CUET UG Chemistry Booster Test - 2Diazonium Salts -

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CUET UG Chemistry Booster Test - 2Diazonium Salts

⏱️ 30 Minutes

❓ 20 Questions

📌 Answers are locked once submitted — results and explanations appear at the end.

CUET UG Chemistry Booster Test - 2Diazonium Salts

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QUESTION 1 OF 20

In the general formula for diazonium salts (ArN₂⁺X⁻), what is the correct identity of the components?

Answer Review

1 In the general formula for diazonium salts (ArN₂⁺X⁻), what is the correct identity of the components?

A Ar is an alkyl group, X is a cation

B Ar is an aryl group, X is an anion like chloride or fluoroborate

C Ar is an aryl group, X is a metal ion

D Ar is an amine group, X is a halogen gas

💡 Short Explanation

�� Ar represents an aromatic (aryl) group. �� X⁻ acts as the counter anion. �� Common anions include Cl⁻ and BF₄⁻.

✅ Correct Answer Explanation

Diazonium salts have the general formula ArN₂⁺X⁻. → Here, Ar denotes an aryl group such as phenyl (C₆H₅–). → X⁻ is an anion such as chloride, bromide, hydrogensulphate, or fluoroborate. → Thus Option B correctly identifies both components.

❓ Why Other Options Are Incorrect

�� Option A → Ar is not an alkyl group.
�� Option C → X is an anion, not a metal ion.
�� Option D → Ar is not an amine group and X is not a halogen gas.

🎯 Strategy

Used

Elimination

Application:

�� Identify the correct meaning of Ar and X⁻ in diazonium salts.

Final Logic:

�� Ar = aryl group and X⁻ = counter anion.

🧠 Memory Trick

Ar = Aromatic Ring

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Diazonium Salts

2 What is the IUPAC name of the compound C₆H₅N₂⁺HSO₄⁻?

A Benzenediazonium chloride

B Benzenediazonium hydrogensulphate

C Phenyl nitrogen sulphate

D Diazonium benzene sulphide

💡 Short Explanation

�� C₆H₅N₂⁺ is the benzenediazonium ion. �� HSO₄⁻ is hydrogensulphate ion. �� Both combine to form benzenediazonium hydrogensulphate.

✅ Correct Answer Explanation

The cation is benzenediazonium ion. → The counter ion is hydrogensulphate (HSO₄⁻). → Therefore the correct name is Benzenediazonium hydrogensulphate.

❓ Why Other Options Are Incorrect

�� Option A → Contains chloride instead of hydrogensulphate.
�� Option C → Not accepted nomenclature.
�� Option D → Incorrect naming format.

🎯 Strategy

Used

Substitution

Application:

�� Identify cation and anion separately.

Final Logic:

�� Benzenediazonium + HSO₄⁻ = Benzenediazonium hydrogensulphate.

🧠 Memory Trick

HSO₄⁻ → Hydrogensulphate

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Diazonium Salt Nomenclature

3 Why are arenediazonium salts more stable than alkyldiazonium salts?

A Aryl groups are less bulky than alkyl groups.

B The positive charge on the diazonium ion is dispersed due to resonance with the benzene ring.

C Alkyl groups have a strong +I effect that destabilizes the nitrogen.

D They are prepared at higher temperatures.

💡 Short Explanation

�� Aromatic rings allow resonance stabilization. �� Positive charge becomes delocalized. �� This increases stability.

✅ Correct Answer Explanation

Arenediazonium ions are stabilized through resonance with the aromatic ring. → Delocalization of positive charge lowers the energy of the ion. → Alkyldiazonium ions lack this resonance stabilization and therefore decompose readily.

❓ Why Other Options Are Incorrect

�� Option A → Bulkiness is not the main reason.
�� Option C → Not the primary explanation.
�� Option D → Stability is not due to preparation temperature.

🎯 Strategy

Used

Conceptual Reasoning

Application:

�� Compare resonance stabilization in aryl and alkyl systems.

Final Logic:

�� Resonance stabilizes arenediazonium salts.

🧠 Memory Trick

Aryl + Resonance = Stability

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Stability of Diazonium Salts

4 Aliphatic amines form highly unstable diazonium salts. According to the text, what gas is liberated quantitatively during this process?

A Hydrogen gas

B Oxygen gas

C Nitrogen gas

D Chlorine gas

💡 Short Explanation

�� Alkyldiazonium salts are unstable. �� They decompose rapidly. �� Nitrogen gas is released quantitatively.

✅ Correct Answer Explanation

Alkyldiazonium salts decompose almost immediately after formation. → The diazonium group leaves as highly stable molecular nitrogen (N₂). → Nitrogen gas evolution is quantitative.

❓ Why Other Options Are Incorrect

�� Option A → Hydrogen is not produced.
�� Option B → Oxygen is not released.
�� Option D → Chlorine gas is not formed.

🎯 Strategy

Used

NCERT Fact Recall

Application:

�� Recall decomposition behavior of alkyldiazonium salts.

Final Logic:

�� Nitrogen gas is evolved.

🧠 Memory Trick

Diazonium → N₂ Out

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Alkyldiazonium Salts

5 During the preparation of diazonium salts, nitrous acid is not added directly. How is it produced?

A By heating nitric acid

B By the reaction of sodium nitrite with hydrochloric acid in situ

C By passing NO₂ gas through water

D By the oxidation of ammonia

💡 Short Explanation

�� Nitrous acid is unstable. �� It is generated in situ. �� NaNO₂ and HCl are used.

✅ Correct Answer Explanation

Nitrous acid (HNO₂) is unstable and cannot be stored. → Therefore it is generated in the reaction mixture: [ NaNO_2 + HCl \rightarrow HNO_2 + NaCl ] → This freshly formed nitrous acid then diazotizes the aromatic amine.

❓ Why Other Options Are Incorrect

�� Option A → Does not generate HNO₂.
�� Option C → Not the NCERT preparation method.
�� Option D → Unrelated process.

🎯 Strategy

Used

Contextual Matching

Application:

�� Recall diazotisation conditions.

Final Logic:

�� HNO₂ is generated from NaNO₂ and HCl.

🧠 Memory Trick

NaNO₂ + HCl = HNO₂

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Diazotisation

6 Identify the reaction type:
The conversion of primary aromatic amines to diazonium salts is called:

A Acetylation

B Nitration

C Diazotisation

D Ammonolysis

💡 Short Explanation

�� Aromatic amine reacts with nitrous acid. �� Diazonium salt is formed. �� The process is diazotisation.

✅ Correct Answer Explanation

Conversion of primary aromatic amines into diazonium salts using nitrous acid at low temperature is called diazotisation.

❓ Why Other Options Are Incorrect

�� Option A → Acetylation introduces an acetyl group.
�� Option B → Nitration introduces NO₂.
�� Option D → Ammonolysis involves NH₃ substitution.

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

�� Match the reaction description to the named reaction.

Final Logic:

�� Aromatic amine → Diazonium salt = Diazotisation.

🧠 Memory Trick

Diazo Salt → Diazotisation

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Diazotisation

7 Arrange the optimal temperatures for the following processes in increasing order:
Diazotisation of aniline
Hydrolysis of diazonium salt to phenol
Heating anilinium hydrogensulphate to form sulphanilic acid

A I, II, III

B II, I, III

C III, I, II

D I, III, II

💡 Short Explanation

�� Diazotisation occurs at 273–278 K. �� Hydrolysis occurs around 283 K. �� Sulphanilic acid formation requires much higher temperature.

✅ Correct Answer Explanation

Diazotisation: 273–278 K → Hydrolysis to phenol: ~283 K → Sulphanilic acid formation: much higher heating temperature Hence: I < II < III

❓ Why Other Options Are Incorrect

�� Options B, C, D do not follow the actual temperature sequence.

🎯 Strategy

Used

Ordering

Application:

�� Compare standard reaction temperatures.

Final Logic:

�� Diazotisation < Hydrolysis < Sulphanilic acid formation.

🧠 Memory Trick

Diazo → Phenol → Sulphanilic

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Diazotisation and Sulphanilic Acid

8 Why is the diazonium salt not generally stored?

A It is highly volatile and evaporates.

B It is highly unstable and must be used immediately after preparation.

C It reacts with glass containers.

D It polymerizes into a plastic mass.

💡 Short Explanation

�� Diazonium salts are unstable. �� They decompose on standing. �� Therefore they are used immediately.

✅ Correct Answer Explanation

Arenediazonium salts remain stable only at low temperatures. → On warming or prolonged storage they decompose. → Hence they are generally prepared fresh and used immediately.

❓ Why Other Options Are Incorrect

�� Option A → They do not evaporate.
�� Option C → They do not react with glass.
�� Option D → Polymerization is not the issue.

🎯 Strategy

Used

Elimination

Application:

�� Identify the principal limitation of diazonium salts.

Final Logic:

�� Instability prevents storage.

🧠 Memory Trick

Prepare Fresh, Use Fresh

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Stability of Diazonium Salts

9 List 1 (Diazonium Compound) | List 2 (Behavior Towards Water)

List 1	List 2
1. Benzenediazonium chloride (cold)	a. Soluble and stable
2. Benzenediazonium chloride (warm)	b. Reacts to form phenol
3. Benzenediazonium fluoroborate	c. Insoluble in water

A 1-a, 2-b, 3-c

B 1-c, 2-a, 3-b

C 1-b, 2-c, 3-a

D 1-c, 2-b, 3-a

💡 Short Explanation

�� Cold diazonium chloride is stable and soluble. �� Warm solution gives phenol. �� Fluoroborate is water insoluble.

✅ Correct Answer Explanation

Benzenediazonium chloride (cold) → soluble and stable. → Benzenediazonium chloride (warm) → hydrolyses to phenol. → Benzenediazonium fluoroborate → insoluble in water. Thus: 1 → a 2 → b 3 → c

❓ Why Other Options Are Incorrect

�� Options B, C, and D incorrectly interchange the properties.

🎯 Strategy

Used

Option Grouping

Application:

�� Match each diazonium salt with its known behavior.

Final Logic:

�� Cold stable, warm hydrolysis, fluoroborate insoluble.

🧠 Memory Trick

Cold-Stable, Warm-Phenol

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Properties of Diazonium Salts

10 What happens to benzenediazonium chloride if it is left to dry completely?

A It becomes more stable.

B It sublimates.

C It decomposes easily.

D It transforms into benzenediazonium fluoroborate.

💡 Short Explanation

�� Dry diazonium salts are unstable. �� They decompose readily. �� Therefore they are handled in solution.

✅ Correct Answer Explanation

Benzenediazonium chloride is relatively stable only in cold aqueous solution. → In the dry state it becomes highly unstable and decomposes easily. → This is why it is generally not isolated as a dry solid.

❓ Why Other Options Are Incorrect

�� Option A → Stability decreases.
�� Option B → Sublimation does not occur.
�� Option D → No such conversion occurs.

🎯 Strategy

Used

NCERT Fact Recall

Application:

�� Recall the physical properties of benzenediazonium chloride.

Final Logic:

�� Dry benzenediazonium chloride decomposes readily.

🧠 Memory Trick

Dry Diazonium = Decomposition

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Physical Properties of Diazonium Salts

📄 Passage

Diazonium group being a very good leaving group, is substituted by other groups such as Cl⁻, Br⁻, I⁻, CN⁻ and OH⁻ which displace nitrogen from the aromatic ring. The nitrogen formed escapes from the reaction mixture as a gas. Replacement by halide or cyanide ion: The Cl⁻, Br⁻ and CN⁻ nucleophiles can easily be introduced in the benzene ring in the presence of Cu(I) ion. This reaction is called Sandmeyer reaction.

Based on the passage, what happens to the nitrogen from the diazonium group during displacement?

A It becomes part of the cyanide group.

B It gets reduced to ammonia.

C It escapes from the reaction mixture as a gas.

D It forms a precipitate with Cu(I).

💡 Short Explanation

�� Diazonium group is a good leaving group. �� Nitrogen leaves as N₂ gas. �� This drives the substitution reaction.

✅ Correct Answer Explanation

During displacement reactions of diazonium salts, the diazonium group is replaced by groups such as Cl⁻, Br⁻, CN⁻ or OH⁻. → The nitrogen part leaves the aromatic ring as molecular nitrogen gas. → Since N₂ is very stable, its escape helps the reaction proceed forward.

❓ Why Other Options Are Incorrect

�� Option A → Nitrogen does not become part of cyanide.
�� Option B → It is not reduced to ammonia.
�� Option D → It does not form a precipitate with Cu(I).

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

�� The passage directly states that nitrogen escapes as gas.

Final Logic:

�� Diazonium displacement releases N₂ gas.

🧠 Memory Trick

Diazonium → N₂ escapes

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Displacement Reactions of Diazonium Salts

📄 Passage

Based on the passage, which nucleophiles are explicitly mentioned to be introduced via the Sandmeyer reaction?

A F⁻, OH⁻, I⁻

B Cl⁻, Br⁻, CN⁻

C NO₂⁻, SO₃H⁻

D CH₃⁻, NH₂⁻

💡 Short Explanation

�� Sandmeyer reaction uses Cu(I) ion. �� Cl⁻, Br⁻ and CN⁻ are introduced. �� These replace the diazonium group.

✅ Correct Answer Explanation

The passage states that Cl⁻, Br⁻ and CN⁻ nucleophiles can be introduced into the benzene ring in the presence of Cu(I) ion. → This named reaction is called the Sandmeyer reaction.

❓ Why Other Options Are Incorrect

�� Option A → These are not the Sandmeyer set mentioned in the passage.
�� Option C → NO₂⁻ and SO₃H⁻ are not mentioned for Sandmeyer reaction.
�� Option D → CH₃⁻ and NH₂⁻ are not used in this reaction.

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

�� Use the exact nucleophiles given in the passage.

Final Logic:

�� Sandmeyer introduces Cl⁻, Br⁻ and CN⁻.

🧠 Memory Trick

Sandmeyer = Cl, Br, CN

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Sandmeyer Reaction

13 If you want to introduce a bromine atom into a benzene ring using copper powder and HBr, the reaction is known as:

A Sandmeyer reaction

B Gattermann reaction

C Hofmann bromamide degradation

D Carbylamine reaction

💡 Short Explanation

�� Gattermann reaction uses copper powder. �� HBr introduces bromine. �� Diazonium group is replaced by Br.

✅ Correct Answer Explanation

In the Gattermann reaction, diazonium salts are treated with copper powder and corresponding halogen acid such as HCl or HBr. → When HBr is used, bromine is introduced into the benzene ring. → Therefore, copper powder + HBr indicates Gattermann reaction.

❓ Why Other Options Are Incorrect

�� Option A → Sandmeyer reaction uses Cu(I) salts like CuBr, not copper powder with HBr.
�� Option C → Hofmann bromamide degradation converts amides to amines.
�� Option D → Carbylamine reaction forms isocyanides.

🎯 Strategy

Used

Elimination

Application:

�� Identify the named reaction from the reagent copper powder.

Final Logic:

�� Copper powder + HBr = Gattermann reaction.

🧠 Memory Trick

Gattermann = Copper Powder

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Gattermann Reaction

14 Consider the following regarding Sandmeyer and Gattermann reactions:
Both reactions introduce halogens into the benzene ring.
Sandmeyer uses Cu(I) ion while Gattermann uses copper powder.
Gattermann reaction provides a better yield than Sandmeyer.

A I and II only

B II and III only

C I and III only

D I, II, and III

💡 Short Explanation

�� Both can introduce Cl or Br. �� Sandmeyer uses Cu(I) salts. �� Gattermann uses copper powder.

✅ Correct Answer Explanation

Statement I is correct because both Sandmeyer and Gattermann reactions can replace the diazonium group with halogens like chlorine or bromine. → Statement II is correct because Sandmeyer uses Cu(I) salts, while Gattermann uses copper powder with corresponding acids. → Statement III is incorrect because Sandmeyer generally gives better yield than Gattermann.

❓ Why Other Options Are Incorrect

�� Option B → Includes incorrect Statement III and omits Statement I.
�� Option C → Includes incorrect Statement III and omits Statement II.
�� Option D → Statement III is incorrect.

🎯 Strategy

Used

Option Grouping

Application:

�� Check each statement using named reaction differences.

Final Logic:

�� I and II are correct; III is wrong.

🧠 Memory Trick

Sandmeyer Salt, Gattermann Powder

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Sandmeyer and Gattermann Reactions

15 When benzenediazonium chloride is treated with potassium iodide, what is the main organic product?

A Phenol

B Iodobenzene

C Cyanobenzene

D Fluorobenzene

💡 Short Explanation

�� KI provides iodide ion. �� Diazonium group is replaced by iodine. �� Product is iodobenzene.

✅ Correct Answer Explanation

Benzenediazonium chloride reacts with potassium iodide, where iodide ion replaces the diazonium group on the benzene ring. → Nitrogen gas is released, and the final aromatic product is iodobenzene. [C_6H_5N_2^+Cl^- + KI C_6H_5I + KCl + N_2]

❓ Why Other Options Are Incorrect

�� Option A → Phenol forms by hydrolysis of diazonium salt.
�� Option C → Cyanobenzene forms using CuCN.
�� Option D → Fluorobenzene forms via benzenediazonium fluoroborate.

🎯 Strategy

Used

Substitution

Application:

�� Identify the group supplied by KI.

Final Logic:

�� KI supplies I⁻, so the product is iodobenzene.

🧠 Memory Trick

KI gives Iodobenzene

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Replacement Reactions of Diazonium Salts

16 Which reducing agent is oxidised to phosphorous acid when reducing a diazonium salt to an arene?

A Ethanol

B Hydrochloric acid

C Hypophosphorous acid (phosphinic acid)

D Nitrous acid

💡 Short Explanation

�� Hypophosphorous acid acts as a reducing agent. �� It converts diazonium salts into arenes. �� During the reaction it is oxidized to phosphorous acid.

✅ Correct Answer Explanation

Arenediazonium salts can be reduced to arenes using hypophosphorous acid (H₃PO₂). → In this reaction, the diazonium group is replaced by hydrogen. → Hypophosphorous acid itself gets oxidized to phosphorous acid (H₃PO₃). [ ArN_2^+X^- \xrightarrow{H_3PO_2} ArH + N_2 ]

❓ Why Other Options Are Incorrect

�� Option A → Ethanol reduces diazonium salts but is oxidized to ethanal, not phosphorous acid.
�� Option B → Hydrochloric acid is not the reducing agent.
�� Option D → Nitrous acid is used in diazotisation, not reduction.

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

�� Focus on the clue "oxidised to phosphorous acid."

Final Logic:

�� Only hypophosphorous acid forms phosphorous acid upon oxidation.

🧠 Memory Trick

H₃PO₂ → H₃PO₃

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Reduction of Diazonium Salts

17 In a coupling reaction, at which position does the phenol molecule predominantly couple with the diazonium salt?

A Ortho position

B Meta position

C Para position

D Ipso position

💡 Short Explanation

�� Phenol activates ortho and para positions. �� Para position is less sterically hindered. �� Major azo dye forms at the para position.

✅ Correct Answer Explanation

In coupling reactions, the diazonium ion acts as an electrophile. → Phenol activates the aromatic ring through resonance. → Coupling occurs mainly at the para position because it is more accessible and less sterically crowded than the ortho position. → The major product formed is p-hydroxyazobenzene.

❓ Why Other Options Are Incorrect

�� Option A → Ortho product may form in minor amounts.
�� Option B → Meta position is not activated by –OH.
�� Option D → Ipso substitution does not occur here.

🎯 Strategy

Used

Conceptual Elimination

Application:

�� Use directing effects of the hydroxyl group.

Final Logic:

�� Phenol couples predominantly at the para position.

🧠 Memory Trick

Phenol + Diazonium = Para Product

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Coupling Reactions

18 Identify the reaction type:
The coupling reaction of a diazonium salt with aniline is an example of:

A Nucleophilic addition

B Electrophilic substitution

C Free radical substitution

D Elimination

💡 Short Explanation

�� Diazonium ion behaves as an electrophile. �� Aniline ring undergoes substitution. �� The reaction forms azo compounds.

✅ Correct Answer Explanation

The diazonium ion attacks the activated aromatic ring of aniline. → A hydrogen atom on the aromatic ring is replaced by the azo group. → Since substitution occurs via an electrophile, the process is classified as an electrophilic substitution reaction.

❓ Why Other Options Are Incorrect

�� Option A → No addition reaction occurs.
�� Option C → Free radicals are not involved.
�� Option D → No elimination takes place.

🎯 Strategy

Used

Contextual/Tonal Matching

Application:

�� Identify the mechanism involved in azo coupling.

Final Logic:

�� Coupling proceeds through electrophilic aromatic substitution.

🧠 Memory Trick

Azo Coupling = EAS

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Coupling Reactions

19 Why are diazonium salts considered important for synthesizing aryl fluorides and iodides?

A Because they are the only compounds that contain halogens.

B Because aryl fluorides and iodides cannot be prepared by direct halogenation of benzene.

C Because diazonium salts are cheaper than halogens.

D Because the reaction is endothermic.

💡 Short Explanation

�� Direct fluorination is difficult to control. �� Direct iodination is not a convenient preparation route. �� Diazonium salts provide an effective alternative.

✅ Correct Answer Explanation

Diazonium salts serve as versatile intermediates for introducing F and I into aromatic rings. → Aryl fluorides are commonly prepared using the Balz–Schiemann reaction. → Aryl iodides are readily obtained by treatment of diazonium salts with KI. → These compounds are not conveniently prepared by direct halogenation of benzene.

❓ Why Other Options Are Incorrect

�� Option A → Many compounds contain halogens.
�� Option C → Cost is not the reason.
�� Option D → Endothermic nature is irrelevant.

🎯 Strategy

Used

NCERT Fact Recall

Application:

�� Recall the synthetic importance of diazonium salts.

Final Logic:

�� Diazonium salts provide routes unavailable through simple direct halogenation.

🧠 Memory Trick

Diazonium → F and I Gateway

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Importance of Diazonium Salts

20 Arrange the following compounds based on their molecular mass (from lowest to highest):
I. Benzene
II. Chlorobenzene
III. Benzenediazonium chloride

A I, II, III

B III, II, I

C II, I, III

D I, III, II

💡 Short Explanation

�� Benzene contains only C and H. �� Chlorobenzene contains one chlorine atom. �� Benzenediazonium chloride contains N₂ and Cl, giving the highest mass.

✅ Correct Answer Explanation

Approximate molar masses: • Benzene (C₆H₆) ≈ 78.1 g mol⁻¹ • Chlorobenzene (C₆H₅Cl) ≈ 112.5 g mol⁻¹ • Benzenediazonium chloride (C₆H₅N₂Cl) ≈ 140.6 g mol⁻¹ Therefore: [ {Benzene} < {Chlorobenzene} < {Benzenediazonium chloride}] Hence: I → II → III

❓ Why Other Options Are Incorrect

�� Option B → Reverse order.
�� Option C → Chlorobenzene is heavier than benzene.
�� Option D → Benzenediazonium chloride is heavier than chlorobenzene.

🎯 Strategy

Used

Dimensional/Unit Analysis

Application:

�� Compare molecular masses based on atomic composition.

Final Logic:

�� Addition of Cl and N₂ increases molecular mass successively.

🧠 Memory Trick

Benzene < Chlorobenzene < Diazonium Salt

📚 Class XII – Chemistry Part II – Chapter: Amines – Topic: Diazonium Salts and Their Properties

CUET UG Chemistry Booster Test – 2Diazonium Salts

CUET UG Chemistry Booster Test - 2Diazonium Salts

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