CUET UG Chemistry Booster Test - 3 Introduction & Nomenclature (Aldehydes and Ketones)
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QUESTION 1 OF 20
Regarding the electronic properties of the carbonyl group:
1. It has high polarity explained on the basis of resonance involving neutral and dipolar structures.
2. The carbonyl carbon acts as an electrophilic Lewis acid.
3. It is non-polar compared to ethers.
QUESTION 2 OF 20
Compounds in which the carbon of the carbonyl group is bonded to the nitrogen of an –NH₂ moiety are classified as:
QUESTION 3 OF 20
What fundamental sub-unit constitutes an aldehyde functional group?
QUESTION 4 OF 20
A ketone group cannot exist at the terminal position of an open carbon chain because:
QUESTION 5 OF 20
What is the common name of the naturally occurring aldehyde derived from vanilla beans?
QUESTION 6 OF 20
Which specific class of compounds are heavily utilized as starting materials for preparing adhesives, paints, and resins?
QUESTION 7 OF 20
Match the Latin source term with its corresponding common carboxylic acid/aldehyde derivation:
| List-I | List-II |
|---|---|
| 1. Formica (ant) | a. Formic acid |
| 2. Acetum (vinegar) | b. Acetic acid |
| 3. Butyrum (butter) | c. Butyric acid |
QUESTION 8 OF 20
The common name for the ketone CH₃COCH₂CH₂CH₃ is derived by naming the two alkyl groups bonded to the carbonyl group. What is it?
QUESTION 9 OF 20
According to the passage, the carbon atom located exactly two positions away from the aldehyde group (next to alpha) is designated as:
QUESTION 10 OF 20
If a substituent is attached to the carbon immediately adjacent to the carbonyl group in an aldehyde, its locant in the common system is:
QUESTION 11 OF 20
For IUPAC naming of aliphatic open chain aldehydes, the longest carbon chain must:
QUESTION 12 OF 20
What is the IUPAC name for Diisopropyl ketone?
QUESTION 13 OF 20
Identify the correct numbering formatting rule for naming substituents on a branched aldehyde carbon chain.
QUESTION 14 OF 20
Arrange the following steps for deriving the IUPAC name of an open-chain ketone in the correct logical sequence:
(A) Number the chain from the end nearer to the carbonyl group.
(B) Identify the longest continuous carbon chain containing the >C=O group.
(C) Replace the '-e' ending of the parent alkane with '-one'.
(D) Prefix substituents alphabetically with their numerals.
QUESTION 15 OF 20
The common name α-Methylcyclohexanone has the systematic IUPAC name:
QUESTION 16 OF 20
When naming cyclic compounds with an attached aldehyde group:
1. The suffix carbaldehyde is added after the full name of the cycloalkane.
2. The numbering of the ring starts from the carbon atom attached to the aldehyde group.
3. It is named identically to open-chain aldehydes using the suffix -al.
QUESTION 17 OF 20
The compound Phthaldehyde consists of a benzene ring with two aldehyde groups. Its IUPAC name is:
QUESTION 18 OF 20
In naming substituted benzaldehydes via IUPAC rules, the ring numbering assigns position 1 to:
QUESTION 19 OF 20
Mesityl oxide has the corresponding IUPAC name:
QUESTION 20 OF 20
Match the Common Name with the correct IUPAC Name from the examples table:
| List-I | List-II |
|---|---|
| 1. Isobutyraldehyde | a. 2-Methylpropanal |
| 2. Valeraldehyde | b. Pentanal |
| 3. Acrolein | c. Prop-2-enal |
Test Complete!
Answer Review
1 Regarding the electronic properties of the carbonyl group:
1. It has high polarity explained on the basis of resonance involving neutral and dipolar structures.
2. The carbonyl carbon acts as an electrophilic Lewis acid.
3. It is non-polar compared to ethers.
�� Carbonyl group is highly polar. �� Carbonyl carbon is electrophilic. �� Carbonyl compounds are more polar than ethers.
The carbonyl group exhibits resonance between a neutral structure and a dipolar structure, creating significant polarity. Due to the partial positive charge on carbon, the carbonyl carbon behaves as an electrophilic Lewis acid and readily undergoes nucleophilic attack.
- �� Statement 3 is incorrect because carbonyl compounds are polar.
- �� Options B, C and D contain statement 3.
Used
- Concept Analysis
- C=O ⇒ Cδ⁺ and Oδ⁻.
2 Compounds in which the carbon of the carbonyl group is bonded to the nitrogen of an –NH₂ moiety are classified as:
�� Amides contain the –CONH₂ group. �� Carbonyl carbon is directly attached to nitrogen. �� They are carboxylic acid derivatives.
Amides have the general structure R–CONH₂, where the carbonyl carbon is bonded directly to a nitrogen atom of an amino group.
- �� Option A → Carbonyl attached to halogen.
- �� Option C → Carbonyl attached to oxygen.
- �� Option D → Carbonyl attached to two carbon atoms.
Used
- Functional Group Identification
- Amide = CO + NH₂.
3 What fundamental sub-unit constitutes an aldehyde functional group?
�� Aldehydes contain the –CHO group. �� Carbonyl carbon is bonded to hydrogen. �� Distinguishes aldehydes from ketones.
An aldehyde contains a carbonyl group in which the carbonyl carbon is bonded to at least one hydrogen atom. Its general structure is R–CHO.
- �� Option A → Ketone structure.
- �� Option C → Carboxylic acid structure.
- �� Option D → Acyl halide structure.
Used
- Functional Group Recognition
- Aldehyde = CHO.
4 A ketone group cannot exist at the terminal position of an open carbon chain because:
�� Ketone carbonyl carbon is internal. �� It must be attached to two carbon atoms. �� Terminal carbonyl gives an aldehyde.
In ketones, the carbonyl carbon is bonded to two carbon atoms. Therefore, the carbonyl group cannot occur at the end of an open-chain molecule.
- �� Option A → Characteristic of aldehydes.
- �� Option C → Ketones contain no triple bond.
- �� Option D → Carbonyl carbon is sp² hybridized.
Used
- Structure Analysis
- Ketone = C–CO–C.
5 What is the common name of the naturally occurring aldehyde derived from vanilla beans?
�� Vanilla beans contain vanillin. �� Responsible for vanilla fragrance. �� Naturally occurring aldehyde.
Vanillin is the naturally occurring aromatic aldehyde extracted from vanilla beans and is responsible for their characteristic aroma.
- �� Option A → Found in cinnamon.
- �� Option B → Found in meadow sweet.
- �� Option D → Unsaturated aldehyde.
Used
- Fact Recall
- Vanilla → Vanillin.
6 Which specific class of compounds are heavily utilized as starting materials for preparing adhesives, paints, and resins?
�� Widely used in industry. �� Important raw materials. �� Used in adhesives, paints and resins.
Aldehydes, ketones and related carbonyl compounds are extensively used in manufacturing adhesives, paints, resins, plastics, pharmaceuticals and fragrances.
- �� Option A → Less commonly used for such applications.
- �� Option C → Not primary industrial precursors here.
- �� Option D → Mainly intermediates in organic synthesis.
Used
- Application Recall
- Carbonyl compounds = Industrial building blocks.
7 Match the Latin source term with its corresponding common carboxylic acid/aldehyde derivation:
| List-I | List-II |
|---|---|
| 1. Formica (ant) | a. Formic acid |
| 2. Acetum (vinegar) | b. Acetic acid |
| 3. Butyrum (butter) | c. Butyric acid |
�� Formica means ant. �� Acetum means vinegar. �� Butyrum means butter.
Latin Source — Derived Acid Formica (ant) — Formic acid Acetum (vinegar) — Acetic acid Butyrum (butter) — Butyric acid Therefore: 1-a, 2-b, 3-c
- �� Options B, C and D contain incorrect matching pairs.
Used
- Match the Following
- Ant → Formic, Vinegar → Acetic, Butter → Butyric.
8 The common name for the ketone CH₃COCH₂CH₂CH₃ is derived by naming the two alkyl groups bonded to the carbonyl group. What is it?
�� Ketone contains methyl and n-propyl groups. �� Common nomenclature uses alkyl group names. �� Followed by the word ketone.
The structure CH₃COCH₂CH₂CH₃ contains: One methyl group (CH₃–) One n-propyl group (CH₂CH₂CH₃) Hence the common name is: Methyl n-propyl ketone
- �� Option A → IUPAC name.
- �� Option C → Represents pentan-3-one.
- �� Option D → Incorrect carbon count.
Used
- Common Naming Analysis
- Name both alkyl groups + ketone.
9 According to the passage, the carbon atom located exactly two positions away from the aldehyde group (next to alpha) is designated as:
�� Carbon directly attached to CHO = α-carbon. �� Next carbon = β-carbon. �� Greek letters indicate position.
The passage states: α-carbon → directly attached to aldehyde group β-carbon → next carbon after α γ-carbon → next after β Therefore, the carbon located next to α-carbon is the β-carbon.
- �� Option A → Directly attached carbon.
- �� Option C → Third position away.
- �� Option D → Fourth position away.
Used
- Passage-Based Recall
- α → β → γ → δ
10 If a substituent is attached to the carbon immediately adjacent to the carbonyl group in an aldehyde, its locant in the common system is:
�� Adjacent carbon is α-carbon. �� Greek letters are used in common nomenclature. �� α is nearest to carbonyl group.
In the common naming system, the carbon directly attached to the carbonyl carbon is called the α-carbon. Any substituent attached to this carbon is described using the α-locant.
- �� Options A and B are numerical locants used in IUPAC nomenclature.
- �� Option D refers to the next carbon after α.
Used
- Passage-Based Concept
- Adjacent carbon = Alpha carbon.
11 For IUPAC naming of aliphatic open chain aldehydes, the longest carbon chain must:
�� Aldehyde carbon always gets position 1. �� Numbering starts from the –CHO carbon. �� Ensures correct IUPAC nomenclature.
In aldehydes, the carbon atom of the aldehyde group is always included in the parent chain and is assigned carbon number 1. Therefore, numbering begins from the aldehyde carbon.
- �� Option A → Aldehyde carbon must be included.
- �� Option C → Substituents do not determine numbering priority.
- �� Option D → Largest alkyl group is irrelevant.
Used
- IUPAC Rule Recall
- CHO carbon = Carbon-1.
12 What is the IUPAC name for Diisopropyl ketone?
�� Diisopropyl ketone contains two isopropyl groups. �� Longest chain has five carbon atoms. �� Ketone group is at carbon 3.
Structure: (CH₃)₂CH–CO–CH(CH₃)₂ The longest chain contains five carbons with the carbonyl carbon at position 3 and methyl substituents at positions 2 and 4. Hence the IUPAC name is: 2,4-Dimethylpentan-3-one
- �� Option B → Missing one methyl substituent.
- �� Option C → Incorrect numbering.
- �� Option D → Incorrect carbon skeleton.
Used
- IUPAC Structure Analysis
- Two isopropyl groups = methyls at C-2 and C-4.
13 Identify the correct numbering formatting rule for naming substituents on a branched aldehyde carbon chain.
�� Substituents are written as prefixes. �� Positions are indicated by locants. �� Alphabetical order is followed.
In IUPAC nomenclature, substituents are named as prefixes before the parent compound name. Their positions are indicated using numerals, and multiple substituents are arranged alphabetically.
- �� Option B → Size is not used.
- �� Option C → Atomic mass is irrelevant.
- �� Option D → Substituents are prefixes, not suffixes.
Used
- Nomenclature Rule Recall
- Alphabetical prefixes + locants.
14 Arrange the following steps for deriving the IUPAC name of an open-chain ketone in the correct logical sequence:
(A) Number the chain from the end nearer to the carbonyl group.
(B) Identify the longest continuous carbon chain containing the >C=O group.
(C) Replace the '-e' ending of the parent alkane with '-one'.
(D) Prefix substituents alphabetically with their numerals.
�� Find the parent chain first. �� Number from the carbonyl end. �� Convert alkane to ketone name. �� Add substituents last.
The correct sequence is: 1. Identify the longest chain containing C=O. 2. Number it from the end nearest to the carbonyl group. 3. Replace "-e" with "-one". 4. Add substituent names and locants alphabetically. Therefore: (B) → (A) → (C) → (D)
- �� Options A, C and D do not follow standard IUPAC procedure.
Used
- Ordering
- Chain → Number → One → Prefixes.
15 The common name α-Methylcyclohexanone has the systematic IUPAC name:
�� Carbonyl carbon is position 1. �� α-carbon is adjacent to carbonyl carbon. �� Methyl group is therefore at carbon 2.
In cyclohexanone, numbering begins at the carbonyl carbon. The α-carbon is the carbon directly adjacent to the carbonyl carbon, which corresponds to carbon 2. Hence: α-Methylcyclohexanone = 2-Methylcyclohexanone
- �� Option A → Incorrect locant assignment.
- �� Option C → Methyl group would be at β-position.
- �� Option D → Different naming system.
Used
- Cyclic Ketone Numbering
- α-position = Carbon-2.
16 When naming cyclic compounds with an attached aldehyde group:
1. The suffix carbaldehyde is added after the full name of the cycloalkane.
2. The numbering of the ring starts from the carbon atom attached to the aldehyde group.
3. It is named identically to open-chain aldehydes using the suffix -al.
�� Cyclic aldehydes use the suffix "carbaldehyde". �� Ring numbering starts at the carbon attached to CHO. �� Suffix "-al" is not used directly.
For aldehydes attached directly to a cycloalkane ring, the suffix carbaldehyde is used. The carbon attached to the aldehyde group is assigned position 1 for numbering purposes.
- �� Statement 3 is incorrect.
- �� Open-chain aldehydes use "-al", whereas cyclic aldehydes use "carbaldehyde".
- �� Options B, C and D include statement 3.
Used
- Statement Analysis
- Ring + CHO = Carbaldehyde.
17 The compound Phthaldehyde consists of a benzene ring with two aldehyde groups. Its IUPAC name is:
�� Phthaldehyde is the ortho isomer. �� Aldehyde groups occupy positions 1 and 2. �� Hence "1,2-dicarbaldehyde".
Phthaldehyde contains two aldehyde groups attached to adjacent carbon atoms of a benzene ring (ortho arrangement). Therefore, its IUPAC name is: Benzene-1,2-dicarbaldehyde
- �� Option A → Contains only one aldehyde group.
- �� Option C → Meta isomer.
- �� Option D → Para isomer.
Used
- Aromatic Compound Identification
- Phthal = Ortho = 1,2.
18 In naming substituted benzaldehydes via IUPAC rules, the ring numbering assigns position 1 to:
�� Aldehyde group has highest priority. �� Carbon attached to CHO becomes carbon-1. �� All other substituents are numbered relative to it.
For substituted benzaldehydes, numbering starts from the carbon atom directly attached to the aldehyde group because it is the principal functional group.
- �� Options A and C have lower priority.
- �� Option D violates IUPAC rules.
Used
- Priority Rule Application
- CHO always gets position 1.
19 Mesityl oxide has the corresponding IUPAC name:
�� Mesityl oxide is an α,β-unsaturated ketone. �� Contains five carbons. �� Has one methyl substituent and one double bond.
Mesityl oxide has the structure: CH₃COCH=C(CH₃)CH₃ The correct IUPAC name is: 4-Methylpent-3-en-2-one
- �� Option B → Saturated ketone.
- �� Option C → Incorrect numbering.
- �� Option D → No double bond or methyl substituent.
Used
- IUPAC Structure Recognition
- Mesityl oxide = Unsaturated ketone.
20 Match the Common Name with the correct IUPAC Name from the examples table:
| List-I | List-II |
|---|---|
| 1. Isobutyraldehyde | a. 2-Methylpropanal |
| 2. Valeraldehyde | b. Pentanal |
| 3. Acrolein | c. Prop-2-enal |
�� Isobutyraldehyde → 2-Methylpropanal. �� Valeraldehyde → Pentanal. �� Acrolein → Prop-2-enal.
Common Name — IUPAC Name Isobutyraldehyde — 2-Methylpropanal Valeraldehyde — Pentanal Acrolein — Prop-2-enal Therefore: 1-a, 2-b, 3-c
- �� Options B, C and D contain incorrect pairings.
Used
- Match the Following
- Acrolein = Prop-2-enal.
