyl acetate and water. Therefore, the actual molecularity of the reaction is two. However, when water is present in very large excess, its concentration changes negligibly during the reaction. Under these conditions, the concentration of water is effectively constant and becomes part of the rate constant. The rate law can then be written in terms of only the concentration of ethyl acetate. As a result, the reaction appears to follow first-order kinetics even though two reactants participate in the reaction. According to NCERT, such reactions are known as pseudo first-order reactions. The term "pseudo" indicates that the experimentally observed order differs from the actual molecularity because one reactant is present in large excess. Thus, hydrolysis of ethyl acetate in excess water is a classic example of a pseudo first-order reaction.
- �� Option A → The reaction behaves as first order, not zero order.
- �� Option C → The reaction involves two reacting species, not three.
- �� Option D → Fractional-order behavior is not observed in this example.
Concept Application
- Application
- Check whether one reactant is present in large excess.
- Final Logic
- Large excess of one reactant converts a higher-order reaction into an apparent first-order reaction.
"One Reactant in Excess = Pseudo First Order"
20 The derived integrated rate equation for a first-order reaction shows that its half-life (t½) is:
�� First-order reactions have a characteristic half-life. �� Half-life depends only on the rate constant. �� Initial concentration does not affect t½.
For a first-order reaction, the integrated rate equation leads to the expression: t½ = 0.693/k where k is the first-order rate constant. This equation shows that the half-life depends only on the value of the rate constant and is completely independent of the initial concentration of the reactant. This property is unique and extremely important. Regardless of how much reactant is present initially, the time required for the concentration to decrease to half of its value remains the same. Radioactive decay and many decomposition reactions exhibit this behavior. According to NCERT, the concentration independence of half-life is a characteristic feature of first-order reactions and is widely used in kinetic analysis. Therefore, the half-life of a first-order reaction is constant and does not depend on the initial concentration of the reacting species.
- �� Option A → First-order half-life is not proportional to initial concentration.
- �� Option B → Initial pressure does not appear in the half-life expression.
- �� Option D → The Arrhenius frequency factor is unrelated to half-life.
Formula Application
- Application
- Use the first-order half-life equation.
- Final Logic
- t½ = 0.693/k contains no concentration term; therefore, half-life is constant.
"First Order, Fixed Half-Life"
