CUET UG Chemistry Booster Test -3 Carboxylic Acids (Structure, Properties, Reactions & Uses)
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QUESTION 1 OF 20
Properties contrasting carboxylic acids and carbonyl compounds:
(A) Carboxylic acids contain a carbonyl group but do not show standard nucleophilic addition of aldehydes/ketones.
(B) The carboxyl carbon's electrophilicity is reduced due to resonance from the –OH group.
(C) Carboxylic acids are less polar than ethers.
(D) The carboxyl group is electron-withdrawing.
QUESTION 2 OF 20
Which of the following condensed formulas accurately represents succinic acid?
QUESTION 3 OF 20
Hexanedioic acid is a key aliphatic dicarboxylic acid. What is its common name?
QUESTION 4 OF 20
Electrophilic substitution in aromatic carboxylic acids:
(A) The carboxyl group acts as a deactivating group.
(B) The carboxyl group directs incoming electrophiles to the meta position.
(C) They do not undergo Friedel-Crafts alkylation.
(D) The Lewis acid catalyst (AlCl₃) bonds directly to the carboxyl group.
QUESTION 5 OF 20
Match List-I (IUPAC Name) with List-II (Common Name):
| List-I | List-II |
|---|---|
| 1. Ethanedioic acid | a. Malonic acid |
| 2. Propanedioic acid | b. Succinic acid |
| 3. Butanedioic acid | c. Glutaric acid |
| 4. Pentanedioic acid | d. Oxalic acid |
QUESTION 6 OF 20
IUPAC name of HOOC–CH₂–CH(COOH)–CH₂–COOH is:
QUESTION 7 OF 20
Compared to the C=O bond in pure ketones, the C=O bond in carboxylic acids:
QUESTION 8 OF 20
Conjugate base stabilization by resonance effect:
(A) The carboxylate ion has two equivalent resonance structures.
(B) The negative charge is delocalized over two highly electronegative oxygen atoms.
(C) The carboxylate ion is more stabilized than the phenoxide ion.
(D) Resonance is the primary reason carboxylic acids are more acidic than phenols.
QUESTION 9 OF 20
Identify reaction type when alkylbenzenes are treated with alkaline potassium permanganate followed by acidic hydrolysis.
QUESTION 10 OF 20
Arrange the following compounds in order of their typical appearance in the sequential oxidation pathway of a hydrocarbon to a carboxylic acid:
(A) Carboxylic acid
(B) Primary alcohol
(C) Aldehyde
(D) Alkane
QUESTION 11 OF 20
To prepare propanoic acid starting from a halogenated alkane through ascending the series via a nitrile intermediate, which starting material is required?
QUESTION 12 OF 20
Identify reaction type describing the initial interaction between a Grignard reagent (R-MgX) and Carbon Dioxide (O=C=O).
QUESTION 13 OF 20
According to the passage, why do higher aliphatic carboxylic acids (C10 and above) lack distinct odours?
QUESTION 14 OF 20
Based on the passage, the extensive association that prevents the complete breaking of bonds in the vapour phase is attributed to:
QUESTION 15 OF 20
Arrange the following aromatic acids in increasing order of their pKa values (from strongest acid to weakest acid):
(A) 4-Nitrobenzoic acid
(B) Benzoic acid
(C) 4-Methoxybenzoic acid
(D) 3,4-Dinitrobenzoic acid
QUESTION 16 OF 20
Arrange the following haloacetic acids in increasing order of their acidic strength:
(A) FCH₂COOH
(B) ClCH₂COOH
(C) BrCH₂COOH
(D) ICH₂COOH
QUESTION 17 OF 20
Mechanistic steps of Fischer esterification:
(A) Protonation of the carbonyl oxygen activates the carbonyl group.
(B) The alcohol acts as a nucleophile to form a tetrahedral intermediate.
(C) Proton transfer converts the –OH group to a better leaving group (–OH₂⁺).
(D) A neutral water molecule is eliminated to form the protonated ester.
QUESTION 18 OF 20
Identify reaction type when an aqueous solution of sodium or potassium salt of a carboxylic acid undergoes electrolysis to yield a hydrocarbon.
QUESTION 19 OF 20
Match List-I (Carboxylic acid compound) with List-II (Specific industrial role):
| List-I | List-II |
|---|---|
| 1. Sodium benzoate | a. Perfumery blending |
| 2. Hexanedioic acid | b. Food preservative |
| 3. Esters of benzoic acid | c. Electroplating and leather industry |
| 4. Methanoic acid | d. Polymer manufacturing (Nylon-6,6) |
QUESTION 20 OF 20
Higher fatty acids are crucial in daily life applications because their sodium or potassium salts function primarily as:
Test Complete!
Answer Review
1 Properties contrasting carboxylic acids and carbonyl compounds:
(A) Carboxylic acids contain a carbonyl group but do not show standard nucleophilic addition of aldehydes/ketones.
(B) The carboxyl carbon's electrophilicity is reduced due to resonance from the –OH group.
(C) Carboxylic acids are less polar than ethers.
(D) The carboxyl group is electron-withdrawing.
�� Carboxylic acids contain both carbonyl and hydroxyl groups. �� Resonance reduces the electrophilicity of the carboxyl carbon. �� The carboxyl group is strongly electron-withdrawing.
Carboxylic acids possess a carbonyl group, but unlike aldehydes and ketones, they do not readily undergo nucleophilic addition because resonance involving the hydroxyl oxygen reduces the positive character on the carbonyl carbon. The –COOH group also withdraws electron density through both inductive and resonance effects. Therefore, statements A, B and D are correct.
- �� C is incorrect because carboxylic acids are more polar than ethers due to the presence of both carbonyl and hydroxyl groups.
Used
- Statement-Based MCQ
- –OH donates by resonance, reducing carbonyl reactivity.
2 Which of the following condensed formulas accurately represents succinic acid?
�� Succinic acid is a four-carbon dicarboxylic acid. �� It contains two carboxyl groups separated by two methylene groups. �� Its IUPAC name is butanedioic acid.
Structure: [ HOOC-CH_2-CH_2-COOH ] This can be written as: [ HOOC-(CH_2)_2-COOH ] Hence, succinic acid is butanedioic acid.
- �� A = Oxalic acid (ethanedioic acid).
- �� B = Malonic acid (propanedioic acid).
- �� D = Glutaric acid (pentanedioic acid).
Used
- Unit-Based MCQ
- Succinic = Butanedioic = 4 carbons.
3 Hexanedioic acid is a key aliphatic dicarboxylic acid. What is its common name?
�� Hexanedioic acid contains six carbon atoms. �� Its common name is adipic acid. �� It is used in Nylon-6,6 manufacture.
[ HOOC-(CH_2)_4-COOH ] The IUPAC name is hexanedioic acid. Its common name is adipic acid, an important industrial chemical used in polymer production.
- �� A. Glutaric acid = Pentanedioic acid.
- �� C. Succinic acid = Butanedioic acid.
- �� D. Malonic acid = Propanedioic acid.
Used
- Concept MCQ
- Adipic acid → Nylon-6,6 → Hexanedioic acid.
4 Electrophilic substitution in aromatic carboxylic acids:
(A) The carboxyl group acts as a deactivating group.
(B) The carboxyl group directs incoming electrophiles to the meta position.
(C) They do not undergo Friedel-Crafts alkylation.
(D) The Lewis acid catalyst (AlCl₃) bonds directly to the carboxyl group.
�� The –COOH group withdraws electrons from the benzene ring. �� It deactivates the ring and directs substitution to the meta position. �� It interferes with Friedel-Crafts reactions.
The carboxyl group withdraws electron density through both −I and −R effects. As a result: • The aromatic ring becomes less reactive. • Electrophiles preferentially enter the meta position. • Friedel-Crafts alkylation/acylation generally does not occur. • AlCl₃ coordinates strongly with the carboxyl group, further deactivating the ring. Thus A, B, C and D are correct.
- �� Options B, C and D omit one or more correct statements.
Used
- Statement-Based MCQ
- –COOH = Meta director + Ring deactivator.
5 Match List-I (IUPAC Name) with List-II (Common Name):
| List-I | List-II |
|---|---|
| 1. Ethanedioic acid | a. Malonic acid |
| 2. Propanedioic acid | b. Succinic acid |
| 3. Butanedioic acid | c. Glutaric acid |
| 4. Pentanedioic acid | d. Oxalic acid |
�� Ethanedioic acid = Oxalic acid. �� Propanedioic acid = Malonic acid. �� Butanedioic acid = Succinic acid. �� Pentanedioic acid = Glutaric acid.
IUPAC Name — Common Name Ethanedioic acid — Oxalic acid Propanedioic acid — Malonic acid Butanedioic acid — Succinic acid Pentanedioic acid — Glutaric acid Therefore: 1-d, 2-a, 3-b, 4-c
- �� Options B, C and D contain incorrect pairings of dicarboxylic acids.
Used
- Match the Following
- Oxalic (2C) → Malonic (3C) → Succinic (4C) → Glutaric (5C)
6 IUPAC name of HOOC–CH₂–CH(COOH)–CH₂–COOH is:
�� The parent skeleton is propane. �� Three carboxyl groups are attached to carbon 1, 2 and 3. �� Hence the IUPAC name is propane-1,2,3-tricarboxylic acid.
The structure: HOOC-CH2-CH(COOH)CH2-COOH can be viewed as a propane chain where each carbon bears a carboxyl group: CH2(COOH)-CH(COOH)-CH2(COOH) So the correct IUPAC name is: Propane-1,2,3-tricarboxylic acid
- �� Option A is the common name, not IUPAC.
- �� Option B has incorrect parent-chain selection.
- �� Option D has incorrect carbon framework.
Used
- Naming
- 3-carbon chain + 3 COOH groups = propane-tricarboxylic acid.
7 Compared to the C=O bond in pure ketones, the C=O bond in carboxylic acids:
�� The –OH oxygen donates electron density by resonance. �� Resonance delocalizes electrons in the carboxyl group. �� This gives the C=O bond partial single-bond character.
In carboxylic acids, the lone pair on the hydroxyl oxygen participates in resonance with the carbonyl group. This delocalization reduces the pure double-bond character of the C=O bond, giving it some partial single-bond character compared with ketones.
- �� Option A: The double-bond character is reduced, not completely lost.
- �� Option C: The bond is polarized toward oxygen, not carbon.
- �� Option D: Carboxyl carbon is sp² with about 120° bond angles, not 180°.
Used
- Concept MCQ
- Resonance makes bonds "in-between" single and double.
8 Conjugate base stabilization by resonance effect:
(A) The carboxylate ion has two equivalent resonance structures.
(B) The negative charge is delocalized over two highly electronegative oxygen atoms.
(C) The carboxylate ion is more stabilized than the phenoxide ion.
(D) Resonance is the primary reason carboxylic acids are more acidic than phenols.
�� Carboxylate ion has two equivalent resonance forms. �� Negative charge is shared by two oxygen atoms. �� This strong stabilization makes carboxylic acids more acidic than phenols.
The carboxylate ion is highly stabilized because its negative charge is equally delocalized over two oxygen atoms through two equivalent resonance structures. In phenoxide ion, the charge is delocalized partly onto less electronegative carbon atoms of the benzene ring. Therefore, carboxylate ion is more stable than phenoxide ion, making carboxylic acids stronger acids than phenols. Thus, all four statements are correct.
- �� Options B, C and D omit one correct statement.
Used
- Statement-Based MCQ
- Carboxylate = two equal oxygen homes for negative charge.
9 Identify reaction type when alkylbenzenes are treated with alkaline potassium permanganate followed by acidic hydrolysis.
�� KMnO₄ oxidizes alkyl side chains. �� Aromatic ring remains intact. �� Benzoic acid is formed after acidification.
Alkylbenzenes undergo side-chain oxidation with alkaline KMnO₄. The alkyl side chain is oxidized completely to the carboxyl group, while the benzene ring remains unchanged. Acidic hydrolysis gives the corresponding aromatic carboxylic acid. Example: C6H5CH3KMnO4/OH−C6H5COO−H+C6H5COOH3 . Why Other Options Are Incorrect • Option B: No electrophilic substitution occurs. • Option C: No radical halogenation occurs. • Option D: No nucleophilic substitution occurs.
Used
- Reaction Type
- Alkylbenzene + KMnO₄ = side chain becomes COOH.
10 Arrange the following compounds in order of their typical appearance in the sequential oxidation pathway of a hydrocarbon to a carboxylic acid:
(A) Carboxylic acid
(B) Primary alcohol
(C) Aldehyde
(D) Alkane
�� Alkane is first oxidized to alcohol. �� Primary alcohol oxidizes to aldehyde. �� Aldehyde further oxidizes to carboxylic acid.
The usual oxidation sequence is: Alkane Primary Alcohol Aldehyde Carboxylic Acid So the correct order is: (D), (B), (C), (A)
- �� Options B, C and D do not follow the correct oxidation pathway.
Used
- Ordering
- Alkane → Alcohol → Aldehyde → Acid.
11 To prepare propanoic acid starting from a halogenated alkane through ascending the series via a nitrile intermediate, which starting material is required?
�� Nitrile formation increases the carbon chain by one carbon atom. �� Chloroethane contains 2 carbon atoms. �� After nitrile formation and hydrolysis, a 3-carbon acid is obtained.
The conversion occurs as: CH3CH2Cl {KCN} CH3CH2CN (Propanenitrile) [ CH_3CH_2CN \xrightarrow{H^+/OH^-} CH_3CH_2COOH ] (Propanoic acid) Since the nitrile carbon becomes part of the carboxylic acid group, the carbon chain increases by one carbon atom. Therefore, chloroethane is the correct starting material.
- �� A. Chloromethane → Gives ethanoic acid.
- �� C. Chloropropane → Gives butanoic acid.
- �� D. Chlorobutane → Gives pentanoic acid.
Used
- Concept MCQ
- Alkyl halide + KCN = Chain length increases by 1 carbon.
12 Identify reaction type describing the initial interaction between a Grignard reagent (R-MgX) and Carbon Dioxide (O=C=O).
�� Grignard reagents behave as nucleophiles. �� Carbon dioxide contains an electrophilic carbon atom. �� The nucleophile attacks the carbon of CO₂.
The carbon attached to magnesium in a Grignard reagent behaves like a carbanion. RMgX + CO2 RCOO-MgX+ The nucleophilic carbon attacks the electrophilic carbon of carbon dioxide, producing a carboxylate salt. Acidification subsequently forms a carboxylic acid. Hence, the reaction is classified as nucleophilic addition.
- �� A. Electrophilic aromatic substitution occurs in aromatic rings.
- �� C. Elimination involves removal of atoms/groups.
- �� D. Free radical substitution proceeds through radicals.
Used
- Reaction Type
- Grignard attacks CO₂ → Addition → Carboxylic acid.
13 According to the passage, why do higher aliphatic carboxylic acids (C10 and above) lack distinct odours?
�� Higher carboxylic acids are wax-like solids. �� They evaporate very slowly. �� Low volatility reduces odour detection.
The passage states that higher carboxylic acids are wax-like solids and are practically odourless because they have very low volatility. Odour is perceived only when molecules enter the vapour phase and reach olfactory receptors. Since these acids do not vaporize readily, they show little or no smell.
- �� A. They are solids, not gases.
- �� C. Water solubility is unrelated to odour.
- �� D. They do not decompose at room temperature.
Used
- Passage-Based MCQ
- Less volatile = Less smell.
14 Based on the passage, the extensive association that prevents the complete breaking of bonds in the vapour phase is attributed to:
�� Carboxylic acids form strong hydrogen-bonded dimers. �� Association persists even in vapour phase. �� This causes unusually high boiling points.
Carboxylic acid molecules associate through strong intermolecular hydrogen bonding. Two molecules often form cyclic dimers: [ (RCOOH)_2 ] These hydrogen bonds are strong enough that association is not completely destroyed even in the vapour phase. This explains their high boiling points.
- �� A. Carboxylic acids are not ionic compounds.
- �� C. They do not form covalent networks.
- �� D. London forces alone cannot explain such extensive association.
Used
- Passage-Based MCQ
- Carboxylic acids travel in pairs (dimers).
15 Arrange the following aromatic acids in increasing order of their pKa values (from strongest acid to weakest acid):
(A) 4-Nitrobenzoic acid
(B) Benzoic acid
(C) 4-Methoxybenzoic acid
(D) 3,4-Dinitrobenzoic acid
�� Electron-withdrawing groups increase acidity. �� Nitro groups strongly stabilize the carboxylate ion. �� Methoxy donates electrons and decreases acidity.
Acidity increases when electron-withdrawing groups stabilize the conjugate base. Order of electron-withdrawing effect: (NO2)2 > NO2 > H > OCH3 Therefore: 3,4-Dinitrobenzoic acid 4-Nitrobenzoic acid Benzoic acid 4-Methoxybenzoic acid Since stronger acids have lower pKa values, the increasing order of pKa is: (D) < (A) < (B) < (C)
- �� Options B, C and D do not correctly account for the electron-withdrawing and electron-donating effects of substituents.
Used
- Ordering
- More NO₂ groups = Stronger acid = Lower pKa.
16 Arrange the following haloacetic acids in increasing order of their acidic strength:
(A) FCH₂COOH
(B) ClCH₂COOH
(C) BrCH₂COOH
(D) ICH₂COOH
�� Halogens increase acidity through the −I (electron-withdrawing) effect. �� The −I effect follows F > Cl > Br > I. �� Stronger electron withdrawal stabilizes the carboxylate ion more effectively.
The acidity of haloacetic acids depends on the electron-withdrawing inductive effect of the halogen attached to the α-carbon. Order of −I effect: [ F > Cl > Br > I ] Greater electron withdrawal stabilizes the carboxylate ion and increases acidity. Therefore: [ ICH_2COOH < BrCH_2COOH < ClCH_2COOH < FCH_2COOH ] Thus, the increasing order of acidity is: [ (D) < (C) < (B) < (A) ]
- �� Options B, C and D do not follow the correct inductive effect order of halogens.
Used
- Ordering
- F is the most electronegative, so fluoroacetic acid is the strongest.
17 Mechanistic steps of Fischer esterification:
(A) Protonation of the carbonyl oxygen activates the carbonyl group.
(B) The alcohol acts as a nucleophile to form a tetrahedral intermediate.
(C) Proton transfer converts the –OH group to a better leaving group (–OH₂⁺).
(D) A neutral water molecule is eliminated to form the protonated ester.
�� Esterification proceeds through acid-catalyzed nucleophilic addition-elimination. �� Protonation activates the carbonyl carbon. �� Water elimination ultimately produces the ester.
The Fischer esterification mechanism involves: 1. Protonation of the carbonyl oxygen. 2. Nucleophilic attack by alcohol. 3. Formation of a tetrahedral intermediate. 4. Proton transfer converting –OH into –OH₂⁺. 5. Elimination of water. 6. Deprotonation to form the ester. Hence all four statements are correct.
- �� Options B, C and D omit one or more essential mechanistic steps.
Used
- Statement-Based MCQ
- Protonate → Attack → Transfer → Water leaves → Ester forms
18 Identify reaction type when an aqueous solution of sodium or potassium salt of a carboxylic acid undergoes electrolysis to yield a hydrocarbon.
�� Carboxylate ions undergo anodic oxidation. �� Carbon dioxide is released. �� Alkyl radicals couple to form hydrocarbons.
In Kolbe electrolysis: [ RCOO^- \rightarrow R^\bullet + CO_2 ] The radicals formed at the anode combine: [ R^\bullet + R^\bullet \rightarrow R-R ] Thus hydrocarbons are produced through electrolysis of sodium or potassium carboxylates.
- �� A. Clemmensen reduction reduces carbonyl compounds.
- �� C. Wolff-Kishner reduction converts carbonyl groups into methylene groups.
- �� D. HVZ reaction introduces halogen at the α-position of carboxylic acids.
Used
- Reaction Type
- Kolbe = Carboxylate electrolysis → Hydrocarbon formation
19 Match List-I (Carboxylic acid compound) with List-II (Specific industrial role):
| List-I | List-II |
|---|---|
| 1. Sodium benzoate | a. Perfumery blending |
| 2. Hexanedioic acid | b. Food preservative |
| 3. Esters of benzoic acid | c. Electroplating and leather industry |
| 4. Methanoic acid | d. Polymer manufacturing (Nylon-6,6) |
�� Sodium benzoate is a common preservative. �� Hexanedioic acid (adipic acid) is used in Nylon-6,6 production. �� Benzoate esters are used in perfumes. �� Methanoic acid is used in leather and electroplating industries.
Compound — Industrial Role Sodium benzoate — Food preservative Hexanedioic acid (Adipic acid) — Nylon-6,6 manufacture Esters of benzoic acid — Perfumery blending Methanoic acid — Electroplating and leather industry Therefore: 1-b, 2-d, 3-a, 4-c
- �� Options B, C and D incorrectly match one or more industrial applications.
Used
- Match the Following
- Benzoate = Preservative; Adipic = Nylon; Benzoate esters = Perfume; Formic acid = Leather
20 Higher fatty acids are crucial in daily life applications because their sodium or potassium salts function primarily as:
�� Higher fatty acids contain long hydrocarbon chains. �� Their sodium and potassium salts are soaps. �� These compounds are widely used as cleansing agents.
Higher fatty acids such as stearic acid and palmitic acid form sodium or potassium salts when treated with alkali. Examples: [ C_{17}H_{35}COONa ] (Sodium stearate) These salts possess a hydrophobic tail and hydrophilic head, making them effective surfactants used in soaps and detergents.
- �� A. Artificial sweeteners are unrelated compounds.
- �� B. Food preservatives are typically compounds such as sodium benzoate.
- �� D. Solvents for paints are not the primary use of fatty acid salts.
Used
- Concept MCQ
- Fatty acid salt = Soap
